Directions (1-5): The given bar graph shows the rate of interest per year by 4 various chit companies for deposits under three different plan (A, B and C).

1. Raj invested an amount in plan A of finance S for two years and he also invests the same amount in plan C of finance T for two years. If the total amount of simple interest accrued from the two plans is Rs.880, then what is the principal amount?
   1000
   1500
   2000
   2500
   3000
   Option C
   x * 12 * 2/100 + x * 10 * 2/100 = 880
   24x + 20x = 88000
   x = Rs. 2000
   

    

2. The finance U offers compound interest under plan B and finance V offer simple interest under plan B. What is the difference between the interests earned under these plans in two years, if the principal amount is Rs.8400?
   543
   445
   924
   876
   456
   Option C
   SI = 5 * 8400 * 2/100
   SI = Rs. 840
   CI = 8400 * (1 + 10/100)2 – 8400
   CI = Rs. 1764
   Required Difference = 1764 – 840 = Rs. 924
   

    

3. Sam invested his amount Rs.4500 for eight years with finance T under plan B which is offering simple interest and Prem invested Rs.6000 for three years with finance V under plan C which is offering compound interest. What is the difference between the interest earned by Sam and Prem?
   2112
   2008
   2432
   2002
   2080
   Option A
   Interest amount earned by Sam = 4500 * 18 * 8/100 = Rs. 6480
   Interest amount earned by Prem = 6000 * (1 + 20/100)3 – 6000
   = Rs. 4368
   Required Difference = 6480 – 4368 = Rs. 2112
   

    

4. Krupa invested Rs.3000 in finance S under plan C which is offering simple interest for 5 years and Rs.2000 in finance V under plan A which is also offering simple interest for 4 years, What is the total interest earned by Krupa?
   3000
   3210
   3120
   3222
   3111
   Option B
   Total interest = 3000 * 15 * 5/100 + 2000 * 12 * 4/100
   = 2250 + 960
   = Rs. 3210
   

    

5. The finance T offers compound interest under plan C and finance U offer simple interest under plan B. What is the difference between the interests earned under these plans in three years, if the principal amount is Rs.4800?
   123
   134.4
   148.8
   112.7
   126.9
   Option C
   Difference = P * r * r/100 * 100 * 100 * (300 + r)
   = 4800 * 10 * 10/100 * 100 * 100 * (300 + 10)
   = 48 * 310/100
   = Rs. 148.8
   

    

Directions (6-10): The bar graph shows the no. of Red, Blue and Pink color cars in a garage A, B, C, D and E



Line graph shows the probability of a green color car taken from each garage.



6. 
   If 25% of red car taken from garage A and added to garage E, then find the probability of taken two car both are pink colour in garage E
   105/1378
   10/1378
   105/137
   105/378
   16/1378
   Option A
   Garage A:
   Let us take the no. of green colour car be x
   Probability = xc1/(32+x)c1
   9/25 = x/(32+x)
   32*9 +9x = 25x
   16x = 32*9=> x= 18 green colour car
   Garage B:
   Let us take the no. of green colour car be x
   Probability = xc1/(34+x)c1
   3/20 = x/(34+x)
   3*34+ 3x = 20x
   =>3*34= 17x
   X= 6 green colour car
   Garage C:
   Let us take the no. of green colour car be x
   Probability = xc1/(40+x)c1
   1/5 = x/(40+x)
   =>40+x= 5x
   =>4x=40 =>x= 10 green colour car
   Garage D:
   Let us take the no. of green colour car be x
   Probability = xc1/(26+x)c1
   2/15 = x/(26+x)
   52+2x= 15x
   =>13x= 52
   => x= 4 green colour car
   Garage E:
   Let us take the no. of green colour car be x
   Probability = xc1/(40+x)c1
   1/5 = x/(40+x)
   =>40+x= 5x
   =>4x=40 =>x= 10 green colour car

   1) Answer: c)
   Total number of balls in garage E = [(12*25/100)+15] +10+15+10
   = 18+10+15+10
   = 53
   Required probability = 15c2/53c2 = (15*14)/(53*52)
   = 105/1378
   

    

7. If the total no of red colour car and pink colour car from all the garages (A, B, C, D and E) are taken out and filled in a new garage P, then 2 car taken out from garage P find the probability of different colours
   3869/78
   386/7875
   3869/7875
   369/7875
   318/7875
   Option C
   Total number of red colour cars in garage P = (12+8+10+8+15) = 53
   Total number of pink colour cars in garage P = (12+16+18+12+15) = 73
   Required probability = (53*73)/(53+73)c2
   = 53*73/(126*125/1*2) = 3869/7875
   

    

8. Four car taken from garage C, then find the probability of different colour
   216/2303
   216/230
   516/2303
   216/303
   200/2303
   Option A
   Required probability = (10*12*18*10)/50c4
   = (10*12*18*10)/(50*49*48*47/1*2*3*4)
   = (24*9)/(49*47)
   = 216/2303
   

    

9. Total number of balls in garage B and D together is approximately what percentage of the total number of balls in garage C and E together?
   40%
   70%
   60%
   75%
   80%
   Option B
   Required percentage
   = [(8+10+16+6+8+6+12+4)/(10+12+18+10+15+10+15+10)]*100
   = 70/100 * 100 = 70%
   

    

10. Two cars took randomly from garage B. What is the probability of at least one pink colour car?
    42/65
    42/63
    42/61
    42/67
    39/65
    Option A
    Required probability = 1- 24c2/40c2
    = 1 – (24*23/40*39)
    = 1- 23/65
    = 42/65
    

     

Directions (1-5): Find the wrong term in the series:-

1. 1.5.., 9.., 24.., 96.., 384.., 1536.
   1.5
   9
   24
   96
   384
   Option B
   1.5 * 4 = 6
   6 * 4 = 24
   24 * 4 = 96
   96 * 4 = 384

    

