Directions: What will come in place of questions mark(?) in the following number series ?

1. 24, 8, 16, 12, 14,?
   7
   13
   28
   11
   10
   Option B
   The series is,24+8/2, 8+16/2, 16+12/2, 12+14/2 =13…

    

2. 36, 18, ? 27, 54, 135
   18
   12
   72
   14
   9
   Option A
   The series is, (*.5), (*1), (*1.5)…

    

3. 15, 32, 99, 400, 2005, ?
   12048
   12036
   14080
   10025
   12030
   Option B
   The series is, (+1*2), (+1*3), (+1*4)…

    

4. 64, 32, 96, 24, 120, ?
   30
   20
   60
   40
   15
   Option B
   The series is, (÷2), (*3), (÷4), (*5)…

    

5. 3, 7, 13, 23, 41, ?
   72
   78
   85
   75
   90
   Option D
   The series is difference of difference.

    

6. 327, 336, 343, 348, 351, 350
   336
   350
   327
   348
   343
   Option
   The series is, (+9), (+7), (+5), (+3)…

    

7. 520, 527, 541, 562, 625, 737
   562
   527
   541
   625
   737
   Option
   The series is, (+7), (+14), (+28), (+56)…

    

8. 6, 4, 5, 8.5, 20, 46
   8.5
   20
   5
   4
   6
   Option B
   The series is, (5*1), (*1+1), (*1.5+1), (*2+1), (*2.5+1)…

    

9. 33, 38, 45, 63, 83, 108
   38
   63
   83
   33
   45
   Option E
   The series is, (+5), (+10), (+15)…

    

10. 105, 107, 110, 115, 122, 131
    122
    131
    110
    115
    107
    Option B
    The series is, (+2), (+3), (+5) addition of prime numbers.

     

Click here for topic wise Quantitative Aptitude Questions

1. Difference between circumference and diameter of a circle is 60 cm. What will be volume of cylinder, whose height is 14 cm more than that of radius of circle and radius of cylinder is 10 cm ?
   8400
   8500
   8800
   9800
   9200
   Option C
   ATQ, 2πr-2r=60
   2r=28
   r=14
   height of cylinder =14+14=28 cm
   radius=10 cm
   volume of cylinder=πr^2h=22/7*10^2*28=8800 cm^3

    

2. A bag contains 5 oranges, 4 apples and 6 mangoes. 4 fruits are drawn randomly, then find probability of getting all fruits are of mangoes.
   2/91
   1/91
   13/95
   5/96
   6/95
   Option B
   required no. of outcome=6C4
   total no. of outcome=15C4
   probability=(6C4)/15C4
   =6*5*4*3/15*14*13*12= 1/91

    

3. A man brought two articles for rs.1200. He sold one article at a profit of 20% and another article at a loss of 20%. If the selling price of both the articles is equal, then find the cost price of article which is sold at a loss of 20%.
   720
   800
   600
   550
   780
   Option A
   total CP of two article=1200
   CP of one article=x
   CP of another article=1200-x
   x*120/100=(1200-x)80/100
   6x/5=4800-4x/5
   x=480
   CP of article which is sold at a loss of 20%=1200-480=720

    

4. The ratio of the present ages of A and B is 4:3. 4 years hence the age of A will be 20% more than the age of B 6 years hence. Find the difference of their present ages.
   10
   15
   16
   8
   no of these
   Option D
   let the present age of A and B be 4x and 3x respectively
   4x+4=(3x+6)6/5
   4x+4=18x+36/5
   20x+20=18x+36
   2x=16
   x=8
   A’s present age=32
   B’s present age=24
   difference=32-24=8 years

    

5. A,B and C alone can complete the work in 16:24:32 days respectively. All of them started working together but after 2 days A left the job and 7 days before the completion of the work B also left the job. In how many days the work is completed ?
   20
   15
   25
   16
   18
   Option D
   LCM of 16,24 and 32=96
   A’s efficiency=96/6=16
   B’s efficiency=96/24=4
   C’s efficiency=96/32=3
   all work together for 2 days=13*2=26 work
   remaining work=96-26=70
   C alone work for 7 days=7*3=21 work
   remaining work done by B and C together=49/7=7 days
   total time required=2+7+7=16 days

    

