1. Three numbers in the ratio of 1: 2: 3 and their L.C.M is 120. Find their H.C.F?
   10
   15
   20
   25
   30
   Option C
   Let the number be x, 2x,3x. So H.C.F is x. L.C.M of x, 2x, 3x= 6x.
   6x =120 => x= 20.
   

    

2. The ratio between two number is 6:5 if their HCF is 10. Then the numbers are.
   10,20
   60,50
   20,60
   20,50
   40,50
   Option B
   Let the number be 6x, 5x
   HCF of 6x,5x=x
   ie) x=10(given)
   Then the numbers are 6x,5x=60,50
   

    

3. Find the average of first 14 natural number.
   100
   105
   200
   205
   300
   Option B
   average of first n natural number=n(n+1)/2
   here n=14
   average=14(14+1)/2=7×15=105
   

    

4. The sum of ages of three sister born of the intervals of 2 years each is 42 years. What is the age of the youngest sister ?
   10
   11
   12
   13
   14
   Option C
   x+(x+2)+(x+4)=42 (given the intervals are 2 years)
   3x+6=42  x =36/2=12
    Age of the youngest sister=12 years
   

    

5. Cost of a mobile is Rs .5000 and selling price is Rs. 7000.What is the profit percent?
   20
   30
   40
   50
   60
   Option C
   Profit % = p/c.p x 100
   =2000/5000 x 100
   P%=40
   

    

6. Ganesh can do a task in 4days . Prem can do a task in 3 days. How long if will take if both Ganesh & Prem work together?
   1 d 5 hr
   2 d 5 hr
   5 d 2 hr
   4d 6hr
   2 d 6 hr
   Option A
   Ganesh 1day work=1/4
   Prem 1day work =1/3
   (Ganesh+Prem) =1/4+1/3=7/12
   So Ganesh& Prem will complete in 12/7=1 5/7=1day 5hrs together.
   

    

7. If a boat travels with a speed 25km/hr in still water and the speed of stream is 5km/hrs . What would be the time taken by boat to go 40 km upstream?
   2
   3
   4
   5
   6
   Option A
   Upstream speed = x-y km/hr
   =25-5=20 km/hr
   T=distance/speed
   T=40/20=2hrs
   

    

8. What is the simple interest on Rs 60000 at 5 ½% per annum for 2 years?
   4300
   5500
   6600
   4400
   5500
   Option C
   S.I = P X R X T/100=60000 x 5 ½ x 2/ 100
   S.I=Rs 6600
   

    

9. Ram deposits Rs .20,000 for 2years with 5% compound interest. What amount will be get at last?
   Rs .22050
   Rs .32050
   Rs .52050
   Rs .20050
   Rs .12050
   Option A
   Amount= P x (1+r/100)n
   =20000 X (1+5/100)2
   =20000 x 105/100)2
   =20000x 105×105/10000
   =Rs .22050
   

    

10. A florist choose one rose at random from the basket which have rainbow colors of roses. what is the probability of choosing yellow color rose?
    1/7
    1/5
    1/4
    1/3
    1/2
    Option A
    S=(rainbow color roses)
    S=(V,I,B,G,Y,O,R)=N(S)=7
    P(Yellow rose)=P(S)/N(S)=1/7 (Only one yellow rose)
    

     

1. A metro travelling at 72 km/hr crosses another metro of length equivalent to five-sixth of its own length travelling in opposite direction at 60 km/hr in 9 seconds. Find the length of the second metro?
   110
   120
   130
   140
   150
   Option E
   Let the length of the first metro be x,
   So, the length of second metro = (5/6) * x = 5x/6
   According to the question,
   [x + (5x/6)] / [(72 + 60) * (5/18)] = 9 [11x/6] / [132 * (5/18)] = 9
   x = 180
   Length of second metro = (5x/6) = (5/6) * 180 = 150 m
   

    

2. A bag contains 4 red pop sticks, 5 green popsticks and 6 pink pop sticks. If 3 sticks are taken at randomly, then find the probability that 2 sticks are Pink?
   11/12
   27/91
   25/65
   12/97
   13/99
   Option B
   Total probability = 15C3
   Required probability = 6C2 and 9C1
   The probability that 2 are green,
   = > [6C2 and 9C1] / 15C3¬
   = > [15 * 9] / 455
   = > 27/91
   

    

3. The perimeter of the room in rectangular shape is 42 meter. The length of the room is twice the breadth of the room. Find the area of the room?
   98
   99
   97
   95
   96
   Option A
   Perimeter of the room= 2 * (l + b) = 42
   l + b = 21
   l = 2b
   According to the question,
   2b + b = 21
   3b = 21
   b = 7 m
   l = 2b = 14 m
   Area of the room = lb = 14 * 7 = 98 Sq m
   

    

4. P, Q and R investing Rs. 18000, Rs. 24000 and Rs. 30000 respectively. After 4 months, P withdraws one-third of the amount and Q invested Rs. 16000 more. And after 3 months, R withdraw three-fifth of the amount. Find the total profit at the end of the month, if the share of Q is Rs. 52000?
   Rs. 106733
   Rs. 106350
   Rs. 506750
   Rs. 106000
   Rs. 106750
   Option E
   [18000 * 4 + 18000 * (2/3) * 8] : [24000 * 4 + 40000 * 8] : [30000 * 7 + 30000 * (2/5) * 5]
   = > [72000 + 96000] : [96000 + 320000] : [210000 + 60000]
   = > 168000 : 416000 : 270000
   = > 84 : 208 : 135
   Q’s share = 208’s = 52000
   1’s = 250
   Total profit = 427’s = Rs. 106750
   

