1. Directions : What will come in place of questions ( ? ) marks in the following number series ?
   8 , 46 , 80 , 110 , 136 , ?
   168
   158
   208
   425
   384
   Option B
   The series is (+ 38) , (+ 34) , (+ 30) , (+ 26) , (+ 22)

    

2. 29 , 32 , 61 , 93 , 154 , ?
   285
   160
   247
   240
   320
   Option C
   The series is (29 + 32 = 61) , (32 + 61 = 93) , (61 + 93 = 154) , (93 + 154 = 247)

    

3. 65 , 83 , 103 , 125 , ? , 175
   128
   165
   143
   149
   120
   Option D
   The series is , + (8^2 + 1) , + (9^2 + 2) , + (10^2 + 3) , + (11^2 + 4) , + (12^2 + 5) , + (13^2 + 6)

    

4. 12 , 7 , 9 , 16.5 , 37 , ?
   92
   97.5
   45.25
   68.5
   56.75
   Option B
   The series is (*1 + 2) , (*1.5 + 3) , (*2 + 4) , (2.5 + 5)

    

5. 35 , 36, 40 , 49 , 65 , ?
   92
   105
   75
   90
   84
   Option D
   The series is (+ 1^1) , (+ 2^2) , (+ 3^2) , (+ 4^2) , (+ 5^2)

    

6. 425 , 408 , 381 , 344 , 297 , ?
   254
   242
   164
   240
   246
   Option D
   The series is (- 17 ) , (- 27) , (- 37) , (- 47) , (- 57)

    

7. 45 , 52 , 41 , 54 , 37 , ?
   50
   56
   43
   92
   38
   Option B
   The series is (+ 7) , (- 11) , (+ 13) , (- 17) , (+ 19)

    

8. 3600 , 720 , ? , 60 , 30 , 30
   120
   180
   360
   600
   240
   Option B
   The series is ( 3600 / 5 ) , ( 720 / 4 ) , ( 180 / 3 ) , ( 60 / 2 ) , ( 30 /1 )

    

9. 4 , 5 , 12 , 39 , 160 , ?
   800
   805
   482
   540
   640
   Option B
   The series is (* 1 + 1) , (* 2 + 2 ) , (* 3 + 3 ) , ( * 4 + 4 ) , ( * 5 + 5 )

    

10. 24 , 26 , 29 , 28 , 34 , ? , 39
    30
    54
    20
    32
    42
    Option A
    The series is (24 + 5 = 29) , (26 + 2 = 28) , ( 29 + 5 = 39) , (28 + 2 = 30) …

     

1. A alone can complete a piece of work in 15 days and B & C together can complete the same work in 8 1/3 days. B is 100% more efficient than C. How many days is required to complete the work if A and C work together ?
   12 days
   8 days
   6 days
   9 3/8 days
   5 days
   Option D
   LCM of 15 and 8 1/3 days = 75
   efficiency of A = 75/15 = 5
   efficiency of B and C = 75 * 3/25 = 9
   let efficiency of C = 100
   efficiency of B = 200
   ratio of efficiency of B and C = 2 : 1
   efficiency of B = 9 * 2/3 = 6
   efficiency of C = 9 * 1/3 = 3
   time = 75/(5 + 3) = 75/8 = 9 3/8 days

    

2. Rajat alone can complete a piece of work in ‘x’ days and Sujit alone can complete the same work in (x + 5) days. If they together can complete the same work in 6 days, then find in how days Sujit can complete the whole work ?
   10 days
   6 days
   8 days
   5 days
   15 days
   Option E
   1/x + 1/x + 5 = 1/6
   2x + 5 / x^2 + 5x = 1/6
   x^2 + 5x = 12x + 30
   x^2 – 7x – 30 = 0
   x = 10 , – 3
   Days can not come in negative, so that value of x = 10
   Days taken by Sujit to complete the work = x + 5 = 15 days

    

3. A alone can complete a work in 25 days and B alone can complete same work in 45 days. How many days are taken by A and B together to complete 60% of work ?
   14 days
   135/14 days
   68/7 days
   18/5 days
   9 2/5 days
   Option B
   LCM of 25 and 45 = 225
   efficiently of A = 225/ 25 = 9
   efficiently B = 225/45 = 5
   days = 225/14 * 60/100 = 135/14 days
   

    

4. A and B can complete a work in 24 days and B and C together can complete the same work in 30 days. A and C together work for 15 days and after 15 days A and C left the work, remaining work done by alone B. If the efficiency ratio of A and B is 2 : 3, then find in how many days total work will be completed ?
   28 days
   60 days
   40 days
   38 days
   25 days
   Option C
   LCM of 24 and 30 = 120
   total work = 120
   efficiency of A and B = 120/24 = 5
   efficiency of B and C = 120/30 = 4
   efficiency of A = 5 * 2/5 = 2
   efficiency of B = 5 – 2 = 3
   efficiency of C = 4 – 3 = 1
   A and C together work for 15 days = (2 + 1) * 15 = 45
   remaining work = 120 – 45 = 75
   days required to complete remaining work = 75/3 = 25 days
   total days = 15 + 25 = 40days

    

5. P , Q and R together can complete a work in 20 days and the ratio of time taken by P , Q and R is 8 : 6 : 3. How many days is taken by Q and R together to complete the whole work ?
   
