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    18Oct, 2021
    Mixed Quantitative Aptitude Questions Set 229
    1. 375 ml of mixture contains milk and water in the ratio of 16 : 9 respectively. If x ml of water is added into the mixture then the ratio of milk to water in the resultant mixture becomes 3 : 2, find the value x.
      30
      25
      35
      40
      45
      Option B
      Quantity of milk = 375 * 16/25 = 240
      quantity of water = 375 * 9/25 = 135
      ATQ,
      240/135 + x = 3/2
      3x + 405 = 480
      x = 25

       

    2. A and B alone can complete a piece of work in 24 days and 20 days respectively. If efficiency of C is 60% more than A, then find in how many days C complete the work ?
      15 days
      17 days
      20 days
      25 days
      30 days
      Option A
      LCM of 24 and 20 = 120
      efficiency of A = 120/24 = 5
      efficiency of B = 120/20 = 6
      efficiency of C = 5 * 160/100 = 8
      time required = 120/8 = 15 days

       

    3. A shopkeeper marked up an article 25% above its cost price and allowed a discount of 40% on it. If shopkeeper made a loss of rs.128, then find what is the cost price ?
      620
      340
      580
      512
      480
      Option D
      Let CP of article = 100x
      MP of article = 100x * 125/100 = 125x
      SP of article = 125x * 60/100 = 75x
      loss = 100x – 75x = 25x
      CP of article = 128/25x * 100x = 512

       

    4. P and Q started a partnership business with investment of rs.15000 and rs.12000 for 8 months and 6 months respectively. If total profit of the business is 6400, then what is profit share of P ?
      3200
      4450
      3800
      4200
      4000
      Option E
      Profit sharing ratio of P and Q = 15000 * 8 : 12000 * 6 = 5 : 3
      profit share of P = 6400 * 5/8 = 4000

       

    5. A man invested rs. 25000 at the rate of 20% in compound interest for 1 year. How much amount he received if he invested for compounded half yearly.
      42000
      22000
      30250
      28140
      34400
      Option C
      Rate of compound interest for half yearly = 20/2 = 10%
      rate of CI after 1 year = 10 + 10 + 10 * 10/100 = 21%
      CI = 25000 * 21/100 = 5250
      amount = 25000 + 5250 = 30250

       

    6. Directions : What will come in place of questions mark in the following questions given below ?
      20^2 + 328 – 84 = 28% of 300 + ?
      320
      480
      340
      610
      560
      Option E
      400 + 328 – 84 = 84 + ?
      ? = 560

       

    7. √1156 + 12^2 – 19 * 5 = ?
      82
      84
      83
      92
      93
      Option C
      34 + 144 – 95 = ?
      ? = 83

       

    8. 42% of 800 + 120% of 1400 – 520 = ?
      3200
      1496
      1445
      1296
      2050
      Option B
      336 + 1680 – 520 = ?
      ? = 1496

       

    9. 450/3 + 320 – 210 + 150 = ?
      520
      440
      420
      450
      410
      Option E
      150 + 320 + 150 – 210 = ?
      ? = 410

       

    10. 350 ÷ 7 of 25 + 340 + (12)^2 = ?
      328
      486
      284
      320
      325
      Option B
      350 /(7 * 25) + 340 + 144 = ?
      ? = 486

       

    01
    17Oct, 2021
    Mixed Quantitative Aptitude Questions Set 228
    1. 4 men or 8 women can do a work in 15 days, then in how many days 6 men and 12 women can complete the whole work ?
      4 days
      3 days
      5 days
      6 days
      8 days
      Option C
      Efficiency ratio of men and women = 2 : 1
      total work = 4 * 2 * 15 = 120
      days required = 120/ 6 * 2 + 12 * 1 = 5 days

       

    2. If simple interest earned on a certain sum of money at certain rate of interest after 5 years is 2/7 times the amount earned on the same sum of money after 5 years, then what is the rate interest ?
      10%
      6%
      12%
      8%
      15%
      Option D
      Let amount = 7x
      SI = 2x
      P = 7x – 2x = 5x
      rate of interest = 2x * 100/5x * 5 = 8%

       

    3. Average of 12 numbers is 60. If average of first six and last four numbers is 70 and 50 respectively and ratio of seventh and eighth number is 3 : 2, then find the 8th number ?
      50
      40
      80
      70
      75
      Option B
      Total 12 numbers = 12 * 60 = 720
      total of first six numbers = 70 * 6 = 420
      total of last four numbers = 50 * 4 = 200
      8th number = (720 – 420 + 200) 2/5 = 100 * 2/5 = 40

       

    4. Sanjay saves 25% of his monthly income. If his monthly expenditure is increased by 40% while his monthly savings remain same, then find the percentage increase in his monthly income ?
      36%
      40%
      28%
      30%
      40%
      Option D
      Let income of Sanjay = 100x
      savings = 100x * 25/100 = 25x
      expenditure = 100x – 25x = 75x
      increased expenditure = 75x * 140/100 = 105x
      income = 105x + 25x = 130x
      % increased income = 130x – 100x/100 * 100 = 30%

       

    5. 490 ml of mixture contains milk and water in the ratio of 4 : 3 respectively. If 140 ml of mixture is taken out and 50 ml of water is added, then what is the ratio of milk to water in final mixture ?
      2 : 3
      4 : 5
      3 : 2
      1 : 1
      2 : 5
      Option D
      Quantity of milk = 490 * 4/7 = 280
      quantity of water = 490 * 3/7 = 210
      140 ml of mixture is taken out,
      (280 – 140 * 4/7)/(210 – 140 * 3/7 + 50) = 200/200 = 1 : 1

