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1Dec, 2021

Mixed Quantitative Aptitude Questions Set 239

A train , 240 m long crosses a man, walking along the line in opposite direction at the rate of 3 km/hr in 10 seconds. What is the speed of train ?
80 km/hr

75 km/hr

83.4 km/hr

92.8 km/hr

68 km/hr

Option C
Let speed of train = x m/hr
240/(3 + x) 5/18 = 10
x = 83.4 km/hr
A boat takes a total of 24 hours to over 90 km in downstream and 90 km in upstream. If the ratio of speed of boat in sill water and speed of stream is 4 : 1, then find how much time is required to cover 120 km distance in down stream speed ?
8 hours

14 hours

20 hours

15 hours

12 hours

Option E
Let speed of boat in still water = 4x
speed of stream = x
downstream speed = 4x + x = 5x
upstream speed = 4x – x = 3x
90/5x + 90/3x = 24
x = 2
downstream speed = 5 * 2 = 10 km/hr
time = 120/10 = 12 hours
A equilateral tringle and a square have the same area. If the perimeter of the square is 88cm, then find what is area of the equilateral tringle ?
196 cm^2

256 cm^2

144 cm^2

484 m^2

125 cm^2

Option D
Perimeter of square = 88cm
side of square = 88/4 = 22cm
area of square = 22 * 22 = 484 cm^2
area of tringle = 484 cm^2
Pipe A can fill a tank in 15 hours and pipe B can fill the same tank in 60 hours, pipe C can empty in 10 hours. Pipe A and B are kept opened for 10 hours in the beginning and then pipe C is also opened, what is the time taken to empty the tank ?
60 hours

40 hours

30 hours

25 hours

50 hours

Option E
Capacity of the tank = 15, 60, 10 = 60 units
efficiency of pipe A = 60/15 = 4 units
efficiency of pipe B = 60/60 = 1
efficiency of pipe C = 60/10 = 6 units
tank filled in 1st 10 hours = (4 + 1) * 10 = 50 units
now, when all the pipe work together, 1 unit of water will out in every minute from tank.
50 units of water will be in 50 hours.
The ratio of age of A and B, 6 years ago was 3 : 4. Sum of the present age of B and C is 80 years. C is 12 years elder to A. Find the difference of age of B and C after 4 years ?
5 years

6 years

8 years

4 years

12 years

Option D
6 years ago age of A = 3x
age of B = 4x
present age of A = 3x + 6
present age of B = 4x + 6
present age of C = 3x + 6 + 12 = 3x + 18
4x + 6 + 3x + 18 = 80
7x = 56
x = 8
age of B after 4 years = 4x + 6 + 4 = 42 years
age of C after 4 years = 3x + 18 + 4 = 46 years
difference = 46 – 42 = 4 years
Directions : What will be wrong number in the following wrong number series ?
120, 83, 113, 93, 105, 99, 101
113

83

105

120

99

Option D
The series is, (- 6 * 7), (+ 5 * 6), ( – 4 * 5), ( + 3 * 4), ( – 2 * 3), ( + 1 * 2)
1898, 1870, 1657, 1608, 1096, 1015, 15
1096

1015

1898

15

1870

Option E
The series is ( – 5^2 ), (- 6^3), (- 7^2), (- 8^3 ), (- 9^2), (- 10^3)
48, 84, 156, 300, 590, 1164
48

156

300

590

1164

Option D
The series is, ( * 2 – 12), ( * 2 – 12)…
2, 6, 12, 24, 30, 42, 56
24

12

30

42

2

Option A
The series is , (1^2 + 1), (2^2 + 2), (3^2 + 3)…
1, 6, 24, 60, 120, 210
6

1

60

24

210

Option B
The series is, (1^3 – 1), (2^3 – 2), (3^3 – 3), (4^3 – 4)…

01

30Nov, 2021

Mixed Quantitative Aptitude Questions Set 238

Directions : What will come in place of questions marks (?) in the following questions ? ( You are not to calculate the exact value )
(20.24% of 749.81) ÷ 2.89 + 85.20 = ?
125

