1. A vessel contains 48 liters mixture of milk and water in the ratio of 5 : 3. If x liter of water is mixed in this mixture, then the ratio of milk to water becomes 3 : 2. What is the value of ‘x’ ?
   4
   3
   5
   2
   6
   Option D
   Quantity of milk in 48 liter of mixture = 48*5/8 = 30
   Quantity of water in 48 liter of mixture = 48*3/8 = 18
   30/18+x = 3/2
   60 = 54 + 3x
   3x = 6
   x = 2

    

2. A and B can complete a work alone in 48 days and 40 days respectively. A and B started work in together after 10 days, B left the work then in how many days the total work will be completed ?
   14
   42
   28
   22
   36
   Option E
   LCM of 48 and 40 = 240
   Total work = 240
   efficiency of A = 240/48 = 5
   efficiency of B = 240/40 = 6
   A and B complete the work in 10days = (5 + 6)10 = 110
   remaining work = 240 – 110 = 130
   remaining completed by A = 130/5 = 26
   Total days required to complete total work = 26 + 10 = 36 days

    

3. P sells a mobile to Q at a profit of 25%. Q sells it to R at a profit of 20%. R sells it at a loss of 30% to S. If S days rs.42000 for it, then what is the cost price of the mobile for P ?
   58000
   40000
   52000
   20000
   48000
   Option B
   Let, CP of mobile for P = 100x
   SP of mobile for P = 100x*125/100 = 125x
   CP of mobile for Q = 125x
   SP of mobile for Q = 125*120/5 = 150x
   CP of mobile for R = 150x
   SP of mobile for R = 150x*70/100 = 105x
   CP of mobile for S = 105x
   S pays = 42000
   105x = 42000
   x = 42000/105 = 400
   CP of mobile for P = 100 * 400 = 40000

    

4. The ratio of speed of boat in still water to that of speed of current is 9 : 5. If the boat can row downstream speed in 8 hours, then what will be time taken by boat to go same distance in upstream speed.
   26 hours
   17 hours
   28 hours
   18 shours
   22 hours
   Option C
   Let, speed of boat in still water = 9x
   and speed of stream = 5x
   downstream speed of boat = 14x
   upstream speed of boat = 4x
   Let distance = D
   D/14x = 8, D = 112x
   Time = 112x/4x = 28 hours.

    

5. Ram and Rahul started the business with investment in the ratio of 4 : 3. Ram and Rahul invest his amount for 14 months and 12 months respectively. What is the profit sharing ratio of Ram and Rahul ?
   9 : 7
   5 : 3
   4 : 3
   14 : 9
   3 : 8
   Option D
   Profit sharing ratio of Ram and Rahul = (4*14) : (3*12) = 56 : 36 = 14 : 9

    

6. Directions : In the following questions there are two equations given. you have to solve both the equations and give answer.
   I. 3x^2 – 23x + 40 = 0
   II. 4y^2 + 17y + 15 = 0
   X > Y
   X < Y
   X ≥ Y
   X ≤ Y
   X = Y or no relation.
   Option A
   I. 3x^2 – 15x – 8x + 40 = 0
   3x = 15 , 8
   x = 5 , 2.67
   II. 4y^2 + 12y + 5y + 15 = 0
   4y = -12 , -5
   y = -3 , -1.25

    

7. I. x^2 – 11x + 28 = 0
   II. y^2 – 20y + 96 = 0
   
   X > Y
   X < Y
   X ≥ Y
   X ≤ Y
   X = Y or no relation.
   Option B
   I. x^2 – 7x – 4x + 28 = 0
   x = 7 , 4
   II. y^2 – 12y – 8y + 96 = 0
   y = 12 , 8

    

8. I. x^2 + 12x + 32 = 0
   II. y^2 + 6y + 8 = 0
   X > Y
   X < Y
   X ≥ Y
   X ≤ Y
   X = Y or no relation.
   Option D
   I. x^2 + 8x + 4x + 32 = 0
   x = -8 , -4
   II. y^2 +4y + 2y + 8 = 0
   y = -4 , -2

    

9. I. x^2 – 23x + 126 = 0
   II. y^2 – 14y + 45 = 0
   X > Y
   X < Y
   X ≥ Y
   X ≤ Y
   X = Y or no relation.
   Option C
   I. x^2 – 14x – 9x + 126 = 0
   x = 14 , 9
   II. y^2 – 9y – 5y + 45 = 0
   y = 9 , 5

    

10. I. x^2 – x – 12 = 0
    II. y^2 + 2y – 8 = 0
    X > Y
    X < Y
    X ≥ Y
    X ≤ Y
    X = Y or no relation.
    Option E
    I. x^2 – 4x + 3x – 12 = 0
    x = 4 , -3
    II. y^2 + 4y – 2y – 8 = 0
    y = -4 , 2

     

1. A can do a piece of work in 25 days. If B is 20% more efficient than A, then in how many days three – fifth of the work is completed by A and B working together ?
   2 3/4 days
   8 1/5 days
   4 days
   6 9/11 days
   6 11/14 days
   Option D
   Let efficiency A = 5
   efficiency of B = 5 *6 /5 = 6
   total work = 25 * 5 = 125
   3/5 of the work = 3/5*125 = 75
   time = 75/5+6 = 6 9/11days

    

2. A can do 1/5 of the work in 5 days and B can do 1/4 of the work in 6 days. If they earned total rs.4900, then how much money will A get ?
   2400
   4800
   2500
   3200
   1450
   Option A
   A can do total work = 5 * 5 = 25 days
   B can do total work = 4 * 6 = 24 days
   LCM of 25 and 24 = 600
   Total work = 600
   efficiency of A = 600/25 = 24
   efficiency of B = 600/24 = 25
   A get = 4900 * 24/49 = 2400