   18 days
   25 days
   26 days
   30 days
   32 days
   Option B
   Time ratio of P , Q and R = 8 : 6 : 3
   LCM of 8, 6 and 3 = 24
   efficiency ratio of P, Q and R = 24/8 : 24/6 : 24/3 = 3 : 4 : 8
   let efficiency of P , Q and R = 3x , 4x and 8x respectively.
   total work = 20 ( 3x + 4x + 8x ) = 300x
   time taken by Q and R together complete the work = 300x / 12x = 25 days

    

6. The efficiency of Rohit is 40% more than Suraj. If Suraj alone can do a work in 14 days, then find how many days is taken by Rohit to complete the whole work ?
   10 days
   15 days
   22 days
   13 days
   18 days
   Option A
   Efficiency of Suraj = 5x
   Efficiency of Rohit = 5x * 140/100 = 7x
   total work = 14 * 5x = 70x
   time taken by Rohit to complete the work = 70x/7x = 10 days

    

7. A and B can do a work in 10 days B and C can do the same work in 12 days and A and C can do the same work in 15 days. How many days by A, B and C together to complete total work ?
   5 days
   8 days
   14 days
   15 days
   6 days
   Option B
   LCM of 10 , 12 and 15 = 60
   efficiency of A and B = 60/10 = 6
   efficiency of B and C = 60/12 = 5
   efficiency of A and C = 60/15 = 4
   A + B + B + C + A + C = 15
   A + B + C = 7.5
   time = 60/7.5 = 8 days

    

8. 12 men do a work in 18 days. They started work together and after 8 days, 3 more joined with them. In how many days the remaining work will be completed ?
   8 days
   9 days
   12 days
   18 days
   15 days
   Option A
   Let the remaining work completed in ‘x’ days
   12 * 18 = (12 * 8) + (15 * x)
   15x = 120
   x = 8 days

    

9. Rita , Gita and Sita can do a piece of work in 24 days , 20 days and 15 days respectively. If they got total wages of rs. 3800, then find difference between the wages got by Sita and Gita.
   500
   800
   480
   400
   620
   Option D
   LCM of 24 , 20 and 15 = 120
   total work = 120
   efficiency of Rita = 120/24 = 5
   efficiency of Gita = 120/20 = 6
   efficiency of Rita = 120/15 = 8
   difference = 3800 * 8 – 6/19 = rs.400
   

    

10. If 12 men can complete a piece of work in 20 days and 15 women can complete the same work in 24 days, then in how many days 8 men and 8 women can complete the whole work ?
    15 days
    18 days
    17 days
    12 days
    24 days
    Option B
    12 men * 20 days = 15 women * 24 days
    m/w = 3/2
    total work = 12 * 3 * 20 = 720
    time = 720 / (8 * 3 + 8 * 2 ) = 720/40 = 18 days

     

1. A person is 30 years older than his son . After 6 years , the age of that person is four times the age of son that time. What is age of his son after 10 years from now ?
   14 years
   16 years
   18 years
   18 years
   14.5 years
   Option A
   Let the age of his son = x
   age of person = x + 30
   after 6 years ,
   4 (x + 6) = x + 30 + 6
   3x = 12
   x = 4
   age of son after 10 years = 10 + 4 = 14 years

    

2. The sum of age of A and B is 38 years. After 8 years the age of B is 2 years more than A. What is the age of B before 5 years ?
   13 years
   14 years
   15 years
   20 years
   18 years
   Option C
   Let the age of A = x years
   age of B = (38 – x) years
   after 8 years,
   (38 – x + 8) – (x + 8) = 2
   x = 18
   age of B before 5 years = 38 – x – 5 = 15 years

    

3. The age of B is 8 years more than A, the age of C is 11 years less than B and the age of A is 5 years less than D. If the sum of age of A , B ,C and D is 70 years, then find the sum of age of A and B after 2 years ?
   40 years
   15 years
   45 years
   38 years
   23 years
   Option D
   Let the age of D = x years
   the age of A = (x – 5) years
   the age of B = ( x – 5 + 8 ) = x + 3 years
   the age of C = (x + 3 – 11) = x – 8 years
   total sum of age of A , B ,C and D = 70
   x + ( x – 5) + (x +3) + (x -8) = 70
   4x – 10 = 70
   x = 20 years
   The age of A = 20 – 5 = 15 years
   The age of B = 20 + 3 = 23 years
   sum = 15 + 23 = 38 years

    

4. The age of son is one-third of his father. If after 5 years the age of father and son becomes 5 : 2, then find the sum of age of father and son.
   50 years
   60 years
   55 years
   45 years
   46 years
   Option B
   Let the age of father = 3x
   the age of son = x
   after 5 years,
   3x + 5/x + 5 = 5/2
   6x + 10 = 5x + 25
   x = 25
   sum = 3x + x = 4x = 4 * 15 = 60 years

    

5. The average present age of A , B and C is 30 years and the ratio between the present age of A and C is 4 : 5. If the age of B is 8 years less than the age of C, then what is age of B after 2 years ?
   26 years
   29 years
   23 years
   25 years
   30 years
   Option B
   Let the A and C 4x and 5x respectively
   the age of B = 5x – 8
   total age of A , B and C = 30 * 3 = 90 years
   4x + 5x + 5x – 8 = 90
   14x = 98
   x = 7
   the age of B after 2 years = (5x – 8) + 2 = 29 years

    

6. The sum of present age of A , B and C is 52 years and the age of A is 3/5th of age of B. If after 11 years the age of B is equal to the three times the present age of C, then find present of C ?
   26 years
   28 years
   30 years
   14 years
   25 years
   Option E
   Let the present age of B = 5x
   the age of A = 3x
   Let the present of C = y years
   5x + 11 = 3y
   y = 5x + 11/3
   3x + 5x + (5x + 11)/3 = 52
   9x + 15 x + 5x + 11 = 156
   29x = 145
   x = 5
   the present age of B = 5 * 5 = 25 years

    