135

120

130

145

Option B
20% of 750/3 + 85 = ?
? = 135
(12.138 * 4 + 4.98 * 7.99) ÷ ( 9.12 + 1.85) = ?
5

6

8

12

15

Option C
( 12 * 4 + 5 * 8) ÷ 9 + 2 = ?
? = 88/11
? = 8
√100.12 – √63.87 + √144.01 * 5.32 = ?
58

82

94

62

52

Option D
10 – 8 + 12 * 5 = ?
? = 62
(34.07)^2 + (15.89)^2 -√576.02 + 45.88 = ?
1520

1430

1434

1334

1324

Option C
1156 + 256 – 24 + 46 = ?
? = 1434
449. 75 ÷ 8.82 + 19.95 * 3.22 + √675.82 = ?
152

183

130

136

120

Option D
450 ÷ 9 + 20 * 3 + √676 = ?
? = 50 + 60 + 26
? = 136

Directions : What will be wrong number in the given wrong number series ?

12, 13, 24, 72, 288, 1440
12

13

1440

24

72

Option B
The series is, * 1, * 2, * 3 …
520, 525, 540, 585, 720, 1120
525

720

1120

720

585

Option C
The series is, + 5, + 15, + 45, + 135, + 405
185, 166, 189, 160, 191, 156
185

189

160

156

166

Option D
The series is, -19, + 23, -29, + 31, -33
9, 12, 27, 84, 339, 1544
339

84

27

9

1544

Option E
The series is, (* 1 + 3), (* 2 + 3), (* 3 + 3)…
325, 329, 340, 354, 379, 415
329

379

354

340

415

Option D
The series is, + 4, + 9, + 16, + 25, + 36

02

29Nov, 2021

Mixed Quantitative Aptitude Questions Set 237

A starts a business with rs.4000 and B joins him after 3 months with rs. 16000. If total profit of the business is rs.2000, then find profit share of B.
2000

1000

1200

850

1500

Option E
Profit sharing ratio of A and B = (4000 * 12) : (16000 * 9)
= 48 : 144 = 1 : 3
profit share of B = 2000 * 3/4 = 1500
The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio ?
5 : 3

18 : 19

21 : 22

3 : 8

5 : 4

Option C
Let number of boys and girls are 7x and 8x respectively
ratio after increased =
7x * 6/5 : 8x * 11/10 = 21 : 22
The ratio between the present ages of P and Q is 5 : 7 respectively. If the difference between Q’s present age and P’s age after 6 years is 2 what is the total P’s and Q’s present age ?
32 years

68 years

50 years

48 years

26 years

Option D
Let present age of P and Q = 5x and 7x
7x – (5x + 6) = 2
x = 4
total = 12x = 12 * 4 = 48 years
The ratio of milk to water in total 56 liter of mixture is 5 : 3. If ‘x’ liter of milk and water is added in the mixture so that ratio becomes 25 : 18, then find the value of ‘x’.
20 liters

12 liters

18 liters

15 liters

22 liters

Option D
Quantity of milk in the mixture = 56 * 5/8 = 35
water = 56 * 3/8 = 21
35 + x/21 + x = 25/18
x = 15 liter
4 kg of rice at rs.8 per kg is mixed with 8 kg of wheat at rs.12 per kg. What is the average price of the mixture ?
12

10.66

5

8

12

Option B
Total cost of 4 kg rice = 4 * 8 = 32
total cost of 8 kg wheat = 8 * 12 = 96
average = 128/12 = 10.66
Directions : What will come in place of questions marks (?) in the following questions given below ?
15% of 220 + 20 * 15 – √1156 = ?
320