2. 18.., 20.., 19.., 22.., 22.., 24.., 27
   18
   20
   19
   22
   24
   Option E
   add 1, 2…… to the alternative terms.
   The wrong term is, 24

    

3. 11.., 12.., 25.., 76.., 304.., 1526
   11
   12
   25
   76
   304
   Option E
   11 * 1 + 1 = 12
   12 * 2 + 1 = 25
   25 * 3 + 1 = 76
   76 * 4 + 1 = 305
   305 * 5 + 1 = 1526
   1526 * 6 + 1 = 9157
   The wrong term is, 304
   

    

4. 90.., 86.., 95.., 79.., 103.., 68.., 117
   90
   86
   103
   68
   95
   Option C
   90, 86, 95, 79, 104, 68, 117
   -4 +9 -16 -25 +36 -49
   The difference is, – 22, + 32, – 42, – 52, – 62, – 72,…..
   The wrong term is, 103
   

    

5. 4.., 12.., 60.., 360.., 2520.., 20160
   4
   12
   60
   360
   2520
   Option A
   3 * 4 = 12
   12 * 5 = 60
   60 * 6 = 360
   360 * 7 = 2520
   2520 * 8 = 10160
   The wrong term is, 4
   

    

Directions (6-10): Find the number in place of ? in the following series


6. 1.., 16.., 81…, 256…, 625…, 1296.., ..?
   2401
   2210
   2230
   2300
   2450
   Option A
   The pattern of the series is 1^4, 2^4, 3^4, 4^4, 5^4……..

    

7. 14.., 17.., 15.., 18.., 16.., 19.., ?
   17
   18
   19
   21
   22
   Option A
   The pattern of the series is +3,-2, +3, -2………..

    

8. 7380.., 4428.., 2656.8.., 1594.08.., 956.448.., 573.87.., ?
   344.322
   233.55
   211.77
   322
   333.33
   Option A
   The pattern of the series is *3/5, *3/5, *3/5……………

    

9. 7.., 13.., 24.., 40.., 61.., ?
   78
   87
   88
   81
   80
   Option B
   The difference of difference is 5.

    

10. 1.6.., 16.., 192.., 2688.., ?.., 774144..
    43008
    44550
    42009
    32008
    46008
    Option A
    The pattern of the series is *10, *12, *14, *16……………

     

1. A shopkeeper gets a discount of 20% on an article and sells it at 10% profit. What is the profit percent if discount given is 60% ?
   107.5%
   127.5%
   147.5%
   143.5%
   117.5%
   Option C
   % profit = (100+10) [(100-10)/(100-60)] – 100 = 590/4 = 147.5%

    

2. Time taken by a train to cross a platform of length 60 km given that it crosses a pole in two and a half hours running at 60 km/hr
   2hrs
   2.5hrs
   3hrs
   1.5hrs
   3.5hrs
   Option E
   length of train = 2.5 * 60 = 150 km
   So time taken to cross platform of length 60 km with speed 60 km/hr
   = (150+60)/60 = 3.5hrs
   

    

3. Age of M five years ago if 6 years hence ratio of age of M to N will be 14: 11, and 1 year ago the ratio was 7: 5.
   12
   14
   15
   17
   19
   Option D
   (M+6)/(N+6) = 14/11
   And (M-1)/(N-1) = 7/5
   Solve the equations, M = 22, so 5 years ago = 22 – 5 = 17 years
   

    

4. Time taken by P to complete 1/5th of work if Q takes 6 days to complete 3/5th of work and together they take 5 days to complete 3/4th of work
   2
   3
   4
   5
   6
   Option C
   P and Q completes 3/4th work in 5 days, so complete 1 work in 4/3 * 5 = 20/3 days
   Q complete 3/5 work in 6 days, so complete work in 5/3 * 6 = 10 days
   So in 1 day P completes = 3/20 – 1/10 = 1/20
   So to complete 1/5th work = 1/5 * 20 = 4 days
   

    

5. Average age of 2 students included in a group of 5 students with average age 18 years given that addition of these 2 students in group makes average increase by 1.
   21.5 years
   20years
   8.5 years
   21 years
   11.5 years
   Option A
   Total age of 2 students added to group = 18*2 + 7*1 = 43
   So their average age = 43/2 = 21.5 years
   

    

6. What is the profit percent earned selling a product for Rs.30000, if the amount of profit earned on selling the product was Rs.10000?
   40
   50
   60
   70
   80
   Option B
   S.P = Rs.30000, C.P = 30000 – 10000 = Rs.20000

   Profit % = (S.P – C.P)/C.P * 100 = 1/20000 * (30000 – 20000) * 100 = 50%

    

7. If the selling price of the Sofa was twice the cost price, then what is the profit percent earned while selling that sofa for Rs.2000?
   110
   100
   90
   80
   70
   Option B
   C.P = S.P/2 = 2000/2 = Rs.1000

   Profit % = (S.P – C.P)/C.P * 100 = 1/1000 * (2000 – 1000) * 100 = 100%

    

8. Salaries of Ragu and Vaishu are in the ratio 2: 5. If the salary of each is increased by Rs.2000, the new ratio becomes 4: 9. What is Vaishu’s salary?
   45000
   35000
   25000
   15000
   5000
   Option C
   (2x + 2000)/ (5x + 2000) = 4/9

   => x = 5000

   R’s salary = Rs.10000 and V’s salary = Rs.25000

    

9. Find Cost price of a product when S.P is Rs.33 and profit is 10%?
   20
   30
   40
   50
   60
   Option B
   C.P = 100 * S.P/ (100 + Gain %)

   = 100 * 33/ (100 + 10) = Rs.30

    

10. Find Selling price of the product is when C.P is Rs.40 and loss is 25%?
    30
    50
    70
    90
    55
    Option A
    S.P = (100 – Loss %) / 100 * C.P

    = (100 – 25)/100 * 40 = Rs.30

     

1. Simplify: 6363 x 9999
   4545900
   63623637
   66623637
   63623666
   63623688
   Option B
   63630000 – 6363 = 63623637