7. 10 years ago P was half of Q in age . At present the ratio of their ages is 3 : 4. Find the sum of their ages after 3 years.
   46 years
   35 years
   62 years
   41 years
   52 years
   Option D
   10 years ago , let the age of Q = 2x
   and the age of P = x
   at present , the age of P = x + 10
   the age of Q = 2x + 10
   x + 10/2x + 10 = 3/4
   6x + 30 = 4x + 40
   2x = 10
   x = 5
   sum of their ages after 3 years = 2x + 13 + x + 13 = 23 + 18 = 41 years

    

8. The age of father is 40% more then his son. After 5 years the age of father is 16 years more than the age of son. Find the present age of father.
   45
   56
   42
   58
   56
   Option E
   Let age of son = 5x
   and father age = 5x * 140/100 = 7x
   after 5 years,
   (7x + 5) – (5x + 5) = 16
   2x = 16
   x = 8
   the age of father = 7x = 7 * 8 = 56 years

    

9. The difference between the present age of A and B is 20 years. After 3 years their ages are in the ratio 9 : 19. Find the present age of B.
   40 years
   35 years
   26 years
   14 years
   46 years
   Option B
   Let present age of A = x years
   present age of B = x + 20 years
   after 3 years, the age of A = x + 3
   the age of B = x + 23
   x + 3 / x + 23 = 9/19
   19x + 57 = 9x + 207
   10x = 150
   x = 15
   the age of B = 15 + 20 = 35 years

    

10. The present age of father is 5 times that of his son. After 4 years he will be 4 times that of his son. Find the age of father 3 years ago.
    34 years
    56 years
    42 years
    57 years
    48 years
    Option D
    Let the age of son = x years
    the age of father = 5x years
    After 4 years,
    the age of son = x + 4
    the age of father = 5x + 4
    4 (x + 4) = 5x + 4
    4x + 16 = 5x + 4
    x = 12 years
    the age of father 3 years ago = 5 * 12 – 3 = 57 years

     

1. A started a business by investing rs.45000. After 6 months B joined business with rs.35000 and profit of the business at the end of the year is rs. 17500. What is profit share of B ?
   4800
   5250
   4900
   12000
   8500
   Option C
   Profit sharing ratio of A and B = (45000 * 12) : (35000 * 6 ) = 18 : 17
   total profit = 17500
   profit of B = 17500 * 7/25 = 4900

    

2. Three friends A , B and C started a business by investing capital in the ratio of 3 : 4 : 6 for time period of 2 : 5 : 6. What is their profit sharing ratio ?
   5 : 4 : 3
   2 : 3 : 4
   3 : 10 : 8
   3 : 4 : 8
   10 : 5 : 18
   Option C
   Let capital invested A , B and C are 3x and 4x and 6x respectively
   Profit sharing ratio = (3x * 2) : (4x * 5) : (6x * 6 )
   = 6x : 20x : 36x = 3 : 10 : 18 = 3: 10 : 18

    

3. A , B and C enters into a partnership with a total capital of rs.17400. Capital of C is rs.1400 less than capital of A and capital of C rs.200 more than the capital of B. If at the end of the year total profit of the business is rs.3480, then find difference between profit share A and B ?
   540
   380
   340
   320
   400
   Option D
   Let capital of A = x
   capital of C = x – 1400
   capital of B = x – 1400 – 200 = x – 1600
   x + x – 1400 + x – 1600 = 17400
   3x = 20400
   x = 6800
   capital of A = 6800
   capital of B = 6800 – 1600 = 5200
   capital of C = 6800 – 1400 = 5400
   ratio = 6800 : 5200 : 5400 = 34 : 26 : 27
   difference = 3480 * 8/87 = 320

    

4. A and B entered into a partnership business by investing rs.8000 and rs.5000 for x months and (x + 2) months respectively. Total profit of the business at the end of the year is rs.3300 and profit share of A is 300 more than profit share of B. Find for how many months A invested capital ?
   8 months
   5 months
   2 months
   9 months
   6 months
   Option E
   Investment ratio of A and B = 8000 : 5000 = 8 : 5
   profit sharing ratio of A and B = 8 * x : 5 ( x + 2) = 8x : 5x + 10
   8x – (5x + 10)/13x + 10 = 300/3300
   3x – 10 /13x + 10 = 1/11
   33x – 110 = 13x + 10
   20x = 120
   x = 6
   A invested his capital for 6 months

    

5. Ram , Shiva and Hari started a business with capital in the ratio of 8 : 6 : 5. After 8 months Ram withdrawal 25% of capital while Hari increased 20% of his investment . If at the end of the year total profit of business is rs. 14000, then what is the the profit share of Hari ?
   6000
   4000
   8000
   12000
   7000
   Option B
   Let amount invested by Ram , Shiva and Hari = 8x , 6x and 5x
   profit sharing ratio of Ram , Shiva and Hari = (8x * 8 + 6x * 4) : (6x * 12) : (5x * 8 + 6x * 4)
   = 88x : 72x : 64x
   = 11 : 9 : 8
   total profit = 14000
   profit share of Hari = 14000 * 8/28 = 4000

    

6. A started a business with some amount and after 4 months B joined business with rs.2400. If profit of A at the end of the year is rs.2800 out of the total profit of rs. 4200, then find how much amount invested by A ?
   43000
   24000
   34000
   25000
   32000
   Option E
   Let A invested rs.x
   profit sharing ratio of A and B = (x * 12) : (24000 * 8) = x : 16000
   profit share of A = 2800
   x / x + 16000 = 2800/4200
   3x = 2x + 32000
   x = 32000

    

7. A and B started a business with capital of rs.8000 and trs.6000 respectively. After 1 1/2 years B left the business while another person C joined the business with capital of rs. 7000. If at the end of the 2 years profit share of C is rs.560 , then what is total profit of the business ?
   4820
   3240
   1350
   4560
   2480
   Option D
   Profit sharing ratio of A , B and C = (8000 * 2) : (6000 * 1.5) : (7000 * .5) = 32 : 18 : 7
   total profit of the business = 560/7 * 57 = 4560

