1. Two friends A and B appeared for an selection . Let E1 be the event that A is selected and E2 is the event that B is selected. The probability of E1 is 2/5 and that of E2 is 3/7. Find the probability that both of them are selected.
   
   2/35
   4/35
   6/35
   5/35
   3/35
   Option C
   Given, E1 be the event that A is selected and
   E2 is the event that B is selected.
   P(E1)= 2/5
   P(E2)=3/7
   Let E3 be the event that both are selected.
   P(E1)=P(E1)×P(E2) as E1 and E2 are independent events:
   P(E3) = 2/5*3/7
   P(E3) =6/35
   The probability that both of them are selected is 6/35

    

2. A policeman forgot the last digit of an 11 digit land line phone number. If he randomly dials the final 2 digits after correctly dialing the first nine, then what is the chance of dialing the correct number
   1/40
   1/30
   1/200
   1/10
   1/100
   Option E
   It is given that last two digits are randomly dialed.
   Then each of the digits can be selected out of 10 digits in 10 ways.
   Hence required probability
   =(1/10)2
   =1/100

    

3. Six boys and five girls stands in queue for buy a pizza in a shop. The probability that they stand in alternate positions is:
   1/452
   1/462
   1/262
   1/362
   1/162
   Option B
   Total number of possible arrangements for Six boys and five girls stand in queue =11!
   When they occupy alternate position the arrangement would be like:
   bgbgbgbgbgb
   Thus, total number of possible arrangements for boys,
   = 6*5*4*3*2
   Total number of possible arrangements for girls,
   =5*4*3*2
   Required probability
   =6*5*4*3*2*5*4*3*2/11*10*9*8*7*6*5*4*3*2
   = 1/462

    

4. From 4 roses and 5 jasmines , the garland has to be formed with 5 flowers and it contain at least one rose. In how many ways the garland can be formed?
   119
   125
   110
   115
   120
   Option B
   (4C1 * 5C4 ) + (4C2 * 5C3) +(4C3 *5C2) +(4C4 *5C1) =60+60+40+5
   =125

    

5. There are 12 members in a committee. If a group of 5 members has to be selected from the committee in such way that one member is always included, in how many different ways the selection can be done?
   335
   300
   320
   330
   310
   Option D
   1 is permanent. We have to choose other from 11
   =11C4 = 330

    

6. The ratio of apples and oranges is 5:2 and total count is 35 .A basket of 4 fruits should be taken. What is the probability that the selected group contains 1 apple and 2 oranges?
   900 /1209
   900 /1309
   100 /1309
   800 /1309
   700 /1309
   Option B
   basket should contain one apple and 2 oranges = 10C2 *25C1 *32C1
   Total probability =35C4
   So the required probability =900 /1309

    

7. How many groups of 6 students can be formed from 8 boys and 7 girls ?
   4005
   5005
   6005
   2005
   3005
   Option B
   Total no . of students = 8 + 7 = 15
   No. of groups = 15C6 = 15! / {6! (15 – 6)!} = 15! / (6! 9!)
   = (15 x 14 x 13 x 12 x 11 x 10) / (6 x 5 x 4 x 3 x 2 x 1)
   = 5005

    

8. How many different ways the letters can be formed “JOBUPDATES” so that all the vowels never come together?
   3644520
   3600520
   3633520
   3611520
   3622520
   Option D
   All the come together = 6! 4!
   Total choices = 10!
   All vowels never come together =10! -6! 4! =3611520
   

    

9. In a box there 4 marbles in blue , 6 marbles in yellow, 3 marbles in red color and we have to take 3 marbles and what is the probability taking all marbles in same colour ?
   259
   278
   286
   216
   206
   Option C
   4C3 +6C3 +3C3 =25
   13C3 =286

    

10. A box contains dozen of chocolates out which 3 are milk rest are cocoa. Two chocolates are taken out. What is the probability of one chocolate is milk and another one is cocoa?
    4/22
    6/22
    11/22
    9/22
    10/22
    Option D
    Probability = 3c1 *9c1 / 12c2 = 3*9 /66 = 9/22

     

1. By selling a bag of Rs.810 the mano incurs a loss of 10%. What is the gain or loss percentage if he sells the same bag at Rs. 930?
   
   3.3%
   4.3%
   3.3%
   5.3%
   7.3%
   Option C
   CP = 810 / 0.9 = 900
   New SP = Rs. 930
   Profit (%) = [930-900 / 900] X 100 = 3.3%

    

2. A fruitseller loses Rs. 40 by selling some oranges at the rate of Rs. 3 per orange and gains Rs.60, if he sells them at Rs. 3.25 per orange. The number of oranges sold by him ?
   
   4 oranges
   40 oranges
   400 oranges
   300 oranges
   450 oranges
   Option C
   Alternatively: Rs. 0.25 is the difference on 1 orange
   Rs. 1 is the difference on 1/0.25 = 4 orange
   Rs. 100 is the difference on 4 x 100 = 400 oranges

    

3. A dealer buys a refrigerator at Rs. 20000 and gets 10% and 20% successive discounts. He spends 10% of his CP on transport.At what price (in rupees) should he sell the refrigerator to earn a profit of 10% ?
   