300

284

299

340

Option D
33 + 300 – 34 = ?
? = 299
3240 – 2240 + 2050 – 1800 = ?
2030

1250

3140

1240

1350

Option B
? = 5290 – 4040
? = 1250
√1296 – 30% of 120 + 40 + ? = 188
152

320

145

148

200

Option D
36 – 36 + 40 + ? = 188
? = 148
(18)^2 – (12)^2 + 420 – 120 = ?
320

126

440

480

520

Option D
324 – 144 + 420 – 120 = ?
? = 480
(15)^2 – 30 * 8 + (40)^2 = ?
1485

1575

1340

1585

1235

Option D
225 – 240 + 1600 = ?
? = 1585

03

28Nov, 2021

Mixed Quantitative Aptitude Questions Set 236

Directions : In the following questions, two equations I and II are given. You have to solve the equations and give answer the questions.
I. x^2 + 13x + 42 = 0
II. y^2 + 8y + 12 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option D
I. x^2 + 7x + 6x + 42 = 0
x = -7, -6
II. y^2 + 6y + 2y + 12 = 0
y = -6, -2
I. x^3 = 2744
II. y^2 = 289
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option E
I. x^3 = 2744
x = 14
II. y^2 = 289
y = 17, -17
I. x^2 – 2x – 24 = 0
II. y^2 + 3y – 40 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option E
I. x^2 – 6x + 4x – 24 = 0
x = 6, -4
II. y^2 + 8y – 5y – 40 = 0
y = -8, 5
I. 2x^2 + 10x + 12 = 0
II. y^2 + 10y + 25 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option A
I. 2x^2 + 6x + 4x + 12 = 0
x = -3, -2
II. y^2 + 5y + 5y + 25 = 0
y = -5, -5
I. (x – 2)^2 = x – 2
II. y^2 – 14y + 48 = 0

X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option B
I. (x – 2)^2 = x – 2
x^2 – 4x + 4 = x – 2
x^2 – 5x + 6 = 0
x^2 – 3x – 2x + 6 = 0
x = 3, 2
II. y^2 – 8y – 6y + 48 = 0
y = 8, 6
Directions : What will come in place of questions mark (?) in the following questions below ?
36% of 1800 + 80% 495 – (8)^2 = ?
970

880

440

980

1020

Option D
648 + 396 – 64 = ?
? = 980
12 * ? + (10)^2 = (16)^2 – 10 * 6
5

8

2

14

12

Option B
12 * ? + 100 = 256 – 60
12 * ? = 196 – 100
? = 8
32 * 3 + 60% of 300 = (?) + √400
14

15

12

16

24

Option D
96 + 180 = (?)^2 + 20
(?)^2 = 256
? = 16
264 ÷ 24 + 190 ÷ 5 = ? ÷ 5
245

315

255

320

240

Option A
264/24 + 190/5 = ?/5
? = (11 + 38) * 5
? = 245
?/27 * 60 = 12 * 3 * 5/?
520

620

440

540

480

Option D
(?)^2 = 12 * 3 * 5 * 27 * 60
(?)^2 = 36 * 5 * 9 * 3 * 12 * 5
? = √(36 * 25 * 9 * 36 )
? = 36 * 5 * 3
? = 540

04

27Nov, 2021

Mixed Quantitative Aptitude Questions Set 235

6 men or 8 women or 3 boys completed certain work in a day is equal. Find in how many days a man and a boy can complete the three-fourth of same work together ?
2 days

3 days

5 days

6 days

1.5 days

Option E
Let total work = 48
6 men = 8men = 3 boys
efficiency of a man = 48/6 = 8
efficiency of a woman = 48/8 = 6
efficiency of a boy = 48/3 = 16
days require = 48/(16 + 8) * 3/4 = 1.5 days
A sum becomes rs.9280 in 6 years and becomes rs.10440 in 8 days at the same rate on simple interest. Find compound interest earned in 2 years on rs.6000 at same rate of interest ?
1520