    

3. P, Q and R can do a piece of work in 20 days, 30 days and 40 days respectively. If they started the work together but after 6 days P left the work and remaining work done by Q and R together, they in how many days total work will be completed ?
   14 days
   12 days
   20 days
   16 days
   6 days
   Option B
   LCM of 20, 30 and 40 = 120
   total work = 120
   efficiency of P = 120/20 = 6
   efficiency of Q = 120/30 = 4
   efficiency of R = 120/40 = 3
   they completed the work together in 6 days = (6 + 4 + 3)6 = 78
   remaining work = 120 – 78 = 42
   time taken by Q and R together to complete remaining work = 42/4+3 = 6 days
   total time = 6 + 6 = 12 days

    

4. A group of 25 men is supposed to do a work in 30 days. After 15 days 5 more men is employed and the work is employed in 1 day before the scheduled time. If 5 more men were not employed, then in how many days it have been delayed ?
   2
   3.2
   1.9
   2.5
   1.8
   Option E
   work completed by 25 men in 15 days = 25 * 15 = 375
   now total men = 25 + 5 = 30
   work completed before 1 day
   total work = 375 + 30 * 14 = 795
   If 5 men is not employed,
   time taken by 25 men to complete work = 795/25 = 31.8
   work will be delayed = 31.8 – 30 = 1.8 day

    

5. A and B can do a piece of work in 18 days and 24 days respectively. If they work in alternative day starting with A, then in how many days the work is completed ?
   22 2/5
   20 4/8
   20 1/2
   3/4
   3
   Option C
   LCM of 18 and 24 = 72
   Total work = 72
   efficiency of A = 72/18 = 4
   efficiency of B = 72/24 = 3
   A and B work in alternate day.
   A and B completed work in 2 days = 4 + 3 = 7
   10(2 day) = 10(7 work)
   20 day = 70 work
   A completed 4 work in 1 day so, 2 work completed in 1/2 day.
   total time = 20 + 1/2 = 20 1/2 day.

    

6. A and B can do a piece of work in 25 days and 30 days respectively and they start working together for 10 days. After 10 days A left the work and C joins and the remaining work in completed by B and C together in 5 days. Find the days in which C can do the work ?
   50 days
   40 days
   46 days
   32 days
   58 days
   Option A
   LCM of 25 and 30 = 150
   total work = 150
   efficiency A = 150/25 = 6
   efficiency of B = 150/30 = 5
   A and B completed work in 10 days = (6 + 5) 10 = 110
   remaining of work = 150 – 110 = 40
   B and C completed in 5 days = 40/5 = 8
   efficiency of C = 8 – 5 = 3
   C alone completed total work = 150/3 = 50 days.

    

7. A and B can do a piece of work in 20 days and 30 days respectively. They start working together after some days A left the work and remaining work completed by B in 15 days. Find in how many days A left the work ?
   20
   6
   4
   12
   8
   Option B
   LCM of 20 and 30 = 60
   efficiency of A = 60/20 = 3
   efficiency of B = 60/30 = 2
   B alone work for 15 days = 15 * 2 = 30 work
   Time taken to do remaining by A and B together = 30/3+2 = 6 days
   After 6 days A left the work.

    

8. A can do 80% of a work in 20 days. A and B together can do the remaining work in 4 days. Then in how many days B alone would take to do the total work ?
   120
   130
   50
   40
   100
   Option E
   A work done = 20*5/4 = 25 days
   Remaining work = 1/5
   time taken by A and B to do total work = 5 * 4 = 20 days
   LCM of 25 and 20 = 100
   efficiency of A = 100/25 = 4
   efficiency of A and B = 100/20 = 5
   efficiency of B = 5 – 4 = 1
   Time taken by B to do total work = 100/1 = 100 days

    

9. P and Q can do a piece of work in 20 days and 40 days respectively. They start the work but Q leaves the work 8 days before the completion. Find how many days is required to complete the work ?
   4
   8
   12
   14
   20
   Option B
   LCM of 20 days and 40 days = 40
   Total work = 40
   efficiency of P = 40/20 = 2
   efficiency of Q = 40/40 = 1
   work done by P in 8 days = 8 * 2 = 16 days
   Remaining work = 40 – 16 = 24 work
   Time taken by P and Q remaining work = 24/2+1 = 8 days

    

10. A and B undertake to complete a work for rs.3000. A and B can do a piece of work on 12 days and 15 days respectively and with the help of C they complete the work in 4 days. Then how much money C get ?
    1200
    1320
    1840
    1540
    1450
    Option A
    LCM of 12, 15 = 60
    Total work = 60
    efficiency of A = 60/12 = 5
    efficiency of B = 60/15 = 4
    total efficiency of A, B and C = 60/4 = 15
    efficiency of C = 15 -(5 + 4) = 6
    share of C = 3000 * 6/15 = 1200

     

1. The ratio of age of A to B is 6 : 7 and also the ratio of age of C to B is 17 : 14. If the average of their ages is 43 years, then find the ratio of ages B 3 years ago to age of C after 1 year.
   4 : 5
   2 : 5
   1 : 5
   9 : 4
   3 : 4
   Option E
   Ratio of age of A and B = 6 : 7
   ratio of age of B and C = 14 : 17
   ratio of age of A, B and C = 12 : 14 : 17
   Average of A, B and C = 43 years
   total age = 43 * 3 = 129
   present age of B = 129 * 14/43 = 42
   present age of C = 129 * 17/43 = 51
   ratio of B and C = (42-3) : (51+1) = 3 : 4

    