   Rs.17400
   Rs.17424
   Rs.15424
   Rs.16424
   Rs.14424
   Option B
   Price after 10% discount = 20000 – 10 % of 20000 = 20000 – 0.1 x 20000 = 18000
   Price after another 20% discount = 18000 – 20 % of 18000 = 14400
   Price after 10% of transportation charges = 14400 + 14400 x 0.1 = 15840
   Price after 10% of profit = 15840 + 15840 x 0.1 = Rs.17424
   ∴ Selling price = 8712

    

4. A vegetableseller use a weighing balance that shows 1500 g for a kilogram. He further marks- up his cost price by 40%. what is the profit percentage ?
   115 %
   112 %
   102 %
   110 %
   105 %
   Option D
   Let the cost price of one gram be Rs. 1, then the mark up price be Rs. 1.2 per g.

   Let the cost price of one gram be Rs. 1, then the marked price be Rs. 1.4per g
   he sells 1000 g to 1500 g,
   he charges 1500 X 1.4 = Rs. 2100 for 1000g ie) Rs.1000
   profit %= 2100 -1000 / 1000 X 100 = 110 %

    

5. A shop keeper sells rice at the cost price but dishonestly he uses a weight of 900 g instead of 1kg. Then what is his percentage of profit?
   
   13.1%
   12.1%
   12%
   11%
   11.1%
   Option E
   Profit (%) = goods lefts / goods sold X 100 = ( 100 / 900 ) X 100 = 11.1%
   

    

6. Srujan purchases guava at Rs. 5 per dozen and sells them at Rs. 12 for every 5 guavas. What is the profit percentage ?
   
   424 %
   454 %
   486 %
   409 %
   476%
   Option E
   Cost price (CP) = 5 / 12 ,
   Selling price (SP) = 12 / 5
   Profit (%) = [ (SP – CP) / CP ] x 100
   ∴ Profit (%) = [( 12 / 5 – 5 / 12 ) / (5/ 12) ] X 100 = 476 %

    

7. Two third of a bedsheets was sold at a profit of 5% and the remainder at a loss of 2%. If the total profit was Rs. 400, the value of the bed sheets (in rupees) was :
   
   Rs. 400
   Rs. 450
   Rs. 420
   Rs. 300
   Rs. 410
   Option A
   Total profit = 15000 x ( 2 / 3 ) x 5 % ( find from the option)
   = 15000 x ( 2 / 3 ) x ( 5 / 100)
   = 500
   Total loss = 15000 x ( 1 / 3 ) x 2 %
   = 5000 x ( 1 / 3 ) x ( 2 / 100)
   = 100
   Net gain = ( 500 – 100 ) = Rs. 400

    

8. A discount of 20% in the price of wheat makes customers to purchase 6 kg more for Rs. 240. What is the original price per kg of the wheat ?
   
   Rs. 12 per kg
   Rs. 10 per kg
   Rs. 30 per kg
   Rs. 14 per kg
   Rs. 20 per kg
   Option B
   discount in price = 20% ( 1 / 5 )
   Increase in amount = 25 % (1 / 4) = 6 kg
   original amount of wheat needed = 6 X 4 =24 kg
   ∴ Original price of the wheat = 240 / 24
   = Rs. 10 per kg

    

9. In a sweet stall the owner cheats both to his whole-seller and his customer by 10% by his faulty weighing machine .He actually weighs 10% more while purchasing from wholesaler and weighs 10% less while selling to his customer. What is his net profit percentage, when he sells at CP ?
   
   22 2/9%
   12 2/9%
   13 2/9%
   15 2/9%
   16 2/9%
   Option A
   Amount purchased = 1100 g
   Amount sold = 900 g
   Profit % = (200 / 900) X 100
   = 22 2/9%

    

10. A man buys pens at150 rupees per dozen and sells them at 30 rupees per piece. What is the profit?
    Rs.200
    Rs.220
    Rs.210
    Rs.260
    Rs.250
    Option C
    Each dozen carries cost 150 rupees and are sold for
    12 x 30 = 360 rupees
    profit = SP-CP
    profit = Rs.210

     

1. A work is to be completed in 40 days and 110 men were set to work, each working 8 hours a day. After 30 days, 4/5 of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 10 hours a day?
   44
   34
   54
   64
   74
   Option A
   30 * 110* 8 / 4/5 = 10 * x* 10 / 1/5
   =>x= 66
   more men required= 110-66 =44

    

2. Two pipes 1 and 2 can fill a tank in 10 hours and 30 hours respectively while a third pipe can empty the full tank in 25 hours. All the three pipes are opened in the beginning. After 15 hours, third pipe is closed. In how much time, will the tank be full?
   12 hours 45 min
   16 hours 45 min
   11 hours 45 min
   16 hours 35 min
   10 hours 45 min
   Option B

   Total work
   1—- 10
   2—– 30
   total—-300
   3—– (-25)
   So third pipe 1 hour work = 300/-25 = -12
   Tank filled in 1 hour = 10+30 -12= 23
   So work done in 10 hours= 230
   Remaing work = 300-230 =70
   70 work will be done by 1 and 2 in 70/ ( 10+30)= 1.75= 105 min= 1 hr 45 min
   so work gets completed in 15+1 h 45m = 16 hours 45 min

    

3. 
   A worker was paid Rs. 1700per day for 30 days. but he was absent for 4 days and Rs. 15 was taken as penalty per day for absence. He was paid the full salary only for 18 days as he came late on the other days. Those who came late were given only half the salary for that day. What was the total salary paid per month to a worker who came on time everyday and was never absent?
   