1840

2540

1340

1260

Option E
SI for 2 years = 10440 – 9280 = 1160
SI for 6 years = 1160/2 * 6 = 3480
sum = 9280 – 3480 = 5800
rate interest = 3480/(5800 * 6) *100 = 10%
CI for 2 years = 10 + 10 + 10 * 10/100 = 21%
CI = 6000 * 21/100 = 1260
A bat was sold at rs,1260 after giving 30% discount on market price. If discount was not given, then he would have earned 50% profit. Find cost price of bat ?
1400

1280

1800

1200

1440

Option D
Market price of bat = 1260/70 * 100 = 1800
CP = 1800/150 * 100 = 1200
Two trains travel from Mumbai to Bangalore and Bangalore to Mumbai in 10 hours and 12 hours respectively. Both trains started simultaneously at 8 am and the train started from Mumbai met with accident at 12 pm. Find percentage reduction in speed of train started from Mumbai, if they meet each other at 2 pm, assume there is no loss of time in accident ?
30%

48%

50%

42%

20%

Option C
Ratio of speed is inversely proportional to time taken if distance is constant.
Let speed of Mumbai to Bangalore travelling train = 6x km/hr
speed of Bangalore to Mumbai travelling train = 5x km/hr
Let total distance = 60x km
let speed of train after accident = y km/hr
60x = 4 (6x + 5x) + 2 (y + 5x)
y = 3x km/hr
reduction in speed = 6x – 3x/6x * 100 = 50%
The radius of a circle is 14 km. What is area of another circle having radius 1.5 times of the actual circle ?
1540 cm^2

1386 cm^2

1440 cm^2

1450 cm^2

1240 cm^2

Option B
Radius of another circle = 14 * 1.5 = 21 cm
area = πr^2 = 22/7 * 21 * 21 = 1386 cm^2
Directions : What will come in place of questions (?) mark in the following missing series ?
4, 2, 3, 7.5, 26.25, ?
120.125

118.5

114.5

118.125

120

Option D
The series is, (* .5), (* 1.5), (* 2.5), (* 3.5), (* 4.5)
148, 196, 268, 364, 484, ?
650

640

452

620

628

Option E
The series is, (+ 48), (+ 72), (+ 96), (+ 120), (+ 144),
46, 52, ?, 136, 256, 466
84

78

68

76

80

Option D
The series is, (+ 2^3 – 2), (+ 3^3 – 3), (+ 4^3 – 4), (+ 5^3 – 5), (+ 6^3 – 6),
16000, 8000, 24000, 6000, ?, 30000, 5000
40000

18000

12000

42000

30000

Option E
The series is, (÷ 2), (* 3), (÷ 4), (* 5), (÷ 6)
24, 28, 36, 52, 84, ?
240

148

120

124

168

Option B
The series is, (+ 4), (+ 8), (+ 12), (+ 32), (+ 64),

05

26Nov, 2021

Mixed Quantitative Aptitude Questions Set 234

6 men or 8 women or 3 boys completed certain work in a day is equal. Find in how many days a man and a boy can complete the three-fourth of same work together ?
2 days

3 days

5 days

6 days

1.5 days

Option E
Let total work = 48
6 men = 8men = 3 boys
efficiency of a man = 48/6 = 8
efficiency of a woman = 48/8 = 6
efficiency of a boy = 48/3 = 16
days require = 48/(16 + 8) * 3/4 = 1.5 days
A sum becomes rs.9280 in 6 years and becomes rs.10440 in 8 days at the same rate on simple interest. Find compound interest earned in 2 years on rs.6000 at same rate of interest ?
1520

