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27Jul, 2020

Quantitative Aptitude: Simplification Questions Set 98

What will come at the place of question mark in the following questions?(You are not expected to find exact value)
59.90% of 849.99 – 38.88% of 599.85 = ?

274

265

256

276

None of these

Option D
=60/100 * 850 – 39/100 * 600
=510-234=276
199.95/399.98 × 21^2 − (11)^2 =?
98.0

99.5

100.5

101

None of these

Option B
=200/400 *441 – 121
=220.5-121=99.5
80 × 5 + 25 × 11 – 20 × 13 = ?
505

385

400

415

None of these

Option D
=400+275-260
=415
990% of 40 + 750% of 50 − 600% of 40 = ?
611

603

491

501

531

Option E
=990/100 * 40 + 750/100 * 50 – 600/100 * 40
=396 + 375 – 240 = 531
499.95 / 4.98 + (5.97)^3 -204.69 =?
111

120

123

107

101

Option A
=500/5 + 216 – 205
=100 + 216 – 205
=111
Find the approximate value of the following questions:
2011.11 + 210.1 + 211.01 =?

2432

2501

2534

2358

None of these

Option A
19.88% of 2299.98 + 19.99% of 4699.91 = ? + 35.88% of 449.99
1208

1424

1350

1520

1238

Option E
20/100 * 2300 + 20/100 * 4700 = x + 36/100 * 450
460 + 940 = x + 162
1400 = x + 162
x = 1238
25.999 × 8.004 × 15.998 =?
3328

3400

3520

3290

None of these

Option A
=26* 8 * 16=3328
699.954 ÷ 7.983 × 4.020 =?
315

300

330

350

None of these

Option D
=700 / 8 * 4 = 350
12.11% of 599.988 =?

60

82

72

68

55

Option C
12/100 * 600 = 72

01

26Jul, 2020

Quantitative Aptitude: Simple/Compound Interest Set 16

Pratyush lent Rs.21600 to be divided between her two daughters who aged 9 years and 11 years such that both of them would get an equal amount at certain age when lent at rate of 10% SI per anuum. If their investments are in ratio of 51:57 respectively.Then at what age both will received same amount?
9 years

10 years

14 years

15 years

18 years

Option E
p+q = 21600
p/q = 51/57
p = 10200 q = 11400
10200+10200*10*(p-9)/100 = 11400+11400*10*(p-11)/100
p= 18 years
Sum of money becomes Rs.1815 at 7% SI after 3 years. Same sum of money becomes Rs. 2235 at same interest after 7 years.Find the sum of money?
Rs 1500

Rs 1400

Rs 1350

Rs 1450

None of these

Option A
2235-1815 = P/100(7*7-7*3)
Sum = Rs 1500
Ramesh invests in a company Rs. 124000 for 9 years at 5% SI. Income tax at the rate of 19% is deducted from interest earned at the end of every year. Find the amount at the end of 9th year?
Rs 1,25,587

Rs 1,78,158

Rs 1,69,198

Rs 1,55,188

None of these

Option C
For 1 year = 124000*5/100 = Rs 6200
income tax = 6200*81/100 = Rs 5022
For 9 years = Rs 45198
Amount = 124000+45198 = Rs 1,69,198
Akansha lent a part of Rs. 15900 to Rashi at 6% SI. Rest to Anvesha at 5% SI. After 4 years she got an amount of Rs 19376 in total. Then what is the amount paid by Anvesha in total?
Rs 9500

Rs 10,200

Rs 11,500

Rs 12,000

None of these

Option B
3476 = p*6*4/100 + (15900-p)*5*4/100
p =7400
Anvesha = 8500+8500*4*5/100 = Rs 10200
What amount would Rs.2500 fetch if it is lent at 8% SI for 15 years?
Rs 6000

Rs 4200

Rs 4500

Rs 5000

Rs 5500

Option E
SI = 2500*8*15/100
=3000
Amount = 2500+3000 = Rs 5500
The simple interest on a certain sum for 2 years at 10% per annum is Rs. 80. The corresponding compound interest is which of the following?
Rs 84

Rs 95.50

Rs 89.25

Rs 88

Rs 90

Option A
Sum = 100 x80/2 x 10 =Rs 400
C.I. = Rs.400x (1+10)^ 2/100 – 400 = Rs 84
If the difference between the simple interest and compound interests on some principal amount at 10% for 3 years is Rs. 45, then the principal amount is which of the following?
Rs 1342

