1. What should come in place of question mark (?) in the following questions?

   A)25 , 38 , 64 , 103 , 155 , ?
   

   220
   195
   205
   225
   None ofthese
   Option A
   25(+13) , 38(+26) , 64 (+39) , 103 (+52) , 155 (+65) , 220

    

2. B) 1 , 5 , 11 , 19 , 29 , ?
   40
   41
   38
   45
   None of these
   Option B
   1*1+0=1
   2*2+1=5
   3*3+2=11
   4*4+3=19
   5*5+4=29
   6*6+5=41

    

3. C) 100 , 96 , 87 , 71 , 46 , ?
   8
   20
   10
   15
   None of these
   Option C
   100(-2^2) , 96(-3^2) , 87(-4^2) , 71(-5^2) , 46(-6^2), 10

    

4. D) 512 , ? , 216 , 25 , 64 , 9
   36
   343
   81
   49
   None of these
   Option D
   512(8^3) , 49(7^2) , 216(^3) , 25(5^2) , 64(4^3) , 9(3^2)

    

5. E) ? , 6 , 7 , 16 , 51 , 208
   12
   13
   15
   8
   None of these
   Option A
   12*0.5+0=6
   6*1+1=6
   7*2+2=16
   16*3+3=51
   51*4+4=208

    

6. What should come in place of question mark (?) in the following given questions(just calculate the approximate value) ?

   A) 0.049 ÷ 0.001 × 60.989 = 29.966% of 399.98 × ?

   25
   30
   32
   35
   20
   Option A
   49*61=(30/100)*400x
   2989=120x
   x=25

    

7. B) 1400 ÷ 35.0098 + √676 ×20.0801 = ?
   610
   500
   560
   540
   None of these
   Option C
   40 + 26 * 20
   40 + 520 = 560

    

8. C)0.5% of 356 + 0.7% of 779 = ?
   9
   7
   8
   5
   None of these
   Option B
   1.78 + 5.453 = 7

    

9. D) 119.97% of 1600.024 + 40.08% of 2000.001 = 2399.998 + 25.001% of ?
   1254
   1280
   1150
   1360
   1400
   Option B
   (120/100) *1600 + (40/100) *2000 = 2400 +(25/100) *x
   1920 + 800 = 2400 + 0.25x
   2720 = 2400 + 0.25x
   320 = 0.25 x
   x=1280

    

10. E) 0.12% of 400 + 0.15% of 880 = ?
    
    2
    1
    5
    8
    7
    Option A
    0.48 + 1.32 = 1.8

     

Solve the following questions and find the value that will come in place of ‘?’.

1. (0.2)^48 ÷ (0.04)^16 * (0.008)^2 = (0.2)?
   21
   22
   23
   24
   25
   Option B
   (0.2)^48 ÷ (0.04)^16 * (0.008)^2 = (0.2)?

   (0.2)^48 /(0.2)^32 * (0.2)^3 * 2 = (0.2)?

   (0.2)^48 – 32 + 6 = (0.2)?

   ? = 22

    

2. 80 % of 605 – 14.285 % of 420 + √1444 * √16 = ? * √576
   18
   19
   20
   21
   24
   Option E
   80 % of 605 – 14.285 % of 420 + √1444 * √16 = ? * √576

   484 – 60 + 152 = ? * 24

   24 = ?

    

3. 52 * 8 – 90 % of 40 = ? + 18 * √841
   -123
   -124
   -125
   -146
   -142
   Option E
   52 * 8 – 90 % of 40 = ? + 18 * √841

   416 – 36 = ? + 522

   ? = -142
   

    

4. 120% of 700 + 60% of 385 – ? = 37 * 19
   142
   236
   328
   368
   354
   Option D

   120% of700 + 60% of 385 – ? = 37 * 19

   840 + 231 – ? = 703

   ? = 368
   

    

5. 12.5% of 560 + 83.33% of 138 + 62.5% of 552 = ?
   458
   530
   450
   440
   238
   Option B
   12.5% of 560 + 83.33% of 138 + 62.5% of 552 = ?

   1/8 * 560 + 5/6 * 138 + 5/8 * 552 = ?

   70 + 115 + 345 = ?

   530 = ?

    

6. 13^2 + 15^2 + 11^2 =?
   234
   125
   656
   515
   575
   Option D
   ?= 169 + 225 + 121 =515

    

7. Simplify :43 * 37 + 54 * 46 =?
   4055
   4085
   4015
   4075
   4065
   Option D
   ?= (40 + 3)(40 – 3) + (50 + 4)(50 – 4)

   = 1600 – 9 + 2500 – 16

   = 4075

    

8. Simplify:2.25 * 16 + 5.25 * 8 =? + 83
   -5
   -15
   -25
   -35
   -10
   Option A
   ? + 75 = 36 + 42 = 78

   => ? = 78 – 83 = -5

    

9. 15% of 1080 + 25% of? = 182
   85
   80
   70
   82
   60
   Option B
   162 + 25% of ? = 182

   => 25% of ? = 182 – 162 = 20

   => ? = 20 * 100/25 = 80

    

10. 144 * 36 – 100 * ? = -1000
    61.84
    66.84
    65.84
    65
    61
    Option A
    144 * 36 – 100 *? =-1000