1840

2540

1340

1260

Option E
SI for 2 years = 10440 – 9280 = 1160
SI for 6 years = 1160/2 * 6 = 3480
sum = 9280 – 3480 = 5800
rate interest = 3480/(5800 * 6) *100 = 10%
CI for 2 years = 10 + 10 + 10 * 10/100 = 21%
CI = 6000 * 21/100 = 1260
A bat was sold at rs,1260 after giving 30% discount on market price. If discount was not given, then he would have earned 50% profit. Find cost price of bat ?
1400

1280

1800

1200

1440

Option D
Market price of bat = 1260/70 * 100 = 1800
CP = 1800/150 * 100 = 1200
Two trains travel from Mumbai to Bangalore and Bangalore to Mumbai in 10 hours and 12 hours respectively. Both trains started simultaneously at 8 am and the train started from Mumbai met with accident at 12 pm. Find percentage reduction in speed of train started from Mumbai, if they meet each other at 2 pm, assume there is no loss of time in accident ?
30%

48%

50%

42%

20%

Option C
Ratio of speed is inversely proportional to time taken if distance is constant.
Let speed of Mumbai to Bangalore travelling train = 6x km/hr
speed of Bangalore to Mumbai travelling train = 5x km/hr
Let total distance = 60x km
let speed of train after accident = y km/hr
60x = 4 (6x + 5x) + 2 (y + 5x)
y = 3x km/hr
reduction in speed = 6x – 3x/6x * 100 = 50%
The radius of a circle is 14 km. What is area of another circle having radius 1.5 times of the actual circle ?
1540 cm^2

1386 cm^2

1440 cm^2

1450 cm^2

1240 cm^2

Option B
Radius of another circle = 14 * 1.5 = 21 cm
area = πr^2 = 22/7 * 21 * 21 = 1386 cm^2
Directions : What will come in place of questions (?) mark in the following missing series ?
4, 2, 3, 7.5, 26.25, ?
120.125

118.5

114.5

118.125

120

Option D
The series is, (* .5), (* 1.5), (* 2.5), (* 3.5), (* 4.5)
148, 196, 268, 364, 484, ?
650

640

452

620

628

Option E
The series is, (+ 48), (+ 72), (+ 96), (+ 120), (+ 144),
46, 52, ?, 136, 256, 466
84

78

68

76

80

Option D
The series is, (+ 2^3 – 2), (+ 3^3 – 3), (+ 4^3 – 4), (+ 5^3 – 5), (+ 6^3 – 6),
16000, 8000, 24000, 6000, ?, 30000, 5000
40000

18000

12000

42000

30000

Option E
The series is, (÷ 2), (* 3), (÷ 4), (* 5), (÷ 6)
24, 28, 36, 52, 84, ?
240

148

120

124

168

Option B
The series is, (+ 4), (+ 8), (+ 12), (+ 32), (+ 64),

06

24Nov, 2021

Mixed Quantitative Aptitude Questions Set 233

A container which contains 80 liters of milk and water in the ratio of 3 : 2. How much quantity of mixture should be replaced with water so that in the final mixture, ratio of milk to water is 9 : 11 ?
25 liters

32 liters

28 liters

20 liters

42 liters

Option D
Quantity of milk = 80 * 3 /5 = 48 liters
Quantity of water = 80 * 2 /5 = 32 liters
let ‘x’ liters of mixture is replaced with water.
(48 – x * 3/5 ) / (32 – x * 2/5 + x) = 9/11
x = 20 liters
Ram bought a chair for rs.480 and marked is at rs.720. If he made a profit of 25% on selling the table then find percentage discount allowed by Ram on the chair ?
15%

20%

18%

45%

16.67%

Option E
SP of chair = 480 * 125/100 = 600
MP = 720
discount percentage = 720 – 600/720 * 100 = 16.67%
A alone can do a work in 25 days whereas B and C together can do some work in 20 days. A and B together worked for 8 days then A left the work. If efficiency of C is half of efficiency of A, then in how many days remaining work will be completed b A and C together ?
5 days