2. The age of Shankar’s father is four times more than the age of Shankar. 6 years hence, Shankar’s father age is three times the age of Shankar. Find the sum of the age of Shankar and his father.
   24
   45
   36
   25
   20
   Option C
   Let the age of Shankar = x
   his father age = x + 4x = 5x
   6 years hence, (x + 6) 3 = 5x + 6
   3x + 18 = 5x + 6
   x = 6
   The age of Shankar = 6
   the age of his father = 5 * 6 = 30
   sum = 6 + 30 = 36 years

    

3. The present age of a father is 2 years more than four times the age of his daughter. After 6 years, the age of father will be 2 years less than thrice the age of the daughter. What is the fathers present age ?
   28 years
   34 years
   32 years
   42 years
   56 years
   Option B
   Let the age of daughter = x
   the age of her father = 4x + 2
   After 6 years,
   4x + 2 + 6 = (x + 6) 3 – 2
   4x + 8 = 3x + 16
   x = 8
   present age of her father = 4 * 8 + 2 = 34 years

    

4. In a family, the average age of father and mother is 29 years. If the average age of father, mother and their two sons is 20 years, then what is the age of elder son whose age is 2 years more than the younger one ?
   8 years
   9 years
   14 years
   19 years
   12 years
   Option E
   Total age of father and mother = 29 * 2 = 58
   total age of father, mother and their two sons = 20 * 4 = 80
   Total age of their two sons = 80 – 58 = 22
   The age of younger son = 22 – 2/2 = 10 years
   age of elder son = 10 + 2 = 12 years

    

5. The average of four persons is 43 years. When a new person come, average age of all the five persons is increased by 2 years. What is the age of new person ?
   52 years
   40 years
   53 years
   30 years
   34 years
   Option C
   Total age of four persons = 43 * 4 = 172
   After joining new person average age of all five persons = 43 + 2 = 45
   total age of five persons = 45 * 5 = 220
   age of new person = 225 – 172 = 53 years

    

6. The ratio of present age of P and Q is 3 : 4. After 15 years the ratio of age of P and Q is 6 : 7, then find the age of Q before 4 years.
   25 years
   17 years
   32 years
   42 years
   43 years
   Option B
   Let the present age of P and Q = 3x and 4x respectively.
   After 15 years,
   3x + 15/4x + 15 = 6/7
   24x + 90 = 21x + 105
   3x = 15,
   x = 5
   age of Q before 3 years = ( 4 * 5) – 3 = 17 years

    

7. Five years ago, the average age of P, Q and R was 25 years and seven years ago, the average age of Q and R was 20 years. Find the present age P.
   32 years
   25 years
   34 years
   36 years
   26 years
   Option D
   Total age of P, Q and R before 5 years = 25 * 3 = 75
   total present age of P,Q and R = 75 + 15 = 90
   total age of Q and R seven years ago, = 20 * 2 = 40
   total present age of Q and R = 40 + 14 = 54
   present age of P = 90 – 54 = 36 years

    

8. The ratio between the present ages of A and B is 5 : 8. After 4 years, the ratio between their will be 2 : 3. If the present age of C is 2 years more than the average present age of A and B, then find the present age of C ?
   25 years
   35 years
   24 years
   18 years
   28 years
   Option E
   Let the present age of A and B = 5x and 8x respectively .
   After 4 years,
   5x + 4/8x + 4 = 2/3
   16x + 8 = 15x + 12
   x = 4
   present age of A = 5 * 4 = 20
   present age of B = 8 * 4 = 32
   the present age of C = (20 + 32)/2 + 2 = 28 years

    

9. Four years ago, the average age of A and B was 20 years. Now C has joined with them and their average ages become 32 years. What is the present age of C in years ?
   40 years
   32 years
   52 years
   48 years
   42 years
   Option D
   Four years ago, total of A and B = 20 * 2 = 40
   total present age A and B = 40 + 8 = 48
   total age of A, B and C = 32 * 3 = 96
   age of C = 96 – 48 = 48 years.

    

10. The present age of father is 60% more then the present age of his son. If after 4 years, the sum of age of father and son is 86 years, then what is the present age of son ?
    32 years
    30 years
    40 years
    44 years
    20 years
    Option B
    Let present age of son = 5x
    present age of father = 5x * 160/100 = 8x
    after 4 years,
    8x + 4 + 5x + 4 = 86
    13x + 8 = 86
    x = 6
    present age of son = 5x = 5 * 6 = 30 years.

     

1. A ,B and C started a partnership business with investment in the ratio of 6 : 3 : 4. After one year A withdrawal half of his investment and B doubled his investment. Total profit of the business at the end of the two years is rs. 52000, then what is the sum of profit share of B and C ?
   42000
   34000
   38000
   51000
   40000
   Option B
   Let the investment of A,B and C = 6x, 3x and 4x respectively.
   profit sharing ratio of A,B and C = (6x * 1 + 3x * 1) : (3x * 1 + 6x * 1) : (4x * 2)
   = 9x : 9x : 8x = 9 : 9 : 8
   Total profit share of B and C = 52000 * 17/26 = 34000

    

2. P started a business with the investment of rs.5500. After four months Q and R joined the business with investment of rs.6000 and rs.4500 respectively. At the end of the one year they earned total profit rs.22500. Find profit share of R ?
   5400
   7500
   5000
   4850
   3250
   Option A
   profit sharing ratio of P,Q and R = (5500 * 12) : (6000 * 8) : (4500 * 8) = 11 : 8 : 6
   profit share of R = 22500 * 6/25 = 5400

    

3. Amit and Sumit invested rs.5000 and rs.7500 in a partnership business. After one year Amit added rs.2500 and sumit added rs.2000 in the business. If profit of Sumit at the end of two years is rs.13600, then find the total profit of the business ?
   20800
   14500
   10000
   23600
   28400
   Option D
   Profit sharing ratio of Amit and Sumit = (5000 * 1 + 7500 * 1) : (7500 * 1 + 9500 * 1) = 25 : 34
   profit share of sumit = 13600
   total profit of the business = 13600 * 59/34 = 23600