    => 100 x ? = 144*36 + 1000

    = 5184 + 1000 = 6184

    => ? = 61.84

     

1. P1 and P2 are the two pockets were made by mixing chilli powder and turmeric powder in the ratio 3:5 and 5:9 respectively.If 60 grams of P1 and x grams of P2 are mixed to get pocket P3, then fid out the value of x , if the ratio of chilli and turmeric in the new pocket P3 is 35:61?
   70g
   56g
   98g
   84g
   112g
   Option D
   In x gram of P2
   chilli = 5x/14
   turmeric= 9x/14
   in 60 gm in P1
   chilli=60 * 3/8= 45/2
   turmeric=60 85/8=75/2
   and =>(45/2 +5x/14) / (75/2+9x/14) = 35/61
   =>x= 84g

    

2. Rakesh bought a loan Rs.3,00,000 in a newyear scheme which gives r% per annum at Compound interest and this scheme doubles the loan in 72/r years which is double of the rate of interest given by the scheme.Find the total amount paid by Rakesh at the end of 48 years?
   12lac
   34lac
   45lac
   48lac
   64lac
   Option D
   given 72/r= 2r
   => r=6%
   So the loan amount double in 12 years.
   =>6,00, 000= 3,00,000 ( 1+ r/100 ) ^12
   =>1+ r/ 100 ) ^ 12= 2
   So required loan amount to pay = 3,00,000 ( 1+ r/100 ) ^ 48 = 3,00,000 *2^ 4 = Rs. 48,00,000

    

3. karthik and kathir’s current age is 7: 5 and 3 years back their ages were 16:11. So what is the age of kathir after 5 years?
   
   15
   25
   30
   40
   23
   Option C
   let their ages be 5x and 7x .
   so 7x-3/5x-3 = 16/11
   => x= 5
   Hence the age of kathir = 5* 5+ 5= 30 years

    

4. Person 1 started a business y investing Rs. A after 4 months person 2 also joined with the investment of Rs. x+ 10,000. But the end of the year their profit are same. Then what is the amount invested by person 2?
   20,000
   14,000
   15,000
   45,000
   30,000
   Option E
   p1 P2
   investment x x+10,000

   time 12 8
   12x 8x+ 80,000
   12x= 8x + 80,000
   =>x=20,000
   hence person 2 investment = 30,000

    

5. An house is on sale is said to 50% above its original price. But after the seller gives discount and gets only 20% profit. Find the percentage of discount ?
   10%
   20%
   30%
   40%
   50%
   Option B
   let the original price of the house = 100x
   Then said price= 100x * 150/100= 150x
   SP= 120x
   discount% = 30x/150x * 100 = 20%
   

    

6. If the sum of the speed of a boat upsteam and down stream is 36kmph and speed of the stream is 1/3 of the speed of the boat. Find the time taken to travel 108 km upstream and 96km downstream by the boat?
   10 hrs
   11 hrs
   12hrs
   13hrs
   14hrs
   Option D
   speed of boat =36/2= 18kmph
   speed of stream = 1/3 * 18 = 6kmph
   Time = 108/18-6 + 96/ 18+ 6
   =13hrs

    

7. Person A and Person B are 10 km apart. A can walk at an average speed of 2 km/hr and B at 3 km/h. If they start walking towards each other at 5:30 pm, when they will meet?
   
   7:30 pm
   7:30 pm
   10:30 pm
   9:30 pm
   6:30 pm
   Option A
   Suppose they will meet after T hours.
   Distance = Speed x Time
   Sum of distance traveled by them after T hours
   3T + 2T = 10 km
   T = 2 hours.
   So they will meet at 5:30 pm + 2 hours = 7:30 pm

    

8. Find the greatest possible length of scale which can be used to measure the iron bar 8m 3cm, 8m 34cm and 9m 30cm exactly.
   63cm
   64cm
   61cm
   62cm
   60cm
   Option D
   Required measure of scale = HCF of 803, 834 and 930
   = 62 cm

    

9. A seller marked an article at Rs 500 and sold it allowing 20% discount. If his profit was 25%, then the cost price of the article was
   
   Rs.310
   Rs.300
   Rs.320
   Rs.280
   Rs.330
   Option C
   ∵ Marked price of an article = 500
   ∴ SP of an article = 500 x (100 – 20)/100
   = (500 x 80)/100
   = 400

   Hence, cost price of an article = (400 x 100)/(100 + 25)
   = (400 x 100)/125
   = 320

    

10. Kajal traveled 12000 km by plane1 which formed (1/5) of his trip. One-third of the whole trip he traveled by plane2 And the rest of the journey he performed by plane3. The distance traveled by plane3 was ?
    20,000 km
    15,000 km
    18,000 km
    24,000 km
    28,000 km
    Option E
    Let the total distance be y km.
    Then, 1y / 5 = 12000
    ⇒ y = (12000 x 5) /1= 60000 km.

    Distance traveled by plane 2
    = (1/3 X 60000) = 20,000 km.

    Distance traveled by plane3
    = [60000- (20000 + 12000) ] km.
    = 28,000 km.

     

Directions: The following number series are based on a certain pattern. One number out of all is incorrect and does not follow the pattern. Find that odd one out.