       

    6. Directions : What will come in place of questions marks (?) in the following given number series ?
      30, 62, 126, 254, 510, ?
      920
      1022
      648
      840
      1220
      Option B
      The series is (*2 + 2), (*2 + 2), (*2 + 2)…

       

    7. ?, 9, 25, 61, 125, 225
      5
      4
      6
      8
      2
      Option A
      The series is (+2^2), (+4^2), (+6^2), (+8^2), (+10^2)

       

    8. 35, 42, 56, 77, ?, 140
      135
      140
      130
      105
      112
      Option D
      The series is (+7), (+14), (+21), (+28), (+35)

       

    9. 8, 16, 48, 192, 960, ?
      4820
      5760
      1920
      3200
      9600
      Option B
      The series is (*2), (*3), (*4), (*5), (*6)

       

    10. 320, 330, 350, 385, 430, ?
      320
      520
      640
      510
      650
      Option D
      The series is difference of difference.

       

    02
    14Oct, 2021
    Mixed Quantitative Aptitude Questions Set 227
    1. A, B and C entered into a partnership business and A gets profit rs.960 out of total profit rs.5120. C invested rs.14000 for 8 months and B invested rs. 8000. If A invested rs.4000 more than that of B and 4 months less that of C, then find what is the profit share of C ?
      2120
      1345
      1240
      2240
      1050
      Option D
      Investment of A = 8000 + 4000 = 12000
      time period for investment of A = 8 – 4 = 4months
      profit sharing ratio of A, B and C = (12000 * 4) : (8000 * 12) : (14000 * 8) = 3 : 6 : 7
      profit share of C = 5120 * 7/16 = 2240

       

    2. Amit invested rs.22500 in scheme X offering 10% compound interest for 2 years. If he invested 40% of the money received by him from scheme X in another scheme Y offering 20% simple interest for 4 years, then how much amount received by him from scheme Y ?
      12340
      38450
      19602
      20505
      23420
      Option C
      CI received after 2 years = 22500 * 10/100 * 10/100 = 4725
      total amount = 22500 + 4725 = 27225
      40 % of 27225 = 10890
      SI received after 4 years = 27225 * 40/100 * 4 * 20/100 = 8712
      total amount = 10890 + 8712 = 19602

       

    3. The monthly income of A is rs.28000 and he saves 28 4/7% of his monthly income. If the monthly expenditure of B is rs.4000 more than A and also expenditure of B is 20% less than his income, then find saving of B is how much percent more or less than savings of A ?
      20%
      30%
      15%
      25%
      22%
      Option D
      Income of A = 28000
      savings of A = 28000 * 2/7 = 8000
      expenditure of A = 28000 – 8000 = 20000
      expenditure of B = 20000 + 4000 = 24000
      income of B = 24000/4 * 5 = 30000
      saving of B = 30000 – 24000 = 6000
      % less = 8000 – 6000/8000 * 100 = 25%

       

    4. The ratio of male to female in a company is 5 : 3 and the number of male in the company is 1250. If the number of female and male is increased by 10% and 8% respectively, then find what percent change in total population ?
      5.2%
      6%
      8%
      7.25%
      8.75%
      Option E
      The number of male = 1250
      the number of female = 1250/5 * 3 = 750
      the number of male after increased = 1250 * 108/100 = 1350
      the number of female after increased = 750 * 110/100 = 825
      total population = 1250 + 750 = 2000
      total population after increased = 1350 + 825 = 2175
      change in population = 2175 – 2000/2000 = 8.75%

       

    5. A man travels 150 km to a place in 3 hours 20 minutes and he returns to the starting point in 4 hours 10 minutes. Let x be the rate for the entire trip. Then in how many kilometers per hour more or less than x ?
      4 km/hr
      2 km/hr
      4.5 km/hr
      5 km/hr
      8 km/hr
      Option D
      Time taken to cover 150 km in going trip
      3 hours 20 minutes = 3 20/60 = 3 1/3 hours
      speed in going trip = 150 *3/10 = 45 km/hr
      time taken to cover 150 km in return trip = 4 hours 10 minutes = 4 1/6 hours
      speed in return trip = 150 * 6/25 = 36 km/hr
      average speed = 2 * 45 * 36/ 45 + 36 = 40 km/hr
      required difference = 45 – 40 = 5 km/hr

       

    6. Direction : What will come in place of question(?) mark in the following questions given below ?
      60% of 1800 + 24% of 3500 – 32% of 150 = ?
      1992
      1872
      2092
      1532
      1240
      Option B
      1080 + 840 – 48 = ?
      ? = 1872

       

    7. 3/5 * 4/7 * 5/12 * 1015 = ?
      120
      145
      167
      89
      52
      Option B
      ? = 3/5 * 4/7 * 5/12 * 1015
      ? = 145

       

    8. 4545 + 4320 – 2540 + 320 = ?
      3642
      2720
      4520
      6645
      3435
      Option D
      4545 + 4320 + 320 – 2540 = ?
      ? = 6645

       

    9. 330 – 345 + 421 – 22% of 1500 = ?
      76
      32
      45
      52
      65
      Option A
      330 + 421 – 345 – 330 = ?
      ? = 76

       

    10. 552 ÷ 24 * 5 + 113 – 85 = ?
      144
      143
      320
      245
      145
      Option B
      23 * 5 + 113 – 85 = ?
      ? = 143

       