    

4. X,Y and Z started a business with investment ratio of 4 : 3 : 5. If they invested for 5 months, 8 months and 4 months respectively, then what is profit sharing ratio of X,Y and Z ?
   4 : 2 : 5
   2 : 5 : 3
   10 : 9 : 5
   3 : 4 : 8
   5 : 6 : 5
   Option E
   Profit sharing ratio of X, Y and Z = (4 * 5) : (3 * 8) : (5 * 4) = 20 : 24 : 20 = 5 : 6 : 5

    

5. A and B investment rs.8000 and rs.6000 for 12 months and 14 months respectively in the business. If 25% of total profit is given to B as salary for managing business and remaining profit is distributed in their profit sharing ratio and profit share of A is rs.3200, then find total profit of the business ?
   8400
   6900
   4800
   8000
   4800
   Option D
   Profit sharing ratio of A and B = (8000 * 12) : (6000 * 14) = 8 : 7
   Let total profit of the business = 100x
   salary given to B = 100x * 25/100 = 25x
   remaining profit = 100x – 25x = 75x
   profit share of A = 75x * 8/15 = 40x
   40x = 3200
   x = 80
   total profit of the business = 100x = 100 * 80 = 8000

    

6. Lipu and Papu start a business with initial investments in the ratio of 9 : 11 and their annual profit were in the ratio of 3 : 1. If Lipu invested the money for 11 months, then Papu invested his money for how many months ?
   3 months
   8 months
   4 months
   14 months
   7 months
   Option A
   Let Papu invested his money for x months.
   9 * 11/ 11 * x = 3/1
   x = 3 months

    

7. A , B and C enter into partnership business. A invests some money at the beginning, after 4 months B invests double the money of A’s invests and after 6 months C invests thrice the amount of A. If total profit of the business is rs.9200 at the end of one year, then how much profit B get ?
   4600
   2800
   3400
   3200
   3800
   Option D
   Let A invests = rs.x
   B invests = 2x
   C invests = 3x
   profit sharing ratio of A , B and C = (x * 12 ) : (2x * 8) : (3x * 6)
   =6 : 8 : 9
   profit share of B = 9200 * 8 /23 = 3200
   

    

8. X , Y and Z entered into a partnership farm with investing rs. 12000, rs. 18000 and rs. 20000 respectively. X being a working partner gets 20% of the annual profit for the work. Find the profit share of X in an annual profit of rs. 25000 ?
   8600
   7300
   9800
   5820
   8750
   Option C
   Profit sharing ratio of X , Y and Z = 12000 : 18000 : 20000 = 6 : 9 : 10
   X gets profit for being a working partner = 25000 * 20 /100 = 5000
   remaining profit = 25000 – 5000 = 20000
   profit share of X of the remaining profit = 20000 * 6 /25 = 4800
   total profit of X = 5000 + 4800 = 9800

    

9. A and B started a business by investing rs.15000 and rs.20000 respectively. By mistake they divided the total profit in the ratio of 1 : 3, so that A loses rs.500. What is total profit of the business ?
   1400
   2400
   4200
   2800
   5200
   Option D
   Profit sharing ratio of A and B = 15000 : 2000 = 3 : 4
   Let total profit of the business = rs. x
   profit sharing ratio of A = 3x/7
   By mistake profit share of A = x/4
   A losses = 500
   = 12x – 7x/28
   x = 500 * 28/5 = 2800
   total profit of the business = rs.2800

    

10. A and B started a business with capital of rs.28000 and rs.35000. After 6 months, A invests rs.4000 more, after 8 months B withdrawal rs. 5000 while C joins with capital of rs.40000. Annual profit of the business is rs.9200, then how much profit A get ?
    4300
    3600
    4800
    5200
    5500
    Option B
    profit sharing ratio of A, B and C =(28000* 6 + 32000 * 6) : (35000 * 8 + 3000 * 4) : (40000 * 4) = 9 : 10 : 4
    profit share of A = 9200 * 9/23 = 3600

     

1. A mixture contains milk and water in the ratio of 9 : 5. 14 liters of mixture is replaced by water, so that ratio of milk and water became 27 : 29. Find the quantity of initial mixture ?
   40
   56
   38
   42
   70
   Option B
   Let quantity of milk and water = 9x and 5x
   (9x – 14 * 9/14) / (5x-14 * 5/14 + 14) = 27/29
   (9x – 9)/(5x + 9) = 27/29
   261x – 261 = 135x + 243
   x = 4
   Initial quantity of mixture = 9x + 5x = 14x
   = 14 * 4 = 56 liters

    

2. In a mixture quantity of milk and water 20 liters and 15 liters respectively. How much quantity of mixture will be replaced with water, so that ratio between milk to water became 12 : 23 ?
   14
   28
   18
   20
   25
   Option A
   ratio of milk and water = 4 : 3
   Let ‘X’ liters of mixture will be replaced with water.
   (20-x * 4/7) / (15 – x * 4/7 + x) = 12/23
   (20 – 4x/7) / (15 – 3x/7 + x) = 12/23
   140 – 4x/105 + 4x = 12/23
   x = 14

    

3. A solution contains lemon juice and water in the ratio of 4 : 1 . If 10 liter of solution is drawn and 15 liter of water is added, then ratio between juice to water become 2 : 3. Find the initial quantity of juice in the solution.
   32 liters
   14 liters
   8 liters
   20 liters
   42 liters
   Option D
   Let quantity of juice and water in the solution 4x and x.
   (4x – 8)/ (x – 2 + 15) = 2/3
   4x – 8/ x + 13 = 2/3
   x = 5
   quantity of juice in the solution initially = 4x = 4 * 5 = 20 liters