    

2. 3034 – (1002/20.04)
   2984
   3490
   3345
   2345
   1234
   Option A
   3034/( 1002/20.04) = 3034 /( 1002/2004) x 100 = 3034- 50 = 2984

    

3. If 5^n =46625 then 5^ n-2 =?
   1865
   1123
   1456
   4356
   2378
   Option A
   5 ^n-2 = 5 ^n/ 5 ^2 = 46625/25 =1865

    

4. If (64 ^2) – (36^ 2) = 20 x X .Find the value of X?
   140
   456
   120
   320
   140
   Option E
   20 x X = (64 2) – (36 2)
   = ( 64 + 36) (64 -36) = 100 x 28 =2800
   X= 2800/20 =140
   

    

5. 57% of 501 -131.17 =? – 25%of 599
   366
   266
   566
   466
   166
   Option C
   57% of 501 -131.17 =? – 25%of 599
   57*500/100 -131 =? – 25 * 600/100
   285-131=? -150
   ?=566
   

    

6. √840.89 × 2.56 + 119.9% of 449.7 – 179.80% of 779.9 + 59.9% of 1800 = ?
   101
   202
   303
   404
   505
   Option C
   √841*3+120% of 450-180% of 780+60% of 1800=?
   29*3 +120/100 * 450 – 180/100 * 780 + 60/100 * 1800 =?
   87+540-1404+1080=?
   303=?
   

    

7. 24.67% of 779.56 + √3248.55× 11.98 + 864.76=?
   1744
   1675
   1677
   1355
   1789
   Option A
   25% of 780 + √3249 * 12 + 865=?
   195 + 684 + 865=?
   1744=?
   

    

8. 3(3/4) + 4(2/5) – 3(1/8) + 6(2/5) = ?
   15(57/40)
   10(57/50)
   10(54/40)
   11(57/40)
   10(57/40)
   Option E
   3(3/4) + 4(2/5) – 3(1/8) + 6(2/5) = ?
   (3+4-3+6) (3/4+2/5-1/8+2/5)=?
   10(57/40) = ?

    

9. 15.008% of 600.123 + 22.22 % of 650.005 + 147.112 = ?
   170
   560
   380
   234
   420
   Option C
   (15/100) * 600 + (22/100) * 650 + 147 = ?
   90 + 143 + 147 = ?
   380 = ?
   

    

10. 23.34 × 15.09 – 60.12 + (? ÷ 31.08) = 292.113
    431
    217
    230
    456
    112
    Option B
    285 + (? ÷ 31) = 292
    ? = 217
    

     

Directions (1-5): The given chart shows the percentage of expenditure of Francis, Shyam, Ragan, Emi and Tina in a family.Total Expenditure=Rs.20,000

1. What is the average amount of money spends by Ragan, Francis and Shyam together?
   2300
   4200
   3000
   2800
   4500
   Option B
   Required average
   = (35 + 10 + 18)/(3 * 100) * 20000
   = 4200
   

    

2. If the ratio of income to savings is 5:1, then what is the savings of the family?
   1000
   2000
   3000
   4000
   5000
   Option E
   Expenditure = 5x – x = 4x
   4x = 20000
   x = Rs.5000
   

    

3. If the family bought only watch and shirt for Shyam and the cost price of the watch is Rs.1200, then what is the cost price of shirt?
   500
   600
   700
   800
   900
   Option D
   Shyam = 10/100 * 20000 = Rs.2000
   CP of shirt = 2000 – 1200 = Rs.800
   

    

4. What is the difference between the amounts spends on Emi and Tina?
   2600
   2700
   2800
   2900
   3000
   Option A
   Difference = 25 – 12/100 * 20000 = Rs.2600

    

5. What is the central corresponding angle of Francis?
   114
   129
   112
   126
   131
   Option D
   Required angle = 360 * 35/100 = 126 degree

    

Directions (6-10): Total number of students in a school = 5500.



6. If half of the students in violet group are male then what is the percentage of girls ?
   330
   440
   880
   760
   445
   Option C
   Total no.of students = 5500 , violet = 32%,
   Half of violet =16%
   =>girls 16%, boys16%
   No.of girls 16% of 5500=880 .

    

7. What is the total number of students in yellow and red group?
   1265
   1345
   1556
   1445
   1765
   Option A
   no of students in yellow group 11 % of 5500 =605
   no of students in red group 12 % of 5500 =660
   total=1265
   

    

8. What is the ratio of students in green and blue group?
   4:13
   5:13
   9:13
   5:13
   4:12
   Option C
   no of students in green group 18 % of 5500 =990
   no of students in blue group 26 % of 5500 =1430
   ratio= 990:1430 = 99 :143=9:13
   

    

9. In each group 1% of students are selected as school volunteers .How many number of volunteers are there ?Approx
   55
   44
   42
   41
   50
   Option A
   No. of students in green group =990
   1% =9.9 = 10
   No. of students in red group =660
   1% =6.6 = 7
   No. of students in yellow group =605
   1% =6.05= 6
   No of students in blue group =1430
   1% =14.3= 14
   No. of students in violet group =1815
   1% =18.15 = 18
   So total volunteers = 10+ 7+ 6+ 14+18=55.

    

10. Rs. 5 is collected from red group for inaugural function. How much amount will be collected?
    3300
    2200
    4400
    2500
    5500
    Option A
    No .of students in red group =660
    Collected amount = 660x 5 = Rs.3300
    

     

Directions: The following series follow some pattern. Find the number in each series which does not follow that pattern and is unfit in the seies.