    

5. Man can do a work in 15 days, Woman can do it in 12 days but Boy can do (3/4)th of the work in 18 days. Find the time taken by all together to complete the work?
   1 1/23
   4 4/23
   5 5/23
   6 4/23
   1 4/21
   Option
   man’s one day work = 1/15
   Woman’s one day work = 1/12
   Boy can do the whole work in, = 18 * (4/3) = 24 days
   Boy’s one day work = 1/24
   (Three)’s one day work = (1/15) + (1/12) + (1/24)
   = > (8 + 10 + 5)/120
   = > 23/120
   They can complete the whole work in, = 120/23 = 5 5/23 days
   

    

6. Person 1 is thrice as good a workman as person 2 and so takes 30 days less than person 2 for doing a job. Calculate the time in which they can do the job together is.
   12
   12.5
   11
   11.25
   13
   Option D
   Let person 1 can finish the whole work in x days.
   Person 2 can finish the same work in 3x days.
   then 3x-x= 2x= 30
    x= 15 days
   Person 1 can finish the work in 15 days.
   Person 2 can finish in 45 days.
   A+B work = 1/15 + 1/45 = 4/45
   A+B can finish the work in 45/4 = 11 ¼ days
   

    

7. 32 men and 24 women together can complete a work in 16 days. 40 men can complete the same work in 32 days.How many days will 32 women can complete the same work ?
   10
   20
   30
   40
   50
   Option B
   (32 M + 24 W)* 16= 40 M * 32
   = 40M * 16 * 2
   32M + 24W = 80M
   24W =48M
   1W=2M——-1
   32W=64M—–2
   Now 40 men complete the work in 32 days.
   So 64 men complete the same work in 32* 40 / 64 = 20 days.
   Hence 32 women complete the same work in 20 days.
   

    

8. Four examiners can examine a certain number of answer papers in 10 days by working for 5 a day. for how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?
   10
   15
   20
   25
   30
   Option A
   M1 * D1* H1 / W1 = M2 * D2* H2 / W2
   M1 = 4 D1= 10 H1= 5
   W1 = 1 M2 =2 D2 = 20
   H2 = ? W2= 2
   4*10 *5/1 = 2* 20 *H2/2
   =>H2= 10H
   

    

9. 2 boys and 3 girls together or 4 boys can complete a piece of work in 20 days. 3 boys and 3 girls will complete the same work in how many days?
   15
   16
   17
   18
   19
   Option B
   2 boys + 3 girls= 4 boys
   =>2 boys = 3 girls
   =>3 boys + 3 girls = 5 boys ( 3 girls= 2 boys)
   M1D1= M2D2
   =>4* 20 = 5 *D2
   D2 = 16 days.
   

    

10. Varun gets Rs. 700 for every day that the works. If he runs Rs.19600 in a month of 62 days, for how many days did he work?
    23
    25
    27
    28
    40
    Option D
    Varun gets Rs.700 for 1 day of work
    Amount received by varun for 62 days.
    Number of days Varun worked in a month = 19600/ 700 =28 days.
    

     

Directions (1-10): Find the wrong term in the following series each of which follows some particular pattern:

1. 22 .., 220.., 11.., 330.., 8.35
   22
   220
   11
   330
   8.35
   Option E
   22*10=220
   220/20=11
   11*30=330
   330/40=8.25 (not 8.35)
   

    

2. 16.., 21.., 52.., 161.., 704
   16
   21
   52
   161
   704
   Option D
   (16*1) + 5=21
   (21*2)+10=52
   (52*3) +15=171
   (171*4)+20=704
   

    

3. 225…, 223.., 167.., 119.., 81.., 43
   225
   223
   167
   119
   81
   Option E
   (15^2+1)-3=223
   (13^2+3)-5=167
   (11^2+5)-7=119
   (9^2+7)-9= 79( not 81)
   (7^2 + 5)-11=43
   

    

4. 10.., 40.., 480.., 30730…, 7864320
   10
   40
   480
   30730
   7864320
   Option D
   10 * 4=40
   30* 42=480
   480* 43=30720 (not 30730)
   30720* 44=7864320
   

    

5. 1. 5 .., 3.., 5.5.. , 9.., 13.5
   1.5
   3
   5.5
   9
   13.5
   Option C
   1.5*2=3
   3*1.5=4.5 (not 5.5)
   4.5*2=9
   9*1.5=13.5
   

    

6. 4.., 12.., 56..,224..,230
   4
   12
   56
   224
   230
   Option E
   4+8=12
   12*4=48
   48+8=56
   56*4=224
   224+8=232
   

    

7. 310.., 311.., 323.., 336.., 380
   310
   311
   323
   336
   380
   Option E
   310-9+10=311
   311-8+20=323
   323-7+30=346 (not 336)
   346-6+40=380

    

8. 12.., 1 8.., 20.., 42.., 46.., 66
   12
   18
   20
   42
   46
   Option E
   (12*1)+6=18
   (12*2)-4=2 0
   (12*3)+6=42
   (12*4)-4=4 4 (not4 6)
   (12*5)+6=66
   

    

9. 1.5.., 7.5.., 1.5.., 3.75.., 1.25.., 2.625
   1.5
   7.5
   3.75
   1.25
   0.75
   Option E
   1.5 *5 =7.5
   7.5/5=1.5
   1.5*2.5=3.75
   3.75/5=0.75 (not 1.25)
   0.75*3.5=2.625
   