    03
    9Oct, 2021
    Mixed Quantitative Aptitude Questions Set 226
    1. A shopkeeper X sold an article for rs.850 at a profit of 25%. Another shopkeeper Y sold the another article and earned 30% more profit than the profit earned by X. If the selling price of article Y is three-fifth of selling price of article X, then find the profit percent of article Y ?
      64 2/17%
      76 8/17%
      52 3/34%
      52 3/8%
      78%
      Option B
      SP of article X = 850
      CP of article X = 850 * 100/125 = 680
      profit = 170
      profit of article Y = 170*130/100 = 221
      SP of article Y = 850 * 3/5 = 510
      CP = 510 – 221 = 289
      profit percent = 221/289* 100 = 76 8/17%

       

    2. Mixture A contains milk and water in the ratio of 3 : 2 respectively, while mixture B contains water and milk in the ratio of 4 : 3 respectively. If the quantity of water in mixture B is twice the quantity of water in mixture A, then find the quantity of milk in mixture A is what percent quantity of water in mixture B ?
      68%
      60%
      82%
      75%
      56%
      Option D
      Quantity of milk and water in mixture A = 3x and 2x
      according to questions,
      quantity of water in mixture B = 2*2x = 4x
      quantity of milk in mixture B = 4x/4 *3 = 3x
      required percentage = 3x/4x*100 = 75%

       

    3. 340 liters of mixture of milk and water is contained in a container having milk and water mixed in the ratio of 3 : 1 respectively. 76 liters of this mixture is taken out from the container and replaced with (x + 7) liters of milk so that the ratio of water to milk is 6 : 11. What is the value of ‘x’ ?
      42
      48
      38
      35
      52
      Option D
      Quantity of milk in the container = 340 * 3/4 = 255
      quantity of water in the container = 340*1/4 = 85
      76 liters of mixture is taken out and (x + 7) liter of water is added.
      (255 – 57) / 85 – 19 + (x + 7) = 11/6
      198/(73 + x) = 11/6
      11x = 385
      x = 35

       

    4. A can do a piece of work in 30days while B and C together can complete the work in 20 days and A and C together can complete the work in 24 days. If B is worked in two-fifth of his efficiency, then in how many days A and B together complete half of the work ?
      8 days
      6 days
      8 1/3 days
      5 days
      10 days
      Option E
      LCM of 30 , 20 and 24 = 120
      efficiency of A = 120/30 = 4
      efficiency of B and C = 120/20 = 6
      efficiency of A and C together = 120/24 = 5
      efficiency of C = 5- 4 = 1
      efficiency of B 6- 1 = 5
      two-fifth of efficiency B = 5 * 2/5 = 2
      time required to complete half of the work = 60/2 + 4 = 10 days

       

    5. Rohan and Sivan started a business together with initial investments of rs. 1500 and rs.1800 respectively. If after 2.5 years profit share of Rohan and Sivan are rs(x + 80) and (x + 120) respectively, then find the difference between profit of Rohan and Sivan ?
      180
      120
      320
      130
      340
      Option B
      Profit sharing ratio of Rohan and Sivan = (1500 * 2.5) : (1800 * 2.5) = 5 : 6
      x + 80/x + 120 = 5/6
      6x + 480 = 5x + 600
      x = 120

       

    6. Directions : In each of these questions given below two equations. You have to solve both the equations and give answer.
      I. x^2 – 7√3 + 36 = 0
      II. y^2 – 6√2 + 16 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 – 4√3 – 3√3 + 36 = 0
      x = 4√3 , 3√3
      II. y^2 – 4√2 – 2√2 + 16 = 0
      y = 4√2, 2√2

       

    7. I. x^2 + √2x – 12 = 0
      II. y^2 – 8√3 + 48 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option B
      I. x^2 + 3√2 – 2√2 – 12 = 0
      x = -3√2, 2√2
      II. y^2 – 4√3 – 4√3 + 48 = 0
      y = 4√3, 4√3

       

    8. I. x^2 – 36 = 0
      II. y^2 – 15y + 36 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 = 36
      x = 6, -6
      II. y^2 – 12y – 3y + 36 = 0
      y = 12, 3

       

    9. I. y^2 = 144
      II. 2x^2 – 12x + 16 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. y^2 = 144
      y = 12, -12
      II. 2x^2 – 8x – 4x + 16 = 0
      2x = 8, 4
      x = 4, 2

       

    10. I. x^2 – 2x – 195 = 0
      II. y^2 – 24y + 128 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 – 15x + 13x – 195 = 0
      x = 15, -13
      II. y^2 – 16y – 8y + 128 = 0
      y = 16, 8

       

    04
    7Oct, 2021
    Mixed Quantitative Aptitude Questions Set 225
    1. What is the monthly income of Jitu ?
      I. Jitu spends 85% of his income on various expenses and remaining amount he saved.
      II. Monthly saving of Jitu are rs.7500.
      III. Out of total money spent by Jitu in a month, one-fifth is spent on rent and remaining amount of rs.34000 on other items.
      Only I and II sufficient
      Only II and III sufficient
      Only I and II sufficient
      Neither I nor II and III is sufficient
      Any of the two statements is sufficient
      Option E
      Let income of Jitu = rs.x
      from I and II,
      15% of x = 7500
      x = 7500 * 100/15 = 50000
      From I and III,
      x * 85/100 * 4/5 = 34000
      x = 50000
      from I and III
      4/5 th of expenditure = 34000
      expenditure = 42500
      income = 42500 + 7500 = 50000
      thus, answer can be find out by any of two given statement

       

    2. How much time will require the train to reach from point X to point Y ?
      I. The train will pass the other train of equal length of 400m running opposite in direction in 16 secs
      II. Distance between point X and Y is 252 km.
      III. The 400m long train crosses a signal pole in 20sec.
      Only I and II is sufficient
      Only II and III is sufficient
      Neither of any statement is sufficient
      All statements are sufficient
      Only I and III is sufficient
      Option B
      Statement I is not required to get answer
      from statement III,
      Speed of train = 400/20 = 20 m/sec
      speed( in km) = 20 * 18/5 = 72 km/hr
      from statement II,
      time = 252/72 = 3.5 hr
      statement II and III required to get answer.