   Rs.2400
   Rs.1200
   Rs.1000
   Rs.2500
   Rs.3000
   Option A
   Let the each day salary = Rs. x
   Then 18x + 8*x/2 – 60 = 1700
   =>x= 1700/22
   So monthly salary = 1700/22 * 30 = Rs.2400

    

4. Person A can do a piece of work in 10 days and person B can do it in 12 days. They work together for 3 days. Then person B leaves and A alone continues. 2 days after that C joins and the work is completed in 2 days. In how many days can C do it, if he works alone?
   20
   30
   40
   50
   60
   Option C
   Total work efficiency
   A 10 6
   60
   B 12 5

   3 days of A+B work = 11* 3 =33
   Remaining work = 60-33 = 27
   2 days of A work = 2* 6=12
   2* efficiency of A + 2 * efficiency of C = 15
   2*6 + 2*C = 15
   =>C= 3/2
   So C will complete the whole work in 60/3/2 = 40 days

    

5. Two men undertake to do a piece of work for Rs. 1200. One alone could do it in 12 days and the other in 16 days. With the assistance of a boy, they finish it in 6 days. The boy’s share should be-
   
   rs.150
   Rs. 200
   Rs.225
   Rs.300
   Rs.210
   Option A
   Ratio of efficiency = 24/12: 24/16 :24/ 6 – ( 24/12 + 24/16)
   = 4:3:1
   so boy’s share = 1/ ( 4+3+1) * 1200 = Rs.150

    

6. Arun can do as much work in 4 days as lalitha can do in 5, and lalitha can do as much work in 6 days as suma in 7 days. In what time will suma do a piece of work which Arun can do in a week?
   12 5/ 24 days
   10 5/ 24 days
   11 5/ 24 days
   13 5/ 24 days
   14 5/ 24 days
   Option B
   arun * 4 = |Lalitha * 5
   Arun: Lalitha= 5:4
   Similarly lalitha : Suma= 7:6
   So Arun : Lalitha: Suma=35:28:24
   so efficiency of Arun= 35
   Work done in 7 days by arun = 7* 35= 245
   Suma will do 245 work in = 245/24 = 10 5/ 24 days

    

7. The work done by 8 men in 24 days is equal to the work done by 12 women in 20 days and is also equal to the work done by 16 children in 18 days. A man, a woman and a child working together take 20 days to complete a particular job. In how many days will the same job be completed by 4 women and 10 children working together?
   2
   7
   4
   5
   6
   Option D
   8 M * 24 = 12w * 20
   M = 5W/4
   12W * 20 = 16C * 18
   W= 6C/5
   1M+ 1W +1C= 5w/4 + W + 5W/6 = 37W/12
   2W+ 5C= 2W+ 5*5W/6 =37W/6
   M1*D1=M2*D2
   37/12 *10 = 37/6 * Days
   days= 5

    

8. Akil, Bindhu and Jay can do a job in 20, 30 and 40 days respectively. The three started the job together; Akil left the job 4 days before it was completed and Bindhu left the job 3 days before it was completed. In how many days was the job completed?
   12
   11
   15
   14
   17
   Option A
   Total work efficiency
   Akil-> 20 6
   Bindhu-> 30 120 4
   Jay -> 40 3
   Let them completed the work in x days.
   6( x-4) + 4( x-3) + 3x= 120
   => x= 12 days

    

9. 2 and 3 are equally efficient, but the efficiency of 1 is half of each 2 and 3. 1 and 2 started a work and 3 days later 3 joined them. If 1 alone can do the work in 14 days, then in how many more days the work will be completed?
   5
   3
   4
   1
   2
   Option D
   efficiency –> 1:2 = 1:2
   efficiency—> 2:3 = 1:1
   1:2:3 = 1:2:2
   days = 1: 1/2: 1/2 ( days inversly proportional to efficiency)
   total work efficiency
   1–> 14 days 14 1
   2—> 7 days 2
   3—> 7 days 2
   Work done by 1& 2 in 3 days= 3*3= 9
   remaining work = 14-9 =5
   time taken by 1 and 2 and 3 to finish 5 works = 5/5 =1
   so more days required= 1

    

10. person 1 and 2 can do a work in 20 and 25 days respectively. After doing collectively 10 days of work, they leave the work due to illness and person 3 completes rest of the work in 3 days. How many days person3 alone can take to complete the whole work?
    20
    21
    33
    49
    30
    Option E
    work efficiency
    person 1–>20 5
    100
    person 2—>25 4
    work completed by person 1 and 2 in 10 days= 9*10 = 90 work
    remaining work = 100-90 = 10
    10 work done by person 3 in 3 days.
    so efficiency 10/3
    So person 3 can complete in 100/ 10/3 = 30 days

     

1. A sum of money fetches Rs. 480 as simple interest at the rate of 10% per annum after 12 years What is the sum?
   
   250
   200
   350
   400
   500
   Option D
   Principal = SI * 100 / T* R
   = 480 *100/ 10*12 = Rs. 400

    

2. The simple interest is occured on an amount of Rs. 40,000 at the end of 3 years isRs. 14,400. What would be the compound interest accured on the same amount at the same rate in the same period?
   Rs.7640.64
   Rs.7540.64
   Rs.8640.64
   Rs.9640.64
   Rs.6640.64
   Option A
   R= 14,400 * 100/ 40,000 * 6 = 6%
   CI= 40,000 ( 1+ 6/100 )^3 – 1) = Rs.7640.64

    

3. 2, 16, 112, 672, 3360,?
   13440
   3340
   5609
   12340
   55090
   Option A
   Multiply by 8 ,7, 6, 5, 4 respectively.