    

10. 16.., 30.., 41.., 50.., 63.., 74
    16
    30
    41
    50
    63
    Option D
    16+4+10=30
    16+5+20=41
    16+6+30=52(not 50)
    16+7+40=63
    16+8+50=74
    

     

Directions (1-10): Find the wrong term in the following series each of which follows some particular pattern:

1. 34.., 43…, 70.., 131.., 394
   34
   43
   70
   131
   394
   Option D
   34+3^2=43
   43+3^3=70
   70+3^4=151 (not 131)
   151+3^5=394
   

    

2. 33…, 37.., 51..,71.., 109
   33
   37
   51
   71
   109
   Option E
   33+4*1= 37
   37+4*3=51
   51+4*5=71
   71+4*7=99 (not 109)
   

    

3. 99.., 36.., 14.., 8.., 5.66
   99
   36
   14
   8
   5.66
   Option C
   (99/3) +3=36
   (36/3)+3=15 (not 14)
   (15/3)+3= 8
   (8/3)+3=5.66
   

    

4. 30.., 54.., 74.., 110.., 150
   30
   54
   74
   110
   150
   Option C
   30 +8=38
   38+16=54
   54+24=78 (not 74)
   78+32=110
   110+40=150
   

    

5. 234…, 240.., 248..,262.. , 288
   234
   240
   248
   262
   288
   Option E
   234 +2+4=240
   240+3 + 5=248
   248+6+8=262
   262+7+9=278 (not 288)
   

    

6. 70.., 73.., 79.., 113.., 176
   70
   73
   79
   113
   176
   Option C
   70+ 1*3 =73
   73 + 3*5=78 (not 79)
   78 + 5*7 =113
   113+7*9=176
   

    

7. 1563…, 1557.., 1545.. , 1527.., 1500
   1563
   1557
   1545
   1527
   1500
   Option E
   1563 – 6=1557
   1557-12=1545
   1545-18=1527
   1527-24=1503
   

    

8. 235.., 240.., 271…, 321…, 443
   235
   240
   271
   321
   443
   Option B
   235 + 32 +1=245 (not 240)
   245 + 52 +1=271
   271 +7 2 +1=321
   321+ 112 +1=443
   

    

9. 4450…, 4353…, 4259…, 4168…, 4070
   4450
   4353
   4259
   4168
   4070
   Option E
   4450 – 102+3=4353
   4353 – 102+6=4259
   4259 – 102+9=4168
   4168 – 102+12=4080 (not 4070)
   

    

10. 50.., 170.., 600.., 120.., 20..,140
    50
    170
    600
    120
    20
    Option B
    50 * 3= 150 (not 170)
    150* 4=600
    600/5=120
    120/6=20
    20*7=140
    

     

Directions (1-5): Study the following information carefully and answer the questions that follow:

There are three garments A, B and C sold shirts and pants in January 2019.

Number of shirts sold in garment C is 28 less than the number of pants sold in garment B. Number of shirts sold in garment B is 240, which is 20% more than the number of pants sold in the same garment.

Total number of items sold in company A is 50% of the total number of items sold in company B. Number of desktops sold in company A is half of the number of laptops sold in company B.

The ratio of the number of shirts sold in garment A to that of the number of pants sold in garment C is 25: 27.

1. Number of shirts sold in garment A is what percentage more/less than number of pants sold in garment B?
   10% less
   20% less
   30% less
   40% less
   50% less
   Option E

   Required percentage = (200 – 100)/200 * 100

   = 100/200 * 100 = 50% less

    

2. What is the ratio of the total number of pants sold in all the garments together to that of the total number of items sold in garment C?
   
   120: 70
   110: 70
   115: 70
   117: 70
   100: 70
   Option D
   Required ratio = (120 + 240 + 108): 280

   = 468: 280

   = 117: 70

    

3. What is the difference between the total number of items sold in garments A to that of C?
   60
   67
   72
   54
   None of these
   Option A
   Required diff = 280 – 220 = 60

    

4. If garment D sold number of pants is 20% more than that of garment A and the ratio of the number of pants sold in garment D to that of shirts is 2: 3. What is the total number of items sold in garment D?
   360
   300
   350
   200
   230
   Option A

   Number of pants sold in garment D = 120 * (120/100) = 144

   Number of shirts sold in garment D = 144 * (3/2) = 216

   Required total = 144 + 216 = 360

    

5. If 20% of the shirts sold in garment B is defective, find the number of non – defective shirts sold in garment B?
   191
   148
   165
   123
   192
   Option E
   Required number of shirts= 240 * 80/100 = 192

    

Directions (6-10): Study the following information carefully and answer the questions that follow:

In one of the college there are 1300 students. The college has five departments – COMPUTER, ENGLISH, SCIENCE, Maths and Arts. Out of the total number of female students in the college, 30% study in COMPUTER department, 22% study in SCIENCE department, 18% study in ENGLISH department, 12% study in Arts department and remaining 90 female students study in Maths department. Out of the total number of male students in the college, 18% study in COMPUTER department, 20% study in SCIENCE department, 30% study in Arts department, 22% study in ENGLISH department and the remaining students study in Maths department.

6. The total number of male students studying in the Maths and ENGLISH department together is approximately what percent of the total number of students (both male and female) studying in COMPUTER and SCIENCE department together?
   
