9Jun, 2020
Mixed Quantitative Aptitude Questions Set 203
  1. The present age of Aisha is 12 years more the present age of Rahuman. After 5 years the ratio of ages of Rahuman and Aisha will be 3: 5, then find the age of Rahuman, after 2 years?
    10
    15
    20
    25
    30
    Option B
    Present age of Aisha = 12 + Present age of Rahul

    After 10 years, the ratio of ages of Rahuman and Aisha = 3: 5 (3x, 5x)

    5x – 3x = 12

    2x = 12

    x = 6

    The age of Rahuman, after 2 years = 3x – 5 + 2 = 15 years

     

  2. The present age of N is twice the present age of P. The ratio between the present ages of Q and P is 7: 4. If the age of N after 6 years will be 30 years, then find the age of Q before 6 years?
    15
    20
    25
    30
    25
    Option A
    The ratio of present age of N and P = 2 : 1

    The ratio of present age of Q and P = 7 : 4

    The present age of N, P and Q = 8 : 4 : 7

    The age of N, after 6 years = 30 years

    The present age of N = 24 years

    8’s = 24

    1’s = 3

    The age of Q before 6 years = 7x – 6 = 15 years

     

  3. Akil started the business investing Rs. 19000 and after 6 months Anush joined him with Rs. 28000. At the end of one year the total profit is Rs.16500.Akil’s profit share?

    4500
    5500
    7500
    8500
    9500
    Option E
    Akil’s share

    = > 19/33*16500

    = > Rs.9500

     

  4. Akil started the business investing Rs. 19000 and after 6 months Anush joined him with Rs. 28000. At the end of one year the total profit is Rs.16500.Anush’s profit share?
    7000
    2000
    5000
    3000
    6000
    Option A
    = > 14/33 * 16500

    = > 7000

     

  5. Two expresses running the same direction at the speed of 60kmph and 80kmph respectively. If the length of the expresses is 200m and 100m respectively, then find the time taken by first express crosses the second one?

    51
    52
    53
    54
    55
    Option D
    300 = (80-60) * (5/18) * x

    300 = 20 * (5/18) * x

    x = 54 seconds

     

  6. The train 1 crosses the pole in 18 seconds at the speed of 60kmph and the train 1 crosses the 700m train 2 which is running opposite direction of train 1 at the speed of 20kmph, then find the time taken by train 1 crosses the another train?
    40
    45
    30
    35
    20
    Option B
    x = 60 * 5/18 * 18

    x = 300m

    300+700 = 80 * 5/18 * x

    x = 45 seconds

     

  7. Time taken by A to complete 1/5th of work, if B takes 6 days to complete 3/5th of work and together they take 5 days to complete 3/4th of work?
    3
    4
    5
    6
    7
    Option B
    A and B completes 3/4th work in 5 days, so complete 1 work in 4/3 * 5 = 20/3 days

    B complete 3/5 work in 6 days, so complete work in 5/3 * 6 = 10 days

    So in 1 day A completes = 3/20 – 1/10 = 1/20

    So to complete 1/5th work = 1/5 * 20 = 4 days

     

  8. Time taken by a Sadhapthi express to cross a plat form of length 60 km given that it crosses a pole in two and a half hours running at 60 km/hr?
    3
    3.5
    4
    4.5
    5
    Option B
    Length of train = 2.5 * 60 = 150 km

    So time taken to cross platform of length 60 km with speed 60 km/hr

    = (150+60)/60

    = 3.5 hrs

     

  9. A bag contains 4 Red flowers, 3 white flowers, 5 orange flowers and 6 pink flowers. If two flowerss are drawn out randomly, then find the probability that both are either orange or pink?
    25 / 153
    15 / 153
    25 / 154
    12/ 153
    25 / 143
    Option A
    Total number of flowers = 4 + 3 + 5 + 6 = 18 flowers

    n(S) = 18C2

    Probability that both Orange or pink

    n(E) = 5C2 or 6C2

    P(E) = n(E) / n(S) = [5C2 or 6C2] / 18C2

    P(E) = 25 / 153

     

  10. A bag contains 4 Red marbles, 3 white marbles, 5 orange marbles and 6 blue marbles. If four marbles are drawn out randomly, then find the probability that all the marbles are of different colours?

    1/13
    2/17
    3/14
    4/15
    4/18
    Option B
    n(S) = 18C4

    n(E) = 4C1 and 3C1 and 5C1 and 6C1

    P(E) = n(E) / n(S) = [4C1 or 3C1 or 5C1 or 6C1] / 18C4

    P(E) = (4 * 3 * 5 * 6) / [(18 * 17 * 16 * 15) / (1 * 2 * 3 * 4)]

    P(E) = 2 / 17