Rs 1398

Rs 1444

Rs 1452

None of thee

Option D
Sum = Difference x (100)^3/r^2(300 + r)
= 45 x (100)^3/10^2 (300 + 10)
= 45000//31 = Rs 1452
If the difference between the CI and SI on a sum of money at 5% per annum for 2 years is Rs.15.Find the Simple Interest ?
Rs 750

Rs 500

Rs 250

Rs 600

None of these

Option D
15 =P*( 5/100)^2
P = Rs 6000
SI =(6000*5*2)/100 = Rs 600
The effective annual rate of interest corresponding to nominal rate of 4% per annum payable half yearly will be which of the following?

4.40

4.04

4.0

4.05

None of these

Option B
A sum was invested at compound intrest to Rs.800 in 3 years and to Rs.840 in 4 years.Find rate of interest per annum?
5%

4%

2%

7%

None of these

Option A
Rate of intrest = (100 × 40)/(800×1) = 10/2 = 5%

02

23Jul, 2020

Quantitative Aptitude: Partnership Set 16

Three persons Akansha, Banya, Caryl invested in a company in the ratio of 4:5:6. After 6 months Caryl withdraw half of his capital. If the sum invested by Akansha is 36000, then the profit earned by Caryl out of the total profit of 60000 is which of the following?
30000

45000

35000

Cannot be determined

None of these

Option A
Sum invested by Akansha = 4x = 36000
X = 9000
Investment made by Akansha, Banya , Caryl =36000, 45000, 54000
Ratio in which the profit will be divided- 36000*12 : 45000*2 : 54000*6 + 27000*6
=4:5:9.
So Caryl share = (9/18)*60000 = 30000
Two friends Avinash and Brijesh invested in a company with 115000 and 75000 rupees respectively. They agree that 40% of profit should be divided equally among them and rest is divided between them according to their investment. If Avinash got 500 rupee more than Brijesh, then the total profit is which of the following?
3200.25

3958.34

3500.25

3984.32

None of these

Option B
Ratio in which the profit will divide =23:15.
Let the profit be P,
now, [(23/38) – (15/38)]*(60/100)*P = 500
P = 3958.34
Priyal, Queen, Riya invested in the ratio of 6:5:7. After the end of business term, they receive the profit in ratio 3:1:5. Find the ratio of time in which they invested in the business?
25:15:30

45:51:65

35:14:50

40:45:52

None of these

Option C
Take time as T1,T2 and T3
(6*T1/5*T2) = 3/1, u will get T1/T2 = 5:2
Similarly, (5*T2/7*T3) = 1/5, u will get T2/T3 = 7/25
Three persons P,Q and R enter into a partnership by investing in ratio of 4:5:8. After one year P invest more 4300 and Q withdraws 3200. Now, the ratio of investment changes to 5:4:7. Approximately how much P invested initially?
12550

14500

13550

14755

None of these

Option D
After1 year – 4x+4300 : 5x-3200 : 8x
so, to find X = (4x+4300)/(5x-3200) = 5/4
so investment made by P = (33200/9)*4 = 14755
Three partners Priyal, Queen and Rashi invest a total sum of 2,40,000. At the end of the year Priyal get 15000 rupee, Queen get 20000 and Rashi get 25000 rupees as profit. How much amount is invested by Priyal and Rashi together?
16000

15000

12000

10000

None of these

Option A
Ratio in which they get profit =3:4:5
So total amount invested by Priyal and Rashi = (8/12)*24000 = 16000
Priyal, Queen and Riya invested in a company with 40000, 50000 and 60000 rupees respectively. After one year Priyal withdraw 10000 and Riya invest 5000. After another one year Queen invest 15000 more and Priyal deposit 5000 more. At the end of 3 years, profit between Priyal, Queen and Riya are distributed in the ratio of which of the following?
21:33:38

25:30:33

35:41:45

52:55:60

None of these

Option A
Investment made by Priyal, Queen and Riya are 40000, 50000, 60000 initially.
In second year =30000, 50000, 65000
In third year = 35000, 65000, 65000
So final ratio = 105000: 165000: 190000.
i.e 21:33:38
Rashi got 5000 as her share out of the total profit of 9000. Riya had invested 3000 rupees for 6 months while Rashi invested for the whole year. Find the amount invested by Rashi?
1750