   12.5%
   45%
   25%
   11%
   13%
   Option B
   Number of male student in Maths department = 80
   Number of male student in ENGLISH department = 176
   Total male of Maths and ENGLISH = 256
   Total number of students in COMPUTER department = 294
   Total number of students in SCIENCE department = 270
   Total students of SCIENCE and COMPUTER = 564
   Required percentage = 256 * 100/564 = 45%
   

    

7. If the male students in SCIENCE department is increase by 20%, the male students in the Maths department increase by 10%, 25% of male student increased by Arts department and 16 male students Joins COMPUTER department and the number of male students in the ENGLISH department is same, what is the percentage increase in the number of male students in the college?
   4.5%
   14.5%
   22.5%
   10.5%
   5.5%
   Option B
   Number of male students in SCIENCE department = 160 * 120/100 = 192
   Number of male students in Maths department = 80 * 110/100 = 88
   Number of male students in Arts department = 240 * 125/100 = 300
   Number of male students in COMPUTER department = 144 + 16 = 160
   Number of male students in ENGLISH department = 176
   New total number of male students in the college = 916
   Required percentage = (916 – 800) * 100/800 = 14.5%
   

    

8. If 50 female students from COMPUTER department are transferred to the Arts department and 20 male students from Arts department are transferred to the COMPUTER department, what is the ratio of the number of female student to the number of male students in the Arts department after the transfer the students?
   1: 2
   1: 8
   1: 5
   3: 2
   5: 2
   Option A
   After transferred the number of female students in Arts department
   = 60 + 50 = 110
   After transferred number of male students in Arts department
   = 240 – 20 = 220
   Required ratio = 110: 220 = 1: 2
   

    

9. What is the average number of students (both male and female) who study in COMPUTER, Arts and SCIENCE department together?
   220
   245
   213
   214
   288
   Option E
   Average = (294 + 300 + 270)/3 = 864/3 = 288

    

10. What is the difference between the number of students (both male and female) studying in ENGLISH department and the number of students (both male and female) studying in Maths department?
    90
    92
    94
    96
    98
    Option D
    Difference = 266 – 170 = 96

     

Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer.

1. A and B started a business with Rs.10000 and Rs.15000 respectively. After 6 months C joined them with Rs.20000.

   Quantity I: B′s share in total profit of Rs.4,00,000 at the end of 2 years.

   Quantity II: Annual Salary of Druv after tax deduction if he earns Rs.20,000 per month and pays a tax of 20% each month.

   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I = Quantity II
   Option A
   Quantity I: A: B: C = 10000*24 : 15000*24 : 20000*18=2:3:3

   B=3/8 *400,000= Rs.150000

   Quantity II: Salary after deduction = 20,000*12*80/100 = Rs.192000
   Hence, Quantity I < Quantity II

    

2. Lalith can do a work in 16 days. Arul is 60% more efficient than Lalith.
   Quantity I: Time taken by Lalith and Arul together to do the work.

   Quantity II: Time taken by Lalith and Arul to do the work together when Lalith works at doubles his original efficiency and Arul works at half his original efficiency.

   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I = Quantity II
   Option C
   Quantity I: Lalith =16 days; Arul= 16 * 100/160=10 days

   Lalith+arul together = 16*10/(26)=80/13 days

   Quantity II: Lalith = 16 days; Arul = 10 days

   Lalith (double efficiency) = 8 day; Arul (half efficiency) = 20 days

   Lalith+Arul together = 80/14
   Hence, Quantity I > Quantity II

    

3. A bag contains 3 Yellow, 4 black and 2 white balls. Two balls are drawn at random.

   Quantity I: Probability that none of the flowers drawn is white.

   Quantity II: Fraction of work completed by Thanu in 7 days if she is 20% more efficient than Meenu who can complete the work in 12 days.

   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I = Quantity II
   Option A
   Quantity I: 7C2/9C2=7/12

   Quantity II: Meenu-> 10 days => fraction of work in 7 days = 7/10

   Hence, Quantity I < Quantity II

    

4. The Person took a loan from bank at 12% P.A. simple interest. After 3 years he had to pay back Rs.16200 as interest.

   Quantity I: Loan taken by person from the bank.

   Quantity II: Amount after 2 years for a principal of Rs.35,000 at interest rate of 10% compounded annually.

   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I = Quantity II
   Option C
   Quantity I: P=16200*100/(3*12)=Rs.45,000

   Quantity II: A= 35000*121/100=Rs.42350

   Hence, Quantity I > Quantity II

    

5. A fisherman can row 9Kmph in still water. It takes him twice as long to row up as to row down the river.

   Quantity I: Rate of stream.

   Quantity II: Speed of a person in still water who can row upstream at 4kmph and downstream at 2kmph.

   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I = Quantity II
   Option E
   Quantity I: 9+y=2(9-y)

   y = 3kmph

   Quantity II: x = (4+2)/2=3kmph

   Hence Quantity I = Quantity II

    

6. Quantity I: Train A crosses the pole in 28 sec at the speed of 90 kmph.

   Quantity II: Train B crosses the 500 m platform in 54 sec at the speed of 108 kmph.

   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I = Quantity II
   Option A
   Answer: b)

   Distance = speed * time

   Quantity I:

   Let the length of train A be x,

   Then,

   x = 90 * 5/18 * 28

   x = 700 m

   Quantity II:

   Let the length of train B be x,

   Then,

   500 + x = 108 * 5/18 * 54

   500 + x = 1620

   x = 1120

   Quantity I > Quantity II

    

7. Quantity I: The Simple interest on that sum at the rate of 20 % per annum for 2 years is Rs. 1000.

   Quantity II: Rs. 2500

   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I = Quantity II
   Option E
   Quantity I:

   SI = pnr/100

   1000= p * 20/100 * 2

   p = Rs. 2500

   Quantity II: Rs. 2500

   Quantity I = Quantity II

    

8. Quantity I: If the ratio of ages of Vishnu and Thaja, 5 years ago is 10: 16 and difference of their age is 30 years, then find the sum of the present age of Varun and Tharun?