1. 96.., 46.., 72.., 180.., 630.., 2835
   96
   46
   72
   180
   630
   Option B
   96 * 0.5 = 48 (not 46)

   48 * 1.5 = 72

   72 * 2.5 = 180

   180 * 3.5 = 630

   630 * 4.5 = 2835

    

2. 42…, 86…, 348…, 2094…, 16758
   42
   86
   348
   2094
   16758
   Option E
   42 * 2 + 2 = 86

   86 * 4 + 4 = 348

   348 * 6 + 6 = 2094

   2094 * 8 + 8 =16760 (16758)

    

3. 48…, 1764…, 1632.., 2622…, 2530
   48
   1764
   1632
   2622
   2530
   Option E
   48 1764 1632 2622 2532
   +12^3-12 -11^2-11 +10^3-10 -9^2-9

    

4. 1582…, 1602…, 1634…, 1690…, 1782…, 1920
   1582
   1602
   1634
   1690
   1920
   Option E
   1582 1602 1634 1690 1782 1922

   20 32 56 92 140

   12 24 36 48

    

5. 124…, 63…64…, 130.., 524.., 4200.., 67214
   63
   64
   130
   524
   67214
   Option E
   124 * 0.5 + 1 =63

   63 * 1 + 1 = 64

   64 * 2 + 2 = 130

   130 * 4 + 4 = 524

   524 * 8 + 8 = 4200

   4200 * 16 + 16 = 67216 (not 67214)

    

Directions: The following series follow some pattern. Based on the same pattern find the number in place of (?) in each series.

6. 7512.., 3756…, 1252…, ?… , 62.6
   231
   313
   455
   320
   334
   Option B
   The pattern is, ÷ 2, ÷ 3, ÷ 4, ÷ 5,….
   The answer is, 313
   

    

7. 36…, 32…, 73…, 203…, 837…, ?..
   3210
   4149
   4500
   4677
   4433
   Option B
   The pattern is, *1 – 22, *2 + 32, *3 – 42, *4 + 52, *5 – 62,….
   The answer is, 4149
   

    

8. 3278…, 5384…, 6086…, 6320…, ?… , 6424
   5678
   6740
   6398
   5566
   6889
   Option C
   3278 5384 6086 6320 6398 6424
   2106 702 234 78 26
   The difference is, ÷ 3
   The answer is, 6398
   

    

9. 819…, 818…, 408…, 135…, ?..
   31
   31.5
   32
   32.75
   33
   Option D
   The pattern is,
   (819 – 1)/1 = 818
   (818 – 2)/2 = 408
   (408 – 3)/3 = 135
   (135 – 4)/4 = 32.75
   The answer is, 32.75
   

    

10. 1276…, 1280…, 1296…, 1360…, ?… , 2640
    1212
    1313
    1414
    1515
    1616
    Option E
    The pattern is, +4^1, +4^2, +4^3, +4^4,….
    The answer is, 1616
    

     

1. Harish sold a chair for Rs. 2000 and incurred a loss. Had harish sold the item for Rs. 3600, his gain would have been equal to three times of the amount of loss that he incurred. At what price should he sell the chair to gain 20 %?
   Rs. 2880
   Rs. 4480
   Rs. 5280
   Rs. 9080
   Rs. 6080
   Option A
   Loss = C.P – 2000
   Profit = 3600 – C.P
   Profit = 3*Loss
   3600 – C.P = 3 * [C.P – 2000]
   3600 – C.P = 3C.P – 6000
   9600 = 4C.P
   C.P = 9600/4 = Rs. 2400
   SP = 2400 * (120/100) = Rs. 2880
   

    

2. The sum of lengths of Sadhapthi express and Rajdhani express is 640 m. The speed of train Sadhapthi to that of Rajdhani is in the ratio of 3 : 4. The time taken by Sadhapthi express and Rajdhani express to cross an electronic pole is in the ratio of 4 : 5. Find the difference between the length of the two expresses?
   120
   140
   160
   180
   200
   Option C
   Let the length of Sadhapthi express be x m,
   So, the length of Rajdhani express = 640 – x
   The speed of Sadhapthi to that of Rajdhani is in the ratio = 3 : 4 (3y, 4y)
   Time = Length of train / Speed
   4 = x / 3y
   x = 12y -> (1)
   (640 – x) / 4y = 5
   640 – x = 20y
   640 – 12y = 20y
   640 = 32y
   y = 20
   The length of Sadhapthi = x = 12 * 20 = 240 m
   The length of Rajdhani = 640 – x = 640 – 240 = 400 m
   Required difference = 400 – 240 = 160 m
   

    

3. The speed of the ship in still water is 36 km/hr and the speed of stream is 12 km/hr. The time taken by ship to travel from A to B downstream is 3 ½ hours less to travel from B to C upstream. If the distance between A to B is 24 km more than the distance between B to C, then find the distance between A to B?
   200
   145
   210
   216
   234
   Option D
   The speed of downstream = 36 + 12 = 48 km/hr
   The speed of upstream = 36 – 12 = 24 km/hr
   Let the distance between B to C be x km,
   The distance between A to B = (x + 24) km
   Given,
   x / 24 – (x + 24) / 48 = 7/2
   (2x – x – 24) / 48 = 7/2
   x – 24 = 168
   x = 192
   The distance between A to B = x + 24 = 192 + 24 = 216 km
   

    

4. Person 1 and person 2 are 585 km away and both of them start moving towards each other at the same time. After some time when person 1 has travelled 360 km he meets Person 2. What is the ratio of the speed of person 1 to that of person 2?
   2:3
   4:5
   2:5
   1:4
   None of these
   Option
   

    

5. A mixture of oil and water in a jar contains 32 liters oil and 10 liters water. A liter of oil and A liter of water is added to a new mixture. If 40 % of new mixture is 24 liters, then find the value of X (In liters)?
   5
   7
   9
   11
   13
   Option C
   (40/100) * New mixture = 24
   New mixture = 24 * (5/2) = 60 liters
   Given,
   32 + A + 10 + A = 60
   42 + 2A = 60
   2A = 18
   A= 9
   

    