6. A train crosses a bridge and a platform of length 650m and 800m in 20 sec and 30 sec respectively. Find the speed of the train(in km/hr).
   300 km/hr
   280 km/hr
   200 km/hr
   180 km//hr
   240 km/hr
   Option D
   let the length of train=x
   x+650/20=x+800/30
   3x+1950=2x+1600
   x=350
   speed of train=350+650/20=50 m/sec
   speed of train (in km/hr)=50*18/5=180 km/hr
   

    

7. A,B and C enter into a partnership by investing in the ratio of 3:4:5. After 1 year, B invests another 15000 and C at the end of 2 years also invest 10000. At the end of 3 years profit are shared in the ratio of 3:5:7.. Find initial investment of C.
   60000
   50000
   65000
   70000
   80000
   Option B
   let A,B and C invest be 3x, 4x and 5x respectively
   A’s total investment=3x*3=9x
   B’s total investment=(4x*1)+(4x+15000)*2=12x+30000
   C’s total investment=(5x*2)+(5x+10000)*1=15x+10000
   9x/12x+30000=3/5
   45x=36x+90000
   9x=90000
   x=10000
   C’s initially invested=5*10000=50000

    

8. Difference between SI and CI in certain amount of principal is rs.60. If the rate of interest is 20% in both cases, then find the SI after 3 years in same rate of interest.
   
   850
   600
   900
   1200
   950
   Option C
   ATQ, 60=PR^2//100^2
   60=P*400/1000
   P=1500
   SI after 3 years=1500*20/100*3=900

    

9. In a vessel milk and water are in the ratio of 5:3. If 48 liter of mixture is taken out from the vessel and 30 liter of water is added, then new ratio of milk and water becomes 4:3. Find the initial quantity of mixture in vessel.
   368
   280
   365
   440
   320
   Option A
   let the milk and water be 5x and 3x
   (5x-30)/3x-18+30=4/3
   15x-90=12x-48
   3x=138
   x=46
   total quantity of mixture=8x=8*46=368

    

10. The income of A and B is in the ratio of 3:2 and their expenditure in the ratio of 4:3. If each of them save rs.4000, then find income of A ?
    9000
    8400
    9500
    6500
    7000
    Option B
    let the income of A and B be 3x and 2x respectively
    3x-4000/2x-4000=7/3
    9x-12000=14x-2800
    5x=14000
    x=2800
    income of A=2800*3=8400
    

     

Click here for topic wise Quantitative Aptitude Questions

Read the following statements and answer the questions:

1. What is the distance between state A and state B?
   a)Two persons P and Q started simultaneously from A to B wit their speeds in ratio 4:5.
   b)Q reached A one hour earleir than P to B.
   c)The difference between speeds of P and Q is 20 kmph.
   a and b only
   a and c only
   a only
   b and c only
   All a,b and c are required
   Option E
   

    

2. What is the speed of boat in still water?
   a)The boat covers 10 km in h hours in downstream.
   b)The boat covers same distance in 5 hours in upstream.
   c)The speed of stream is one third of that of boat in still water.
   Only a and b are sufficient
   Only b and c are sufficient
   a and either b or c are sufficient
   Cannot be determined
   None of these
   Option C
   Upstream=(5+2)/2=3.5
   using a and c,
   u + u/3 =5
   4u=15
   u=3.7 kmph

    

3. What is ratio of invetsments of A,B andC?
   a)Total investments is Rs 12000 in which A’s contribution is Rs 4500.
   b)Ratio of invetments of A to B is 4:3 and B to C is 3:1.
   Only a is sufficient
   Only b is sufficient
   Either b or c is sufficient
   a and b together are not required
   None of these
   Option B
   4:3:1 = A:B:C

    

4. What is Shivani’s present age?
   a)Shivani is 3 years older than Srikant.
   b)The ratio between Srikant and Renu age is 3:4.
   Only a is sufficient
   Only b is sufficient
   Either a or b is sufficient
   Neither a or b are sufficient
   Both a and b are sufficent
   Option D
   We cannot find the exact age .

    

5. What is the salary of Priyanka in group of Priyanka,Queen and Rishi,whose average salary is Rs 36,700?
   a)Total salaries of Queen and Zaira is Rs 78650.
   b)Total salaries of Priyanka and Queen is Rs 97550.
   Only a is sufficient
   Only b is sufficient
   Either a or b is sufficient
   Both a and b are sufficent
   Neither a nor b are sufficient
   Option A
   

    

6. What are the marks obtained by Jack in History?
   a)Average marks obtained by Jack in History , Geography and Computer is 125.
   b)Average marks obtained by Jack in Hindi,English and Commerce is 134.
   