7 1/3 days

15 days

8 days

14 days

Option B
LCM of 25 and 20 = 100
efficiency of A = 100/25 = 4
efficiency of B and C = 100/20 = 5
efficiency of C = 4/2 =2
efficiency of B = 5 – 2= 2
A and B worked for 8 days = 8 ( 4 + 3) = 56 work
remaining work = 100 – 56 = 44
remaining work will be completed A and C together = 44/4 + 2 = 7 1/3 days
Train A travelling at 72 km/hr crosses a platform of 160 m in 18 seconds and train B travelling at 90 km/hr crosses the same platform in 15 seconds. Find the length of train B ?
320m

240m

210m

225m

215m

Option E
Speed of train A = 72 * 5/18 = 20 m/sec
distance covered by train A = 20 * 18 = 360 m
length of train A = 360 – 160 = 200m
speed of train B = 90 * 5/18 = 25 m/sec
distance covered by train B = 25 * 15 = 375 m
length of train B = 375 – 160 = 215 m
A is 6 years younger than B and ratio of present age of B to C is 12 : 5. If ratio of present age of A to C is 2 : 1, then find present age of B ?
32 years

34 years

42 years

36 years

40 years

Option D
Let present age of B = 12x
age of C = 5x
age of A = 12x – 6
12x – 6/5x = 2/1
12x – 6 = 10x
2x = 6
x = 3
present age of B = 12 * 3 = 36 years
Directions : What will come in place of questions marks ( ? ) in the following questions below ?
35% of 320 + 440 – √1024 = ?
540

320

340

620

520

Option E
112 + 440 – 32 = ?
? = 520
124 * 4 – 320 ÷ 5 + √361 – 18 = ?
225

320

435

433

520

Option D
496 – 64 + 19 – 18 = ?
? = 433
495 ÷ 5 + (21)^2 – (20)^2 = ?
324

420

325

140

260

Option D
99 + 441 – 400 = ?
? = 140
1240 + 2520 – 3540 + 4250 = ?
4340

5470

4240

3450

4470

Option E
? = 8010 – 3540
? = 4470
(12)^2 + (18)^2 – (20)^2 + (14)^2 = ?
365

264

345

420

540

Option B
144 + 324 + 196 – 400 = ?
? = 264

07

13Nov, 2021

Mixed Quantitative Aptitude Questions Set 232

The ratio of the milk to water in a mixture is 4 : 3. 21 liter of mixture is taken out and 8 liter of milk and 14 liter of water is added in mixture, so that new ratio of milk to water becomes 320 : 17, then find initial quantity of milk in the mixture ?
84 liters

35 liters

63 liters

80 liters

72 liters

Option A
Let quantity of milk and water in the mixture = 4x and 3x respectively
(4x – 21 * 4/7 + 8)/(3x – 21 * 3/7 + 14) = 20/17
4x – 4/3x + 5 = 20/17
x = 21
Initial quantity of milk in the mixture = 4x = 4 * 21 = 84 liters
A alone can do 40% of work in 8 days and B alone can do 30% of work in 12 days. If efficiency of C is 50% more than A, then find in how many days A, B and C together will be completed 90% of work ?
5 days

8 days

12 days

6 days

4 days

Option D
Total days required to complete the work by A = 8/40 * 100 = 20
total days required to complete the work by B = 12/30 * 100 = 40
LCM of 20 and 40 = 40
efficiency of A = 40/20 = 2
efficiency of B = 40/40 = 1
efficiency of C = 2 * 150/100 = 3
days required = 40/6 * 90/100 = 6 days
The ratio of present age of A and B is 3 : 4. If the ratio of age of A after 6 years and age of B before 4 years is 6 : 5, then find the age of B after 4 years ?
42 years