1875

1775

Cannot be determined

None of these

Option B
Amount invested by Rashi = X
12X : 3000*6
X:1500
So Rashi share = [X/(1500+X)]*9000 = 5000
X = 75*25 = 1875
Two persons Akash and Brijesh invested in a company by investing Rs 10,000 and Rs 12,000 respectively. After 8 months, both took out Rs 2,000. What is the profit of Brijesh from a total profit of Rs 24,800 after the end of a year?
16400

15500

13600

14200

None of these

Option C
Akash : Brijesh= 10000*8 + 8000*4 : 12000*8 + 10000*4
=14 : 17
So Brijesh gets = (17/31) * 24,800= 13600
X, Y and Z invested Rs 1000 for 8 months, Rs 1200 for 6 months and Rs 1500 for some months. Out of a total profit of Rs 5,675 as profit, X received Rs 2000. For how much months did Z invested?
6 months

3 months

2 months

5 months

None of these

Option D
=1000*8 : 1200*6 : 1500*x
=80 : 72 : 15x
So 80/(80+72+15x) * 5675 = 2000
X = 5
X, Y and Z received their profit shares in the ratio of 4 : 6 : 9 respectively. X and Y received a total of Rs 60,000. What is the amount that Z and X got together?
78000

75000

72000

70000

None of these

Option A

03

20Jul, 2020

Quantitative Aptitude: Simplification Questions Set 97

What approximate value will come in place of the question mark (?) in the following questions? (You are not expected to calculate the exact value).
(41.39)^2 + (7.99)^2 − (22.22)^2 =?
1261

1340

1540

1365

None of these

Option A
=1681+64-484
=1261
41% of 601.25 – 250.18 = ? – 77% of 910
680

690

650

615

None of these

Option B
=40*(600/100)-250=x=77/100 *910
=240-250 =x-700
x=690
15.08× 11.899 + 22.92 × 14.96 = ?
505

480

495

510

525

Option E
=15*12+23*15
=180+345
=525
√1224.25 × 17.06 + √2304= ?
525

600

635

643

None of these

Option D
=35*17+48
=595+48=643
52000 ÷ 60 × 30 = ? × 40.25
620

610

630

650

None of these

Option D
=866.66*30 =x*40
=26000=40x
x=650
16.5% of 1399.925 + 114.80% of 1210 = ?
1620

1610

1600

1590

None of these

Option A
16.5/100 *1400 + 115/100 -1210
=1620
√623.98 + √729.45 = ?
55

52

50

48

None of these

Option B
=25+27=52
What will come in place of questions mark (?) in the following questions ?
(1.05 + 0.04)^2−? = 4 × 1.07 × 0.04
1.0404

1.40

0.04

1.04

None of these

Option A
(1.1)^2-4.25*0.04)=1.0404
29^2 × 6 ÷ 9 + 9^3 + 71 = (? )3 − 430
19

17

13

15

12

Option E
=841*0.66+729+71=x^3-430
=555+800=x^3-430
=1355=x^3-430
x^3=1785=12
4.5 times of 5/16 of 30% of 215 = ?
12.555

10.005

1.004

8.254

9.070

Option E
4.5/10 * 5/16 * 30/100 * 215
0.45*0.3125**0.3*215
=9.070

04

17Jul, 2020

Quantitative Aptitude: Mixture and Alligation Questions Set 11

Varsha covered 180 km distance in 10 hours. The first part of his journey she covered by bike, then he hired a auto. The speed of the bike and auto is 25 kmph and 15 kmph respectively. The ratio of the distances covered by the bike and the auto is which of the following?
7:5

1:5

3:10

9:11

None of these

Option A
Average Speed of bike and auto both= 180/10 = 18kmph
15………………….25
…………18…………..
7…………………….3
The ratio of time taken by auto to bike = 7:3
The ratio of distances covered by auto to bike = 7 * 15 : 3 * 25 =7:5
A mixture of rice is sold at Rs.3 per Kg. This mixture is formed by mixing the rice of Rs.2.10 per kg and Rs.2.52 per kg. What is the ratio of price of cheaper to costlier quality in the mixture if profit of 25% is being earned?
1:8