       

    3. What is the length of a running train A crossing another running train B ?
      I. A and B two train take 18secs to cross each other, while running opposite direction.
      II. The length of train B is 180m
      Only I and II is sufficient
      Only II is sufficient
      Either I or II statement
      Neither I nor II is sufficient
      Only I sufficient
      Option D
      Length of train A = l meters
      from I, time taken by train to cross each other = 18secs
      let speed of train A and B = x and y respectively
      relative speed of A and B = (x + y) m/s
      from II, length of train B = 180 meters
      180 + l/x + y = 18
      thus, we can not calculate answer by using these two statements.

       

    4. What will be respective ratio of saving of A and B.
      I. Income of A is 4% less than that of C and also expenditure of A is 12.5% less than that of C. B spend 3/5 th of his income.
      II. C save rs. 7000 and A save rs.7400. Income of B is rs.1000 more than that of C.
      Only I is sufficient
      Only II is sufficient
      Either I or II statement
      Neither I nor II is sufficient
      Only I and II is sufficient
      Option E
      Let income of C = 25x
      income of A = 25x * 96/100 = 24x
      let expenditure of A = 7y
      expenditure of C = 8y
      B spend 3/5 th of his his income
      from II
      saving of C = 7000
      saving of A = 7400
      Income of B is 1000 that of C
      from I and II,
      expenditure of A = 24x – 7y = 7400
      expenditure of C = 25x – 8y = 7000
      by solving two equations,
      x = 600 and y = 1000
      income of B = 25 * 600 + 1000 = 16000
      saving B = 16000 * 2/5 = 6400
      Ratio = 7400 : 6400 = 37 : 32
      statement I and II is required

       

    5. What is the CI on a sum at the end of 3 years ?
      I. CI at the end of two years is rs.110
      II. Difference between CI and SI at the end of two year is rs.100 and rate of percent is 10%.
      Only I is sufficient
      Only II is sufficient
      Either I or II statement
      Neither I nor II is sufficient
      Only I and II is sufficient
      Option B
      From I,
      Sum can not be find out as rate is not given
      From II,
      Difference PR^2/100^2
      100 = P *100/10000
      P = 10000
      only statement II is sufficient.

       

    6. I. x^2v- 41x + 348 = 0
      II. y^2 – 20y + 99 = 0
      X < Y
      X > Y
      X ≥ Y
      X ≤ Y
      X = Y or no relation.
      Option B
      I. x^2 – 29x – 12x + 99 = 0
      x = 29, 12
      II. y^2 – 11y – 9y + 99 = 0
      y = 11, 9

       

    7. I. 2x^2 – 2x _ 24 = 0
      II. 3y^2 – 8y + 4 = 0
      X < Y
      X > Y
      X ≥ Y
      X ≤ Y
      X = Y or no relation.
      Option E
      I. 2x^2 – 8x + 6x – 24 = 0
      x = 8, – 6
      x = 4, -3
      II. 3y^2 – 6y – 2y + 4 = 0
      3y = 6, 2
      y = 2, .67

       

    8. I. 5x^2 – 28x + 15 = 0
      II. 3y^2 – 29 y + 68 = 0
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. 5x^2 – 25x – 3x + 15 = 0
      5x = 25, 3
      x = 5, .6
      II. 3y^2 – 17y – 12y + 68 = 0
      y3y = 17, 12
      y = 5.66, 4

       

    9. I. x^3 = 4913
      II. y^2 = 225
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option B
      I. x^3 = 4913
      x = 17
      II. y^2 = 225
      y = 15, -15

       

    10. I. 2x^2 – 20x + 48 = 0
      II. y^2 – 15y + 56 = 0
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option A
      I. 2x^2 – 12x – 8x + 48 = 0
      2x = 12, 8
      x = 6, 4
      II. y^2 – 8y – 7y + 56 = 0
      y = 8, 7

       

    05
    5Oct, 2021
    Mixed Quantitative Aptitude Questions Set 224
    1. What is the monthly income of Jitu ?
      I. Jitu spends 85% of his income on various expenses and remaining amount he saved.
      II. Monthly saving of Jitu are rs.7500.
      III. Out of total money spent by Jitu in a month, one-fifth is spent on rent and remaining amount of rs.34000 on other items.
      Only I and II sufficient
      Only II and III sufficient
      Only I and II sufficient
      Neither I nor II and III is sufficient
      Any of the two statements is sufficient
      Option E
      Let income of Jitu = rs.x
      from I and II,
      15% of x = 7500
      x = 7500 * 100/15 = 50000
      From I and III,
      x * 85/100 * 4/5 = 34000
      x = 50000
      from I and III
      4/5 th of expenditure = 34000
      expenditure = 42500
      income = 42500 + 7500 = 50000
      thus, answer can be find out by any of two given statement

       

    2. How much time will require the train to reach from point X to point Y ?
      I. The train will pass the other train of equal length of 400m running opposite in direction in 16 secs
      II. Distance between point X and Y is 252 km.
      III. The 400m long train crosses a signal pole in 20sec.
      Only I and II is sufficient
      Only II and III is sufficient
      Neither of any statement is sufficient
      All statements are sufficient
      Only I and III is sufficient
      Option B
      Statement I is not required to get answer
      from statement III,
      Speed of train = 400/20 = 20 m/sec
      speed( in km) = 20 * 18/5 = 72 km/hr
      from statement II,
      time = 252/72 = 3.5 hr
      statement II and III required to get answer.