   Only a is sufficient
   Only b is sufficient
   Either a or b is sufficient
   Neither a or b is sufficient
   Both a and b are sufficient
   Option D
   

    

7. How many persons are there in classroom?
   a)The avg weight of class is 46 kgs.
   b)If 2 persons weighting 38 kg and 32 kg leave the classroom and are replaced by 48 kg and 40 kg the the avg weight is increased by 2.5 kg.
   Only a is sufficient
   Only b is sufficient
   Either a or b is sufficinet
   Both a and b is sufficient
   Neither a or b is sufficient
   Option B
   Total =46 * x
   New total=48.5 * x
   48.5x – 46*x=48+40-38-32

    

8. What is profit earned by seling a mobile for Rs 17525?
   a)The CP of five such TVs is equal to the SP of 4 such TVs.
   b)13% profit is erned by selling each mobile.
   Only a is sufficient
   Only b is sufficient
   Either a or b is sufficient
   Both a and b is sufficinet
   Neither a nor b is sufficinet
   Option C
   From a)
   CP=4/5=100*17525/125
   From b)
   CP=113*17525/100

    

9. How many male and female can complete a piece of work in 15 days?
   a)If 12 male can complete the same work in 20 days.
   b)If 10 female and 6 male complete the same work in 12 days.
   Only a is sufficient
   Only b is sufficient
   Either a or b is sufficient
   Both a and b are sufficient
   Neither a nor b is sufficient
   Option D
   

    

10. Find the two digit number?
    a)Sum of two digit no is 6.
    b)Difference between 2 digit number is 0.
    Only a is sufficient
    Only b is sufficient
    Either a or b is sufficient
    Neither a nor b is sufficient
    Both a and b are sufficient
    Option E
    

     

Click here for topic wise Quantitative Aptitude Questions

1. Find the wrong number in the series?
   13 , 18 , 27 , 40 , 63 , 98
   18
   27
   98
   63
   40
   Option B
   13 + 5 =18
   18 + (5+3)=26
   26 + (5+3+6)=40

    

2. 5 , 45 , 82 , 113 , 135 , ?
   145
   154
   160
   165
   None of these
   Option A
   Difference of 40 , 37 , 31 , 22 , 10
   Then -3 , -6 , – 9 , -12

    

3. 1000 , -24 , 232 , ? , 184 , 180
   172
   168
   178
   182
   None of these
   Option B
   1000-4^5= -24
   -24 + 4^4=232
   232-4^3 =168

    

4. 5 , 7 , 11 , 19 , 35 , ? , 131
   67
   65
   68
   72
   None of these
   Option A
   +2 , +4 , +8 , + 16 , +32 , +64

    

5. Find the wrong term in the series:
   44 , 51 , 65 , 85 , 114 , 149
   85
   44
   51
   149
   114
   Option A
   44+7=51
   51+14=65
   65+21=86

    

6. Find the wrong term in the series:

   59 , 58 , 50 , 23 , -41 , -164 , -382

   -155
   -150
   -164
   -160
   None of these
   Option C
   59-1^3=58
   58-2^3=50
   50-3^3=23

    

7. 40 , 40 , 20 , 60 , 15 , 75 , ?
   12.5
   10
   9.5
   15
   None of these
   Option A
   40*1=40
   40*0.5=20
   20*3=60

    

8. 12 , 14 , 19 , 36 , ? , 358
   101
   105
   95
   98
   None of these
   Option A
   

    

9. 4 , ? , 4 , 9 , 32 , 155
   2
   1
   3
   4
   5
   Option C
   4*1-1=3
   3*2-2=4

    

10. 12 , 23 , 35 , 49 , ? , 93
    65
    67
    68
    69
    None of these
    Option B
    

     

1. A vessel contains 192 litres of milk.A vendor draws out x% of milk and replaced it with same quantity of water.He repeasted the same process for 3 times.And thus the milk content in mixture is only 81 itres.Then how much percent he withdrew any time?
   15%
   20%
   25%
   30%
   40%
   Option C
   81 = 192 (1-x/100)^3

    

2. A vessel contains 30 litres of milk and water in ratio x:y rspectively.When 10 litres of mixture is taken out and replaced it with water,then ratio becomes 2:3.Then waht is the initial quantity of milk in vessel?
   15 litres
   18 litres
   16 litres
   22 litres
   None of these
   Option B
   

    