    

8. Amit and Suraj invested rs. 4000 and rs. 6000 for 8 months and 7 months respectively. Total profit of the business is rs.3330. If they donate 20% of profit to charity fund, after that they distribute profit in their investment ratio, then what is profit share of Suraj ?
   1720
   1240
   1512
   1420
   1250
   Option C
   Profit sharing ratio of Amit and Suraj = (4000 * 8) : (6000 * 7) = 32 : 42 = 16 : 21
   total profit = 3330
   They donate to fund = 3330 * 20/100 = 666
   remaining profit = 3330 – 666 = 2664
   profit share of Suraj = 2664 * 21/37 = 1512

    

9. A and B started a business with capital of rs.4800 and rs.6000 for 2 years and 1.5 years respectively. Profit share of A how much percent more or less than B ?
   8%
   6 2/3%
   8 1/5%
   4%
   8.5%
   Option B
   Profit sharing ratio of A and B = (4800 * 2) : (6000 * 1.5) = 16 : 15
   percentage more = 1/15 * 100 = 6 2/3%
   

    

10. M and N two friends started a partnership business by investing rs.8500 and rs.7000 respectively. M invested his capital for 8 months and N invested for 7 months. If profit of M is rs.760 more than profit of N, then what is profit share of M ?
    2540
    3630
    4500
    2720
    1840
    Option D
    Profit sharing ratio of M and N = (8500 * 8) : (7000 * 7)
    = 68 : 49
    profit share of M = 760/68 – 49 * 68 = 2720

     

1. In a mixture of milk and water of the volume of 80 liter the ratio of milk to water is 3: 2. How much quantity of water will be added to make mixture is equal ?
   16
   15
   12
   18
   20
   Option A
   Quantity of milk in the mixture = 80 * 3/5 = 48
   and water = 80 * 2/5 = 32
   let “x” liter of water to be added,
   48 = 32 + x
   x = 16

    

2. In what ratio must rice at rs.60 per kg be mixed with rice of rs.74 per kg, so that the mixture must be worth rs.64 per kg ?
   2 : 1
   2 : 5
   4 : 3
   2 : 1
   5 : 2
   Option E
   By using alligetion method,
   60 74
   64
   10 4
   ratio = 5 : 2
   

    

3. A vessels contains 80 liters of wine, 20 liters are taken out from vessel is replaced by water and the same process is further replaced two times, then find the quantity of wine left in final solution ?
   12.45 liter
   30.60 liter
   33.75 liter
   40.85 liter
   52.85 liter
   Option C
   Using the formula, wine left over = x ( x – y/x)^n
   = 80 ( 80 – 20/80 )^3
   = 80 ( 3/4)^3 = 80 * 27/64 = 33.75 liter
   

    

4. Two alloy A and B are made of copper and zinc in the ratio of 4 : 1 and 4 : 3 respectively. If these two alloys are to be mixed to form a new alloy in which same elements are in the ratio 2 : 1, then what is ratio of alloy A and alloy B in the new alloy ?
   2 : 3
   4 ; 5
   3 : 2
   5 : 7
   3 : 4
   Option D
   By using formula
   4/5 4/7
   2/3
   2/21 2/15
   ratio = 5 : 7

    

5. In a mixture of wine and water is in the ratio of 5 : 3. If 16 liters of mixtures taken out and replaced with water, so that the ratio of wine and water becomes 3 : 5. Find the initial quantity of wine in the mixture.
   24
   28
   24
   25
   12
   Option D
   Let quantity of wine and water in the mixture is 5x and 3x respectively.
   (5x – 16 * 5/8)/(3x – 16 * 3/8 + 16) = 3/5
   5x – 10/3x – 6 + 16 = 3/5
   5x – 10/3x + 10 = 3/5
   25x – 50 = 9x + 30
   16x = 80
   x = 5
   quantity of wine in the initial mixture = 5 * 5 = 25 liter

    

6. A vessels contains mixture in which 20% water and rest quantity is milk. If 28 liter of more water is to be added in the vessel , then quantity of water becomes 3/8th of mixture. What is the quantity of milk in the vessel initially ?
   80 liters
   65 liters
   42 liters
   68 liters
   78 liters
   Option A
   Quantity of water = 20%
   quantity of milk = 80%
   ratio = 80 : 20 = 4 : 1
   let quantity of milk and water in the vessel is 4x and x respectively.
   28 liter of water is to be added,
   4x /x + 28 = 5 / 3
   12x = 5x + 140
   7x = 140
   x = 20
   quantity of milk = 4 * 20 = 80 liters

    

7. Two mixtures A and B in the ratio of juice and water are 3 : 1 and 1 : 2 respectively, mixed in the ratio of 2 : 3. If the juice in final mixture is 48 liter, then find the quantity of water in final mixture ?
   252
   250
   144
   245
   320
   Option A
   By using alligation,
   3/4 1/3
   2/5
   1/15 7/20
   ratio = 4 : 21
   quantity water = 48/4 * 21 = 252 liters
   

    

8. A seller mixed sugar cost rs.45 per kg with sugar cost rs. 38 per kg. These mixture he sold at rs.48 per kg so that he can earn 20% profit. Find in what ratio he mixed the two types of sugar ?
   4 : 3
   6 : 7
   2 : 5
   1 : 2
   2 : 3
   Option C
   SP of mixed sugar = 48
   CP of mixed sugar = 48/6 * 5 = 40
   using alligetion method,
   45 38
   40
   2 5
   ratio = 2 : 5

    