       

    3. What is the length of a running train A crossing another running train B ?
      I. A and B two train take 18secs to cross each other, while running opposite direction.
      II. The length of train B is 180m
      Only I and II is sufficient
      Only II is sufficient
      Either I or II statement
      Neither I nor II is sufficient
      Only I sufficient
      Option D
      Length of train A = l meters
      from I, time taken by train to cross each other = 18secs
      let speed of train A and B = x and y respectively
      relative speed of A and B = (x + y) m/s
      from II, length of train B = 180 meters
      180 + l/x + y = 18
      thus, we can not calculate answer by using these two statements.

       

    4. What will be respective ratio of saving of A and B.
      I. Income of A is 4% less than that of C and also expenditure of A is 12.5% less than that of C. B spend 3/5 th of his income.
      II. C save rs. 7000 and A save rs.7400. Income of B is rs.1000 more than that of C.
      Only I is sufficient
      Only II is sufficient
      Either I or II statement
      Neither I nor II is sufficient
      Only I and II is sufficient
      Option E
      Let income of C = 25x
      income of A = 25x * 96/100 = 24x
      let expenditure of A = 7y
      expenditure of C = 8y
      B spend 3/5 th of his his income
      from II
      saving of C = 7000
      saving of A = 7400
      Income of B is 1000 that of C
      from I and II,
      expenditure of A = 24x – 7y = 7400
      expenditure of C = 25x – 8y = 7000
      by solving two equations,
      x = 600 and y = 1000
      income of B = 25 * 600 + 1000 = 16000
      saving B = 16000 * 2/5 = 6400
      Ratio = 7400 : 6400 = 37 : 32
      statement I and II is required

       

    5. What is the CI on a sum at the end of 3 years ?
      I. CI at the end of two years is rs.110
      II. Difference between CI and SI at the end of two year is rs.100 and rate of percent is 10%.
      Only I is sufficient
      Only II is sufficient
      Either I or II statement
      Neither I nor II is sufficient
      Only I and II is sufficient
      Option B
      From I,
      Sum can not be find out as rate is not given
      From II,
      Difference PR^2/100^2
      100 = P *100/10000
      P = 10000
      only statement II is sufficient.

       

    6. I. x^2v- 41x + 348 = 0
      II. y^2 – 20y + 99 = 0
      X < Y
      X > Y
      X ≥ Y
      X ≤ Y
      X = Y or no relation.
      Option B
      I. x^2 – 29x – 12x + 99 = 0
      x = 29, 12
      II. y^2 – 11y – 9y + 99 = 0
      y = 11, 9

       

    7. I. 2x^2 – 2x _ 24 = 0
      II. 3y^2 – 8y + 4 = 0
      X < Y
      X > Y
      X ≥ Y
      X ≤ Y
      X = Y or no relation.
      Option E
      I. 2x^2 – 8x + 6x – 24 = 0
      x = 8, – 6
      x = 4, -3
      II. 3y^2 – 6y – 2y + 4 = 0
      3y = 6, 2
      y = 2, .67

       

    8. I. 5x^2 – 28x + 15 = 0
      II. 3y^2 – 29 y + 68 = 0
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. 5x^2 – 25x – 3x + 15 = 0
      5x = 25, 3
      x = 5, .6
      II. 3y^2 – 17y – 12y + 68 = 0
      y3y = 17, 12
      y = 5.66, 4

       

    9. I. x^3 = 4913
      II. y^2 = 225
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option B
      I. x^3 = 4913
      x = 17
      II. y^2 = 225
      y = 15, -15

       

    10. I. 2x^2 – 20x + 48 = 0
      II. y^2 – 15y + 56 = 0
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option A
      I. 2x^2 – 12x – 8x + 48 = 0
      2x = 12, 8
      x = 6, 4
      II. y^2 – 8y – 7y + 56 = 0
      y = 8, 7

       

    06
    4Oct, 2021
    Mixed Quantitative Aptitude Questions Set 223
    1. Train A leaves kolkata at 8am and is travelling at a speed of 70 km/hr, 4 hours later another train B leaves kolkata and is travelling in same direction as train A in how many time (in minutes) train B will be 25 km ahead train A, if speed of train B is 100 km/hr ?
      475 minutes
      610 minutes
      340 minutes
      620 minutes
      368 minutes
      Option B
      Distance covered by train A in 4 hours = 70 * 4 = 280 km
      total distance should be covered by train B from kolkata for ahead 25 km to train A
      required time = 280 + 25/100-70 = 305/30 * 60 = 610 minutes

       

    2. In a box there are 3 red balls, 7 white balls and 5 orange balls. If one bottle is drawn at random from the cartoon what is the probability that it is either red balls or white balls ?
      2/7
      8/9
      3/4
      5/7
      2/3
      Option E
      probability = (3C1) + (7C1)/15C1 = (3 + 7)/15 = 2/3

       