2:5

3:4

5:9

None of these

Option B
S.P= x + 25*x/100 = 3;
x = 2.4
210………………….252
…………240…………..
12…………………….30
=2:5
From the 50 l of a solution, 5 l of solution is taken out and after it, 5 l of water is added to the rest amount of solution. Again 5 l of solution and water is drawn out and it was replaced by 5 l of water. If this process is continued similarly for the third time, the amount of solution left after the third replacement is what?
38.50 l

36.45 l

40.50 l

35.85 l

None of these

Option B
=50*45/50 *45/50 *45/50
=36.45 l
Wheat worth Rs. 126 per kg and Rs. 134 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 177 per kg, the price of third variety of whaet per kg will be which of the following?
224

230

245

265

None of these

Option A
126*1+134*1+2y=177*4
260+2y=708
2y=708-260=448
y=448/2 = 224
One quantity of boron priced at Rs 9.30 per Kg is mixed with another quality at a certain rate in the ratio 8:7. If the mixture so formed be worth Rs 10 per Kg, what is the rate per kg of the second quality of aluminium?
9.50

10.60

10.80

11.50

None of these

Option C
Let the rate of second quality be Rs p per Kg.
9.30…..…………p
…………10………….
8………………………7
7p– 70 = 5.6
p = 10.80
A bottle contains 50 l of milk. 10 l of this milk is taken out and replaced with water. This process is repeated twice. Find the amount of remaining milk in mixture?
128/5 l

75 l

125 6/3 l

91 l

None of these

Option A
50 [1 – (10/50)]3 =128/5 l
A 144 l of mixture contains HCL and H2SO4 in the ratio 5 : 7. How much HCL need to be added to this mixture so that the new ratio is 23 : 21 respectively?
32 l

25 l

27 l

29 l

None of these

Option A
=144 =5:7
=60 : 84
Now == 21 = 84
=23 = 92
=92-60 = 32 l
A bottle contains 30 l mixture of HCL and H2SO4 in the ratio of p:q respectively. When 10 l of the mixture is taken out and replaced it H2SO4, then the ratio becomes 2:3. Then what is the initial quantity of HCL in bottle?
30 l

25 l

18 l

15 l

None of these

Option C
p+q =30 l
(p-10*p/p+q)/ (q-10*q/(p+q) + 10) = 2/3
2p-4/3q = 20
p =18 l
The ratio of Solution “X” and Solution “Y” in the jar is 3:2 when 10 l of the mixture is taken out and is replaced by the Solution “Y”, the ratio become 2:3. The total quantity of the mixture in the bar is ?
30 l

25 l

35 l

40 l

45 l

Option A
Initial =3:2 ;
After replacement its = 2:3
2/3 = (1 – 10/p)
p=30 l
‘P’ Liters of the mixture contains HCL and H2SO4 in the ratio 4:3. If 13 l of H2SO4 is added then the ratio becomes 1:1. Then what is the final quantity of H2SO4 in the mixture?
50 l

52 l

55 l

58 l

69 l

Option B

05

17Jul, 2020

Quantitative Aptitude: Probability Questions – Set 13

A bag contains 5 ruby balls and 7 black balls. Two balls are drawn at random without replacement, and then find the probability of that one is ruby and other is black?
35/66

41/69

36/68

30/60

None of these

Option A
(First ruby ball is drawn and then black ball is drawn) + (first black ball is drawn and then ruby ball is drawn)
(5/12)*(7/11)+(7/12)*(5/11) = 35/66
A bag contains 3 ruby balls and 8 blue ball and another bag contains 5 ruby balls and 7 blue balls, one ball is drawn at random from either of the bag, find the probability that the ball is ruby?
85/265

91/264

70/250

75/310

None of these

Option B
Probability=Probability of selecting the bag and probability of selecting ruby ball
(1/2)*(3/11) + (1/2)*(5/12) =91/264
X and Y are two persons standing in a circular arrangement with 10 more people. Find the probability that exactly 3 persons are seated between X and Y?
1/5

3/9

2/11

1/10

None of these

Option C
Fix X at one point then number of places where Y can be seated is 11.
Now, exactly three persons can be seated between X and Y, soonly two places where Y can be seated.
So, X = 2/11
12 friends are seated at a circular table. Find the probability that 3 particular friends always seated together?
4/52

5/50

2/15

3/55

None of these

Option D
Total probability=(12-1)! = 11!
Desired Probability = (10 – 1)! = 9!
So, Probability= (9! *3!) /11! =3/55
Find the probability that in a leap year, the numbers of Wednesday are 53?
2/7