25 years

26 years

28 years

40 years

Option D
Let the present age of A and B = 3x and 4x
3x + 6/ 4x – 4 = 6/5
15x + 30 = 24x – 24
x = 6
the age of B after 4 years = 4x + 4 = 28 years
A man goes from a place A to B at a speed of 12 km/hr and returns from B to A at a speed of 18 km/hr. What is the average speed for the whole journey ?
12 km/hr

24 km/hr

14 km/hr

14 2/5 km/hr

15 2/5 km/hr

Option D
Average speed = 2xy /x + y
= 2 * 12 * 18/12 + 18 = 14 2/5 km/hr
A boat covers 12 km upstream and 18 km downstream in 3 hours while it covers 36 km upstream and 24 downstream in 6 1/2 hours, what is the speed of stream ?
5 km/hr

4 km/hr

6 km/hr

2 km/hr

8 km/hr

Option D
12/x – y + 18/x + y = 3
36/x – y + 24/x + y = 13/2
let x – y = a, x + y = b
12/a + 18/b = 3
36a + 24/b = 13/2
By multiplying ‘3’ in equation (i)
36/a + 54/b = 9
36/a + 24/b = 13/2
30/b = 9 – 13/2
b = 12
36/a + 9/2 = 9
36/a = 9/2
a = 8
x – y = 8
x + y = 12
2x = 20
x = 10
y = 2
Directions : What will come in place of questions marks (?) in the following number series ?
345, 358, 375, ?, 417, 446
380

382

392

394

396

Option D
The series is, (+ 13), (+ 17), (+ 19), (+ 23), (+ 29),
5, 11, 35, 143, 719, ?
4240

4319

4465

4978

4565

Option B
The series is, ( * 2 + 1), ( * 3 + 2), ( * 4 + 3), ( * 5 + 4), ( * 6 + 5),
20, 18, 38, 56, 94, ?
155

100

120

125

150

Option E
The series is, (20 + 18), (18 + 56), (56 + 94)
35, 40, 55, 80, 115, ?
145

180

160

172

165

Option C
The series is, (+ 5), (+ 15), (+ 25), (+ 35), (+ 45),
35, 18, 19, 30, ?, 157.5
64

62

58

96

86

Option B
The series is, ( * 5 + .5), (* 1 + 1), (* 1.5 + 1.5), (* 2 + 2), (* 2.5 + 2.5)

08

9Nov, 2021

Mixed Quantitative Aptitude Questions Set 231

I. x^2 – 11x + 18 = 0
II. y^2 – 16 y + 39 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option E
I. x^2 – 9x – 2x + 18 = 0
x = 9, 2
II. y^2 – 13y – 3y + 39 = 0
y = 13, 3
I. 2x^2 + 19x + 35 = 0
II. 2y^2 + 7y + 5 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option D
I. 2x^2 + 14x + 5x + 35 = 0
2x = -14, – 5
x = -7, -2.5
II. 2y^2 + 5y + 2y + 5 = 0
2 = -5, -2
y = -2.5, -1
I. x^3 = 512
II. y^2 – 13y + 40 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option C
I. x^3 = 512
x = 8
II. y^2 – 8y – 5y + 40 = 0
y = 8, 5
I. (x – 4)^2 = 0
II. 2y^2 – 5y + 2 = 0
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option A
I. x^2 – 4x – 4x + 16 = 0
x = 4, 4
II. 2y^2 – 4y – y + 2 = 0
y = 2, .5
I. x^4 = 1296
II. y^3 = 216
X > Y

X < Y

X ≥ Y

X ≤ Y

X = Y or no relation

Option E
I. x^4 = 1296
x = 6
II. y^3 = 216
y = 6
Directions : What will come in place of questions (?) marks in the following questions given below ?
21 * 25 – (8)^3 + (16)^2 – ? = (17)^2
25

22

38

64

20

Option E
525 – 512 + 256 + ? = (17)^2
269 + ? = 289
? = 20
672 ÷ 28 + 22 * 19 – (15)^2 = ?
218