    3. Two persons A and B alone can do a piece of work in 10 days and 12 days respectively. A and B together worked for 4 days and remaining worked by C alone. If efficiency of C is 20% less than the efficiency of B then find in how many days total work will be completed ?
      5 days
      8 days
      7 days
      12 days
      6 days
      Option B
      LCM of 10 and 12 = 60
      efficiency of A = 60/10 = 6
      efficiency of B = 60/12 = 5
      work completed by A and B together in 4 days = (6 + 5)* 4 = 44 work
      remaining work = 60 – 44 = 16 work
      efficiency of C = 5 * 80/100 = 4
      time required to complete the work = 16/4 = 4 work
      total time to complete the work = 4 + 4 = 8 days

       

    4. a and B invested rs.2500 and rs.3100 in a business respectively. After 6 months A left the business and C joined with a capital of rs.2200. At the end of 1.5 years the profit received by A and B together is how much percent more or less than that by C ?
      125 3/8%
      140 10/11%
      48 3/5%
      152 3/7%
      215 3/8%
      Option B
      Profit sharing ratio of A , B and C = (2500 * 1.5) : (3100 * .5) : (2200 * 1) = 75 : 31 : 44
      more % = (75 + 31) – 44/44 * 100 = 140 10/11%

       

    5. Sudha is travelling from point A to B which is 560 km apart with a certain speed. While returning he covers half the distance with 30% less speed than the usual speed and cover the remaining distance with a speed of 140 km/hr. If time taken in both cases is equal, then find the speed of Sudha while going from point A to B ?
      75 km/hr
      80 km/hr
      72 km/hr
      84 km/hr
      108 km/hr
      Option B
      Let speed of Sudha while travelling from point A to point B = 10x km/hr
      time taken by Sudha while travelling from A to B = 560/10x
      time taken by Sudha while returning = 280/7x + 280/140
      560/10x = 280/7x + 2
      56/x – 40/x = 2
      x = 8
      speed of Sudha = 10 * 8 = 80 km/hr

       

    6. Directions : What will come in place of questions (?) marks in the following questions below ?
      (15)^2 – (18)^2 + 312 = ? + 47
      319
      120
      184
      133
      166
      Option E
      225 – 324 + 312 = ? + 47
      – 99 + 312 = ? + 47
      ? = 166

       

    7. ∛1331 + 38% of 1200 – ? = 98.20
      421.50
      213.40
      368.80
      254.20
      281.20
      Option C
      11 + 456 – ? = 98.20
      ? = 368.80

       

    8. 1/14 + 2/7 – 1/42 = ?
      2/7
      1/3
      4/5
      3/5
      4/7
      Option B
      (3 + 12 – 1) /42 = ?
      ? = 1/3

       

    9. 42.30 – (11)^2 + 520 – ? = 218.40
      240.80
      312.90
      422.90
      222.90
      128.46
      Option D
      562.30 – 121 – ? = 218.40
      ? = 222.90

       

    10. 3/4 of 420 + 320 – 4/5 of 215 = ? + 85
      420
      422
      540
      325
      378
      Option E
      315 + 320 – 172 = ? + 85
      ? = 378

       

    07
    3Oct, 2021
    Mixed Quantitative Aptitude Questions Set 222
    1. While we add 4 to the numerator of the fraction and increases denominator by 50% then both become equal. When the numerator is increased by 5 and denominator is doubled then it becomes equal to the original fraction. What will be two times of that fraction ?
      2/5
      5/3
      2/7
      4/5
      4/3
      Option B
      Let the numerator and denominator of a fraction be x and y respectively.
      ATQ, x + 4 = 3y/2
      x + 5/2y = x/y
      by solving two equations,
      x = 5, y = 6
      original fraction = 5/6
      required fraction = 5/6 * 2 = 5/3

       

    2. Two dices are rolled together, then find probability of getting a number of one dice greater than the number on other dice ?
      2/3
      7/6
      5/6
      2/5
      4/7
      Option C
      total number of cases = 6 * 6 = 36
      total cases of getting same number = (1,1), (2,2), 3,3), (4,4), (5,5), (6,6) = 6
      probability = 1 – 6/36 = 5/6

       

    3. P, Q, R are three inlet pipes. Time taken by P and Q together to fill half of the tank is same as time taken by pipe R alone to fill one-sixth of the tank. If P, Q, R together can fill the tank in 9 hours, then find time taken by pipe R alone to fill the tank ?
      34 hours
      42 hours
      24 hours
      36 yours
      40 yours
      Option D
      ATQ, 2(P+Q) = 6R
      P + Q = 3R
      P + Q + R = 1/9
      4R = 1/9
      R = 36 hours

       

    4. A man cuts a square field of maximum possible area from his circular field. Find the area of the remaining circular field, if the cost of grass cutting of the square field at rs. 4 per m^2 is rs.882 ?
      154 m^2
      126 m^2
      200 m^2
      348 m^2
      180 m^2
      Option B
      Let side of square be = a meters
      radius of circle = r meters
      area of the square field = 220.5 m^2
      diagonal of the square field = 21 m
      radius of the circular field = 10.5 m
      area of the circular field = 346.5 m^2
      area of the remaining circular field = 126 m^2

       

    5. Rohit invested rs.1600 on CI for two years at the rate of R% p.a and gets amount of rs.2304. If man invested same sum on SI for same period of time at the rate of ( R – 8)%, then find interest he will get ?
      450
      384
      420
      640
      260
      Option B
      ATQ,
      2304 = 1600 ( 1 + R/100)^2
      48/40 = ( 1 + R/100)
      R = 20%
      New rate = (20 – 8) = 12%
      required interest = 1600 * 12 * 2/100 = 384