6. 5 years ago, the age of Person 1 and 7 years hence, the age of Person 2 is in the ratio of 1: 2. 5 years hence, the age of Person 1 and Person 2 is in the ratio of 15: 19. Find the present age of Person 2?
   34
   33
   32
   31
   30
   Option B
   5 years ago, the age of Person 1 and 7 years hence, the age of Person 2 is in the ratio = 1 : 2 (x, 2x)
   Present age of Person 1 and Person 2 = x + 5, 2x – 7
   5 years hence, the age of Person 1 and Person 2 is in the ratio = 15 : 19
   By question,
   = > (x + 5 + 5) / (2x – 7 + 5) = (15/19)
   = > (x + 10) / (2x – 2) = (15/19)
   = > 19x + 190 = 30x – 30
   = > 11x = 220
   = > x = 20
   The present age of Person 2 = 2x – 7 = 33 years
   

    

7. Three men started a business by investing Rs. 30000, Rs. 40000 and Rs. 50000 respectively. Man 1 is a working partner and Man2 and Man 3 is a sleeping partner in a business. For managing the business, Man 1 will get 10 % of profit and the remaining will be shared by three of them. Find the difference between the share of Man 1 and Man 2, if the total profit at the end of the year is Rs. 92000?
   2300
   2100
   2500
   3400
   3330
   Option A
   Man 1 get = 92000 * (10/100) = Rs. 9200
   Remaining = 92000 – 9200 = Rs. 82800
   The share of three,
   = > 30000 : 40000 : 50000
   = > 3 : 4 : 5
   12’s = 82800
   1’s = 6900
   The share of Man1 = 9200 + (3 * 6900) = Rs. 29900
   The share of Man 2 = (4 * 6900) = Rs. 27600
   Required difference = 29900 – 27600 = Rs. 2300
   

    

8. Makesh got compund interest on a certain sum for 3 years at 15 % per annum is Rs. 20835, then find the corresponding simple interest he got for the same sum?
   12000
   16000
   18000
   20000
   22000
   Option C
   Let the sum of money be x,
   x * [(1 + (15/100))3 – 1] = 20835
   x * [(115/100)3 – 1] = 20835
   x * [(12167/8000) – 1] = 20835
   x * (4167/8000) = 20835
   x = 20835 * (8000 / 4167) = Rs. 40000
   Corresponding SI:
   SI = (40000 * 3 * 15) / 100 = Rs. 18000
   

    

9. 8 Males and 6 Females can do a work in 12 days. 10 males and 6 females can do the same work in 10 days. How long will 12 males and 8 females can take to do the work?
   7 2/11
   5 2/11
   10 2/11
   8 2/11
   4 2/11
   Option D
   Total work = (male (or) female) * days
   Work equal. So,
   (8 m + 6 f) * 12 = (10 m + 6 f) * 10
   48 m + 36 f = 50 m + 30 f
   6 f = 2 m
   3 f = 1 m
   8 m + 6 f = 24 f + 6 f = 30 f
   12 m + 8 f = 36 f + 8 f = 44 f
   Female days
   30 12
   44 ?
   (30 * 12) = (44 *x)
   x = (30 * 12) / 44 = 8 2/11 days
   

    

10. Lara thrown two dice simultaneously. Find the difference of the dice is divisible by 3?
    5
    6
    7
    3
    1
    Option B
    Possibilities of getting the difference of the dice is divisible by 3
    = > (1, 4), (2, 5), (3, 6), (4, 1), (5, 2), (6, 3) = 6
    

     

Directions: The following questions are accompanied by three statements I, II and III. You have to determine which statement/s is/are sufficient to answer the question.

1. What is the amount invested by A?
   Statement I: Total amount received by B after 3 years is Rs.4800 at compound interest.
   Statement II: B and A invested their amount at the rate of 10% per annum.
   Statement III: A and B invested their amount at simple interest and compound interest respectively and the difference between the interests received by both after 2 years is Rs.1200.
   
   Only I and II are sufficient
   Only II and III are sufficient
   Either II alone or I and II together to sufficient
   All I, II and III necessary to the answer the question
   The question can’t be answered even with all I, II and III
   Option E
   From statement I,
   Let the amount invests by B = x
   4800 = x * (1 + R/100)^3
   So, Statement I alone is not sufficient to answer the question.
   From statement II,
   R = 10%
   So, Statement II alone is not sufficient to answer the question.
   From statement III,
   Let the amount invests by A = x
   Let amount invests by Bl = y
   SI = y * 2 * R/100 = yR/50
   CI = x * (1 + R/100)2 – x
   CI – SI = 1200
   or
   SI – CI = 1200
   So, Statement III alone is not sufficient to answer the question.
   

    

2. What is the sum of the ages of person 1 and 2?
   Statement I: Ratio of the ages of 1 to 3 is 4: 5 and the ratio of the ages of 1 to 4 is 1: 3.
   Statement II: Sum of the ages of 2,3 and 4 is 125 years and 5 years ago the ratio of the ages of 1 to 4 is 3: 11.
   Statement III: 4’s age is 200% more than that of 1’s age and the difference between the ages of 1 and 4 is 40 years.
   
   Only I and II are sufficient
   Only II and III are sufficient
   Either II alone or I and II together to sufficient
   All I, II and III necessary to the answer the question
   The question can’t be answered even with all I, II and III
   Option A
   From statement I,
   p1/p3 = 4/5
   p1/p4 = 1/3
   So, Statement I alone is not sufficient to answer the question
   From Statement II,
   p2 + p3 + p4 = 125
   (p1 – 5)/(p4 – 5) = 3/11
   So, Statement II alone is not sufficient to answer the question
   From statement III,
   p4 = 300/100 * p1
   p4: p1 = 3: 1
   2x = 40
   x = 20
   p1= 20 years
   p4 = 3 * 20 = 60 years
   So, Statement III alone is not sufficient to answer the question
   From statement I and II,
   p1 and p4’s present age be x and 3x respectively
   (p1 – 5)/(p4 – 5) = 3/11
   (x – 5)/(3x – 5) = 3/11
   = > 11x – 55 = 9x – 15
   = > 2x = 40
   = > x = 20
   Present age of p1 and p4 is 20 and 60 years respectively
   p3’s present age = 20/4 * 5 = 25 years
   p2’s present age = 125 – (25 + 60) = 125 – 85 = 40 years
   Sum of the ages of p1 and p2 = (20 + 40) = 60 years
   Hence, statement I and II alone is sufficient to answer the given question.
   