    

4. 4,9, 19, ?, 79, 159, 319
   35
   39
   28
   50
   34
   Option B
   Clue *2+1

    

5. 474, 459, 429,369,249, ?
   6
   5
   8
   9
   10
   Option D
   subract 15, 30…. from the appropriate term.

    

6. 7, 10, 16, 28, 52, ?, 196
   100
   87
   96
   88
   102
   Option A
   Add 3, 6 ,12….

    

7. Two taps A and B can deliver water to a drum at the rate of 4 lit/min and 6 lit/min respectectively. If capacity of drum is 2400 li then what part of drum will remain empty after one hour of starting of both taps?
   1/2
   3/4
   2/3
   1/5
   1/4
   Option B
   Total water delivered to the dam in one hour =(4+6)x60(1 hr=60 min) =600 liters
   Filled part of dam =600/2400=1/4
   Empty part of dam=1-1/4=3/4

    

8. Three pipes A,B and C can fill a cistern in 12 hr. 16 hr and 20 hr. respectively. all the pipes are opened together and after working two hours pipes B and c are closed. Find time taken by pipe A to fill the remaining part of cistern.
   7.3
   8
   6.5
   5.9
   11
   Option A
   capacity of tank=L.C.M of (12,16,20)=240unit/hr.
   Efficiency of pipe A =240/12=20 unit/hr.
   Efficiency of pipe B =240/16=15 units/hr.
   Efficiency of pipe C =240/20=12 unit/hr.
   Let pipe A taken x hour to fill the remaning part 20(x +2)+15 x 2 + 12x 2=240
   =20x + 40+30+24=240
   =20x=146
   =x=7.3hrs

    

9. Sai can type 180 pages in two hours while raj can type 240 pages in one and half hour. if total pages earned by them is Rs.3100.then what is the share of Sai?
   1120
   2245
   1678
   1116
   1453
   Option D
   Ratio of efficiencies of Sai and Raj
   =180/2:240/3/2 =9:16
   share of Sai=9/25 x3100=Rs=1116

    

10. 30 workers working 7 hours a day can finish a piece of work in 18 days. if the laborers work 6 hours a day. Then What is the number of workers required to finish the same piece of work in 30 days?
    10
    12
    18
    19
    21
    Option E
    Required numper of Laborers =30x7x18/6×30=21

     

Directions: The following number series follow a specific pattern. Find the number which is wrong in the respective series.

1. 10, 26, 46, 75, 120, 180
   180
   26
   75
   10
   46
   Option A
   10 .. 26 .. 46 .. 75.. 120 190
   + 16 ..20 .. 29 .. 45 .. 70
   + 2*2 3*2 4*2 5*2

    

2. 20, 36, 56, 64, 124 , 180
   124
   36
   64
   20
   56
   Option C
   20 ..36 .. 56 .. 84.. 124 .. 180

   + 16.. 20.. 28 .. 40 .. 56

   + 4 .. 8 ..12 .. 16
   

    

3. 1, 11, 202, 264, 287, 266
   202
   1
   111
   261
   287
   Option D
   1.. 111 .. 202.. 264 .. 287 .. 261

   + 110 .. 91 .. 62.. 23 .. -26

   – 19 .. 29 .. 39 .. 49
   

    

4. 5, 7, 13, 23, 61, 133
   23
   5
   7
   61
   233
   Option A
   5 7 13 25 61 133

   + 2 6 12 36 72

   x 3 2 3 2
   

    

5. 5, 15, 30, 55, 97, 160
   15
   30
   55
   97
   160
   Option E
   5 15 30 55 97 165

   + 10 15 25 42 68

   + 2*2+1 3*2+1 4*2+1 5*2+1
   

    

6. 20, 30, 45, 65, 106, 160
   20
   30
   45
   65
   106
   Option D
   20 30 45 69 106 160

   + 10 15 24 37 54

   + 5 9 13 17
   

    

7. 10, 20, 31.5, 45.5, 63, 80
   80
   63
   20
   10
   31.5
   Option A
   10 20 31.5 45.5 63 85

   + 10 11.5 14 17.5 22

   + 1.5 2.5 3.5 4.5
   

    

8. 100, 90, 70, 57, -76, -1320
   100
   90
   70
   57
   -76
   Option C
   100 90 79 57 -76 -1320

   – 10 11 22 133 1244

   + 1 11 111 1111
   

    

9. 500, 498, 490, 440, 186 ,-1370
   500
   498
   490
   440
   186
   Option D
   500 498 490 446 186 -1370

   – 2 8 44 260 1556

   + 6 6*2 6*3 6*4
   

    

10. 10, 26, 41, 53, 60, 70
    70
    60
    53
    26
    10
    Option A
    10 26 41 53 60 60

    + 16 15 12 7 0

    – 1 3 5 7
    

     

1. The mercahnt sold a sofa Rs. 5000with 10% discount on it.what would be the selling price of the sofa if he gave 20% discount?
   4000
   5000
   4500
   6000
   6500
   Option A
   MP *90/100 = 5000
   Mp= 5000*90/100 = Rs.4500
   SP with 21% discount=4500/90 * 100 *80/100 = Rs.4000

    

2. Rs.1700 glass bottle is offered 18% discount and Rs.2850 glass flower vase at 30% discount. If we buy 18 glass bottle and 34 glass vase how much
   approximate discount will get?
   5%
   7%
   4%
   6%
   8%
   Option B
   Total discount = 1700 * 18 *18 /100 + 2850 *34 *30/100 =8415
   d% = 8415/ ( 1700*18 + 2850*34) *100
   d% = 6.6%
   d%= 7%

    

3. In a city a seller buys a cycle and TV for Rs.65,000. He sold the cycle at a profit 20% and the TV at a loss of 15% . If he sold both the things at the same price then what is the cost price of cheaper thing ?
   23456
   18000
   26951
   34215
   22435
   Option C
   Cycle + Tv= Rs.65,000
   Cycle * 120/100 = TV * 85/100
   cycle : TV= 85:120 =17:24
   Hence 17/ 41 * 65,000 = Rs.26951

    

4. A seller marked the price of the article so as it included profit 25%.He allowed discount 0f 165 on the marked price. Find his actual profit ?
   