1. 1000, 995, 999,9 80, 950, 830
   1000
   995
   999
   980
   950
   Option C
   1000 .. 995 .. 990 .. 980 .. 950 830

   – 5 .. 5 .. 10 .. 30 .. 120

   ….x 1 .. 2 .. 3 .. 4
   

    

2. 20, 25, 31.1, 38.4, 40, 57
   20
   25
   40
   57
   31.1
   Option C
   20 …. 25 …. 31.1 …. 38.4 …. 47 …. 57

   ……+ 5 …. 6.1 …. 7.3 …. 8.6 …… 10

   ………. + 1.1 …. 1.2 …. 1.3…. 1.4
   

    

3. 200, 184,164, 135, 90, 40
   200
   184
   164
   90
   20
   Option E
   200 184 164 135 90 20

   – 16 20 29 45 70

   + 2^2 3^2 4^2 5^2
   

    

4. 1, 1, 5, 70, 2000, 115500
   1
   5
   70
   2000
   115500
   Option D
   1 1 5 70 2100 115500

   x 1 5 14 30 55

   + 2^2 3^2 4^2 5^2
   

    

5. 15, 25, 36, 52, 70, 115
   15
   25
   36
   52
   70
   Option E
   15 25 36 52 77 115

   + 10 11 16 25 38

   + 1 5 9 13
   

    

6. 30, 31, 36, 41, 56, 87
   30
   31
   36
   41
   56
   Option C
   30 31 34 41 56 87

   + 1 3 7 15 31

   + 2^1 2^2 2^3 2^4
   

    

7. 300, 245 , 190, 160, 150, 175
   300
   245
   190
   160
   150
   Option C
   300 245 195 160 150 175

   – 55 50 35 10 -25

   -5 15 25 35
   

    

8. 10, 13, 21, 47, 84, 155
   10
   13
   21
   47
   84
   Option D
   10 13 21 42 84 155

   + 3 8 21 42 71

   + 5 13 21 29

   + 8 8 8
   

    

9. 20, 24.5, 30.5, 39.5, 53.5 , 72.5
   53
   20
   30.5
   24.5
   39.5
   Option A
   20 24.5 30.5 39.5 53 72.5

   + 4.5 6 9 13.5 19.5

   +1. 5 3 4.5 6

   + 1.5 1.5 1.5
   

    

10. 14, 34, 64 , 124, 262
    14
    34
    64
    124
    262
    Option D
    + 14 34 64 122 262

    + 20 3 0 58 140

    + 1+3^2 1+3^3 1+3^4
    

     

1. Latha and Vinoth are travelling from the cities A and B, Which are 120 km apart .Latha takes 1 hour more than Vinoth to reach the city B at a particular speed. If Latha doubles her speed the she will take 30 minutes less than Vinoth to reach the city B. Find the speed of Latha travels from the city A to B.
   120
   125
   135
   130
   100
   Option A
   Distance = 1200 km
   Let latha speed= x kmph.
   Let Vinoth speed= y kmph.
   then 120/ x – 120/ y = 1
   Also 120/y – 120/2x = ½
   Adding the above equations we get x= 120 kmph.
   

    

2. Mani started to his office from home at 7.a.m by car. After going a while his car repaired. He tried to restarted for 2 hrs and come back his home by walk at 1.p.m. If the car runs 10kmph and his walking speed is 1 kmph the what is the distance his car has repaired.
   
   1 1/3
   5 8/9
   4 5/9
   3 7/11
   2 1/7
   Option D
   Time between 7 a.m and 1.pm= 6hrs
   Time taken to walk = 6 – 2= 4 hrs
   Let the distance to be find = x kmph
   =>x/10 + x/1 = 4
   =>x= 40/ 11 = 3 7/11 Km

    

3. Three cars start its race in a circular stadium . First car completes round in 180 sec, second in 320 sec and third in 270 seconds. At what time they meet again at the starting point?
   
   3090
   4050
   3490
   5090
   5509
   Option B
   Required time =LCM ( 180, 320, 270)
   = 4050 sec
   

    

4. Sunil can beat manish by 200m race of 2km when they run at speed of 20m/sec and 16m /sec respectively. If Manish increases his speed by 14m /sec then how much time manish can won Sunil in the race of 2 km?
   
   95/2
   90/7
   100/3
   120/7
   96/3
   Option C
   = 2000/60 = 100/ 3 sec
   

    

5. A bus leaves from the bus depot at 5.pm at a speed 60km/hr towards bengaluru. After 3 hours another bus also leaves from the depot and follows the same direction of the first bus. In how much time will the second bus be 20km ahead of the first bus if the speed of the second bus is 70 km/hr?
   
   30
   20
   15
   20
   25
   Option D
   First Bus travels = 3 hours and distance = 3* 60 = 180 km
   Difference of two buses speeds = 70- 60 = 10km
   Distance ahead = 20 km/hr
   So 180+ 20= 200 km
   Required time = 200/10 = 20 hours
   

    

6. 8) A car can cover a distance of 72 km / hr in a uniform speed. Suppose if the car reduced its speed 12kmph it will take one hour more to to reach its destination. Find the initial speed of the car?
   