3. A vessel contains “x” itres of milk.A person stoled 50 litres of milk and replaced it with same quantity of water.He repeated the same process further two times.And thus milk in vessel is only “x-122′ litres.Then what is quantity of water in final mixture?
   100 l
   125 l
   130 l
   122 l
   None of these
   Option D
   x-122=x(1-50/x)^3
   x=250 l
   Milk=250-122=128 l
   water=122

    

4. In a 250 litres of mixture of soda and water,water is x%.The person sold 50 litres of mixture and replaced wth same quantity of water.If percent of soda in final mixture is 64%,then what is yhe percentage of soda in initial mixture?
   80%
   75%
   70%
   65%
   None of these
   Option A
   Soda=250*(100-x/100)
   Then,50 litres replaced it,
   250*(100-x/100) – 50*(100-x/100) = 64% of 250
   x =20%
   remaining=80%

    

5. From a vessel of soda,which contains 200 litres of soda ,the vendor replaces each time with water wjen he sells 40 itres of soda .Everytime he sells out only 40 litres of soda .After replacing the soda with water the fourth time,the total amount of water in the mixture is which of the following?
   80.05 l
   85.50 l
   81.92 l
   78.025 l
   None of these
   Option C
   Amount of soda left after 4th time=200(1-40/100)^4
   =200(4/5)^4
   =200*256/625 = 81.92

    

6. A vessel was full of soda.Mani used to draw out 20% of the soda from vessel and replaced it with water.He has repeated the same process 4 times and thus there was only 512 gm of soda left in vessel,the rest part of the vessel was filled with water.What is the initial amount of soda in the vessel?
   1.05 kg
   1.15 kg
   1.25 kg
   1.30 kg
   None of these
   Option C
   512 = x(1-1/5)^4
   x = 1.25 kg

    

7. The ratio of soltion “X ” and “Y” in vessel is 3:2 when 10 litres of mixture is taken out and is replaced by solution “Y” ,the ratio becomes 2:3.What is the total quantity of mixture in the vessel?
   30 l
   25 l
   20 l
   15 l
   None of these
   Option A
   2/ 3 =(1-10/n)
   

    

8. A container is filled with liquid,4 parts of which are soda and 5 parts chemical.How much of mixture must be drwan off and replaced iwth water so that the mixture may be half soda and half chemical?
   1/5
   1/6
   1/10
   1/15
   1/28
   Option C
   4:5==9
   1:1==2
   8:10
   9:9

    

9. A vessel contains 50 itres of soda.10 litres of this soda is takne out and replaced with water.This process is repeated twice.Find the amount of remaining soda in the mixture?
   128/5 l
   125/4 l
   118/3 l
   Cannot bed etermined
   None of these
   Option A
   =50(1-10/50)^3

    

10. 144 litres of mixture contain soda and water in ratio 5:7.How much soda need to be added to this mixture so that new ratio is 23:21 respectively?
    30 l
    32 l
    35 l
    28 l
    None of these
    Option B
    

     

1. Rs 12,200 was partly invested in scheme X at 10% p.a compound interest(compounded annually) for 2 year and partly in scheme Y at 10% p.a. simple interest for 4 years. Both the schemes give equal interests. How much was invested in scheme X?
   Rs 7000
   Rs 8000
   Rs 9000
   Rs 8500
   Rs 10000
   Option B
   Let it be Rs x. in scheme X
   So in Y=(12200-x)
   Therefore,[(1+10/100)^2 -1] = [(12200-x) *10*4] /100
   x=Rs 8000
   

    

2. Mani borrows Rs 8000 at 20 percent compound rate of interest. At end of ech year he pays back Rs 3000,How much amount should he pay at end of third year to clear all his dues?
   Rs 5140
   Rs 6504
   Rs 5904
   Rs 4750
   None of these
   Option C
   At end of first year,=8000+1600=9600
   Amount=9600-3000-6600
   At end of econd year=6600+1320=7920
   Amount=7920-3000=4920
   Amount at third year=4920+984=Rs 5904

    

3. Shubhra borrows money at 4% p.a and lends it at 6% p.a compound interest compounded half yearly and thus gains Rs 209 in a year.What is the amount of money she borrows?
   Rs 6000
   Rs 10000
   Rs 12000
   Rs 15000
   None of these
   Option B
   Let amount borrowed be Rs 100.
   Intrest to be paid=Rs 4
   Gain=6.09-4=Rs 2.09
   Actual amunt borrowed=209/2.09 * 100

    