   4
   2
   6
   3
   5
   Option E
   Let the CP be rs.100
   Then marked price = rs 125
   SP = 84 /100 * 125 =Rs.105
   Profit % = 105 -100 % = 5%

    

5. Hari allows a trade discount of 10% and a cash discount 6% on the marked price of the goods and gets a net gain of 10% of the cost.
   Find how much price be marked for the sale?
   29
   30
   31
   32
   33
   Option A
   discount = (10 +6 – 10* 6/100 )%
   =15.4%= 15%
   x*85/100= 110
   =>x =129.4
   =>reqiured percentage = 29%

    

6. A person allows 20% discount on the marked price and there is a loss of 15% . If he sold his things at the marked price ,then find out the profit percentage?
   6.25%
   7.15%
   8.25%
   9%
   5%
   Option A
   80x/100 = 100 – 15 = 85
   =>x= 850/8 which he sells at marked price.
   profit = 850/8 – 100 = 50/8 = 6. 25 %

    

7. Gokul sold his goods in such a way that even after allowing 25% discount on cash , he gains 40%.If the cost price of the thing is Rs.280, Then what is the marked price of the thing?
   540
   523
   543
   515
   525
   Option B
   Let the marked price be x
   Then 100- 25 % of x = 280 + 40% of 280
   => 75%of x= 392
   =>x=Rs.523.

    

8. If the manufacturer gains 5 %, the wholesale dealer 10 % and the retailer 20 %, then find the cost of production of a table if the retail price was Rs 5000
   
   4200
   3607.50
   3478.50
   4300.50
   4200
   Option B
   Let the cost of Production = Rs. P
   Then, as per question,

   =>(105/100∗110/100∗120/100∗P)=5000
   =>693/500 * P=5000
   =>P=Rs.3607. 50

    

9. Seetha gains 10% by selling her craft for a certain price. If she sells it at double the price, the percentage of profit will be.
   110
   120
   130
   160
   115
   Option B
   Let the C.P. = x,
   Then S.P. = (110/100)x = 11x/10
   New S.P. = 2(11x/10) = 22x/10

   Profit = 22x/10 – x = 12x/10

   Profit% = (Profit/C.P.) * 100
   => (12x/10) * (1/x) * 100 = 120 %

    

10. A car is sold for Rs. 1,40,000 with a loss of 30%. At what price it should be sold to get profit of 15%.
    2,15,000
    2,20,000
    2,30,000
    2,45,000
    2,50,000
    Option
    Let at Rs x it can earn 15% pr0fit
    70:1,40,000 = 115:x

    x = (1,40,000*115)/70
    = Rs.2, 30,000
    

     

1. The respective ratio of the present ages of Prem and Suresh is 1:2. After 6 years the ratio of their ages will be 11:20. 9 years before what was their respective ratio of their ages?
   3:5
   1:5
   2:5
   1:4
   3:2
   Option C
   Let the present age of Prem and suresh be x and y.
   So, x/y = 1/2
   and x+6/ y+6 = 11/20
   =>x=27 and y= 54
   So required ratio = 18/45 = 2/5

    

2. How many different words can be formed with the letters of the word UNIVERSITY so that all the vowels are together?
   60480
   60840
   60440
   60880
   60450
   Option A
   Required number of ways= 4!* 7!/ 2 = 60480

    

3. the radius of the circular wheel is 4 m.how many revolutions will it make in travelling 11 kilometer?
   100
   150
   200
   250
   300
   Option D
   Number of revolutions= 11000/ (2* 22/7 * 7) = 250

    

4. A shop keeper marks his vegetables 60% above the cost price and gives of 30% on the marked price. the what is the profit percentage he gets?
   10
   11
   12
   13
   14
   Option C
   Let the CP be Rs.100
   S.P = 70/100 * 160 = Rs.112.
   P% = 12/100 * 100 = 12%

    

5. 60 workers working 14 hours in a day and complete the work in 36 days. If the workers work 12 hours per day, then the number of workers need to complete the same work in 60 days are
   
   34
   36
   38
   40
   42
   Option E
   Required number of workers= 60*14*36 / 12*60 =42

    

6. Rani bought 62 pens. Sona bought 43 pens. Arun bought 66 pens and Seetha bought 73 pens. What was the average number of pens they purchased?
   57
   58
   60
   61
   59
   Option D
   Average = 62+43+66+ 73/ 4 =61

    

7. The marked price of the handbag is Rs.1500 .If it is sold at a 40% discount and the dealer earns 50% profit. The find what is the cost price of the bag?
   500
   600
   700
   800
   900
   Option B
   SP = 60/100 * 1500 =Rs.900
   Profit = 50%
   CP = 100/150 * 900 =Rs.600

    