   37
   23
   65
   45
   36
   Option E
   Let x be the required speed to be find.
   72/ ( x-12) – 72/ x= 1
   =>x2-12x-864=0
   =>x2- 36x +24x-864=0
   =>( x+24) (x-36) =0
   =>x= 36 km
   

    

7. A cyclist can cross a street of 600 m in 9 sec. Find the speed of the cycle?
   
   8
   1
   5
   4
   3
   Option D
   Speed= 600 /( 9*60) = 600/ 540 m /sec
   = 600/ 540 * ( 18/5 ) = 4 kmph

    

8. If there is a hotels on a national highway which is 36 km apart , then find how many hotels will pass by the buses in 3 hours if the speed of the bus is 60 kmph.?
   
   2
   3
   5
   6
   4
   Option C
   distance travel by the bus = 60 * 3= 180 km
   Number of hotels= 180/ 36 = 5

    

9. In a reservation counter three phones ring at the intervals of 40 sec, 48 sec and 60 sec. If they ring at 10.30 a.m then at what time all the three phones ring
   together?
   
   10.10
   10.34
   10.40
   10.15
   10.20
   Option B
   Time taken to ring together = LCM( 40, 48, 60) = 240 seconds = 4 min
   If the phones ring together at 10.30 a. m, Then the next ring together after 4 minutes ie) 10.34. a.m.

    

10. Vinay want to travel to Delhi from Banglore. it’s 600 kilometre. If he opt for train , it takes twelve hour more than the flight. If the speed of the train is doubled ,it takes ten hours less than the flight. what’s the speed of the flight?
    250
    220
    230
    240
    200
    Option A
    Speed of the train = 600 / 12 = 50 km / hr
    If it speed doubled = 50 x 2 = 100 km/hr
    So 100 / 10 = 10 times increased.
    Then original time 12-10 = 2 hrs
    Therefore speed = 500 / 2 = 250 kmph .
    

     

1. The sum of ages of three brother born of the intervals of 2 years each is 42 years. What is the age of the youngest brother ?
   10
   12
   11
   8
   9
   Option B
   x+(x+2)+(x+4)=42 (given the intervals are 2 years)
   3x+6=42 
   x =36/2=12
    Age of the youngest brother=12 years
   

    

2. Cost of a table is Rs .5000 and selling price is Rs. 7000.What is the profit percent?
   20
   30
   40
   50
   25
   Option C
   Profit % = p/c.p x 100
   =2000/5000 x 100
   P%=40
   

    

3. Ganesh can do a task in 4days . Prem can do a task in 6 days. How long if will take if both Ganesh & Prem work together?
   1day 4hrs
   2day 4hrs
   2day 6hrs
   3day 4hrs
   4day 4hrs
   Option C
   Ganesh 1day work=1/4
   Prem 1day work =1/6
   (Ganesh+Prem) =1/4+1/6=5/12
   So Ganesh& Prem will complete in 12/5=2day 4hrs together.
   

    

4. If a boat travels with a speed 50km/hr in still water and the speed of stream is 10km/hrs . What would be the time taken by boat to go 80 km upstream?
   3
   2
   1
   4
   8
   Option B
   Upstream speed = x-y km/hr
   =50-10=40 km/hr
   T=distance/speed
   T=80/40=2hrs
   

    

5. what is the simple interest on Rs 60000 at 5 ½% per annum for 2 years?
   5000
   4500
   6600
   4000
   6500
   Option C
   S.I = P X R X T/100=60000 x 5 ½ x 2/ 100
   S.I=Rs 6600
   

    

6. Ram deposits Rs .20,000 for 2years with 5% compound interest. What amount will be get at last?
   Rs .12050
   Rs .22050
   Rs .20050
   Rs .13050
   Rs .15050
   Option B
   Amount= P x (1+r/100)n
   =20000 X (1+5/100)2
   =20000 x 105/100)2
   =20000x 105×105/10000
   =Rs .22050
   

    

7. A florist choose one rose at random from the basket which have rainbow colors of roses. what is the probability of choosing yellow color rose?
   1/5
   1/8
   1/9
   1/7
   1/4
   Option D
   S=(rainbow color roses)
   S=(V,I,B,G,Y,O,R)=N(S)=7
   P(Yellow rose)=P(S)/N(S)=1/7 (Only one yellow rose)
   

    

8. How many multiples of 2 are there in 10 to 80?
   34
   35
   36
   33
   40
   Option C
   Multiples of 2 =>last digits must be 0, 2, 4, 6, 8
   And first digit 1,2 ,3,4,5,6,7,
   So there are 7 choices for the first number and 5 choices for the second number.
   So there are 5x 7 =3 5 + 1= 36 (include 80) multiples of 2 in between 10 and 80.
   

    

9. In a shop two partners invested in the ratio 10:20 and they got the profits in the ratio 5:4.If the first partner invest the money for 10 months the how many months the second partner invested?
   15
   12
   17
   16
   18
   Option D
   Investment ratio: 10:20
   Profit ratio :5:4
   First partner invested 10 months.
   Second parner invested x (take) months.
   So 10 x 20 / 10 x x = 5/4
   20/x = 5/4
   x = 16 months
   

    

10. Two glasses of equal capacity contains sand and color powder.The ratio of the mixing is 2:3 and 5:4 respectively. These mixture are transferred into a big bowl.Then what is the ratio of sand and color powder in the bowl?
    1:2
    1:1
    1:3
    1:4
    1:6
    Option B
    Ratio= 2 + 5 : 3+4 = 7: 7= 1:1

     