    

3. What is the total surface area of the conical box?
   Statement I: Ratio of height of the box to height of the cylindricall box is 2: 1.
   Statement II: Height of the cylindrical box is equal to the perimeter of the square whose area is 9 cm2.
   Statement III: Radius of the cone is equal to length of the rectangle whose perimeter is 20 cm.
   
   Only I and II are sufficient
   Only II and III are sufficient
   Either II alone or I and II together to sufficient
   All I, II and III necessary to the answer the question
   The question can’t be answered even with all I, II and III
   Option E
   Height of cone/height of the cylinder = 2/1
   So, Statement II alone is not sufficient to answer the question
   From statement II,
   Area of the square = 9
   Side of the square = 3
   Perimeter of the square = 3 * 4 = 12 cm
   Height of the cylinder = 12 cm
   So, Statement II alone is not sufficient to answer the question
   From statement III,
   Radius of the cone = length of the rectangle
   Perimeter of the rectangle = 2 * (l + b) = 20
   So, Statement III alone is not sufficient to answer the question
   

    

4. There are four members p1, p2, p3 and p4 partners in the business. What is the profit share of p2?
   Statement I: p1 and p2 started the business with investment of Rs.x and Rs.2x respectively and after 6 months p3 and p4 joined them with investment of Rs.(x + 1000) and Rs.3x respectively.
   Statement II: At the end of one years and profit Share of p3 is Rs.4000.
   Statement III: At the end of one year the profit ratio of p3 and p4 is 2:3.
   
   Only I and II are sufficient
   Only II and III are sufficient
   Either II alone or I and II together to sufficient
   All I, II and III necessary to the answer the question
   The question can’t be answered even with all I, II and III
   Option D
   From statement I,
   p1= x
   p2 = 2x
   p3= (x + 1000)
   p4 = 3x
   So, Statement I alone is not sufficient to answer the question
   From Statement II,
   p3’s share = Rs.4000
   So, Statement I alone is not sufficient to answer the question
   From statement III,
   Profit ratio of p3/p4 = 2/3
   So, Statement III alone is not sufficient to answer the question
   From I, II and III
   Profit ratio of p1, p2, p3 and p4 = x * 12: 2x * 12: (x + 1000) * 6: 3x * 6
   =12x: 24x: (6x + 6000): 18x
   (6x + 6000)/18x = 2/3
   6x + 6000 = 12x
   x = 1000
   Profit ratio = 12000: 24000: 12000: 18000
   = 2: 4: 2: 3
   p2’s profit share = 4/2 * 4000 = 8000
   All the statements are necessary to answer the question.
   

    

5. What is the initial quantity of the juice in vessel A?
   Statement I: Ratio of the juice and water in vessel A and B is 3: 2 and 4: 3 respectively.
   Statement II: 28 liters of the mixture of B is poured into A and then the ratio of the juice and water in vessel A becomes 17: 12.
   Statement III: 10 liters of the mixture from vessel C is taken out and is poured into vessel A, then the ratio of the juice to water becomes vessel A is 5: 4.
   Only I and II are sufficient
   Only II and III are sufficient
   Either II alone or I and II together to sufficient
   All I, II and III necessary to the answer the question
   The question can’t be answered even with all I, II and III
   Option A
   From statement I,
   juice and water in A = 3: 2
   juice and water in B = 4: 3
   So, Statement I alone is not sufficient to answer the question
   From statement II,
   Vessel B mixture = 28
   Ratio of the juice and water in A = 17: 12
   So, Statement II alone is not sufficient to answer the question
   From statement III,
   Mixture of C = 10
   Ratio of juice and water in C = 5: 4
   So, Statement III alone is not sufficient to answer the question
   From I and II
   juice in 28 liters of B = 4/7 * 28 = 16 liters
   Water in 28 liters of B = 3/7 * 28 = 12 liters
   3x + 16/2x + 12 = 17/12
   34x + 204 = 36x + 192
   2x = 12
   x = 6
   juice in vessel A = 3 * 6 = 18 liters
   So, Statement I and II are necessary to answer the question.

    

Directions: The following questions are accompanied by three statements I and II. You have to determine which statement/s is/are sufficient to answer the question.


6. What is the difference between the total number of employees from A in all the three years together and the number of males from Company A in three years together?
   Statement I: The ratio of the number of males to females from Company A in 2015 is 3:2 and the number of females from company A in 2014 is 20 more than that of the number of males from A in 2016.
   Statement II: If the total number of employees from company A in 2014, 2015 and 2016 60%, 40% and 50% respectively are females.
   
   Only I
   Only II
   Either I or II sufficient
   All I and II necessary to the answer the question
   The question can’t be answered even with all I and II
   Option B
   From statement I,
   Females from A in 2015 = 2/5 * 250 =100
   Males from A in 2015 = 3/5 * 250 =150
   So, Statement I alone is not sufficient to answer the question.
   From statement II,
   Females from A in 2014 = 60/100 * 400 = 240
   Males from A in 2014 = 400 – 240 = 160
   Females from A in 2015 = 40/100 * 250 = 100
   Males from A in 2015 = 250 – 100 = 150
   Females from A in 2016 = 50/100 * 300 = 150
   Males from A in 2016 = 300 – 150 = 150
   Total number of employees from A = 400 + 250 + 300 = 950
   Males from A = 150 + 150 + 160 = 460
   Difference = 950 – 460 = 490
   So, Statement II alone is sufficient to answer the answer.
   

    

7. What is the ratio of the males to females from company C in 2014?
   Which of the following statement is sufficient to answer the question?
   