9. A container contains 60 liters of milk 6 liters of milk taken out from this container and replaced by water. This process was replaced further two times. How much amount of milk left in the container ?
   38.28 liters
   43.74 liters
   24.63 liters
   52.68 liters
   42 liters
   Option B
   Using formula,
   x (x – y/x)^n
   = 60 ( 60 – 6/ 60) ^3
   = 60 ( 54/60)^3
   = 60 * 729/1000 = 43.74 liters

    

10. The ratio of quantity of two varieties of rice of 3 : 2 is mixed. If the of variety of more quantity rice is rs. 15 and the price of the mixture is. rs.16.2 per kg, then find the price of per kg rice which is the less quantity.
    14
    18
    17
    20
    32
    Option B
    Let the price of less quantity rice = x
    = (15 * 3 + x * 2)/ 3 + 2 = 16.2
    45 + 2x = 81
    2x = 81 – 45
    x = 18

     

1. What is perimeter of the rectangle ?
   I. Perimeter of square is 84 cm and length of rectangle is equal is equal to side of square.
   II. The length of rectangle is 40% more than the breadth of rectangle.
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option E
   From I, Side of square = 84/4 = 21cm
   length of rectangle = 21
   from II, let of breadth of rectangle = 5x
   and length = 5x * 140/100 = 7x
   from I and II both,
   breadth of rectangle = 21/7x * 5x = 15
   perimeter of rectangle = (21 + 15)2 = 72 cm
   Both statement are required to find the answer.

    

2. What is the length of train ?
   I. The train crosses a 220 meters long platform in 15 seconds.
   II. The train crosses a person walking in opposite direction in 6 seconds.
   
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option D
   From I, Let length of train = x
   speed of train = y
   x + 220/y = 15
   From II, Let speed of man = z km/hr
   x/y + z = 6
   Both statement I and II are not sufficient to calculate the answer.

    

3. What is the rate of interest ?
   I. Rs. 4000 becomes rs.5200 in 2 years when invested at simple interest.
   II. The same sum is invested in CI and SI for 2 years at same rate of interest and difference between CI and SI is rs.90.
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option C
   From I, Sum = 4000
   2 years interest = 5200 – 4000 = 1200
   1 years interest = 1200/2 = 600
   rate of interest = 600/4000 * 100 = 15%
   from II, P = 4000
   difference = 90
   90 = 4000 * R^2/1000^2
   R = 15%
   either I or II is sufficient.

    

4. What is the speed of boat in still water ?
   I. Boat covers 150 km in upstream speed in 10 hours.
   II. Ratio of speed of downstream and upstream is 5 : 3.
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option E
   From I, Upstream speed = 150/10 = 15 km/hr
   from II, Let downstream speed = 5x
   upstream speed = 3x
   from both I and II,
   downstream speed = 15/3x * 5x = 25 km/hr
   speed of boat = 25 + 15 /2 = 40/2 = 20 km/hr
   Both statement are required to find the answer.
   

    

5. In how many days B alone can do the work ?
   I. A and B together can complete a work is 18 days.
   II. B and C together can complete the same work in 24 days.
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option D
   Alone statement I and II can not find answer
   from both statement I and II together
   LCM of 18 and 24 = 72
   efficiency of A and B = 72/18 = 4
   efficiency of B and C = 72/24 = 3
   Here , we can not find individual efficiency so,
   from both statement I and II we can not calculate the answer.

    

6. What is the area of square ?
   I. The perimeter of square is 36 cm.
   II. The area of rectangle is 96 cm^2 and side of square is 3 cm less than length of rectangular.
   
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option A
   From I, perimeter of square is 36 cm.
   side of square = 36/4 = 9 cm
   area of square = 9 * 9 = 81 cm^2
   From II, Area of rectangle = 96 cm^2
   only from II we can not find the answer.
   only statement I is sufficient.

    

7. How much profit earned selling a table ?
   I. The ratio of cost price and marked price of the table is 5 : 8. After giving some discount profit percent occurred is 28%.
   II. The shopkeeper is given 20% discount on MP and selling price of the table is rs.320.
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option E
   From I , Let CP of table = 5x
   MP = 8x
   profit = 28%
   From II, SP = 320
   discount = 20%
   MP = 320/4 * 5 = 400
   both From I and II,
   MP = 400
   CP = 400/8 * 5 = 250
   profit = 320 – 250 = 70
   Both I and II are sufficient to find answer.

    

8. What is profit share of C ?
   I. A and B start the business with capital of rs.8000 and rs.10000 respectively.
   II. After 4 months C joined the business with capital of rs.6000 and total profit at the end is rs 2200.
   
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option E
   From I, A and B invested rs.8000 and rs.10000 respectively.
   from II, total profit = rs. 2200
   C invested 6000 for 8 months
   Both from I and II,
   Profit sharing ratio of A, b and C = (8000 * 12) : (10000 * 12) : (6000 * 8)
   = 4 : 5 : 2
   profit of C = 2200 * 2/11 = 400
   Both statement I and II is required to find answer.