1. The sum of ages of three brother born of the intervals of 2 years each is 42 years. What is the age of the youngest brother ?
   10
   12
   11
   8
   9
   Option B
   x+(x+2)+(x+4)=42 (given the intervals are 2 years)
   3x+6=42 
   x =36/2=12
    Age of the youngest brother=12 years
   

    

2. Cost of a table is Rs .5000 and selling price is Rs. 7000.What is the profit percent?
   20
   30
   40
   50
   25
   Option C
   Profit % = p/c.p x 100
   =2000/5000 x 100
   P%=40
   

    

3. Ganesh can do a task in 4days . Prem can do a task in 6 days. How long if will take if both Ganesh & Prem work together?
   1day 4hrs
   2day 4hrs
   2day 6hrs
   3day 4hrs
   4day 4hrs
   Option C
   Ganesh 1day work=1/4
   Prem 1day work =1/6
   (Ganesh+Prem) =1/4+1/6=5/12
   So Ganesh& Prem will complete in 12/5=2day 4hrs together.
   

    

4. If a boat travels with a speed 50km/hr in still water and the speed of stream is 10km/hrs . What would be the time taken by boat to go 80 km upstream?
   3
   2
   1
   4
   8
   Option B
   Upstream speed = x-y km/hr
   =50-10=40 km/hr
   T=distance/speed
   T=80/40=2hrs
   

    

5. what is the simple interest on Rs 60000 at 5 ½% per annum for 2 years?
   5000
   4500
   6600
   4000
   6500
   Option C
   S.I = P X R X T/100=60000 x 5 ½ x 2/ 100
   S.I=Rs 6600
   

    

6. Ram deposits Rs .20,000 for 2years with 5% compound interest. What amount will be get at last?
   Rs .12050
   Rs .22050
   Rs .20050
   Rs .13050
   Rs .15050
   Option B
   Amount= P x (1+r/100)n
   =20000 X (1+5/100)2
   =20000 x 105/100)2
   =20000x 105×105/10000
   =Rs .22050
   

    

7. A florist choose one rose at random from the basket which have rainbow colors of roses. what is the probability of choosing yellow color rose?
   1/5
   1/8
   1/9
   1/7
   1/4
   Option D
   S=(rainbow color roses)
   S=(V,I,B,G,Y,O,R)=N(S)=7
   P(Yellow rose)=P(S)/N(S)=1/7 (Only one yellow rose)
   

    

8. How many multiples of 2 are there in 10 to 80?
   34
   35
   36
   33
   40
   Option C
   Multiples of 2 =>last digits must be 0, 2, 4, 6, 8
   And first digit 1,2 ,3,4,5,6,7,
   So there are 7 choices for the first number and 5 choices for the second number.
   So there are 5x 7 =3 5 + 1= 36 (include 80) multiples of 2 in between 10 and 80.
   

    

9. In a shop two partners invested in the ratio 10:20 and they got the profits in the ratio 5:4.If the first partner invest the money for 10 months the how many months the second partner invested?
   15
   12
   17
   16
   18
   Option D
   Investment ratio: 10:20
   Profit ratio :5:4
   First partner invested 10 months.
   Second parner invested x (take) months.
   So 10 x 20 / 10 x x = 5/4
   20/x = 5/4
   x = 16 months
   

    

10. Two glasses of equal capacity contains sand and color powder.The ratio of the mixing is 2:3 and 5:4 respectively. These mixture are transferred into a big bowl.Then what is the ratio of sand and color powder in the bowl?
    1:2
    1:1
    1:3
    1:4
    1:6
    Option B
    Ratio= 2 + 5 : 3+4 = 7: 7= 1:1

     

Directions: The following number series are based on a certain pattern. One number out of all is incorrect and does not follow the pattern. Find that odd one out.

1. 1, 10, 63, 699, 9139
   1
   10
   63
   699
   9139
   Option D
   1 * 5 +5 = 10
   10*7 -7 = 63
   63 *11+11=704
   704*13-13=9139
   

    

2. 107, 423, 955, 1709 , 2660
   107
   423
   955
   1709
   2660
   Option E
   102 – 12 + 23 =107
   202 – 22 + 33 = 423
   302 – 32 + 43 = 955
   402 –42 + 53 = 1709
   502 – 52 + 63= 2691(not2660)
   

    

3. 14, 31, 65, 130, 269
   14
   31
   65
   130
   269
   Option D
   2*14 +3 = 31
   2* 31 +3= 65
   2*65+3= 133(not 130)
   2* 133 +3=269
   

    

4. 7, 10, 10, 5, -5, -28
   7
   10
   5
   -5
   -28
   Option D
   7+ 4^2 – 3^2 – 2^2 = 10
   10+ 5^2 – 4^2 – 3^2 =10
   5+ 6^2 – 5^2 – 4^2 = 5
   5+ 7^2 – 6^2 – 5^2 = -7(not -5)
   -7+ 8^2- 7^2- 6^2 = -28
   

    

5. 0, 28, 180, 648, 1520
   0
   28
   180
   648
   1520
   Option E
   1^3+ 3^3+0 = 28
   3^3 + 5^3 +28= 180
   5^3 + 7^3 +180= 648
   7^3 + 9^3 +648= 1720 (not 1520)
   

    