    

4. Two alloys A and B contains iron and silver in ratio 4 : 3 and 9 : 5 equal quantity of both alloys are melted and recast into a new alloy what is the ratio between iron and silver in new alloy ?
   17 : 11
   5 : 9
   3 : 2
   4 : 5
   15 : 14
   Option A
   quantity iron and silver in alloy A = 4/7 and 3/7 respectively.
   quantity of iron and silver in alloy B = 9/14 and 5/14 respectively.
   new ratio of iron and silver = (4/7 + 9/14) : (3/7 + 5/14)
   = 17 : 11

    

5. In what ratio must two kinds of rice which cost rs.80 per kg and rs.92 per kg be mixed such that the resultant mixture cots rs.84 per kg ?
   3 : 2
   5 : 4
   1 : 2
   2 : 1
   5 : 3
   Option D
   by allegation method,
   80 92
   84
   8 4
   2 : 1

    

6. A shopkeeper mixes two varieties of milk one costing at rs.20 per liter and the other at rs.28 per liter, then he sells the mixture at rs.36 per what ratio he mixed milk ?
   2 : 3
   5 : 4
   2 : 1
   9 : 2
   CND
   Option E
   Here profit percentage is not given so we cant find the ratio.

    

7. A container contains 60 liters of a mixture of milk and water containing 60% milk. How many liters of water must be added to the container, so that quantity of milk is 40% of total mixture ?
   40 liter
   30 liter
   40 liter
   52 liter
   54 liter
   Option B
   Total mixture = 60 liter
   quantity of milk = 60 * 3/5 = 36
   quantity of water = 60 * 2/5 = 24
   now milk is 40% of total mixture,
   total mixture = 36/40 * 100 = 90
   quantity of water in new mixture = 90 – 36 = 54
   extra liter water added = 54 – 24 = 30

    

8. A vessel contains 280 liters of mixture of milk and water and quantity of water is 40% of milk in the vessel. If 40 liters of water added in the vessel, then find the ratio of milk to water in resulting mixture ?
   2 : 3
   4 : 3
   5 : 2
   9 : 5
   5 : 3
   Option E
   Ratio of milk and water = 100 : 40 = 5 : 2
   quantity of milk = 280 * 5/7 = 200
   quantity of water = 280 * 2/7 = 80
   after adding 40 liter of water quantity of water = 80 + 40 = 120
   new ratio = 200 : 120 = 5 : 3

    

9. In a 208 liter of mixture of milk and water the ratio of milk to water is 8 : 5. If ‘x’ liter of water is added in this mixture, so that the ratio of water to milk becomes 7 : 8. What is the value of ‘x’.
   42 liter
   32 liter
   28 liter
   30 liter
   46 liter
   Option B
   quantity of milk = 208 * 8/13 = 128
   quantity of water = 208 * 5/13 = 80
   128/80 + x = 8/7
   x = 32

    

10. A container contains 140 liter of mango juice. 40 liters are taken out of the vessel every day and an equal quantity of water is put in. Find how much mango juice is left in the vessel after 3 days ?
    51.02 liter
    32.12 liter
    25 liter
    46.25 liter
    68.50 liter
    Option A
    using the formula
    mango juice left over = (140 – 40/140)^3 * 140
    = (100/140)^3 * 140
    =125/343 * 140
    = 51.02 liter

     

1. ‘x’ meters long train cross a 360 meters long bridge in 20 sec running at the speed of 108 km/hr. If train cross a man running in opposite direction in 6 sec, then what is the speed of man (in km/hr) ?
   54 km/hr
   58 km/hr
   36 km/hr
   45 km/hr
   72 km/hr
   Option C
   speed of train = 108 * 5/18 = 30m/sec
   x + 360/30 = 20
   x = 240
   Let the speed of man = y m/sec
   240/30 + y = 6
   180 + 6y = 240
   y = 10
   speed of man = 10 * 18/5 = 36 km/hr

    

2. A start driving from Delhi to Bangalore with speed of 20 km/hr and B start driving from Bangalore to Delhi with speed of 28km/hr. If they start at 9 am and distance between Delhi to Bangalore is 240 km, then in how much time they meet each other ?
   4 pm
   4 : 20 pm
   12 : 40 pm
   3 pm
   2 pm
   Option E
   Total Distance = 240 km
   relative speed of A and B = 20 + 28 = 48 km/hr
   Time = 240/48 = 5 hour.
   They start at 9 am they will meet each other at 2 pm.

    

3. A man walking at two-fifth of his usual speed, reaches his destination 6 hour late. What is usual time to reach his destination ?
   5 hours
   2 hours
   4 hours
   6 hours
   8 hours
   Option C
   let original speed of man = 5x
   now his speed = 2x
   ratio of his speed = 5x : 2x
   his time ratio to reach destination = 2y : 5y
   5x – 2x = 6 hours
   x = 2 hours
   His usual time = 2 * 2 = 4 hours.