4. What sum will give Rs 488 as the difference between S.I and C.I. at 10% in 1 1/2 years compounded half yearly?
   Rs 55000
   Rs 50000
   Rs 64000
   Rs 68000
   None of these
   Option C
   Let sum be Rs 100.
   SI=15
   CI=15.6725
   Difference=0.7625 == 488
   

    

5. Rs 20000 was invested by Mani in mutual fund at 10% p.a. at C.I. However every year he has to pay 20% tax on C.I.How much money does Mani have after 3 years?
   Rs 25410
   Rs 25194
   Rs 25640
   Rs 24845
   None of these
   Option B
   

    

6. Shubhra takes a loan of Rs 8400 at 10% p.a compounded annually which is to be repaid in two equal annual installments. One at end of one year and other end of second year. What is the value of each installment?
   Rs 4200
   Rs 4500
   Rs 4840
   Rs 4580
   None of these
   Option C
   8400 = x*(210/121)

    

7. Mani borrows Rs 6375 to be paid back with C.I at 4% p.a by end of two years in two equal yearly installments. How much will each installment will be of?
   Rs 3380
   Rs 2540
   Rs 2505
   Rs 3520
   None of these
   Option A
   25x/26 +625 /676x = 6375
   x = (6375 * 676) / 1275

    

8. If Rs 7200 amounts to Rs 10,368 in C.I at a certain time, then Rs 7200 amounts to what in half of time?
   Rs 8500
   Rs 8640
   Rs 8800
   Rs 8405
   None of these
   Option B
   

    

9. There is 50 percent increase in amount in 5 years at S.I. What will be the C.I of Rs 12000 after 3 years at same rate?
   Rs 3565
   Rs 3972
   Rs 3845
   Rs 3540
   None of these
   Option B
   Let P=Rs 100
   I=Rs 50
   T=5 years
   R=50*100/100*5=10%
   In ci,
   CI=(12000(1+10/100)^^3 -1

    

10. Mani borrows Rs 3000 at 10% C.I. At the end of every year, he pays back Rs 1000.How much amount should he pay at end of 4th year to clear al his debt?
    Rs 541
    Rs 545
    Rs 750.55
    Rs 751.30
    None of these
    Option D
    

     

1. A can do a piece of work in 10 days and B can do a piece of work in 15 days, then how many days together complete the same piece of work ?
   6days
   8days
   4days
   2days
   none of this
   Option A
   solution: xy/x+y
   10*15/10+15 = 6days

    

2. P and Q alone can do a piece of work in x hours and (x+10) hours respectively. If both P and Q together can do same piece of work in 12 hours, then find the time taken by P alone to do the same work is what percent of that of Q alone ?
   100/3%
   200/3%
   220/3%
   95/3%
   none of these
   Option B
   solution: [x*(x+10)]/[x+(x+10)] = 12
   x^2+10x = 24x+120
   x^2-14x-120 = 0
   x=20,-6
   x= 20 hours
   P=20 hours
   Q=30 hours
   %=20/30*100=200/3%
   

    

3. 10 men or 30 boys can do any work in 12 days, then time taken to complete the same work by 10 men and 15 boys .
   8 days
   4 days
   2 days
   5 days
   none of this
   Option A
   solution: 12/(10/10+15/30)= 12/(1+1/2)
   =12*2/3 =8 days

    

4. Sunil can do a work in 12 days and Ravi can do same work in 8 days . If they work toghether for 2 days, then B left the work and remaining work done by A, then how many days total work will be completed.
   9
   12
   10
   14
   18
   Option A
   Sunil can do a work = 12 days
   Ravi can do a work=8 days
   Total work = LCM of 12 and 8=48 work
   efficiency of Sunil = 48/12 = 4 work
   efficiency of Ravi = 48/8 =6 work
   toghether work for 2days = (6+4)*2= 20work
   remain work done by Sunil = 28/4= 7days
   total work completed = 7+2 =9 days

    

5. Sinu and Rinu can do a work 20 days and 30 days respctively . If they got rs.1500 wages in total, then find share of Rinu .
   600
   1200
   800
   1000
   none of these
   Option A
   Total work = LCM of (20 and 30)
   total work = 60
   efficiency of Sinu = 60/20 =3 work/day
   efficiency of Rinu=60/30=2 work/days
   wages of Rinu = 1500*2/5 =rs.600

    