6. 200,190,156, 82 ,10, -338
   200
   190
   156
   82
   10
   Option E
   200- (12 + 32 ) = 190
   190 – (32 + 52 ) = 156
   1 56 –(52 + 72 ) = 82
   82 –( 72 + 92 ) = -48(not 10)
   -48 – (112 +1 32 ) = -338
   

    

7. 60 , 66 , 110 , 198, 264
   60
   66
   110
   198
   264
   Option C
   60 + 6= 66
   60+ 66+6=132 (not 110)
   60+ 132+6= 198
   60+198+6= 264
   

    

8. 20.5, 26.5, 29.5 , 19.5, 26.5
   20.5
   26.5
   29.5
   19.5
   26.6
   Option C
   20.5 + 7.5 – 1.5= 26.5
   26.5 + 5.5 – 2.5=29.5
   29.5+ 3.5 -3.5 = 29.5 (not 19.5)
   29.5 +1.5 – 4.5= 26.5
   

    

9. 84, 42.5, 41, 42.5, 17, 36.5
   84
   42.5
   41
   42.5
   17
   Option D
   84/2 +0.5 = 42.5
   42.5 -1.5 = 41
   84/2 +0.5 = 42.5
   41/2 -3.5 = 17
   84/2 +0.5 = 42.5(not 36.5)
   

    

10. 2, 12 , 8 , 6, 512, 4
    2
    12
    8
    6
    4
    Option E
    Odd place number = triple of previous odd place number
    Even place number = half of previous even place number
    

     

1. A water tank holds 50 gallons of water.Its inlet is 3.5 inch diameter and fills the tank at 2.5 gallons/ min. The outlet of the tank is twice the diameter of the inlet. How many minutes will it take to empty the tank if the inlet is closed, when the tank is fulled the outlet is opened?
   
   10
   12
   11
   15
   14
   Option A
   Since the ratio of flow is proportional to the diameter
   =>outlet flow = 2* 2.5 = 5 gallons/min
   So time taken by outlet pipe to be empty the tank = 50/5 = 10 min

    

2. Three pipes 1,2 and 3 can fill the tank in 30, 40 and 60 minutes respectively. If all the three pipes started to fill the tank in same time and the pipe 3 is closed before 12 minutes of the tank is filled. In what time the tank will be filled?
   
   23
   22
   21
   16
   20
   Option D
   Work done in last 12 minutes= 12( 1/ 30 + 1/40) = 7/10
   remaining work = 1-7/10 = 3/10
   ( 1+ 2+ 3) pipes one minute work = 1/30 +1/40 + 1/60 = 9/120 = 3/40
   So total number of minutes = 3/10 / 3/40 + 12=16 minutes.

    

3. Two pipes A and B can fill an empty tank in 16 hrs 24hrs respectively. Raja opens these two pipes at a time. After 8/3 hrs he comes back and sees there was a leak in the tank. He closed the leakage and so tank took 48/5 hours to be filled completely after closing the leak.Find at what time the leakage will empty the filled tank?
   9.6
   9.5
   9.3
   9.2
   9.1
   Option A
   let the leak can empty the tank in x hrs.
   So 8/3 hrs work of two pipes and leakage = ( 1/16 +1/24 – 1/x) *8/3
   =5/18 – 8/3x
   So remaining part= 1- 5/18 -8/3x= 13/18 + 8/3x
   =>x=9.6 hrs.

    

4. A pipe can fill the tank which is three time faster than another fill pipe. and 16 minutes less that one . Find when will the cistern will be filled if both the pipes are opened together?
   
   7
   6
   4
   3
   8
   Option B
   Let the first pipe takes x minutes to fill the cistern.
   Second pipe takes 3x minutes to fill the cistern.
   =>3x-x =16
   =>x=8 minutes=>3x= 3*8 = 24 minutes
   So both the pipe can fill 24* 8 / 24+8 = 6 minutes
   

    

5. A tank has two inlet pipes which fill the tank 24 minutes 30 minutes respectively and also there will be n outlet pipe.When all the three pipes are opened together it takes 40 minutes to fill the empty tank. How long will the outlet pipe take to empty the tank?
   
   14
   12
   20
   15
   16
   Option C
   Let the outlet pipe can empty the tank in x minutes.
   =>1/24 + 1/30 – 1/x= 1/40 => x=20 minutes.
   

    

6. A tank is 14m long and 8m wide. at what speed should water run through a rectangular pipe 10cm broad and 8 cm deep so that in 6hours 18 minutes water level in the tank raised in 9m?
   
   22
   16
   17
   20
   21
   Option D
   Volume of water flown = 14* 8* 9 =1008 m3
   Let the speed of the water be x km/hr
   =>( x * 1000 * 63/10 ) * 10/100 * 8/100 = 1008
   =>x=20km/hr
   

    

7. Two pipes can fill the tank in 20 hours and 32 hours respectively. a third pipe can empty the tank in 64 hours. If all the pipes are opened at a time the how much time will the tank takes to fill?
   
   7
   8
   9
   6
   5
   Option B
   Part of the tank filled in 1 hr = 1/20 + 1/32- 1/64 = 42/320
   =>tank be filled in 320/42 = 8 hrs (approx)

    

8. Three pipes A,B and C can fill an empty tank in 8 hrs, 12hrs, and 16 hrs respectively. They start filling together the tank.After 2hours pipe C gets closed and another two pipes continue to fill the tank.What is the total time the tank will be filled?
   