1/7

3/7

4/7

5/7

Option A
In a leap year there are 52 complete weeks i.e. 364 days and 2 more days.
These 2 days can be SM, MT, TW, WT, TF, FS, and SS.
So Probablity of Wednesday = 2/7
Study the following and answer the questions:
A carton contains 6 ruby balls and 8 grey balls. Two balls are drawn at random one after one with replacement. What is the probability that both the balls are grey?
16/49

15/45

10/50

14/48

None of these

Option A
Probability = (8/14)*(8/14) = 64/196 =16/49
If the first one is grey and second one is ruby,find the following?
15/49

13/49

10/49

11/49

12/49

Option E
Probability = (8/14)*(6/14) =48/196=12/49
If the both the balls are ruby,find the following?
10/49

9/49

11/49

13/49

None of these

Option B
Probability = (6/14)*(6/14)=36/196=9/49
A carton contains 6 beige, 5 grey and 4 ruby balls. Two balls are drawn at random. What is the probability that there is no ruby ball?
10/21

2/50

3/15

11/21

None of these

Option D
Total balls in carton = 15
Not ruby ball means grey or beige ball i.e. any of (5+6) = 11 balls
So probability = 11C2 / 15C2 =11/21
There are 4 ruby balls, 5 white and 3 grey balls. 3 balls are chosen at random. What is the probability that there is at most 1 grey ball?
48/55

40/55

42/54

50/82

None of these

Option A

06

15Jul, 2020

Quantitative Aptitude: Ratio and Proportion Questions Set 4

Raksha went to buy a toffee worth Rs. x. He gave Rs.10 rupee note to the shopkeeper to buy the toffee then shopkeeper gave rest of the money in the denominations of 50 paise, 1 rupee, and 2 rupees. If the ratio of the number of coins is 4:2:1 respectively. Then what is the price of the toffee?
8

15

4

10

None of these10

Option C
Possible coins = (4, 2, 1) and (8, 4, 2)
If (4, 2, 1) = 0.50*4+2*1+1*2 =6
Cost of Toffee=10-6 =4
In a locality, there are ‘x’ persons. The expenditure of wheat per month is directly proportional to 4 times the square of the number of persons of the locality. If one of them left the locality there was a decrease in consumption of 28 kg wheat per month. Then initially how many persons were in the locality?
4

2

1

5

8

Option A
R1=4×2
R2 = 4(x-1)*2
R1-R2 =28= 2x-1
x =4
Three cheetahs X,Y and Z move in such a way that when X takes 7 steps, Y takes 8 steps and Z takes 9 steps. But 4 steps of X are equal to 5 steps of Y and 6 steps of Z. What is the ratio of their speeds?
32:35:42

25:28:30

30:35:40

35:32:30

None of these

Option D
X: Y: Z = 7:8:9
Size of step, 4X=5Y=6Z
ratio of speeds = 7/4 :8/5 :9/6
=35:32:30
Simran bought 108 earings. While carrying she dropped the earings down. By this, some of them were broken. What cannot be the ratio of broken and unbroken earings?
4:3

1:2

2:5

10:11

None of these

Option A
P,Q,R and S are four numbers if Q is more than P, S is 10 more than Q, R is 5 less than S, P is 10 less than R. Then ratio of P: Q: R: S is?
1:2:3:4

1:2:2:1

1:5:10:15

Cannot be determined

None of these

Option D
From the above values of P,Q,R and S,it cannot be determined.
An amount of sum is to be distributed among Priyal, Queen and Rashi in the ratio of 7:4:5 respectively. If the total share of Priyal and Rashi is 4 times the share of Queen, what is definitely Queen’s share?
500

1500

2500

Data is inadequate

None of these

Option D
Total sum is not given in the question.
If the ratio of X:Y is is 2:3 and that of the Y:Z is 5: 8, then which of the following is true?
Sum = 98; B = 50

Sum = 98; A = 20

Sum=100 : A=25

Sum =125;C=10

None of these

Option B
X:Y:Z = 10:15:24
If sum = 98, A = 10/49 * 98 = 20
The income of Vinayak and Priyanka are in the ratio of 4:5 and their expenditure is in the ratio of 2:3. If each of them saves Rs 5000, then find their income?
15000, 8750