    

9. What is the age of the mother of Rohit ?
   I. The age of Rohit’s father is 3 times more than age of Rohit. After 4 years the ratio of age of Rohit and his father becomes 1: 3 and the age of mother is 4 years less than the age of his father.
   II. The ratio of age of Rohit and his mother is 2 : 7 and before 4 years the age of Rohit and his mother 1 : 6.
   Only statement I is sufficient.
   Only statement II is sufficient.
   Either statement I or statement II is sufficient.
   Neither statement I nor statement II is sufficient.
   Both statement I and II are sufficient.
   Option C
   From I, Let the age of Rohit = x
   the age of his father = 3x + x = 4x
   After 4 years,
   x + 4/ 4x + 4 = 1/3
   3x + 12 = 4x + 4
   x = 8
   age of his father = 4x = 4 * 8 = 32
   age of his mother = 32 – 4 = 28
   From II, Let the age of Rohit = 2x
   the age of his mother = 7x
   before 4 years,
   2x – 4/ 7x – 4 = 1/6
   12x – 24 = 7x – 4
   5x = 20
   x = 4
   age of his mother = 7 * 4 = 28 years

    

10. How much marks scored by Rinu ?
    I. Rinu scored 32% and failed by 48 marks.
    II. She scored 49% which is 54 more marks than pass marks.
    Only statement I is sufficient.
    Only statement II is sufficient.
    Either statement I or statement II is sufficient.
    Neither statement I nor statement II is sufficient.
    Both statement I and II are sufficient.
    Option E
    Either I or II we can not calculate the answer.
    Both statement I and II,
    32% + 48 = 49% – 54
    17% = 102
    1% = 6
    pass marks = 32% + 48 = 192 + 48 = 240 marks
    Both I and II is required to get answer.

     

1. A man goes to his office at a speed of 30 km/hr and return to home at a speed of 45 km/hr. If he takes total 10 hours in all then, what is the distance between his office to home ?
   120 km
   180 km
   340 km
   220 km
   200 km
   Option B
   Let distance = D km
   D/30 – D/45 = 10
   D = 180 km

    

2. The speed of car and bus in the ratio of 4 : 5. Car takes 1 hour more than bus to cover a distance of 240 km, then find speed of bus ?
   40 km/hr
   30 km/hr
   60 km/hr
   84 km/hr
   72km/hr
   Option C
   Let speed of car and bus = 4x and 5x respectively
   240/4x – 240 /5x = 1
   x = 12 km /hr
   speed of bus = 5 * 12 = 60 km/hr

    

3. A train length of 225 meters can cross a pole in 9 sec. How much time taken by train if cross a platform whose length is 255 meters ?
   22 sec
   19 1/5 sec
   12 1/2 sec
   18 sec
   20 sec
   Option B
   Speed of train = 225/9 = 25 m/sec
   time = 225 + 255 / 25 = 19 1/5 sec
   

    

4. Ram goes to office from house at speed of 30 km/hr and reach 2 minutes before his usual time, if he goes at speed of 20 km/hr , then he reaches 3 minutes late. What is distance between office to house ?
   6 km
   5 km
   12 km
   14 km
   8 km
   Option B
   Let distance = D
   (D/20 – D/30) = 5/60 hours
   D = 5 km

    

5. Train A starts from M with the speed f 80 km/hr at 10 am and B starts with the speed of 100 km/hr at 12 pm from N and total distance between M and N is 700 km, find at what time they will cross each other ?
   4:00 pm
   3:00 pm
   2:00 pm
   5:00 pm
   3:30 pm
   Option B
   Speed of train A = 80 km/hr
   distance travel by train A from 10 am to 12 pm = 2 * 80 = 160 km
   remaining distance = 700 – 160 = 540 km
   time = 540/ (80 + 100) = 3 hours
   time = 12 pm + 3 hours = 3:00 pm
   

    

6. 180m length of train crosses a platform at speed of 90 km/hr in 12 sec. Another train ar speed of 144 km/hr crosses same platform in 8 seconds. What is length of the other train ?
   200 m
   400 m
   600 m
   500 m
   300 m
   Option A
   Speed of train = 90 * 5 / 18 = 25 m/sec
   let length of platform = x
   x + 180/25 = 12
   x = 300 – 180 = 120 m
   let length another train = y
   speed of other train = 144 * 5/18 = 40 m/sec
   y + 120/40 = 8
   y = 320 – 120 = 200m

    

7. two trains of length of 145 m and 215 m are running in same direction with speed of 162 km /hr and 108 km/hr respectively. How much time will they take to cross each other ?
   18 seconds
   12 seconds
   15 seconds
   25 seconds
   24 seconds
   Option E
   Speed of 145 m long train = 162 * 5/18 = 45 m/sec
   speed of 215 m long train = 108 * 5/18 = 3 m/sec
   time = 145 + 215/45 – 30= 360/15 = 24 sec

    

8. The sum of the length of train A and B is 700 meters and the speed of train A is 54 km/hr. If they are running in opposite direction, then they can cross each other in 20 seconds. Find the speed of train B ?
   48 km/hr
   75 km/hr
   108 k/hr
   54 km/hr
   72 km/hr
   Option E
   Speed of train A = 54 * 5/18 = 15 m/sec
   total length = 700m
   let speed of train B = x m/sec
   700/(15 + x) = 20
   x = 20 m/sec
   speed of train B = 20 * 18/5 = 72 km /hr

    

9. Two stations P and Q are at a distance of 225 km. Train A starts running from station P and train B starts running from station Q respectively and meet each other after 3 hours. If the speed of train A is 5 km/hr more than the speed of train B, then find speed of train A ?
   42 km/hr
   40 km/hr
   28 km/hr
   32 km/hr
   50 km/hr
   Option B
   Let speed of train B = x km/hr
   speed of train A = (x + 5) km/hr
   total distance = 225 km
   225/(x + 5 + x) = 3
   225 = 6x + 15
   x = 35
   speed of train A = 35 + 5 = 40 km/hr

    

10. Sushant covers a distance by walking for 6 hours. While returning his speed decreased by 2 km/hr and he takes 9 hours to cover the same distance. What was his speed while returning ?
    4 km/hr
    5 km/hr
    8 km/hr
    6 km/hr
    14 km/hr
    Option A
    Let original speed of Sushant = x km/hr
    while returning his speed = (x – 2) km /hr
    x * 6 = 9 ( x – 2 )
    6x = 9x – 18
    x = 6
    his speed while returning = 6 – 2 = 4 km/hr