       

    6. directions : What will be come in place of questions marks (?) in the following questions given below ?
      428, 434, 446, 466, 496 ?
      620
      538
      580
      650
      940
      Option B
      The series is, +(2 * 3), +(3 * 4), +(4 * 5), +(5 * 6), +(6 * 7)

       

    7. 187, 193, 205, ?, 277, 373
      198
      229
      240
      350
      270
      Option B
      The series is (+6), (+12), (+24), (+48), (+96)

       

    8. 144, 72, 108, 270, ?, 4252.5
      320
      620
      825
      945
      480
      Option D
      The series is, (* .5), (* 1.5), (* 2.5), (* 3.5), (* 4.5)

       

    9. 81, ? 76, 92, 67, 103
      73
      85
      65
      76
      84
      Option B
      The series is, (+ 2^2), (- 3^2), (+ 4^2), (- 5^2), (+ 6^2)

       

    10. 11, 13, 22, ?, 115, 241
      48
      56
      75
      50
      82
      Option D
      the series is, +(1^3 + 1), +(2^3 + 1), +(3^3 + 1), +(4^3 + 1), + (5^3 + 1)

       

    08
    30Sep, 2021
    Mixed Quantitative Aptitude Questions Set 221
    1. The number of boys in a class are x and the number of girls are 4 less than the number of boys. The sum of weight of boys is 630 and the average weight of boys is 45 kg. If 2 students are selected for a exam then what will be the probability that the number of boys the numbers of girls are equal ?
      4/9
      35/69
      82/265
      36/129
      1/5
      Option B
      Total number of boys = x
      number of girls = x – 4
      the number of boys = 630/45 = 14
      the number of girls = 14 – 4 = 10
      probability = 14C1 * 10C1 / 24C2
      = 14 * 10 * 2/24 * 23 = 35/69

       

    2. Difference between CI received in first 1.5 years at 20% per annum compounded annually and CI received in last 1.5 years at same rate of interest in compounded half yearly on the same sum is rs.495, then find the sum ?
      32000
      48000
      30000
      52000
      45000
      Option E
      Let sum = 100x
      total rate of in 1st 1.5 years = 20 + 10 + 20 * 10 /100 = 32%
      CI received = 100x * 32/100 = 32x
      CI received in last 1.5 years = 100x * 1.1 * 1.1 * 1.1 – 100x = 33.1x
      difference = 33.1x – 32x = 495
      1.1x = 495
      x = 450
      sum = 100x = 100* 450 = 45000

       

    3. X and Z alone can do a piece of work in 25 days and 30 days respectively, while Y takes as half time as X and Z take together. If they start working alternatively starting by Y, followed X and Z respectively, then find in how many days work will be completed ?
      5 8/17 days
      12 9/11 days
      8 2/5 days
      6 3/5 days
      26 3/8 days
      Option B
      LCM of 25 and 30 = 150
      efficiency of X = 150/25 = 6
      efficiency of Z = 150/30 = 5
      efficiency of Y = 22
      when all three works alternatively
      3 days work = 22 + 6 + 5 == 33 work
      in total 12 days = 12/3 * 33 = 132 work
      remaining work = 150 – 132 = 18
      remaining work completed by Y = 18/22 = 9/11 day
      total days = 12 9/11 days

       

    4. A boat takes total 10 hours to cover the distance of 84 km in upstream and 84 km in downstream. If the speed of boat is increased by 12km/hr, then the new upstream speed is doubled of its usual speed. Find the time taken by boat to cover 140 km in downstream.
      5
      8
      2
      6.5
      2.5
      Option A
      Let speed of boat = x km/hr
      speed of stream = y km/hr
      downstream speed = x + y
      upstream speed = x – y
      new speed of boat = x + 12
      upstream speed = x + 12 – y
      2 (x – y ) = x + 12 – y
      x – y = 12
      upstream speed = 12
      time taken by boat to cover 84 km in upstream 84/12 = 7
      time taken by boat in downstream = 10 – 7 = 3
      downstream speed = 84/3 = 28 km
      time taken by boat to cover 140 km in downstream = 140/28 = 5 hours

       

    5. A and B started a partnership business with investment (x + 500) and (x – 1000) respectively. After 6 months a withdrew 40% of his amount. If profit received by A at the end of the year is 2800 out of the total profit rs.4800, then what is the value of ‘x’ ?
      4000
      2000
      1500
      3000
      5600
      Option D
      Investment of A = (x + 500)* 6 + ( x + 500)* .6 * 6 = 6(1.6x + 800)
      investment of B = (x – 1000) * 12
      profit of A = 2800
      profit B = 4800 – 2800 = 2000
      6( 1.6x + 800)/(x – 1000)12 = 2800/2000
      8x + 4000 = 14x – 14000
      x = 3000

       

    6. I. 2x^2 – 13x + 15 = 0
      II. y^2 – 6y + 8 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. 2x^2 – 10x – 3x + 15 = 0
      2x = 10, 3
      x = 5 , 1.5
      II. y^2 – 4y – 2y + 8 = 0
      y = 4, 2

       

    7. I. x^2 – 27x + 92 = 0
      II. y^2 – 17y + 60 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 – 23x – 4x + 92 = 0
      x = 23, 4
      II. y^2 – 12y – 5y + 60 = 0
      y = 12 , 5

       