6. X,Y and Z completed a work costing rs.1800 . X work for 6 days , Y worked for 4 days and Z worked for 9 days . If their daily wages are in the ratio of 5:6:4, then how much amount will be received by X ?
   600
   500
   400
   200
   none of this
   Option A
   Ratio of the wages of A, B and C = 5:6:4
   X share: Y share : Z share
   =(6*5) : (4*6) : (9*4)
   =30 : 24 : 36 =5:4:6
   X’s share = 5/15*1800 = rs.600

    

7. A & B working together completes work in 24 days while B & C completes the same work in 30 days. If C is 20% more efficient than B, then in how many days working alone A will complete the half of the work ?
   122/7 days
   112/7 days
   119/9 days
   132/7 days
   130/7 days
   Option D
   LCM of 24 & 30=120
   efficiency of A&B working together=5
   efficiency of B&C working together=4
   ATQ, efficiency of C 20% more than B
   ratio of efficiency of B&C =5:6
   balancing both sides b multiplyng by 11
   efficiency of B&C working together =44
   efficiency of A&B working together=55
   efficiency of B=5/11*44=20
   efficiency of A=35
   A alone can do half of work=(120*11)/(2*35)=132/7 days
   

    

8. 12 men can complete a piece of work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20days. If only women were to complete the remaining in 4 days, how many women would be required ?
   35
   30
   45
   40
   50
   Option B
   solution: 12 men*36days=18women*60days
   2men=5women
   8men=20women
   total work=18*60=1080 work
   (20women+20women) is working for 20days
   work completed=40women*20days=800work
   remaining work=1080-800=280 work
   women required=280/4=70 women
   extra women required=70-40=30 women

    

9. Some persons can built a bridge in 100 days, but 25 persons do not join the group to complete the bridge so the work is finished in 150 days. Find out how many persons worked initially ?
   80
   75
   85
   92
   none of these
   Option B
   solution: let total no. of person have in the group initially=x
   total work=100*x
   100*x=(x-25)*150
   x=75
   

    

10. P, Q, R & S can do a work individually in 10, 20, 30 & 40 days respectively. P & Q can do half of the work and the remaining half is done by R & S together. In how many days was the work finished ?
    260/11 days
    245/11 days
    270/11 days
    250/21 days
    280/21 days
    Option D
    solution: LCM of 10, 20, 30, 40=120
    total work=120
    efficiency of P=120/10=12
    efficiency of Q=120/20=6
    efficiency of R=120/30=3
    half the work done by P & Q=60/18=10/3 days
    remaining half work done by R & S= 60/7 days
    total days required=10/3+60/7=250/21days

     

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1. 6 , 8 , 12 , 42 , 160 , ?
   820
   810
   840
   850
   None of these
   Option B
   6*1+2=8
   8*2-4=12
   12*3+6=42

    

2. 6 , 5 , 8 , ? , 90 , 449
   25
   30
   32
   23
   None of these
   Option D
   6*1-1=5
   5*2-2=8

    

3. 3 , 4 , 9 , 23 , ? , 202.5
   60
   64.5
   67.5
   65
   None of these
   Option B
   3*1+1=4
   4*1.5+3=9
   9*2+5=23

    

4. 3 , 3 , 13 , 37 , 105 , ?
   225
   275
   255
   245
   250
   Option A
   3+1^3 – 1= 3
   3+2^3 +2 =13
   13+3^3 – 3 =37

    

5. 37 , 38 , 58 , ? , 293.5
   120
   117
   115
   125
   None of these
   Option B
   37*1+1=38
   38*3/2+1=58

    

6. 8 , 9 , 11 , 19 , 67 , ?
   451
   455
   460
   350
   355
   Option A
   8*1+1=9
   9+(1*2)=11
   11+(2*4)=19
   19+(8*6)=67

    

7. 1650 , ? , 50 , 9.5 , 1.17 , -0.415
   250
   270
   260
   245
   None of these
   Option B
   

    

8. 3 , 14 , 39 , 103 , 270 , ?
   707
   750
   450
   705
   None of these
   Option A
   3+11=14
   14+(11+14)=39
   39+(25+39)=103

    

9. 14 , 18 , ? , 458 , 4458
   62
   50
   56
   55
   58
   Option E
   

    

10. 15 , 80 , 255 , ? , 1295
    630
    624
    520
    555
    585
    Option B
    2^4=16-1=15
    3^4=81-1=80

     

Click here for topic wise Quantitative Aptitude Questions

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1. The average score of a player after 48 innings is 49 and in 49th innings ,player scores 98 runs.In 50th innings,minimum number of runs required to increse his average score by 2 than it was before the 50th innings?
   150
   140
   145
   155
   160
   Option A
   Average score after 48t inning=49
   Averga ecsore after 49th innings=(48*49+98)/49 =50
   Average score after 50th =50+2=52
   =(50*52) -(49*50)