   Quantity II: If the average age of A, B, C and D is 40 years, then find the sum of the ages of all of them?

   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I = Quantity II
   Option C
   Quantity I:

   The ratio of ages of Vishnu and Thaja, 5 years ago = 10: 16 (10x, 16x)

   16x – 10x = 30

   x = 5

   Required sum = 16x + 10 = (16 * 5) + 10 = 90 years

   Quantity II:

   Required sum = 40 * 4 = 160 years

   Quantity I < Quantity II

    

9. Quantity I: A bag contains 3 orange balls and 4 blue balls. If one ball is taken out randomly, then find the probability of selecting the ball of blue color.

   Quantity II: A bag contains 3 lime balls and 4 yellow balls. If one ball is taken out randomly, then find the probability of selecting the ball of lime color.

   Quantity I > Quantity II
   Quantity I >= Quantity II
   Quantity I < Quantity II
   Quantity I <= Quantity II
   Quantity I = Quantity II
   Option A
   Quantity I:

   Required probability = 4C1 / 7C1 = 4/7

   Quantity II:

   Required probability = 3C1 / 7C1 = 3/7

   Quantity I > Quantity II

    

10. Quantity I: Find the volume of the sphere, whose radius is 10.5 cm.

    Quantity II: Find the volume of the cone whose height and diameter is 3.5 cm and 16 cm respectively?

    Quantity I > Quantity II
    Quantity I >= Quantity II
    Quantity I < Quantity II
    Quantity I <= Quantity II
    Quantity I = Quantity II
    Option A
    Quantity I:

    Volume of the sphere = (4/3)*πr3 = 4/3 * 22/7 * 10.5 * 10.5 * 10.5 = 4851 cm3

    Quantity II:

    Volume of the cone = (1/3)*πr2h = 1/3 * 22/7 * 16/2 * 16/2 * 3.5 = 234.66 cm3

    Quantity I > Quantity II

     

Directions (1-5): The following series follow some particular pattern. Following that pattern find the number which will come in place of ‘?’.

1. 22… 37… 63… 98… 148… ?
   271
   211
   198
   209
   189
   Option B
   – 22 + (4^2-1) ,5^2+1……

    

2. 23… 48… 100… 206… ?
   380
   376
   420
   456
   None of these
   Option C
   2+2,*2+4…

    

3. 9…5… 6… 10.5… 23… ?
   76
   53
   45
   68
   60
   Option E
   *0.5+0.5,*1+1………

    

4. 8…4… 4… 6… ?… 30
   12
   15
   22
   28
   16
   Option A
   * 0.5 ,*1,*1.5……..

    

5. 5…9… 19… 37… 75… ?… 299
   128
   149
   259
   276
   188
   Option B
   *2-1,*2+1….

    

Directions (6-10): Find the wrong term in the following series each of which follows some particular pattern:


6. 1333…, 1731…, 2201…, 2749…, 3378
   1333
   1731
   2201
   2749
   3378
   Option E
   11³ + 2 = 1333

   12³ + 3 = 1731

   13³ + 4 = 2201

   14³ + 5 = 2749

   15³ + 6 = 3381

    

7. 16…, 40…, 72…, 106…, 148…, 196
   16
   40
   72
   106
   148
   Option C
   16 + 24 = 40

   40 + 30 = 70

   70 + 36 = 106

   106 + 42 = 148

   148 + 48 = 196

    

8. 7….8…, 18…., 57…, 232…, 1160
   1160
   232
   57
   18
   8
   Option A
   7 * 1 + 1 = 8

   8 * 2 + 2 = 18

   18 * 3 + 3 = 57

   57 * 4 + 4 = 232

   232 * 5 + 5 = 1165

    

9. 71…, 80…, 96…, 121…, 159…, 206
   71
   80
   96
   121
   159
   Option E
   71 + 3² = 80

   80 + 4² = 96

   96 + 5² = 121

   121 + 6² = 157

   157 + 7² = 206

    

10. 321…, 316…, 324…, 309…, 329…, 306
    321
    316
    324
    309
    329
    Option D
    321 – 5 = 316

    316 + 8 = 324

    324 – 12 = 312

    312 + 17 = 329

    329 – 23 = 306

     

1. A park is in triangular shape. It’s area is is 360 Sq cm. The ratio of breadth to that of height is 5: 9. Then find the perimeter of adjacent square park, if the height of the trianglular park is equal to the area of the square park?
   21
   22
   23
   24
   25
   Option D
   The area of the trianglular park = (1/2)*b*h = 360 Sq cm

   The ratio of breadth to that of height = 5: 9 (5x, 9x)

   (1/2)*5x*9x = 360

   45×2 = 720

   X2 = (720/45) = 16

   X = 4

   The height of the trianglular park = 9x = 36 cm = Area of the square park

   a2 = 36

   Side of the square park (a) = 6 cm

   Perimeter of the square park = 4a = 24 cm

    