     

1. A sum of rs.P invested on compound interest annually at certain rate of interest and it three times itself in five years. In how many years the amount to 9 times itself at the same rate of interest ?
   5 years
   8 years
   7 years
   10 years
   12 years
   Option D
   3P = P(1 + R/100)^5
   3 = (1 + R/100)^5
   3^2 = (1 + R/100)5*2
   9 = (1 + R/100)^10
   time = 10 years

    

2. A lends rs. 5500 to B at 20% per annum and B lends the same sum to C at 22% per annum. Find the gain of B after 2 years in simple interest.
   380
   275
   220
   440
   554
   Option C
   B gives the interest to A after 2 years,
   5500 * 20/100 * 2 = 2200
   C gives the interest to B after 2 years
   5500 * 22/100 * 2 = 2420
   the gain of B = 2420 – 2200 = 220

    

3. Difference between compound interest and simple interest on sum of rs.4800 at certain rate of interest after 2 years is rs. 108. What is the rate of interest ?
   14%
   15%
   17%
   12.5%
   24%
   Option B
   CI – SI = PR^2/100^2
   108 = 4800R^2/10000
   R^2 = 108 * 10000/4800
   P^2 = 225
   R = 15%
   

    

4. After two years ratio between simple interest to principle is 2 : 5. If difference between CI and SI after two years is 208, then find principle ?
   4800
   4750
   4540
   4850
   5200
   Option E
   Let principle = 5x
   and SI = 2x
   rate of interest for two years = 2x/5x * 100 = 40%
   rate of interest for 1 years = 40%/2 = 20%
   CI – SI = PR^2/100^2
   208 = P (20)^2/10000
   P = 5200

    

5. Two persons P and Q invested rs. (x + 3400) and (x+ 2200) at the rate of 15% and 20% respectively for two years in simple interest. After two years total SI is rs.7220, then how much amount invested by Q ?
   7600
   9820
   5840
   6450
   9240
   Option A
   (x + 3400) * 15 /100 * 2 + (x + 2200) * 20/100 * 2 =7220
   (x + 3400) * 3/10 + (x+2200)*2/5 = 7220
   (3x + 102000/10) + (2x + 4400/5) = 7220
   (3x + 10200 + 4x + 8800/10) = 7220
   7x + 19000 = 72200
   x = 7600

    

6. Total sum of rs.4740 is invested by two friends A and B in a scheme at the rate interest of 12% p.a for 4 year in SI. If interest received by B is 67.20 more than interest received by A, then find how much amount invested by A ?
   2800
   2300
   1840
   2350
   none of these
   Option B
   A invested = x
   B invested = 4740 – x
   (4740 – x) 12/100 * 4 – x * 12/100 * 4 = 67.20
   48/100 ( 4740 – x – x) = 6720
   12/25 (4740 – 2x) = 67.20
   4740 – 2x = 67.20 * 25/12
   4740 – 2x = 140
   2x = 4600
   x = 2300
   amount invests by A= 2300
   

    

7. What is the compound interest accrued on a sum of 1400 at the rate of 6% in 2 years ?
   
   184.25
   254.08
   334.05
   173.04
   234.14
   Option D
   Compound interest for 2 years
   6 + 6 + 6 * 6/100 = 12.36 %
   compound interest = 1400 * 12.36/100 = 173.04
   

    

8. The compound interest on a certain sum at 20% p.a for 2 years is rs. 98 more than the simple interest on same sum at 15% per annum for 2 years. What is the sum ?
   700
   480
   320
   1000
   650
   Option A
   Let sum is rs.x
   compound interest for 2 years at 20 % p.a
   20 + 20 + 20 * 20 /100 = 44%
   simple interest for 2 years at 15 % = 15% * 2 = 30%
   x * 44/100 – x * 30/100 = 98
   x = 700
   

    

9. A certain sum is deposited at rate of 40% p.a on Compound interest. Difference between interest earned at the 1st and 2nd year is rs.384. What is the sum ?
   4800
   4500
   3200
   4500
   2400
   Option E
   Let sum = 100x
   interest of 1st year = 100x * 40/100 = 40x
   total amount at the end of the 1st year = 100x + 40x = 140x
   interest of 2nd year = 140x * 40/100 = 56x
   difference = 56x – 40x = 16x
   16x = 384
   x = 24
   sum = 100x = 100 * 24 = 2400
   

    

10. What is difference between the compound interest on rs.4000 for 1.5 years at 40% p.a compounded yearly and half-yearly ?
    182
    192
    534
    314
    208
    Option B
    Rate of interest after 1.5 years compounded yearly at 40%p.a
    40 + 20 + 800/100 = 68%
    CI = 4000 * 68/100 = 2720
    Rate of interest after 1.5 years compounded half-yearly
    rate of interest = 40/2 = 20%
    20 + 20 + 20 * 20 /100 = 44%
    44% + 20% + 880/100 = 72.80%
    CI = 4000 * 72.80 /100 = 2912
    difference = 2912 – 2720 = 192

     

1. Two dice are rolled randomly. Find the probability to get sum is 10.
   2/5
   14
   2/9
   1/12
   5/8
   Option D
   Required = (6 , 4 ) , (4 , 6) , ( 5, 5) = 3
   total = 6 * 6 = 36
   probability = 3/36 = 1/12
   

    

2. Two dices are rolled out together, then what is the probability of getting a number of one dice greater than the number of other dice ?
   2/3
   1/6
   3/8
   1/8
   5/6
   Option E
   Non-favorable events = (1 , 1) , (2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) , (6,6) = 6
   total = 6 * 6 = 36
   probability of non-favorable events = 6/36 = 1/6
   probability of favorable events = 1 – 1/6 = 5/6
   

    