    

2. The average age of directors of IDBI Bank having 15 directors was 48 years.When a director aged 56 resigned from the board,another director passed away on same day.A new director joined them aged 36.Next year the average age of all 14 directors was found to be 48 years.What is the age of late director at the time of passing him ?
   45 years
   40 years
   42 years
   48 years
   None of these
   Option C
   Before pssing away=48*15=720
   the age of late drector=720 – (56+x) +36 +14 = 672

    

3. The average expenditure of the bhawan when there are 10 persons is Rs 80 per persona and the average expenditure is Rs 40 when there are 30 persons.If it is known that there are some fixed expenses irrespective of number of persons then the average expenditure per person when there are 50 persons in the bhawan?
   Rs 25
   Rs 30
   Rs 45
   Rs 35
   None of these
   Option D
   x +30 y =1200
   x +10y=800
   y = 20
   Total exp=600+ 40 * 20 = 1400
   =1400/40

    

4. Mr Srikant has 3 sons namely Rishi ,Akash and Krish.Rishi is the eldest son of Mr Srikant while Krish is the youngest one.The present ages of all of them are square numbers.The sum of their ages after 5 years is 44.What is the age of Rishi after 2 years?
   15 years
   18 years
   17 years
   20 years
   None of these
   Option B
   Let square number oe x,y,z
   (x+5)+(y+5)+(z+5)=44
   x+y+x=44-15=29
   Then the possible values of x,y,z= 4, 9 , 16
   Rishi present age=16
   After two years,it wil be 18 years.

    

5. If six years are subyracted from present age of Ramya and remainder is divided by 12,then present age of his grandaughter Priyal is obtaoned.If Priyal is 2 years younger to Manisha whose age is 8 years,then what is Ramya’s present age?
   72 years
   68 years
   78 years
   75 years
   None of these
   Option C
   Let prswnt age of Ramya be x years.
   x – 6/12 = 6
   x – 6 = 72
   x = 78 years

    

6. Shivani’s age is 125% of what it was ten years ago,but 250/3% of what it will be after ten years.What is present age of Shivani?
   45 years
   50 years
   40 years
   Cannot be determined
   None of these
   Option B
   125x/100 = x +10
   125x=100x +1 000
   x=40
   Present age =x +10 =50

    

7. Akansha got married 6 years ago.Her present age is 5/4 tmes her age at time of her marriage.Akansha’ brther was 5 years younger to her at time of her marriage.What is present age of Akansha’ brother?
   25 years
   22 years
   20 years
   26 years
   None f these
   Option A
   Let prensent age of Akansha be x years
   Present age of Akanhsa brother be y years
   x = (x-6)(5/4)
   x = 30
   Akansha brother age=30-5=25 years
   

    

8. At present,the respective ratio between the ages of X and Y is 3:4 and that between X and Z is 1:2.Six years hence,,the sum of X,Y and Z will be 96 years.What is the present age of X?
   16
   18
   15
   12
   10
   Option B
   

    

9. The sum of present ages of Rishi and Akansha is 48 years.Today Akansha is 4 years older tha Srikant.the respective ratio of the present ages of Rishi and Srikant is 4;7.What was Akansha’s age two years ago?
   30 years
   35 years
   42 years
   45 years
   None of these
   Option A
   

    

10. the ratio of present ages of Rishi and Kavya’s age is 3:5 and the ratio of present ages of Kavya and Priyal is 2:3 respectively.If Rishi is two fifth of Priyal age,what is Rishi’s age?
    10
    12
    14
    Data insufficient
    No e of these
    Option D
    

     

1. The difference between simple interest and compound interest on a sum of rs.4400 for 2years is rs.44. What is the rate of interest per annum?
   10%
   15%
   12%
   18%
   20%
   Option A
   Solution: Let the rate of interest be r% per annum.
   ATQ,
   4400×r^2/(100×100)=44
   r= 10%
   

    

2. If the sum of money gets tripled at a certain rate of simple interest in three years, in how many years it will become 9 times of it self with same rate of interest?
   15 years
   9 years
   27 years
   10 years
   12 years
   Option E
   Solution: Let the amount be P and rate of interest be R% per annum.
   ATQ,
   (3P-P)=P×R/100×3
   R=200/3
   Let us the assume that in t years amount will become 18 times itself .
   ATQ,
   (9P-P)=P×200/3×t/100
   t=12 years