   6.7
   6.4
   6.5
   6.1
   6.3
   Option B
   Ratio of efficiency 1/8 :1/12:1/16
   =12:8:6
   Total work =96 ( LCM8,12,16)work done in 2 hrs= 2( 12+8+6)=52 units
   Remaining work= 96-52= 44 units
   So required time = 2+44/10 = 6.4 hours.
   

    

9. Two pipes can fill a tank in 30 hours and 40 hours respectively.While the third pipe can empty in 60 hours. If all the pipes are opened simultaneously, the empty tank will be filled in how much time?
   22
   21
   24
   26
   22
   Option C
   Total work done in one hour by all the pipes= 1/30 +1/40 -1/60
   =5/120 =1/24
   =>In 24 hours the tank wil be filled.

    

10. In a tank, water poured by pipe 1 reached 50% of the maximum marked level in one hour. Pipe 2 poured water and it reaches 12% of the remaining maximum level in the next hour.If the maximum capacity of the tank is 240ltr,Then how much water poured by pipe 2 in second hour?
    
    16
    13
    14.
    12.8
    14.4
    Option E
    Maximum level of water = 240ltr
    Pipe poured in first hour = 50% of 240ltr=120ltr
    Remaining water to be poured= 240 – 120 = 120ltr
    Pipe poured water in second hour =12% of 120 ltr = 14.4ltr
    

     

1. If sum of upstream and between downstream speed of a boat is 80 kmph , and the boat travels 90 km . upstream in 3hr Find the time taken by boat to cover 120 km downstream
   121/5 hr
   13/5 hr
   12/5 hr
   12/7 hr
   12/11 hr
   Option C
   let b= speed of the boat
   w= speed of water
   u= upstream speed= b-w
   d= downstream speed = b+w
   So u +d= 80
   that is b-w+b+w= 80
   =>b= 40
   40-w= 90/3 = 30
   w= 10 kmph
   b+w= 120/t
   t= 120/50 = 12/5 hr

    

2. The difference between simple interest and compound interest of a certain sum of money at 10 % per annum for 2 years is Rs. 40. Then the sum is ;
   Rs.5000
   Rs.4000
   Rs.6000
   Rs.7000
   Rs.8000
   Option B
   CI- SI = P ( r/100 ) ^2
   40 = p( 10/100) ^2
   => P= Rs.4000

    

3. Compound interest of a sum of money for 2 years at 4 percent per annum is Rs . 2500 Simple interest of the same sum of money at the same rate of interest for 2 years will be :
   Rs.2350
   Rs.2456
   Rs.2459
   Rs.2450
   Rs.2451
   Option E
   CI= P( 1+r/100 ) ^t – P
   2500 = P (( 1-4/100)^2 -1)
   => p= 2500 * 625 / 51=Rs. 30637.25
   SI= 30,637.25 * 4* 2/100=Rs.2451

    

4. The are two positive integers a and b . What is the probability that a + b is odd ?
   1/2
   1/3
   1/4
   1/5
   1/6
   Option A
   Sum of positive integers is either odd or even.
   So the probality = 1/2

    

5. Kailash sells apples at a loss of 44 % but he uses a false scale which is 30 % less than its true weight . Find the loss / gain percent ?
   21%
   22%
   20%
   23%
   24%
   Option C
   Let CP = Rs.100 for 100g
   So SP=Rs. 56 for 70g
   and SP =Rs. 80 for 100g
   loss%=100-80/100 * 100 = 20%

    

6. Average age of A ,B and C is 80 years . When D joins them the average age becomes 70 years . A new persons E, whose age is 4 years more than D replaces A and the average of B , C, D and E becomes 75 years . What is the age of A ?
   20 yrs
   21 yrs
   22 yrs
   23 yrs
   24 yrs
   Option E
   A+B+C = 3* 80 = 240 yrs
   A+B+C+D= 4* 70 = 280 yrs
   D age= 280-240 = 40yrs
   => E age= 40 + 4 = 44 yrs
   B+C+D+E age = 75* 4= 300 yrs
   B+C age = 300 – 40-44=216
   A age = 240-216=24 yrs

    

7. The population of sparrows in a particular locality is decreases by certain rate . If the current population of sparrows be 36450 and the ratio of decrease in population for second year and 3rd year be 10 : 9 . What was the population of sparrows 3 years ago ?
   50,000
   55000
   53,000
   52,000
   51,000
   Option A
   Ratio = 10:9
   => 10-9 /10 * 100 = 10%
   So p ( 1-10/100 ) ^3 = 36450
   p= 50,000
   

    

8. Tap A can fill a water tank in 25 minutes , tap B can fill the same tank in 40 minutes and tap C can empty the tank in 30 minutes . If all the three taps are opened together , In how many minutes will the tank be completely filled up or emptied ?
   31 3/10 minutes
   26 7/12 minutes
   34 11/19 minutes
   24 1/5 minutes
   31 11/19 minutes
   Option E
   A–> 25
   B—>40
   C—> -30
   Required answer = (25 x 40 x 30) / (40 x 30 + 25 x 30 – 25 x 40)
   == 600 / 19 = 31 11/19 minutes

    