256

320

217

215

Option D
24 + 418 – 225 = ?
? = 217
55% of 320 + √? = 16 * 8 + 84
36

84

216

1296

26

Option D
176 + √? = 212
√? = 36
? = 1296
√2025 ÷ 9 * 4 + 25 of 20 ÷ 4 = ?
120

132

138

145

136

Option D
45 ÷ 9 * 4 + 25 * 20/4 = ?
? = 20 + 125
? = 145
(?)^3 ÷ 180 = 1200
25

62

65

60

36

Option D
(?)^3 = 1200 * 180
? = 60

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3Nov, 2021

Mixed Quantitative Aptitude Questions Set 230

P is 25% more efficient than Q and he completes a task in 36 days. If R alone complete the same task in 30 days, then find all three together can complete the same task in how many days ?
15 days

18 days

8 days

14 days

12 days

Option E
Ratio of efficiency of A and B = 5 : 4
total work = 36 * 5 = 180
efficiency of C = 180/30 = 6
required time = 180/5 + 4 + 6 = 12 days
A shopkeeper marked up an article 60% above cost price and sell it at rs.960 after allowing discount of 25%. If profit of shopkeeper is rs.160, then find the marked price of article ?
1420

1200

1140

1540

1280

Option E
Let CP of article = 100x
MP of article = 160x
CP = 960 – 160 = 800
100x = 800
x = 8
MP of article = 160 * 8 = 1280
Average of serious of six consecutive even numbers is 25, find the sum of second and fourth number of serious.
43

35

24

48

56

Option D
Let series be x, x + 2 , x + 4, x + 6, x + 8, x + 10
6x + 30/6 = 25
x = 20
2nd and 4th number = (20 + 2 = 22), ( 20 + 6 = 26)
sum = 48
Ratio of investment of A, B and C is 4 : 6 : 9 respectively. At the end of a year, ratio of profit share of A, B and C is 4 : 5 : 6 respectively. If A has invested for a year then find the sum of period of investment of B and C ?
20 months

18 months

14 months

24 months

28 months

Option B
Let investment of A, B and C = 4x, 6x and 9x respectively
period of investment of B and C = a and b months respectively.
ratio of profit share ,
A : B : C = 4x * 12 : 6x * a : 9x * b
4x * 12/6x * a = 4/5
a = 10 months
4x * 12/9x * b = 4/6
b = 8 months
required sum = 10 + 8 = 18 months
Ratio between income and expenditure of Sujit increased by 20% and 33.33% in two successive years and expenditure remains same, then his saving is increased by rs.18000. What is his new income ?
45000

38000

65000

32000

48000

Option E
Income and expenditure of Sujit 15x and 6x respectively.
saving = 15x – 6x = 9x
new income = 15x * 6/5 * 4/5 = 24x
24x – 6x = 9x + 18000
x = 2000
new income = 24 * 2000 = 48000
Directions : What will come in place of questions (?) marks in the following number series ?
36, 18, ?, 27, 54, 135
12

19

20

18

22

Option D
The series is, (* .5), (* 1), (* 1.5), (* 2), (* 2.5)
26, 170, 366, 622, ? 1346
834

946

870

650

820

Option B
The series is, (+ 12)^2, (+ 14)^2, (+ 16)^2, (+ 18)^2, (+ 20)^2
10, 11, 15, 24, ? 65
45

30

38

40

45

Option D
The series is, (+ 1)^2, (+ 2)^2, (+ 3)^2, (+ 4)^2, (+ 5)^2,
8, 16, 43, 168, 511, ?
1452

1234

1020

1842

2024

Option D
The series is, (+ 2)^3, (+ 3)^3, (+ 5)^3, (+ 7)^3, (+ 11)^3,
2, 5, 12, 27, 58, ?
124

240

234

121

320

Option D
The series is, (* 2 + 1), (* 2 + 2), (* 2 + 3), (* 2 + 4), (* 2 + 5),

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