    

3. Difference between the simple interest received in 1.5 years at 24% per annum and that received in 3.5 years at 12% per annum on the same sum is Rs.1440, then find the sum ?
   22000
   30000
   15000
   24000
   26000
   Option D
   solution: 100x*3.5*12/100 – 100X*1.5*24/100=1440
   42x-36x=1440
   x=240
   Required sum = 100x
   =100*240=24000

    

4. A lent of Rs.3000 to B for 2 years and Rs.1000 to C for 4 years on simple interest at the same rate of interest and received Rs.500 in all from both of them as interest. The rate of interest per annum is ,
   10%
   8%
   6%
   9%
   5%
   Option E
   solution: 3000*r/100*2+1000*r/100*4=500
   60r+40r=500
   r=5%

    

5. The interest earned on a certain sum in 2years at 20% pa at CI is twice the interest earned on Rs.2200 for 2years at 10% SI. Find the value of sum.
   3000
   2000
   2250
   1280
   1600
   Option B
   Solutions: p(1+r/100)^2-p=2*2200*10*2/100=880
   p36/25-p=880
   p=2000

    

6. Ram divided his total amount between his brother and sister in the ratio 5:3. His brother invested his share on CI for two years at the rate of 10% and received the interest rs.480 less than his sister ,who invested her share on SI for three years at the rate of 15%. find the share of individual Ram’s brother and sister respectively.
   8000,4800
   6400,5000
   4800,3500
   5000,3000
   none of these
   Option A
   Solution: Let total savings of Ram is rs.8x
   share of his brother =rs. 5x
   and share of sister =rs.3x
   CI received by his brother = 5p [(1+10/100)^2-1]=105p/100
   ATQ, 3p*15/100*3-105p/100=480
   135p/100-105p/100=480
   30p=48000
   p=rs.1600
   Ram’s brother share=1600*5=rs.8000
   Ram’s sister share=1600*3=rs.4800

    

7. Rajat invested rs.P on CI of the rate of 10% for 2 years and suman invested rs.Q on SI at the rate of 20% for 3 years and ratio of interest got by Rajat in 2nd year and total interest got by Suman is 1:3. If Rahul invested rs (P+Q) on SI for 2 years on 12% p.a. and gets rs. 372 as interest. Find amount of Rajat and Suman invested individually.
   1000,550
   1600,800
   1200,900
   1500,600
   none of this
   Option
   Solution: 2nd year CI on 10% =10+10*10/100=11%
   total 3 year SI at 20%=20*3=60%
   According to questions , 11P/60Q=1/3
   P=1/3*60/11=20Q/11
   also given, (20Q/11+Q)*12/100*2=372
   31Q/11*24/100 = 372
   Q =372*1100/31*24
   Q=rs. 550
   P=20*550/11 =rs.1000

    

8. Srikatnta invested a sum of rs.20,000 in a scheme offering simple interest at 30% p.a. after 2 years, he again invested total money he got from scheme in share market of 80 per share, after 3 month he sold all his share at rs. 100 per share. Find his total profit.
   
   8000
   10,000
   6000
   9000
   none of this
   Option A
   Solution: Amount = 20000+20,000*30*2/100=rs.32,000
   Units of share parched =32000/80=400
   selling price of share =400*100=40,000
   Profit = 40,000-32000=8000

    

9. The simple interest accrued on a certain sum is rs. 5000 in 4 years at the rate of 10 p.a. What would be the compound interest accrued on the same sum at the same rate in years ?
   3100
   2625
   1200
   1400
   none of this
   Option B
   solution: Let the sum be rs.x
   x*10/100*4=5000
   x=12500
   CI for 2years @ 10%=10+10*10*10/100
   =21%
   21% of 12500 =2625

    

10. A invested total of rs.80,000 in two schemes M and N for 2 years. In scheme M he invested at 18% p.a. at SI and in scheme N he invested at 20% p.a at CI compounded annually. If SI received is rs.4800 more than CI, then find amount invested by him in scheme N.
    50,000
    30,000
    40,000
    20,000
    none of these
    Option B
    solutions: Let amount invested in scheme N =x
    and in scheme M =80000-x
    rate of interest of scheme N=20+20+20*20/100=44%
    [(80000-x)18*2/100]-44x/100=4800
    2880000-36x/100-44x/100=4800
    80x=2400000
    x=30000