2. priya, Shreya and Riya started a boutique by investing in the ratio of 4: 5: 7. After 4 months, Priya invested Rs. 7500 more but Riya withdraw Rs. 5000 respectively. Find the share of Shreya, if the total profit at the end of the year is Rs. 122720?
   Rs. 12100
   Rs. 52100
   Rs. 62100
   Rs. 32100
   Rs. 42100
   Option D
   The share of Priya, Shreya and Riya

   = > [4x*4 + (4x + 7500)*8]: [5x*12]: [7x*4 + (7x – 5000)*8]

   = > [16x + 32x + 60000]: [60x]: [28x + 56x – 40000]

   = > [48x + 60000]: [60x]: [84x – 40000]

   Total profit = 122720

   = > 48x + 60000 + 60x + 84x – 40000 = 122720

   = > 192x + 20000 = 122720

   = > 192x = 102720

   = > x = 102720/192 = 535

   The share of shreya = 60x = Rs. 32100

    

3. Three years ago, Kamala was 6 years younger than Vimala. The average age of both of them is 25 years. Then find the ratio of age of Kamala and Vimala, five years hence?
   9: 13
   8: 11
   9: 11
   5: 11
   6: 11
   Option C
   Kamala = Vimala – 6 (The age difference between the two people is always same)

   V – K = 6 –> (1)

   The average age of Kamala and Vimala = 25 years

   K + V = 25*2

   K + V = 50 —-> (2)

   solving the equation (1) and (2), we get,

   Vimala = 28 years, Kamala = 22 years

   Required ratio = (22 + 5): (28 + 5) = 27: 33 = 9: 11

    

4. Kavya marked an bamboo chair for Rs. 15000. Had she offered a discount of 10% on the marked price, she would have earned a profit of 8%. Find the cost price.
   Rs. 12500
   Rs. 32500
   Rs. 12000
   Rs. 22500
   Rs. 11500
   Option A
   MP *(90/100) = CP *(108/100)

   15000*(90/100) = CP*(108/100)

   CP = 15000*(90/100)*(100/108)

   CP = Rs. 12500

    

5. Kushal can complete 5/7th of the project in 15 days. Kushal and Vishal together the complete the work in 8 ¾ days. Then find the time taken by kailash to complete the project alone, who is thrice efficient than Vishal?
   7 days
   6 days
   4 days
   5 days
   3 days
   Option D
   Kushal can complete (5/7)*Work = 15

   Kushal can complete the work in = 15*(7/5) = 21 days

   (Kushal + Vishal) together can complete the work in = 35/4 days

   (Kushal + Vishal)’s one day work = 4/35

   vishal = (Kushal + Vishal) – Kushal = (4/35) – (1/21) = 1/15

   Vishal can complete the work in 15 days

   Vishal and Kailash’s efficient ratio = 1: 3

   Vishal and Kailash’s day ratio = 3: 1

   Kailash can complete the work in = (15/3) = 5 days

    

6. The principal amount is Rs.25,000 and the rate of interest is 4%.If the interest was calculated semi-annually, the interest would have been Rs.2060.804 for given time period. Find the interest when compounded annually.
   2010
   2020
   2030
   2040
   2050
   Option D
   Rate semi-annually = 4/2 = 2%

   Interest = Rs2060.804 for given period, means it is not for 1 year, but the whole period.

   Now, CI = 25000+2060.804 = 27060.804

   25000 [1 + 2/100]n = 27060.804
   25000 [1 + 2/100]n = 27060.804
   [51/50]n = 27060804/25000000
   [51/50]n = 27060804/25000000
   [51/50]n = 6765201/6250000
   504 = 6250000 and 514 = 6765201
   So, n = 4 [this is semi-annually]

   Means, actual time period = 4/2 = 2 years

   So, Amount compounded annually = 25000 [1 + 4/100]2 = Rs.27040

   So, CI = 27040 – 25000 = Rs.2040

    

7. Mano got a Simple interest Rs.800 for 1 years.The difference between compound interest and simple interest for 2 years is Rs.40. If the sum is invested for 3 years, what will be the compound interest after 3 years?
   2677
   2155
   2344
   2466
   2522
   Option E
   SI for 1 year = Rs.800, so for 2 years = 2*800 = Rs.1600

   So according to the formula for 2 years, R = 2*(difference between CI and SI)/SI * 100

   R = (2*40/1600) *100 = 5%

   Now use,

   P*R^2/100^2 = (difference between CI and SI)

   P * 5^2/ 100^2 = 40

   P = Rs.16000
   So amount after 3 years = 16000 [1 + 5/100]^3 = Rs.18522

   CI = 18522 – 16000 = Rs.2522
   

    

8. A person invested Rs.25,000 for 8 years and got the interest amount Rs.1750.If rate of interest is increased by 3%, what will be the amount received after given period?
   45000
   25000
   15000
   20000
   40000
   Option A
   According to formula, Time = 1 year

   (25000*r*1)/100 = 1750

   r = 7%
   New rate = 7+ 3 = 10%
   Now, Interest = (15000*10*8)/100 = Rs.20000

   amount = 25000 + 20000 = Rs.45000
   

    

9. The ratio of ages of Arun, 4 years ago to the age of Brundha, 3 years hence is 4: 7. The ratio of age of Arun, 5 years hence to the age of Brundha, 3 years ago is 7: 5. Find the difference between their ages.
   5
   6
   3
   2
   4
   Option D
   Let the present age of Arun and Brundha be a and b,
   Then
   (a – 4)/(b + 3) = 4/7
   7a – 28 = 4b + 12
   7a – 4b = 40 —– (1)
   (a + 5)/(b – 3) = 7/5
   5a + 25 = 7b – 21
   5a – 7b = -49 —– (2)
   Solving (1) & (2)
   a = 16
   b = 18
   Required difference = 18 – 16 = 2
   