   Ratio of the males to females from company A and B in 2014 is 1: 3 and 2: 1 respectively and total employees in 2014 from all the companies together 60% are females.
   The number of females from C in 2014 is half of the number of males from B in 2015.
   Ratio of the number of males to females from C in all the years together is 3: 2 and the 50% of the employees from C in 2015 is females.
   40% of the employees from C in 2014 is left and in this 80% of the employees is girl
   Cannot be determine
   Option A
   From option (A)
   Females from A in 2014 = 400 * ¾ =300
   Females from B in 2014 = 1/3 * 300 =100
   Number of females in 2014 = (400 + 300 + 200) * 60/100 = 540
   Number of females from C in 2014 = 540 – 300 – 100 = 140
   Number of males from C in 2014 = 200 – 140 = 60
   Required ratio = 60: 140 = 3: 7
   This satisfied the given condition.
   From option (B)
   Number of males from B in 2015 is not given
   This not satisfied.
   From option (C)
   Number of females from C in 2015 = 300 * 50/100 = 150
   we cannot find the answer of the question.
   This not satisfied.
   From option (D)
   Number of employees left from C in 2014 = 200 * 40/100 = 80
   Number of females left from C in 2014 = 80 * 80/100 = 64
   This not satisfied the given condition.
   

    

8. Number of females from B in all the years together is what percent of the total number of employees from B in all the years together?
   Statement I: Total number of employees from B in 2017 is 280 and the ratio of the number of females to males from B in 2017 is 4: 3.
   Statement II: 60% of the total number of employees from B in 2014 to 2017 is males.
   
   Only I
   Only II
   Either I or II sufficient
   All I and II necessary to the answer the question
   The question can’t be answered even with all I and II
   Option D
   From statement I,
   Number of females from B in 2017 = 4/7 * 280=160
   Number of males from B in 2017 = 3/7 * 280=120
   So, statement I alone is not sufficient to answer the question.
   From statement II,
   60% of the total number of employees from B in 2014 to 2017 is males.
   So, statement II alone is not sufficient to answer the question.
   From I and II,
   Total number of employees from B in 2014 to 2017 = 300 + 100 + 350 + 280 = 1030
   Number of males from B in 2014 to 2017 = 1030 * 60/100 = 618
   Number of males from B in 2014 to 2016 = 618 – 120 = 498
   Number of females from B in 2014 to 2016 = (300 + 100 + 350) – 498 = 252
   Required percentage = 252/750 * 100 = 33.6%
   Both the statements are necessary to answer the question.
   

    

9. Ratio of the males to females from A, B and C in 2016 is 7: 8, 4: 3 and 2: 3 respectively and the ratio of total number of males from A, B and C in 2017 to the number of males from A, B and C in 2016 is 1: 2. Total number of employees from A, B and C in 2017 is 360.
   From the statement given in the above question which of the following can be determined.
   
   Number of females from A, B and C in 2017
   Average number of males from C in 2014 to 2017
   Ratio of number of males to females from A, B and C in 2017
   Difference between the number of females and males from all the three companys in all the years together (2014, 2015, 2016 and 2017) a) Only A b) Only A and D c) Only A, C and D d) Only A and C e) All A, B, C and D
   sum of males and females
   Option C
   Number of males from A in 2016=7/15 * 300=140
   Number of females from A in 2016=8/15 * 300=160
   Number of males from B in 2016=4/7 * 350=200
   Number of females from B in 2016=3/7 * 350=150
   Number of females from C in 2016=3/5 * 150=90
   Number of males from C in 2016=2/5 * 150=60
   Number of males in 2016=140 + 200 + 60=400
   Number of males in 2017=1/2 * 400=200
   Number of females in 2017=360 – 200=160
   Required ratio males to females in 2017 = 200: 160=5:4
   

    

10. 40% of the employees from C in all the years together is females and the number of males from C in 2015 and 2016 is 180 and 80 respectively. What is the ratio of the number of females from C in 2014, 2015 and 2016?
    7:12:7
    5:14:5
    3:17:5
    2:17:9
    1:7:9
    Option A
    Number of females from C in 2015 = 300 – 180 = 120
    Number of females from C in 2016 = 150 – 80 = 70
    Total number of females from C = (200 + 300 + 150) * 40/100 = 260
    Number of females from C in 2014 = 260 – 120 – 70 = 70
    Required ratio = 70: 120: 70
    = 7: 12: 7

     

1. In a total monthly income of Kiran spends 25% of his income on Rent and 20 % on travelling expenses. 40 % of the remaining income for food and while the remaining income is saved which is equal to Rs. 16500, then find his actual income?
   Rs. 50000
   Rs. 54000
   Rs. 40000
   Rs. 30000
   Rs. 35000
   Option A
   X * (25 + 20)/100 * (60/100) = 16500
   X*(55/100)*(60/100) = 16500
   X = 16500*(100/55)*(100/60)
   X = Rs. 50000
   

    

2. Sai gave 65% of the amount he had to Ria. Ria gave 2/5th of what he received from Sai to Suma. After paying Rs. 320 to the taxi driver out of the amount he gets from Ria, Suma is now left with Rs. 1500. How much amount did Sai have?
   5000
   6000
   7000
   8000
   9000
   Option C
   Let Sai’s amount be x,
   Suma now having the amount of 1500,
   =>(x*(65/100)*(2/5)) – 320 = 1500
   = > x*(65/100)*(2/5) = 1820
   = > x= 1820*(100/65)*(5/2) = Rs. 7000
   Sai initially having an amount of Rs. 7000
   

    

3. In a city 62% of the population is men and remaining are women. Out of the men 74% are educated and remaining is uneducated. Out of women 65% are educate and remaining is uneducated. If total number of uneducated population is 29420, then the population of the city is?
   100000
   200000
   300000
   400000
   50000
   Option A
   (62/100) * x * (26/100) + (38/100) * x * (35/100) = 29420
   => 403x/2500 + 133x/1000 = 29420
   => 1471x/5000 = 29420
   = > x = 29420*(5000/1471)
   => x = 100000
   