10000,8000

11050,8548

13000,8500

None of these

Option A
4p – 2q = 5000 and 5p – 3q = 5000.
P = 8750, therefore income = 8750 and 15000.
A sum of Rs.4880 was divided among students of class A and class B in such a way that each student of class A gets Rs.44.50 and each student of Class B get Rs. 55.25. If the total number of class A and class B students is 100, find the number of class B students?
50

40

60

80

None of these

Option B
P+Q=100 —(i)
44.50 P + 55.25 Q = 4880 —(ii)
Solving (i) and (ii) ,we get Q = 40
An amount of sum is to be divided between Priyanka, Queen and Riya in the ratio of 3:7:12. If the difference between the shares of Priyanka and Queen is Rs.Z, and the difference between Queen and Riya’s share is Rs.3000. Find the total amount of sum?
11500

10100

13200

15000

None of these

Option C
12 c-7 c = 3000
5 c = 3000
c = 600
7 c- 3 c = Z
4 C = Z
4*600 = 2400
22* 600 = 13200

07

14Jul, 2020

Mixed Quantitative Aptitude Questions Set 214

Find the missing term in place of question mark (?) in the following number series:
8, 31, 67, 118, 187, ? , 401

341

305

279

275

None of these

Option C
8(+23) , 31(+36) , 67(+51) , 118(+69) , 187(+92) , 279 (+122) , 401
5 , 11 , 21 , 44 , ? , 175 , 347
81

75

55

86

None of these

Option D
5*2+1=11
11*2-1=21
21*2+2=44
44*2-2=86
86*2+3=175
175*2-3=347
123, 340, 724, 1324, ?

2186

2154

2245

2236

None of these

Option A
5^3-2=123
7^3-3=340
9^3-5=724
11^3-7=1324
13^3-11=2186
3, 8, 23, 76, ?
296

299

285

279

None of these

Option D
3*4-4=8
8*4-9=23
23**4-16=76
76**4-25=279
120, 133, 172, ?, 328, 445
280

289

255

237

None of these

Option D
120+13*1=133
133+13-3=172
172+13*5=237
237+13*7=328
328+13*9=445
What will come in place of the “x” in the following questions:
25% of 400 + 30% of 270 + 48% of 100 = x
229

225

249

236

None of these

Option A
(25/100)*400+(30/100)*270+(48/100)*100 = x
100+81+48=
√361 ×(4/40) 𝑜𝑓 80 + 1024 × 5 ÷ 4 = x
1409

1207

1205

1307

None of these

Option D
19+8+1024*5/4=x
19+8+1280=1307
x% of 400 ÷ 75 + (2/5) of 315 = 30% of 625
1355.15

1200.25

1168.25

1153.12

None of these

Option D
(4x/75)+(2/5)*315=(30/100 )*625
(4x/75)+126=187.5
(4x/75)=187.5-126
(4x/75)=61.5
x=1153.125
27% of 80 x 13.5 =?
288.5

291.6

295.9

300.5

None of these

Option B
68 × 24 – 2% of 1600 = ?²
40

35

45

50

65

Option A

08

12Jul, 2020

Quantitative Aptitude: Quadratic Equations Questions Set 68

In each of these questions, two equations (a) and (b) are given. You have to solve both the equations and give answer.
2m2+11m+14=0
4n2+12n+9=0
if m < n

if m > n

if m ≤ n

If m ≥ n

if m = n or no relation can be established

Option A
From eq (a),2m^2+4m+7m+14=0
2m(m+2)+7(m+2)=0
m= -2,-3.5
From eq (b),(2n+3)^2=0
n= -1.5 , -1.5
m^2 – 4 = 0
n^2 + 6n + 9=0
if m < n

if m > n

if m ≤ n

If m ≥ n

if m = n or no relation can be established

Option B
From eq(a),m = +-2
From eq(b), n^2 + 3n + 3n + 9=0
n = -3 ,- 3
m^2 – 7m + 12 = 0
n^2 + n -12=0
if m < n

if m > n

if m ≤ n

If m ≥ n

if m = n or no relation can be established

Option D
From eq (a), m^2 – 3m – 4m +12=0
m(m-3)-4(m-3)=0
m=3,4
From eq(b) , n(n+4) -3(n+4) = 0
n =3, -4
m^2 = 729
n = √529
if m < n

if m > n

if m ≤ n

If m ≥ n

if m = n or no relation can be established

Option E
m = +-27
n = 23
m^4 – 227 = 398
n^2 + 321 = 346
if m < n

if m > n

if m ≤ n

If m ≥ n

if m = n or no relation can be established

Option E
m^4 = 625 = +-5
n^2 = 346-321 =+-5
x^2 – 12p +35=0
q^2 – 25=0
if x > y

if x ≥ y

if x < y

if x ≤ y

if x = y or there is no relation between ‘x’ and ‘y’