    

10. The average weight of 15 boys is decreased by 5 kg when, one of them weighing 112 kg is replaced by another one. This new one is again replaced by another, whose weight is 15 kg higher than the person he replaced. What is the overall change due to this dual change?
    5
    4
    6
    7
    8
    Option A
    Weight of 1st replaced person = 112 – 15 * 5 = 37
    Weight of 2nd replaced person = 37 + 15 = 52
    Net drop = -75 + 15 = -60
    So the overall change = 60/15 = 4 kg
    

     

(1-5): The following information shows the tax to be collected by the central government of India in 2019 .
Export =11,486 crores
Shops=5252 crores
Toll-4910 crores
Private Companies-6000 crores
Share market=29,952
Total tax collected in 2019 = 57,600 crores

1. Near about 20% of the tax are to be collected through:
   Export
   Shops
   Toll
   Private companies
   Share market
   Option A
   20% of the tax = Rs. (20% of 57600) crores
   = Rs. 11520 crores
   ~= Rs. 11486 crores.
   Rs. 11486 crores is the tax from Export

    

2. If the toll is to be collected through an outsourced agency by allowing a maximum 10% commission, how much amount should be permitted to be collected by the outsourced agency, so that the tax is collected with Rs. 4910 crores?
   Rs. 5000 crores.
   Rs. 5001 crores.
   Rs. 5401 crores.
   Rs. 5200 crores.
   Rs. 5301 crores.
   Option C
   Amount collected = (4910cr) +
   (10% of 4910 cr)
   = Rs. 4910 crores + Rs. (10% of 4910) crores
   = Rs. (4910 + 491) crores
   = Rs. 5401 crores.
   

    

3. The central angle corresponding to sahre market is
   
   127.2°
   147.2°
   187.2°
   167.2°
   157.2°
   Option C
   Central angle corresponding to share market = 29952/57600 x 360° = 187.2°

    

4. 
   The approximate ratio of the tax to be collected through Toll and that through share market is
   1/2
   1/3
   1/4
   1/5
   1/6
   Option E
   Required ratio = 4910/2995=1/6 .
   

    

5. What is the average tax amount in 2019?
   11520 cr
   45678 cr
   12500 cr
   13600 cr
   10500cr
   Option A
   Average=57600/5=11520cr.

    

(6-10): The following table shows the total number of students completed their school in different years in a certain school and the ratio of boys and girls. The percentage of students went to college and the remaining students quit their studies.


6. Find the ratio between the total number of students went to college in the year 2004 and the total number of people who completed their school in 2008 ?
   
   306 : 12
   306 : 125
   36 : 125
   30 : 125
   306 : 11
   Option B
   The total number of students employed in MNC companies in the year 2014
   = > 1800 * (68/100)
   The total number of students who completed their UG degree in 2018 and doing business
   = > 2500 * (20/100)
   Required ratio = [1800 * (68/100)] : [2500 * (20/100)]
   = > 306 : 125
   

    

7. Find the average number of students who completed school in all the given years together?
   2050
   2060
   2070
   2090
   2000
   Option B
   The average number of students who completed their UG degree in all the given years together
   = > (1800 + 2400 + 1600 + 2000 + 2500) / 5
   = > (10300/5) = 2060
   

    

8. Find the difference between the total number of boys who completed their school in the year 2005 to that of total number of girls who completed their school in the year 2007?
   400
   600
   100
   500
   700
   Option D
   The total number of males who completed their degree in the year 2015
   = > 2400 * (2/3) = 1600
   The total number of females who completed their degree in the year 2017
   = > 2000 * (11/20) = 1100
   Required difference = 1600 – 1100 = 500
   

    

9. The total number of students went to college in the year 2005 is approximately what percentage of total number ofwent to college in the year 2007?
   44
   77
   88
   101
   103
   Option E
   The total number of peoples employed in MNC companies in the year 2015
   = > 2400 * (72/100) = 1728
   The total number of peoples employed in MNC companies in the year 2017
   = > 2000 * (84/100) = 1680
   Required % = (1728/1680) * 100 = 102.85 % = 103 %
   

    

10. The total number of students who completed their school in 2006 and what percentage more/less than the total number of girl students who completed their school in the year 2004?
    50
    51
    52
    53
    54
    Option C
    The total number of peoples who completed their UG degree in 2016 and doing business
    = > 1600 * (24/100) = 384
    The total number of female students who completed their UG degree in the year 2014
    = > 1800 * (4/9) = 800
    Required % = [(800 – 384) / 800] * 100 = 52 % less
    

     

1. 5 years ago the average age of friends of 5 members is 32 years. Kayal got married today and the average increased by 3. What is the age of Mr. Kayal?
   20
   22
   23
   24
   25
   Option E
   Present average of five members = 32+5=37
   Sum of ages of five members = 37*5 = 185
   Age of Mr.Kayal => (185+x) /6 = 25
   Age of Mr. Kayal = 25
   

    

2. Kannan and balraman invested in the ratio of 15: 14. The profits are divided in the ratio of 3: 4. If Kannan has invested for 7 months, then Balraman invested for?
   5
   10
   15
   20
   25
   Option B
   Investment ratio = 15:14
   Profits = 3:4, A has invested for 7 months.
   Ratio of Profit = 15*7: 14*x = 15: 2x
   According to the question,
   15/2x = ¾
   60 = 6x
   X = 10 months
   