    

4. Two man travel by their bikes from Gujrat to Kolkata at a speed of 40 km/hr and 48 km/hr respectively. If one of them takes 5 hours lesser time than the other to reach Kolkata then what is the distance between city Gujrat and Kolkata.
   1200 km
   2300 km
   4200 km
   1440 km
   2000 km
   Option A
   Let Distance between Gujrat to Kolkata = D km
   D/40 – D/48 = 5
   48D – 40 D/40 * 48 = 5
   8D/40 * 48 = 5
   D = 1200

    

5. The ratio speed of Car and Bike is 4 : 3. Total Distance between point A and point B is 120 km. If Car and Bike start travelling from point A and bike takes 2 hours more time than car, then what is the speed of Car ?
   28 km/hr
   24 km/hr
   20 km/hr
   24 km/hr
   32 km/hr
   Option C
   Let of Car and Bike = 4x and 3x
   Distance = 120 km
   120/3x – 120/4x = 2
   x = 5
   speed of Car = 4x = 4 * 5 = 20 km/hr

    

6. Rahul goes to his school at rate of 24 km/hr and reaches 8 minutes late. In the next day he goes with 20 km/hr and reached 14 minutes late then, what is distance between his home to school ?
   10 km
   18 km
   14 km
   16 km
   12 km
   Option E
   Let Actual time to each school = x mixture
   In 1at case, speed = 24 km/hr
   Time = (x + 8) minutes
   Distance = 24(x + 8/60)
   In 2nd case, speed = 20 km/hr
   Time = (x + 14) minute
   Distance = 20 (x+14/60)
   24x + 192 = 20x + 280
   4x = 88
   x = 22 minutes
   Distance = 24 (22+8/60) = 12 km

    

7. Sriman covered one third of his journey at a speed of 20 km/hr, one-fourth of the remaining at the speed of 25 km/hr and the remaining journey at a speed of 15 km/hr. what is his Average speed ?
   20km/hr
   300/17 km/hr
   200/17 km/hr
   15km/hr
   25km/hr
   Option B
   LCM of 20, 25, and 15 = 300
   total distance = 300km
   1/3rd of 300 at a speed of 20km/hr
   Time = 100/20 = 5 hours
   1/4th of remaining at a speed of 25 km/hr
   time = 1/4(300 – 100)/25 = 2 hours
   remaining 150km at a speed of 15 km/hr
   time = 150/15 = 10 hour
   Average speed = 300/5 + 2 + 10 = 300/17 km/hr

    

8. If A train crosses 450 meters long platform in 30sec and crosses a pole in 7.5 seconds, then find the length of train ?
   200 meters
   150 meters
   220 meters
   320 meters
   340 meters
   Option B
   Let length of train = x meters
   x + 450/30 = x/7.5
   x = 150 meters

    

9. A and B run 6km/hr and 12 km/hr on a circular track 12 km long, when will they met each other for the first time, if they are running in opposite direction ?
   42 minutes
   32 minutes
   1 hour
   2 hour
   40 minutes
   Option E
   Total Distance = 12 km/hr
   relative speed = 12 + 6 = 18 km/hr
   time = 12/18 = 2/3 = 2/3*60 = 40 minutes.

    

10. A thief steal a bike at 8 pm and drive at a speed of 40 km/hr. Police came to know about theft at 11 pm and start chasing him with the speed of 55 km/hr. After how much kilometers police will catch the thief ?
    440 km
    320 km
    450 km
    520 km
    620 km
    Option A
    speed of thief = 40 km/hr
    he travelled 8 pm to 11pm = 3 hours
    distance covered by thief in 3 ours = 3 * 40 = 120 km
    speed of police = 55 km/hr
    relative speed = 55 – 40 = 15 km/hr
    time taken by police to catch the thief = 120/15 = 8 hours
    distance = 55 * 8 = 440 km

     

1. the total cost price of math book and English book is 2400. If a person sold math book at profit of 20% and English book at profit of 10%, then he earned overall 13.5% profit. What is the difference between cost price of math book and English book.
   840
   750
   720
   940
   500
   Option C
   By applying alligation method,
   20% 10%
   13.5%
   3.5 6.5
   ratio = 7 : 13
   CP of math book = 2400*7/20 = 840
   CP of English book = 2400*13/20 = 1560
   Difference = 1560 – 840 = 720

    

2. The cost price of an article is rs.400 and marked price of an article is rs.480. If there are 15% discount is given on marked price, then what is profit percentage occurred by selling it ?
   4%
   18%
   8%
   2%
   20%
   Option D
   CP of article = 400
   MP of article = 480
   Discount = 480 * 15/100 = 72
   SP of article = 480 – 72 = 408
   profit % = 408 – 400/400 * 100 = 2%

    

3. A man purchased two articles for rs.1250 each. He sold one at 20% profit and the other is 30% loss find the overall profit or loss percentage ?
   17% loss
   8% loss
   5% profit
   5% loss
   14% profit
   Option D
   CP of one article = 1250
   SP = 1250 * 120/100 = 1500
   CP of other article = 1250
   SP = 1250 * 7/10 = 875
   Total CP = 1250 + 1250 = 2500
   total SP = 1500 + 875 = 2375
   Loss % = 125/2500 * 100 = 5%

    

4. The cost price of 10 books is equal to the selling price of 8 books. What is the profit percentage ?
   28%
   23%
   25%
   22%
   20%
   Option C
   Let the CP of a one book = 10x
   CP of 10 book = 100x
   SP of 8 book = 100x
   CP of 8 book = 80x
   profit % = 100x – 80x/80x * 100 = 25%

    

5. The profit obtained by selling of the product for rs.500 is same as the loss when it sold for rs.350. What is the cost price of the product ?
   500
   475
   625
   425
   355
   Option D
   Let CP of the product = x
   SP = 500
   profit = 500 – x
   SP = 350
   loss = x – 350
   500 – x = x – 350
   2x = 850
   x = 425

    

6. If a table is sold at gain of 15% instead at a gain of 8%, then the seller gets rs.84 more. What is cost price of that table ?
   1250
   1340
   1200
   1480
   1400
   Option C
   Let CP of table = 100x
   when it sold at 8% profit, SP of table = 108x
   When is sold at 15% profit, SP of table = 115x
   115x – 108x = 84
   7x = 84
   x = 12
   cost price of table = 100x = 100 * 12 = 1200