8. What is the pricipal amount if the sum of money fetches Rs. 4800 at the rate of 10% per annum after 3 years?
   16,000
   12,000
   10,000
   15,000
   20,000
   Option A
   P = 4800 * 100/ 10* 3= Rs.16,000

    

9. Kayal weights is 70 % of maya weight. Tara weight 45% of maha weight. Maha weight. Maha weight is twice as much as maya.What percentage of kayal weight is Tara’s weight?
   77
   78
   75
   76
   74
   Option B
   Let maya weight= x kg
   Maha weight = 2x kg
   Tara weight = 0.45* 2x
   =0.9 kg
   kayal weight=0.7 x kg
   So required percentage = 0.7x/0.9 * 100 =78% ( approx)

    

10. Roja bought 20 kg of rice for Rs.2200 and sold it at a loss of as much rupees as she received for 40 kg. At what price did she sell the rice?
    110
    100
    90
    200
    210
    Option A
    Let the selling price of rice = Rs. x
    2200 – 20x=40x
    =>x=110 per kg

     

Directions: The following number series follow a specific pattern. Find the number which is wrong in the respective series.

1. 24, 33, 60, 131, 384
   24
   33
   60
   131
   384
   Option D
   24+3^2=33
   33+3^3=60
   60+3^4=141 (not 131)
   141+3^5=384
   

    

2. 23, 27, 41,61, 99
   23
   27
   41
   61
   99
   Option E
   23+4*1= 27
   27+4*3=41
   41+4*5=61
   61+4*7=89 (not 99)
   

    

3. 99, 36, 14, 8, 5.66
   99
   36
   14
   8
   5.66
   Option C
   (99/3) +3=36
   (36/3)+3=15 (not 14)
   (15/3)+3= 8
   (8/3)+3=5.66
   

    

4. 20, 44, 64, 100, 140
   20
   44
   64
   100
   140
   Option C
   20 +8=28
   28+16=44
   44+24=68 (not 64)
   68+32=100
   100+40=140
   

    

5. 224, 230, 238,252 , 278
   224
   230
   238
   252
   278
   Option E
   224 +2+4=230
   230+3 + 5=238
   238+6+8=252
   252+7+9=268 (not 278)
   

    

6. 60, 63, 69, 103, 166
   60
   63
   69
   103
   166
   Option C
   60+ 1*3 =63
   63 + 3*5=68 (not 69)
   68 + 5*7 =103
   103+7*9=166
   

    

7. 1553, 1547, 1535 , 1517, 1490
   1553
   1547
   1535
   1517
   1490
   Option E
   1553 – 6=1547
   1547-12=1535
   1535-18=1517
   1517-24=1493
   

    

8. 225, 230, 261, 311, 433
   225
   230
   261
   311
   433
   Option B
   225 + 3^2 +1=235 (not 230)
   235 + 5^2 +1=261
   261 +7 ^2 +1=311
   311+ 11^2 +1=433
   

    

9. 4440, 4343, 4249, 4158, 4060
   4440
   4343
   4249
   4158
   4060
   Option E
   4440 – 10^2+3=4343
   4343 – 10^2+6=4249
   4249 – 10^2+9=4158
   4158 – 10^2+12=4070 (not 4060)
   

    

10. 50, 170, 600, 120, 20,140
    50
    170
    600
    20
    140
    Option B
    50 * 3= 150 (not 170)
    150* 4=600
    600/5=120
    120/6=20
    20*7=140
    

     

11. 22 , 220, 11, 330, 8.35
    22
    220
    11
    330
    8.35
    Option E
    22*10=220
    220/20=11
    11*30=330
    330/40=8.25 (not 8.25)
    

     

12. 16, 21, 52, 161, 704
    16
    21
    52
    161
    704
    Option D
    (16*1) + 5=21
    (21*2)+10=52
    (52*3) +15=171
    (171*4)+20=704
    

     

13. 225, 223, 167, 119, 81, 43
    225
    223
    167
    119
    81
    Option E
    (15^2+1)-3=223
    (13^2+3)-5=167
    (11^2+5)-7=119
    (9^2+7)-9= 79( not 81)
    (7^2 + 5)-11=43
    

     

14. 10, 40, 480, 30730, 7864320
    10
    40
    480
    30730
    7864320
    Option D
    10 * 4=40
    30* 42=480
    480* 43=30720 (not 30730)
    30720* 44=7864320
    

     

15. 1. 5 , 3, 5.5 , 9, 13.5
    1.5
    3
    5.5
    9
    13.5
    Option C
    1.5*2=3
    3*1.5=4.5 (not 5.5)
    4.5*2=9
    9*1.5=13.5
    

     

16. 4, 12, 56,224,230
    4
    12
    56
    224
    230
    Option E
    4+8=12
    12*4=48
    48+8=56
    56*4=224
    224+8=232
    

     

17. 300, 301, 313, 326, 370
    300
    301
    313
    326
    370
    Option D
    300-9+10=301
    301-8+20=313
    313-7+30=336 (not 326)
    336-6+40=370
    

     

18. 2, 8, 0, 12, 6, 11
    2
    8
    0
    12
    6
    Option E
    (2*1)+6=8
    (2*2)-4= 0
    (2*3)+6=12
    (2*4)-4= 4 (not 6)
    (2*5)+6=11
    

     

19. 1.5, 7.5, 1.5, 3.75, 1.25, 2.625
    1.5
    7.5
    3.75
    1.25
    2.625
    Option D
    1.5 *5 =7.5
    7.5/5=1.5
    1.5*2.5=3.75
    3.75/5=0.75 (not 1.25)
    0.75*3.5=2.625