    8. I. x^2 = 196
      II. y^3 = 4096
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option B
      I. x^2 = 196
      x = 14, -14
      II. y^3 = 4096
      y = 16

       

    9. I. 5x^2 – 7x + 2 = 0
      II. y^2 + 12y + 32 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option A
      I. 5x^2 – 5x – 2x + 2 = 0
      5x = 5, 2
      x = 1, .4
      II. y^2 + 8y + 4y + 32 = 0
      y = -8, -4

       

    10. I. 3x^2 – 19x + 20 = 0
      II. 4y^2 – 6y + 2 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option A
      I. 3x^2 – 15x – 4x + 20 = 0
      3x = 15, 4
      x = 5, 1.33
      II. 4y^2 – 4y – 2y + 2 = 0
      4y = 4, 2
      y = 1. .5

       

    09
    27Sep, 2021
    Mixed Quantitative Aptitude Questions Set 220
    1. A shopkeeper X sold an article for rs.850 at a profit of 25%. Another shopkeeper Y sold the another article and earned 30% more profit than the profit earned by X. If the selling price of article Y is three-fifth of selling price of article X, then find the profit percent of article Y ?
      64 2/17%
      76 8/17%
      52 3/34%
      52 3/8%
      78%
      Option B
      SP of article X = 850
      CP of article X = 850 * 100/125 = 680
      profit = 170
      profit of article Y = 170*130/100 = 221
      SP of article Y = 850 * 3/5 = 510
      CP = 510 – 221 = 289
      profit percent = 221/289* 100 = 76 8/17%

       

    2. Mixture A contains milk and water in the ratio of 3 : 2 respectively, while mixture B contains water and milk in the ratio of 4 : 3 respectively. If the quantity of water in mixture B is twice the quantity of water in mixture A, then find the quantity of milk in mixture A is what percent quantity of water in mixture B ?
      68%
      60%
      82%
      75%
      56%
      Option D
      Quantity of milk and water in mixture A = 3x and 2x
      according to questions,
      quantity of water in mixture B = 2*2x = 4x
      quantity of milk in mixture B = 4x/4 *3 = 3x
      required percentage = 3x/4x*100 = 75%

       

    3. 340 liters of mixture of milk and water is contained in a container having milk and water mixed in the ratio of 3 : 1 respectively. 76 liters of this mixture is taken out from the container and replaced with (x + 7) liters of milk so that the ratio of water to milk is 6 : 11. What is the value of ‘x’ ?
      42
      48
      38
      35
      52
      Option D
      Quantity of milk in the container = 340 * 3/4 = 255
      quantity of water in the container = 340*1/4 = 85
      76 liters of mixture is taken out and (x + 7) liter of water is added.
      (255 – 57) / 85 – 19 + (x + 7) = 11/6
      198/(73 + x) = 11/6
      11x = 385
      x = 35

       

    4. A can do a piece of work in 30days while B and C together can complete the work in 20 days and A and C together can complete the work in 24 days. If B is worked in two-fifth of his efficiency, then in how many days A and B together complete half of the work ?
      8 days
      6 days
      8 1/3 days
      5 days
      10 days
      Option E
      LCM of 30 , 20 and 24 = 120
      efficiency of A = 120/30 = 4
      efficiency of B and C = 120/20 = 6
      efficiency of A and C together = 120/24 = 5
      efficiency of C = 5- 4 = 1
      efficiency of B 6- 1 = 5
      two-fifth of efficiency B = 5 * 2/5 = 2
      time required to complete half of the work = 60/2 + 4 = 10 days

       

    5. Rohan and Sivan started a business together with initial investments of rs. 1500 and rs.1800 respectively. If after 2.5 years profit share of Rohan and Sivan are rs(x + 80) and (x + 120) respectively, then find the difference between profit of Rohan and Sivan ?
      180
      120
      320
      130
      340
      Option B
      Profit sharing ratio of Rohan and Sivan = (1500 * 2.5) : (1800 * 2.5) = 5 : 6
      x + 80/x + 120 = 5/6
      6x + 480 = 5x + 600
      x = 120

       

    6. Directions : In each of these questions given below two equations. You have to solve both the equations and give answer.
      I. x^2 – 7√3 + 36 = 0
      II. y^2 – 6√2 + 16 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 – 4√3 – 3√3 + 36 = 0
      x = 4√3 , 3√3
      II. y^2 – 4√2 – 2√2 + 16 = 0
      y = 4√2, 2√2

       

    7. I. x^2 + √2x – 12 = 0
      II. y^2 – 8√3 + 48 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option B
      I. x^2 + 3√2 – 2√2 – 12 = 0
      x = -3√2, 2√2
      II. y^2 – 4√3 – 4√3 + 48 = 0
      y = 4√3, 4√3

       

    8. I. x^2 – 36 = 0
      II. y^2 – 15y + 36 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 = 36
      x = 6, -6
      II. y^2 – 12y – 3y + 36 = 0
      y = 12, 3

       

    9. I. y^2 = 144
      II. 2x^2 – 12x + 16 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. y^2 = 144
      y = 12, -12
      II. 2x^2 – 8x – 4x + 16 = 0
      2x = 8, 4
      x = 4, 2

       

    10. I. x^2 – 2x – 195 = 0
      II. y^2 – 24y + 128 = 0
      X > Y
      X < Y
      X ≤ Y
      X ≥ Y
      X = Y or no relation.
      Option E
      I. x^2 – 15x + 13x – 195 = 0
      x = 15, -13
      II. y^2 – 16y – 8y + 128 = 0
      y = 16, 8

       

    10