9. A dog starts to chase a man . When the man goes 20 steps the dog moves 16 steps and 10 steps of the dog are equal to 14 steps of the man . The ratio of the speeds of the dog and the man is :
   28 : 25
   28 : 25
   28 : 25
   28 : 25
   28 : 25
   Option D
   dog : man
   Steps –> 16 : 20
   distance–> 14 : 10
   =224 : 300
   speed= 28 : 25

    

10. A train runs with a speed of 400 km/hour. What will be its speed in m/sec?
    112.11 m/sec
    111.11 m/sec
    113.11 m/sec
    115.11 m/sec
    117.11 m/sec
    Option B
    Speed in km/ hour =400

    Speed in m/sec = 400 x 5/18 = 500/9 m/sec = 111.11 m/sec

     

1. Two trains are running at 80kmph and 40 kmph respectively n the same direction. Fast train completely passes a man sitting in the slower train 10 seconds.What is the length of the fastest train?
   200
   222.22
   124.9
   300.3
   243.8
   Option B
   Relative speed= ( 80- 40 )kmph= 40 kmph
   = 40* 10/18 m /sec= 200/ 9 m/sec
   length of the fastest train= 200/9 * 10 = 2000/9 = 222.22 m
   

    

2. A hunter shoot a gun twice at an interval of 50 seconds. A passer in a bike moving towards the gun and hears the gun fire at an interval 48seconds. If the speed of the sound is 672 m/s then what is the speed of the bike?
   28
   24
   25
   26
   27
   Option A
   Distance travel by sound = 2 seconds = distance travel by the passer
    672 * 2 = S * 48
    =>S= 28 m/s
   

    

3. Three persons running clock wise around track and their time periods to run a circle are 2 min, 6 min, 10 min respectively. Find the time interval after which they meet for the first time at the starting point?
   20
   25
   30
   35
   33
   Option C
   LCM( 2, 6, 10) =30
   Hence every 30 minutes they will meet at starting point.
   

    

4. Two men can do a piece of work in x days. But y women can do it in 3 days . Then yhe ratio of the work done y 1 man and 1 woman is :
   2y:2x
   2y:4x
   5y:x
   3y:2x
   3y:5x
   Option D
   1 man’s 1 day’s work = 1/2x
   1 woman’s 1 day’s work = 1/3y
   So, Required ratio = 1/2x : 1/3y = 3y: 2x
   

    

5. Three persons are doing a piece of work for Rs. 600. First and third person are completes 38/ 46 of the work together . What is the amount got by the second person?
   104.35
   102.3
   108.9
   107.50
   115
   Option A
   Work done by the second person = 1- 38/46= 8/46
   Second person amount = 8/46 * 600 = Rs. 104. 35
   

    

6. Dal worth Rs. 126 per kg and Rs. 135 per kg mixed with the third variety in the ratio 1:1:2. And if the mixture dal is worth Rs. 153 per Kg, Then find out the cost of third variety per kg ?
   115.50
   175.50
   125.90
   150
   154.50
   Option B
   Let the cost of third variety will be Rs. x
   Then 126+ 135 + 2x / 4 = 153
   =>2x= 612-261=351
   =>x= Rs. 175.50
   

    

7. Shalu and Kala can complete a work in 6 days. They started together but after 4 days due to some problem kala left the work. If the work is completed after 4 more days, kala could do the work in how many days?
   3/11
   3/7
   3/8
   3/5
   3/12
   Option E
   ( two members) 4 days work = 4* 1/6 = 4/6
   Remaining work = 1-4/6= 2/6
   Shalu will complete 2/6 work in 4 days.
   Shalu will complete 1 work in 12 days.
   Shalu 1 day’s work = 1/12
   kala 1 day’s work = 2/6 – 1/12 = 3/12.

    

8. The respective ratio between the present ages of A and B is 6:11. Four years ago the ratio of their ages was 1:2, respectively. What will be B’s age after five years?
   45
   44
   46
   49
   43
   Option D
   Let the age of A= x
   Age of B= y
   =>x/y= 6/11
   =>x= 6y/11
   given x-4/ y-4 = ½
   =>2x-8 = y-4
   =>2 *6y/11 – 8 = y-4
   =>12y/11 – y = -4+8
   =>y = 44 yr
   Age of B after 5 years = 44 + 5 = 49 yr.
   

    

9. Arun can complete a piece of work in 12 days. Arun and Balu together can complete the same piece of work in 8 days .In how manys , can B alone complete the same piece of work?
   22
   23
   24
   25
   26
   Option C
   Arun’ s 1 days work = 1/12
   ( Arun + Balu) ‘ s 1 day’ s work = 1/8
   Balu’ s 1 day’s work = 1/8 – 1/12 = 1/24
   So balu can do the work in 24 days.
   

    

10. Person 1 can complete a piece of work in 24 days. Person 2 is 20% more efficient than Person 1. Person 3 is 25% more efficient than person2. In how many days Person 2 and 3 together can complete the same piece of work?
    5 1/5
    6 1/7
    8 8/9
    10
    15
    Option C
    Here, Person 1 can complete the work in 24 work in 24 days.
    Person 2 can complete the same work = 24/120 *100 = 20 days.
    C can complete the same work = 20/125 * 100 = 16 days
    So B and C can finish this work = ( 20* 16)/( 20+16) =320/36 = 8 8/9 days