    

7. A man sells an item for rs.600 and make some profit. If he sells it for rs.390 his loss is 2/5th of earlier profit. What is the cost price of the item ?
   425
   550
   750
   450
   645
   Option D
   Let CP of item = x
   If he sells for rs.600
   profit = 600 – x
   If he sells for rs.390
   loss = x – 390
   (600 – x)2/5 = x – 390
   1200 – 2x = 5x – 1950
   7x = 3150
   x = 450

    

8. Sinu sold an item for rs.7200 and he incurred a loss of 20%. At what price should he have sold an item so that to have gained a profit of 18% ?
   12640
   8740
   10620
   945
   1450
   Option C
   SP of an item = 7200
   loss = 20%
   CP = 7200 * 5/4 = 9000
   when he sold at profit of 18%
   SP = 9000 * 118/100 = 10620

    

9. The marked price of the mouse is 25% more than the cost price and when it sold profit earned by shopkeeper is 12.5%. If the marked price of the mouse is rs.750, then how much amount of discount is given when it sold ?
   80
   82
   84
   75
   68
   Option D
   MP of the mouse = 750
   CP of mouse = 750/5 * 4 = 600
   SP = 600 * 112.5/100 = 675
   discount = 750 – 675 = 75

    

10. A sold an article to B at a profit of 20% and B sells it to C at a loss of 40% and C paid for rs.1440. What is the selling price for which A sold ?
    4600
    2400
    3400
    2200
    1400
    Option B
    Let CP of an article for A = 100x
    SP for A = 120x
    CP for B = 120x
    SP for B = 120*3/5 = 72x
    C pays = 1440
    72x = 1440
    x = 20
    SP for A = 120*20 = 2400

     

1. Two dices are rolled down simultaneously, then find the probability of getting sum of results on both dices more than 8.
   2/15
   4/19
   1/8
   5/18
   3/20
   Option D
   possible cases=(3,6), (4,5), (4,6), (5,4), (5,5)
   required probability=10/36=5/18

    

2. A bag contains 6 blue balls and 8 pink balls. If a ball is drawn randomly from it, then find the probability of getting either pink ball or blue ball.
   4
   5
   1
   1/4
   2/5
   Option C
   required probability=6/14+8/14=14/14=1

    

3. In a box there are 4 red balls and 3 blue balls. If two balls are drawn at random, then find the probability of that none is blue.
   2/5
   2/7
   5/8
   4/15
   4/18
   Option B
   required probability=(4C2)/(7C2)
   =4*3/7*6=2/7

    

4. A basket contains 5 white balls , 4 red balls, 2 blue balls and 3 yellow balls. If four balls are picked at randomly. What is the probability that 2 are blue and 2 are red ?
   5/1002
   8/968
   12/1005
   8/950
   6/1001
   Option E
   required=(2C2)*(4C2)
   =(2*1/2*1)*(4*3/2*1)=1*6
   total=14C4=14*13*12*11/4*3*2*1
   =7*13*11
   probability=1*6/7*13*11=6/1001

    

5. When two dices are thrown simultaneously, then find the probability that sum is a prime number which is less than 8 ?
   12/38
   20/36
   20/35
   13/36
   15/48
   Option D
   prime numbers=2,3,5,7
   possibility of 2=(1,1)
   possibility of 3=(1,2), (2,1)
   possibility of 5=(1,4), (4,1), (3,2), (2,3)
   possibility of 7=(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)
   required=1+2+4+6=13
   total=6^2=36
   probability=13/36
   

    

6. When two coins are tossed simultaneously, then find the probability of getting at least one head.
   4/5
   3/4
   8/9
   7/12
   2/15
   Option B
   probability=3/2^2=3/4

    

7. If from a pack of 52 cards, 1 cards is drawn at randomly, find the probability of the card is an ace.
   2/15
   1/13
   4/15
   2/25
   8/18
   Option B
   required=4C1=4
   total=52C1
   probability=4/52=1/13

    

8. Two cards are drawn at random from a pack of 52 cards. What is the probability that both are the queen cards ?
   2/221
   4/225
   5/228
   1/221
   8/125
   Option D
   required=4C2=4*3/2*1=12/2=6
   total=52C2=52*51/2
   probability=6/26*51=1/221

    

9. In how many ways letters of the word ‘LAPTOP’ be arranged such that consonants always come together ?
   50
   75
   40
   72
   80
   Option D
   required ways=3!*4!/2!=72 ways

    

10. A bag contains 4 red balls and 8 balls. If two balls are taken out from the bag, then find probability of at least one ball being red ?
    40/85
    48/65
    55/64
    35/66
    40/86
    Option D
    favorable cases=(1 blue and 1 red) or ( 2 red)
    probability=(4C1)*(8C1)/(12C2)+(4C2)/(12C2)
    =(4*8/12*11/2*1)+(4*3/2*1/12*11)
    =(4*8/11*6)+(2*3/12*11)=16/33+1/22
    =32+3/66=35/66

     

Directions: What will come in place of question mark(?) in the following questions ?