     

20. 6, 20, 31, 40, 53, 64
    6
    20
    31
    40
    53
    Option D
    6+4+10=20
    6+5+20=31
    6+6+30=42(not 40)
    6+7+40=53
    6+8+50=64
    

     

21. 1111, 1110, 1099, 988, – 128
    1111
    1110
    988
    1099
    -128
    Option E
    1111-1=1110
    1110-11=1099
    1099-111=988
    988-1111=- 123 (not -128)
    

     

22. 10, 17, 21, 25, 26
    10
    17
    21
    25
    26
    Option C
    10+7=17
    10+7+5=22
    10+7+5+3=25
    10+7+5+3+1=26
    

     

23. 100 , 909, 999, 1899, 10999
    100
    909
    999
    1899
    10999
    Option E
    100*9+9=909
    100*9+99=999
    100*9+999=1899
    100*9+9999=10899 (not 10999)
    

     

24. 10.5, 15.5, 5.5, 20.5 , 15.5
    10.5
    15.5
    5.5
    20.5
    15.5
    Option E
    10.5+5=15.5
    15.5-10=5.5
    5.5+15=20.5
    20.5-20=0.5 (not 15.5)
    

     

25. 10, 7, 6, 6, 6.5, 7
    10
    7
    6
    6.5
    7
    Option E
    10/2+2= 7
    7/2+2.5= 6
    6/2+3= 6
    6/2+3.5=6.5
    6.5/2+4=7.25 (not 7)
    

     

26. 50, 48.1, 46.11, 42 ,40.0001
    50
    48.1
    46.11
    42
    40.0001
    Option D
    50-1.9=48.1
    48.1-1.99=46.11
    46.11-1.999=44.111 (not 42)
    

     

27. 8, 19, 61, 244 , 1251
    8
    19
    61
    244
    1251
    Option D
    8*2+3=19
    19*3+4=61
    61*4+5=249(not 244)
    249*5+6=1251
    

     

28. 55, 46,39,32,31
    55
    46
    39
    32
    31
    Option D
    55 -5-4=46
    46-4-3=39
    39-3-2=34(not 32)
    34-2-1=31
    

     

29. 200, 45, 14, 7.8, 6.6
    200
    45
    14
    7.8
    6.6
    Option E
    200/5 +5=45
    45/5 +5=14
    14/5+5=7.8
    7.8/5+5=6.56 (not 6.6)
    

     

30. 221, 212, 220, 213, 224, 214
    221
    212
    220
    213
    224
    Option E
    221-9=212
    212+8=220
    220-7=213
    213+6=219 (not 224)
    219-5=214
    

     

1. Lalith calculates his profit percentage on selling the price whereas Rohan calculates his profit on cost price.They find the difference of their profit is Rs. 275.If the selling price for both of them is same and lalith gets 25% profit and Rohan gets 15% profit , then find their selling price?
   Rs. 2350
   Rs.2300
   Rs.2100
   Rs.2250
   Rs.2400
   Option B
   Let the selling price be = Rs.x
   CP of Lalith = (100-25)/ 100 *x= 3x/4
   CP of rohan= 100x/ (100+15) = 20x/23
   Difference = 20x/23 – 3x/4= 275
   => x= Rs.2300

    

2. A vendor purshased basket at the rate of Rs.400 from the whole sale dealer .He marked up the price by 30% and allowed a discount of 8% on each set.Then find the profit percentage?
   12%
   11%
   18%
   19.6%
   15%
   Option
   CP= Rs.400
   MP=400*130/100= Rs.520
   SP= 520 *92/100 = Rs.478.4
   P%= 478.4-400/400 * 100 =19.6%

    

3. Find the successive discount of 20%, 30% and 40% is?
   
   68.8%
   66.4%
   64.4%
   64.6%
   62.4%
   Option B
   Let CP= Rs.100
   So SP = 100 * 80/100 * 70/100 * 60/100
   SP=33.6
   Hence discount= 100- 33.6=66.4

    

4. What is the speed of the train?
   I. Length of the platform is 20% of the length of the train.
   II. The train crosses the platform in 49seconds.
   III. The train crosses the signal pole in 12seconds.
   All I, II & III
   I and Either II or III
   Only II & III
   Any two of the three
   Question cannot be answered even with the information in all three statements.
   Option E
   Length of platform or train is not given.
   So, we can’t answer the question with the information given.

    

5. What is the volume of the cylindrical tub?
   I. Area of the base is 100 square metres.
   II. Height of the tank is 5 metres.
   III. Diameter of the base is equal to height of the tank.
   
   Only I & II
   Only II & III
   Only I & III
   All I, II & III
   Either I and II or III
   Option E
   To get volume of cylinder, we need height and radius.
   So, from statement I and II or statement III volume of cylinder can be calculated.