    

4. M scored 45% marks and failed by 18 marks. N scored 54% marks and get 27 marks more than the passing marks. What is the score of P in the same examination, who secured 75 % marks?
   325
   355
   375
   425
   435
   Option C
   = > 45 % of total marks + 18 = 54 % of total marks – 27
   = > 18 + 27 = (54 – 45) % of total marks
   = > 45 = 9 % of total marks
   = > Total marks = 45*(100/9) = 500
   P’s mark = (75/100)*500 = 375
   

    

5. Find the total number of votes cast in the election if one who got 40 % votes lost by 400 votes.
   1000
   2000
   3000
   4000
   5000
   Option B
   One person got 40 % and another person got 60 %
   According to the question,
   (60 – 40) % of the votes = 400
   20 % of the votes = 400
   Total votes = 400*(100/20) = 2000
   

    

6. A motorist bought two bikes Rs.2400 each. He sell one at 10% profit and another at x% loss in the whole transaction there is no profit or loss, and then find the value of ‘x’
   10
   15
   20
   25
   30
   Option A
   2400*110/100+2400*(100-x)/100=4800
   =>2400*(100-x)/100=4800-2640
   Simplify the above equation, we get x=10%
   

    

7. A vendor marks 50% above the CP and sell at 20% discount. If the profit is double the discount and the discount rate is same, then vendor marks what % more than the CP?
   40
   60
   80
   100
   120
   Option D
   Let us take CP Rs.100
   MP = 150
   SP= 150*80/100=120
   Profit = 120-100=20
   Incase profit = 60
   SP= 160
   MP=160/80*100=200
   Required percentage = 100/100*100=100%
   

    

8. Priti sell an Box at 10% profit. If she bought it 20% less and sell Rs.50 more she gains 100% profit, and then find the cost price of a box.
   100
   150
   200
   250
   300
   Option A
   Let us take CP of a box be x
   SP = 110/100 *x
   CP= 80/100*x
   SP=110/100 *x+50=200/100*80/100*x
   5/10*x=50=>x=100
   

    

9. A shopkeeper got a cooker for Rs. 8100. He allows a discount of 10% on its marked price and still gains 15%. Find the marked price of the cooker?
   Rs. 10350
   Rs. 10500
   Rs. 11290
   Rs. 10320
   Rs. 12450
   Option A
   Selling price = 8100*(115/100) = Rs. 9315
   Marked price*(90/100) = 9315
   Marked price = 9315*(100/90) = Rs. 10350
   

    

10. The profit earned by selling a Wooden cot for Rs. 2540 is the same as the loss incurred by selling the Wooden cot for Rs.1640. At what price should it be sold to make a 30% profit?
    Rs.1317
    Rs.3717
    Rs.2717
    Rs.2007
    Rs.1117
    Option C
    CP = (1640+2540)/2 = 4180/2
    = Rs. 2090
    SP = 2090 * 130/100 = Rs.2717
    

     

Directions: The following series follow some pattern. Find the number in each series which does not follow that pattern and is unfit in the seies.

1. 96…, 46…, 72…, 180…, 630.., 2835..
   96
   46
   72
   180
   630
   Option B
   96 * 0.5 = 48 (not 46)
   48 * 1.5 = 72
   72 * 2.5 = 180
   180 * 3.5 = 630
   630 * 4.5 = 2835
   

    

2. 42…, 86…, 348…, 2094…, 16758
   Option D
   

    

3. 48.., 1764…, 1632..,. 2622…, 2530
   48
   1764
   1632
   2622
   2530
   Option E
   -12^3-12,-11^2-11…..

    

4. 1582…, 1602…, 1634…, 1690…, 1782…, 1920
   1582
   1602
   1634
   1690
   1920
   Option E
   1582 1602 1634 1690 1782 1922
   20 32 56 92 140
   12 24 36 48
   

    

5. 124…, 63…, 64…, 130…, 524…, 4200…, 67214
   124
   63
   64
   130
   67214
   Option E
   124 * 0.5 + 1 =63
   63 * 1 + 1 = 64
   64 * 2 + 2 = 130
   130 * 4 + 4 = 524
   524 * 8 + 8 = 4200
   4200 * 16 + 16 = 67216 (not 67214)
   

    

Directions: The following series follow some pattern. Based on the same pattern find the number in place of (?) in each series.

6. 11…, 19…, 65…, 259…, 1161…, ?
   4321
   5421
   6021
   1161
   2121
   Option C
   11 x 1 + 23 = 19
   19 x 2 + 33 = 65
   65 x 3 + 43 = 259
   259 x 4 + 53 = 1161
   1161 x 5 + 63 = 6021
   

    

7. 8.., 50…, 295.., ? …, 5881…, 17641
   1471
   534
   821
   456
   1231
   Option A
   8 x 7 – 6 = 50
   50 x 6 – 5 = 295
   295 x 5 – 4 = 1471
   1471 x 4 – 3 = 5881
   5881 x 3 – 2 = 17641
   

    

8. 10.., 15.., 35.., 82.5.., ?.., 562.5
   200
   205
   450
   230
   320
   Option B
   10 x 0.5 + 10 = 15
   15 x 1 + 20 = 35
   35 x 1.5 + 30 = 82.5
   82.5 x 2 + 40 = 205
   205 x 2.5 + 50 = 562.5
   

    

9. 1000.., 501…, 170.., 47.5.., ?
   12.7
   14.6
   16.5
   12
   11
   Option C
   1000 ÷ 2 + 1 = 501
   501 ÷ 3 + 3 = 170
   170 ÷ 4 + 5 = 47.5
   47.5 ÷ 5 + 7 = 16.5
   

    

10. 11.., 28.., 39.., 104.., ?.. , 276..
    34
    12
    75
    22
    15
    Option C
    10 + 12 = 11
    20 + 23 = 28
    30 + 32 = 39
    40 + 43 = 104
    50 + 52 = 75
    60 + 63 = 276