1. 440÷20*510÷17+25 ?
   785
   685
   585
   675
   none of this
   Option B
   solution: 22*30+25 =685

    

2. 71.40% of 63-√1296+20=?
   29
   39
   30
   31
   25
   Option A
   solution: 5/7*63-36+20
   =65-36 =29

    

3. 2/5*15/8*16/21*8/28*56 = ?
   32
   80
   128
   64
   none of this
   Option
   solution: 2/5*15/8*16/21*8/28*56
   =8*8 =64

    

4. 35% of 700+52% of 8200-30= ?
   4479
   5569
   7645
   1203
   none of this
   Option A
   solution: 245+4264-30
   =4479

    

5. 3220+3239-3500+2211-2250 = ?
   2920
   3487
   5687
   9056
   none of this
   Option A
   solution: 8670-5750 =2920

    

Directions: What should come in place of questions marks (?) in the following questions ? (You are not required to calculate the exact value)


6. (6391.97÷8)+534.05-986.01 =?
   245
   347
   545
   323
   447
   Option B
   solution: 799+534-986= 347

    

7. (1042.02+?)÷2.99=2019.99÷4.0
   437
   546
   780
   987
   none of this
   Option
   solution: 1515-1042 =473

    

8. 22.02% of 1200 +? -20 =345
   `101
   102
   100
   110
   none of this
   Option
   solution: 264-20+?= 345
   ? =101

    

9. 299.01 + 520.92 – 395.06 + 342.09-212=?
   555
   442
   347
   112
   none of this
   Option
   solution: 1162-607 =555

    

10. 1/5*24.99+1/8*511.99+?=80
    10
    13
    11
    9
    none of these
    Option
    solution: 5+64+?=80
    ?=11

     

Click here for topic wise Quantitative Aptitude Questions

1. Ratio of the ages of A and B is 2:3 and the sum of the squares of their ages is 208 years . Find the age of B 4 years ago.
   6
   4
   9
   8
   none of this
   Option D
   Let,
   their ages be 2x and 3x years .
   (2x)^2+(3x)^2 =208
   4x^2+9x^2 =208
   x^2=16
   x=4 Age of A = 8
   Age of B= 12
   4 years ago age of B = 12-4=8 years.

    

2. The age of father is 5 times that of his son’s age and sum of their ages is 54 years .Find the son’s age after 5 years.
   14
   15
   16
   18
   none of this
   Option
   Let,
   son’s age be x.
   and father’s age 5x years .
   5x+x =54
   x =9 years
   son’s age after 5 years= 14 years

    

3. At present the difference of ages of A and B is 20 years. After 3 years their ages are in the ratio 9:19. Find the present age of B.
   35
   38
   40
   20
   none of this
   Option A
   Let,
   age of A and B after 3 years be 9x and 19x.
   Present age of A =9x-3
   present age of B = 19x-3
   19x-3-(9x-3)=20
   19x-3-9x+3 =20
   10x=20
   x=2
   Present age of B = 19x-3 = 38-3 =35 years.

    

4. At present Ratio of ages of A and B is 8:5. After 2 years it will be 14:9 . Find the age of B 3 years ago.
   22
   23
   25
   28
   none of this
   Option A
   Let,
   Present age of A and B be 8x and 5x .
   ATQ,
   (8x+2)/(5x+2) =14/9
   72x+18=70x+28
   x=5 years.
   Present age of B = 5x =25 years
   3 years ago=22 years.

    

5. At present A is 10 years older than B. After 10 years A will be 4 times as old as B was 10 years ago . find the Ratio of their ages.
   3:2
   4:5
   9:4
   3:4
   none of these
   Option A
   Let,
   B’s present age be x years
   A’s present age = x+10 years
   after 10 years A’s age=x+20
   10 years ago B’s age=x-10
   ATQ, x+20=4(x-10)
   x+20=4x-40
   x=20
   ratio of the age of A & B=30:20=3:2

    

6. The average age of 8 men is increased by 2 years when two of them whose ages are 21 and 23 years replaced by two new men. Find the average age of the two new men.
   48
   35
   40
   30
   none of these
   Option D
   Let the average age of 8 men be x
   total age of 8 men=8x
   these two new men=a and b
   (8x-21-23+a+b)/8=x+2
   8x-44+a+b=8x+16
   x+y=60
   average age of two new men=60/2=30 years

    

7. There are 40 students in a class. The average age of first 10 students is 14.5 years. The average age of the remaining 30 students is 20.5 years. Find the average age of (in years) of the students of the whole class.
   19
   18
   20
   30
   none of this
   Option A
   ATQ, total age of 10 students=14.5*10=145
   total age of remaining 30 students=20.5 *30=615
   average age of students of whole class=145+615/40=19years

    

8. Present age of B is 50% more than that of A and average of present age of B & C is 30 years. If 4 years ago sum of ages of A & B is 32 years then find the sum of ages of A & C .
   54
   52
   46
   45
   none of this
   Option B
   Present age of B 50% more than A.
   Ratio of present age of A and B= 2:3
   total present age of B and C = 30*2=60
   4 years ago some of age of A and B 32 years present age of A and B together =32+8=40 years
   present of A =40*2/5=16 years
   present age of B =40*3/5= 24 years
   present age of C= 60-24= 36 years
   sum of present age of A and C =16+36= 52 years

    

9. The average age of 30 boys in a class is 15 years . One boy aged 20 years left the class but two new boys come in his place whose age differs by 5 years. If the average age of all the boys now in the class still remains 15 years. Find the age of elder newcomer.
   15
   30
   35
   20
   none of this
   Option D
   Total age of 30 boys =15*30=450
   one boys aged 20 years left the remaining 29 students age =430
   after the two newcomer age added then total age of 31 students = 465
   the age of two new comer =465-430= 35 years
   difference the age of two newcomer =5 years
   the age of new elder one = 20 years .

    

10. The Ratio of the present age of Sima and Lima is 2:1. The ratio of their ages after 30 years will be 7:6. Find the different between their ages after 9 years.
    8
    10
    6
    12
    none of these
    Option
    ATQ,
    (2x+30)/(x+30)=7/6
    12x+180 = 7x+210
    5x= 30, x=6
    present age of Sima =12
    present age of Lima =6
    after 9 years their ages 21 and 15 years respectively.
    difference between their ages =21-15=6 years

     

Click here for topic wise Quantitative Aptitude Questions