    

6. Visma invested some amount at the rate of 6% p.a. and at the end of 3 years he got Rs.3 6000 simple interest. How much compound interest he will get on same amount and same rate of interest after 2 years.
   Rs.25000
   Rs.23,900
   Rs,24000
   Rs.24,720
   Rs.10000
   Option D
   P= 36000 *100/ 3*6 =Rs.2,00,000
   CI for first year = 2,00,000 * 6/100 = 12,000
   CI for second year=12,000 + 12,000 *6/100 = 12,000 +720 =12,720
   Total CI = 12,000 + 12,720 =24,720

    

7. The difference between compound interest and simple interest at the same rate Rs. 10000 for 4 years is Rs. 144. The rate of interest per annum is
   12%
   11%
   13%
   14%
   15%
   Option A
   CI-SI= P( r/100 ) ^2
   144= 10,000 ( r/100)^2
   144/10,000 = (r/100) ^2
   r= 12%

    

8. In a group of goats and hens, the number of legs are 24 more than twice the number of heads. What is the number of goats in the group?
   10
   11
   12
   13
   14
   Option C
   let the number of goats = x
   Number of hens = y.
   legs = 4x+2y
   heads= x+y
   S04x+2y-2x-2y= 24
   =>x= 12

    

9. If a and b are positive integers, such that a^b = 64, then (a – b)^a+b–2 = ?
   1
   2
   3
   0
   4
   Option A
   a^b= 64= 4^3
   =>a= 4 and b=3
   So (a – b)^a+b–2= 1 ^ 5=1

    

10. A man bought one bed & one cot at Rs. 2500. He sold bed at 20% profit and cot at 30%. Find the C.P. of cot if selling price of both was same?
    Rs.1800
    Rs.1900
    Rs.1000
    Rs.1100
    Rs.1200
    Option E
    Let the CP of bed= Rs.x
    CP of cot = 2500 -x
    x*120/100 =(2500 -x)130/100
    =>x=1300
    CP of cot = 2500-1300 =Rs.1200

     

1. Person 1 is thrice as good a workman as person 2 and so takes 30 days less than person 2 for doing a job. Calculate the time in which they can do the job together is.
   11 1/4
   12
   11
   12 1/2
   20
   Option A
   Let person 1 can finish the whole work in x days.
   Person 2 can finish the same work in 3x days.
   then 3x-x= 2x= 30
    x= 15 days
    Person 1 can finish the work in 15 days.
    Person 2 can finish in 45 days.
    A+B work = 1/15 + 1/45 = 4/45
    A+B can finish the work in 45/4 = 11 ¼ days
   

    

2. 32 men and 24 women together can complete a work in 16 days. 40 men can complete the same work in 32 days.How many days will 32 women can complete the same work ?
   10
   12
   15
   20
   18
   Option D
   (32 M + 24 W)* 16= 40 M * 32
   = 40M * 16 * 2
   32M + 24W = 80M
   24W =48M
   1W=2M——-1
   32W=64M—–2
   Now 40 men complete the work in 32 days.
   So 64 men complete the same work in 32* 40 / 64 = 20 days.
   Hence 32 women complete the same work in 20 days.
   

    

3. Four examiners can examine a certain number of answer papers in 10 days by working for 5 a day. for how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?
   10
   15
   20
   25
   12
   Option A
   M1 * D1* H1 / W1 = M2 * D2* H2 / W2
   M1 = 4 D1= 10 H1= 5
   W1 = 1 M2 =2 D2 = 20
   H2 = ? W2= 2
   4*10 *5/1 = 2* 20 *H2/2
   =>H2= 10h
   

    

4. 2 boys and 3 girls together or 4 boys can complete a piece of work in 20 days. 3 boys and 3 girls will complete the same work in how many days?
   
   15
   16
   17
   18
   19
   Option B
   2 boys + 3 girls= 4 boys
   =>2 boys = 3 girls
   =>3 boys + 3 girls = 5 boys ( 3 girls= 2 boys)
   M1D1= M2D2
   =>4* 20 = 5 *D2
   D2 = 16 days.
   

    

5. Varun gets Rs. 700 for every day that the works. If he runs Rs.19600 in a month of 62 days, for how many days did he work?
   
   21
   20
   23
   28
   25
   Option D
   Varun gets Rs.700 for 1 day of work
   Amount received by varun for 62 days.
   Number of days Varun worked in a month = 19600/ 700 =28 days.
   

    

6. Person A and Person B can complete a piece of work in 30days and 20 days respectively. Then contracted to complete the work for Rs. 60,000.The share of Person A in the contracted money will be
   
   24,000
   25,000
   20,000
   19,000
   26,000
   Option A
   Total amount = Rs.60,000
   Person A’s 1 day work = 1/30
   Person B’s 1 day work =1/20
   Ratio = 1/30 : 1/20 = 2:3
   Sum of the ratio = 2+3 = 5
   Person A’ s share = 2/5 * 60,000 = Rs.24,000

    

7. There are n number of workers can finish a project work in 15 days. If there are 3 workers could be finished in 5 days less. the original number of workers are:
   
   3
   5
   7
   4
   6
   Option E
   M1M2=M2D2
   n*15 = ( n+3) * 10
   n=6
   

    

8. 84 women can do a piece of work in 36 days. How many women are required to complete the same work in 42 days?
   
   72
   36
   78
   44
   67
   Option A
   84 women – 36 days
   1 women–84 * 36 days
   Number of women required = 84 * 36/42 = 72 women

    

9. Person A earns Rs. 250 in 16 days and person B earns Rs.280 in 20 days. what is the ratio of their earnings?
   
   25:112
   12:112
   120:112
   125:112
   125:110
   Option D
   Required ratio = 250/16 : 280/ 20
   =5000:4480
   =125:112
   

    

10. Hasini and her daughter received Rs. 800 as wages for 5 days work. Hasini’s work was three times more efficiency han her daughter. Then what is the daily wage of her daughter?
    
    35
    40
    45
    55
    65
    Option B
    Hasini: daughter = 3:1
    daughter share = ¼ * 800 = Rs.200
    So daily wage = 200/ 5 = Rs.40