Option B
From eq(a) , x^2 -7x – 5x +35 =0
x(x-7) – 5(x-7)=0
x= 5,7
From eq (b) ,y = 5 , -5
2x^2+5x -12=0
2y^2 -y – 1=0
if x > y

if x ≥ y

if x < y

if x ≤ y

if x = y or there is no relation between ‘x’ and ‘y’

Option E
From eq(a) , 2x^2+8x-3x-12=0
2x(x+4)-3(x+4)=0
x=1.5 , -4
From eq(b) , 2y^2 – 2y +y – 1=0
y = -0.5 , 1
x^2=49
y^2+15y+56 =0
if x > y

if x ≥ y

if x < y

if x ≤ y

if x = y or there is no relation between ‘x’ and ‘y’

Option B
x=7 , -7
y^2 + 7q + 8q + 56=0
y = – 7, -8
4x^2 – 4x+15=0
2y^2 +5y – 7=0
if x > y

if x ≥ y

if x < y

if x ≤ y

if x = y or there is no relation between ‘x’ and ‘y’

Option A
(x+y)^2 = 3136
y +2513 = 2569
if x > y

if x ≥ y

if x < y

if x ≤ y

if x = q or there is no relation between ‘x’ and ‘y’

Option C

09

9Jul, 2020

Quantitative Aptitude: Simplification Questions Set 96

Calculate the approximate value of the question mark (?) in the given questions:
149.88% of 19.89 + √360.81 × 3.98 = ? – 139.89
246

256

305

315

None of these

Option A
30 + 19*4 =x – 140
30 + 7+ = x – 140
x = 246
? + 1349.79 ÷ 4.99 – 124.89 = 120.10% of 1649.98
1765

1835

2135

1555

None of these

Option B
x+ 1350/5 – 125 = 120/100 * 1650
x + 270 – 125 = 1980
x + 145 = 1980
x = 1835
(?)² + 180.44 × 4.8 + 64.9 × 3.9 = 2384.88

55

45

35

40

None of these

Option C
x^2 + 180 * 5 + 65 * 4 = 2385
x^2 + 900 + 260 = 2385
x= 1225
?% of 299.98 = (21.09)² + (18.97)² + (6.15)^3 + 2.22
305

295

335

340

350

Option D
x/100 * 300 = 441 + 361 + 216 + 2
x/100 * 300= 1020
3 x = 1020
x = 340
?^3 × 19.98 + 15.05 % of 450.03 = (14.02)^2 + 5^√31.99
1

3

2

4

9

Option C
x^3 * 20 + 15/100 * 450 = 196 + 2
x^3 *20 + 67.5 = 198
x^3 *20 =130.5
x^3= 6.525
x=1.86 = 2
1575.23 / 45.09 + 25.05 * √255.85 = ?

435

440

395

405

515

Option A
1575 / 45 + 25 * 16
35 + 25 * 16
35 + 400 = 435
25 + 3.9 × 9.9 + 9.98 = ?
65

75

55

45

None of these

Option B
25 + 4 * 10 + 10 = ?
25 + 40 + 10 = ?
x = 75
(350 × 9.99) ÷ 5.4001 + 1245.20 = ?
1805

2455

2005

2105

1945

Option E
(350 * 10) /5 + 1245 = ?
3500/5 + 1245 =?
x = 1945
30.95² – 10.05² + (1987.29 + 24.85 ÷ ?) = 900
1

2

3

4

7

Option A
31^2 – 10^2 + (1987 + 25 / X) = 900
961 – 100 + (2012 /x) =900
861 x +2012 = 900
x = 1.29 = 1
140% of 3780 + 38.78% of 140 = ?
5001

5187

5487

5355

5347

Option E
140/100 * 3780 + 39/100 * 140 = x
5292 + 54.6 = x
5347 = x

10

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