    

3. Lokesh deposits some amount in a bank .He gets simple interest which is 1/8 of the sum. If the number of years is equal to twice the rate percent per annum, then the rate percent per annum is?
   2.5%
   5
   6.7%
   4
   6
   Option A
   S.I = (1/8) P
   (1/8) P = (P × 2r × r) / 100 (Here n=2r)
   1/8 = 2r2 / 100
   r2 = 50/8 = 25/4
   r = 5/2 = 2 ½ %
   

    

4. There are 12 students studying in a coachong class.Out of them 4 from Maharashtra, 5 from Telangana and 3 from Kerala. Three students are to be selected at random. What are the chances that at least one is from Kerala?
   34/56
   34/55
   24/55
   14/55
   13/55
   Option B
   Total probability = 12C3
   Required probability= 1- none is from Kerala
   None is from Kerala,
   = > 9C3
   Required probability= 1- none is from Kerala
   = > 1 – (9C3 / 12C3)
   = > 1 – (21/55)
   = > 34/55
   

    

5. Karan buy an article and made a Loss of Rs. 1500 by selling an article if one-fourth of it is sold at 12% profit and the remaining at 8 % loss. What is the total cost price of the article?
   45000
   46000
   48000
   49000
   50000
   Option E
   Let cost price be x,
   Loss = 1500 = Cp – Sp
   X – [X*(1/4)*(112/100) + x*(3/4)*(92/100)] = 1500
   X – (28x + 69x)/100= 1500
   100x – 97x = 150000
   3x = 150000
   X = Rs. 50000
   

    

6. A boat can travel 19.2 km downstream in 64 minutes. If the speed of the current is 1/5 of the speed of the boat in still water, then find the speed of upstream?
   12
   14
   16
   18
   20
   Option A
   Let the speed of the boat in still water be x km/hr
   Speed of the current = x/5
   Speed of downstream = x + x/5= 6x/5
   Speed of downstream = 19.2*(60/64)= 18 km/hr
   So,
   6x/5= 18
   x = 15 km/hr
   Speed of boat in still water = 15km/hr
   Speed of current = 15/5 = 3 km/hr
   Speed of upstream = 15 – 3 = 12 km/hr
   

    

7. A vendor makes a profit of 10% on the sale of olive oil. If he were to add sunflower oil such that it makes up to 20% of the mixture, by how many percentage points would his profit increase?
   25.5
   27.5
   29.5
   31.5
   33.5
   Option B
   Let’s assume cost of 1 liter of olive oil = Rs 100
   Hence the selling price of 1 liter of oil = Rs (1.1 X 100n) = Rs 110
   According to the question now 20% sunflower oil is there in 1 liter of olive oil and sunflower mixture hence amount of olive oil in the 1 liter of resulting mixture = 80% of 1 liter = 800 ml
   Now price of the new mixture = 80% of 100 = 80
   Now in this case, Cost price = Rs 80
   Selling Price = Rs 110
   Hence profit % = (110-80)/80 X 100 = 37.5%
   Now increase in percentage points = 37.5 – 10 = 27.5
   

    

8. Kishore and Kailash started a business with initial investment of Rs 1300 and Rs 1500 respectively. After 5 months, Kishore added Rs 200. After 4 months, Kailash added Rs 500 and after another 3 months, Kailash added Rs 1000. If at the end of the year. they earned the profit of Rs 35200. Calculate Kishore’s share of profit.
   Rs 11600.
   Rs 13500.
   Rs 13600.
   Rs 23600.
   Rs 13000.
   Option C
   Kishore started a business with initial investment of Rs 1300.
   After 5 months. Kishore added Rs 200.
   If the end of the year, Kishore invested = 1300*5 + 1500’7 = 17000
   Kailash started a business with initial investment of Rs 1500.
   After 4 months, Kailash added Rs 500 and after another 3 months, B added Rs 1000.
   If the end of the year, Kailash invested = 1500*4 + 2000*3 + 3000*5 = 27000
   Total Profit = Rs 35200
   Kishore’s share of profit = 17*35200/44 = Rs 13600.
   

    

9. Srilatha borrowed Rs 30000 from a bank at a rate of 12% per annum for two years at simple interest and lends the same money to Srikala at the rate of 12% for two years but he charged compound interest. What is the overall gain by Srilatha?
   569
   432
   100
   280
   45
   Option B
   the difference between simple interest and compound interest = P (R/1 00)2
   So the overall gain by Srilatha = Rs [30000 X (0.12)2] = Rs 432
   

    

10. A man buys two pants for Rs. 800. He sells first pant at a profit of 15% and second pant at a loss of 5%. After doing both the transactions the man knew that he has neither earned profit nor did he incur any loss. At what cost (in Rs.) did the man sell the loss making pant?
    550
    560
    570
    580
    590
    Option C
    Let the cost price of the first pant be Rs x and that of second pant be Rs y.
    We know that, x + y = 800.
    Now, the first pant was sold at 15% profit and the second pant was sold at 5% loss
    .: Selling price of first pant = x + 15% of x = 1.15x
    Selling price of second pant = y – 5% of y = 0.95y
    Given that there was neither profit nor loss in the transaction.
    .: x + y = 1.15x + 0.95y = 800
    Now, as x + y = 800
    .: x = 800 – y
    1.15x + 0.95y = 800
    :.1.15 (800 – y) + 0.95y = 800
    .:920 – 1.15y + 0.95y = 800
    y = 600
    Selling price = 0.95*600 = 570