3. If 2 cards is drawn at randomly from 52 cards, then find the probability of getting both are red cards.
   13/28
   26/105
   28/108
   25/102
   none of these
   Option D
   Required = 26C2 = 26 * 25/2 = 13 * 25
   total = 52C2 = 52 * 51 / 2 = 26 * 51
   probability = 13 * 25 / 26 * 51 = 25 /102

    

4. In how many ways, we can arrange the letters of the word ‘LIGHT’ ?
   84
   28
   140
   160
   120
   Option E
   Ways = 5! = 5 * 4 * 3 * 2 * 1 = 120
   

    

5. In how many different ways, we can arrange the letters of the word ‘MOUSE’ , so that the middle position is always occupied by ‘S’ ?
   25
   24
   48
   42
   68
   Option B
   Ways = 4! = 4 * 3 * 2 * 1 = 24

    

6. How many ways 6 books can be selected from 14 different books , if two particular books are always selected ?
   495
   480
   231
   384
   520
   Option A
   Available objects = 14 – 2 = 12
   Ways = 12C4 = 12 * 11 * 10 * 9/4 * 3 * 2 * 1 = 495

    

7. A bag contains 2 white balls, 3 pink balls and 2 black balls. 2 balls are drawn randomly. What is the probability that there is no black balls ?
   8/21
   10/21
   1/8
   3/5
   6/11
   Option B
   Required = 5C2 = 5*4/2 = 10
   total = 7C2 = 7 * 6 / 2 = 21
   probability = 10/21

    

8. When two coins are tossed simultaneously, then find the probability of getting at least one tail.
   5
   3
   3/4
   1/4
   2/5
   Option C
   Required = ( 1 head , 1 tail ) , ( 2 tails) = (2C1) + (2C2) = 2 + 1 = 3
   total = 2^2 = 4
   probability = 3/4

    

9. A bag contains 4 red balls, 2 blue balls and 2 green balls . If two balls are drawn randomly from the bag , then find the probability of getting both balls of different color.
   2/7
   5/8
   5/7
   4
   8
   Option C
   probability = 4C1 * 2C1 / 8C2 + 4C1 * 2C1 / 8C2 + 2C1 * 2C1 / 8C2
   (4 * 2 * 2)/ 8 * 7 + (4 * 2 * 2)/ 8 * 7 + (2 * 2 * 2) / 8 * 7 = 2/7 + 2/7 + 1/7 = 5/7

    

10. A group of students sitting around a rectangular table, find probability of 2 specified students sitting together.
    3/8
    2/7
    8/7
    3/8
    6/11
    Option B
    Favorable cases = 6! * 2!
    total cases = 7!
    probability = 6! * 2! /7! = 2/7

     

Directions : The given below table shows that the number of boys and girls studied in five different classes.

1. No. of boys in class A and B together is how many more or less than no. of girls in class C and E together ?
   65
   38
   52
   48
   50
   Option E
   Total no. of boys in class A and B = 48 + 76 = 124
   total of no. of girls in class C and E = 80 + 94 = 174
   difference = 174 – 124 = 50

    

2. What is the ratio of total no. of girls in class B and no. of boys in class D ?
   17 : 19
   15 : 19
   6 : 5
   3 : 4
   19 : 17
   Option E
   Ratio = 38 : 34 = 19 : 17

    

3. No. of boys in class A and C together is what percent more or less than than the no. of girls in class C ?
   50%
   40%
   46%
   56%
   64%
   Option B
   Total no. of boys in class A and C together = 48 + 64 = 112
   girls in class C = 80
   percentage = more = 112 – 80 / 100 = 40%

    

4. What is difference between total no. of students in class D and total no. of students in class A ?
   18
   25
   34
   46
   52
   Option A
   Total students in class D = 34 + 58 = 92
   total students in class A = 48 + 62 = 110
   difference = 110 – 92 = 18

    

5. Total no. of students in class F is 20% more than the total no. of students in class A. If ratio of boys and girls in class F is 2 : 1 , then find total no. of boys in class F and E together.
   125
   170
   280
   240
   270
   Option B
   Total students in class A = 110
   total students in class F = 110 * 6/5 = 132
   boys in class F = 132 * 2/3 = 88
   total boys in class F and E = 88 + 82 = 170

    

Directions : The following pie-chart given below shows that the percentage distribution marks of six different subjects scored by Ram.


6. 
   Difference between total marks scored by Ram in Math and Economics together to total marks scored in English and Chemistry together ?
   35
   46
   68
   54
   82
   Option D
   Total marks in Math and Economics together = 1800 * (20% + 15%)/100 = 630
   Total marks in English and Chemistry together = 1800 * (10% + 22%)/100 = 576
   difference = 630 – 576 = 54
   

    

7. What is the ratio between marks scored by Ram in Physics and in Economics ?
   3 : 2
   1 : 5
   2 : 3
   5 : 4
   2 : 5
   Option D
   Ratio = 25% : 20% = 5 : 4
   

    

8. Total marks scored in Math is what percent more or less than total marks scored in History ?
   67.5%
   28.4%
   87.5%
   92.25%
   50%
   Option C
   Percentage = 15% – 8% / 8% = 100 = 87.5%

    

9. Total marks scored by Ram in Physics and Math together how much more or less than total marks scored in History and Economics together ?
   220
   320
   540
   216
   175
   Option D
   Total marks in Physics and Math together = 1800 * (15 + 25)/100 = 720
   Total marks in Physics and Economics together = 1800 * (20 + 8)/100 = 504
   Difference = 720 – 504 = 216
   

    

10. What is the central angle of marks scored by Ram in English ?
    82 degree
    36 degree
    144 degree
    72 degree
    40 degree
    Option B
    Central angle = 10/100 * 360 = 36 degree