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    31Jul, 2021
    Quantitative Aptitude: Mensuration Questions Set 17
    1. What is the area of a tringle whose sides are 7cm and 9cm ?
      18 √2
      42 √6
      12 √2
      5 √3
      12 √5
      Option E
      S = 7 + 8 + 9/2 = 24/2 = 12
      Area of tringle = √ S(S – a) (S – b) (S – c)
      = √ 12 * 5 * 4 * 3
      = 12 √ 5

       

    2. The perimeter of a square is 96 cm. If the radius of a circle is 3 cm less than the side of that square, then what is area of the circle ?
      1280
      1345
      980
      1045
      1386
      Option E
      perimeter of square = 96cm
      side of square = 96/4 = 24cm
      radius of circle = 24 – 3 = 21 cm
      area of circle = πr^2 = 22/7 * 21 *21 = 1386 cm^2

       

    3. The area of a rectangular field is 252cm^2 and ratio between length and breadth is 9 :7. If cost of wire which is to be fenced is rs.2 per meter, then find cost of fencing the field ?
      240
      340
      130
      145
      128
      Option E
      Let length and breadth are 9x and 7x respectively.
      9x * 7x = 252
      x = 2
      length = 9 * 2 = 18
      breadth = 7 * 2 = 14
      perimeter of rectangular field = 2(18 + 14) = 64m
      cost of fencing wire = 64 * 2 = 128

       

    4. The perimeter of rectangle is 72m and ratio between the length and breadth is 11 : 7. What is the difference between the half of the length and one-seventh of the breadth of rectangle ?
      9m
      6m
      12m
      15m
      17m
      Option A
      Let length and breadth of rectangle 11x and 7x respectively.
      perimeter = 72m
      2(11x + 7x) = 72
      x = 2
      length = 11 * 2 = 22
      breadth = 7 * 2 = 14
      difference = 22/2 – 14 * 1/7 = 11 – 2 = 9m

       

    5. There are two circle A and B and diameter of circle A is equal to be the radius of circle B,. If radius of circle A is 14 cm, Then find the difference between the perimeter of two circle ?
      48cm
      42cm
      154cm
      88cm
      28cm
      Option D
      Radius of circle A = 14 cm
      Diameter of circle A = 14 * 2 = 28
      radius of circle B = 28
      perimeter of circle A = 2 * 22/7 * 14 = 88cm
      perimeter of circle B = 2 * 22/7 * 28 = 176 cm
      difference = 176 – 88 = 88cm

       

    6. Curved surface area of a cylinder is 2640 cm^2 and its height is 20cm. Find the volume of a cylinder.
      27720 cm^2
      4840 cm^2
      22350 cm^2
      32430 cm^2
      16340 cm^2
      Option A
      C.S.A = 2640
      2πrh = 2640
      2 * 22/7 * r * 20 = 2640
      r = 2640 * 7 / 44 * 20 = 21
      volume = πr^2h = 22/7 * 21 * 21 * 20 = 27720 cm^2

       

    7. The length of the rectangle A is 4 m more than the breadth of rectangle and perimeter of rectangle A is 56m. What is the area of rectangle B whose length is equal to the length of rectangle A and breadth is 8 m ?
      64 m^2
      48 m^2
      24 m^2
      128 m^2
      120 m^2
      Option D
      Let breadth of rectangle A = x
      length = x + 4
      perimeter = 56
      2(x + x + 4) = 56
      4x + 8 = 56
      x = 12
      length of rectangle A = 12 + 4 = 16
      length of rectangle B = 16
      breadth = 8
      area = 16 * 8 = 128 m^2

       

    8. A trapezium whose parallel sides are 18 cm and 14 cm long and distance between them ids 9cm. What is the area of trapezium ?
      158 cm^2
      240 cm^2
      144 cm^2
      152 cm^2
      245 cm^2
      Option C
      Area of trapezium = 1/2 * (18 + 14) * 9 = 144 cm ^2

       

    9. If the ratio of two curved surface area of two cylinder A and B are 4 : 5 and ratio of their radius is 2 : 1, then what is the ratio of their volumes ?
      8 : 7
      9 : 10
      13 : 7
      8 : 5
      3 : 4
      Option D
      Let radius of cylinder A and B = r_1 and r_2
      height cylinder A and B = h_1 and h_2
      2πr_1 h_1 / 2πr_2 h_2 = 4/5
      h_1 / h_2 * 2/1 = 4/5
      h_1 / h_2 = 2/5
      ratio of their volumes = π^2r_1 h_1 / π^2r_2 h_2
      (2)^2 * 2 / (1)^2 * 5 = 8/5

       

    10. If the radius of cone is increased by 50% and height is decreased by 40%, then find the percentage change in the volume ?
      55% decrease
      40% increase
      45% decrease
      48% increase
      50% decrease
      Option A
      Let radius of cone = 100
      after increased radius of cone = 100 + 50 = 150
      ratio = 2 : 3
      let height of cone = 100
      after decreased radius of cone = 100 – 40 = 60
      ratio = 5 : 3
      volume = 1/3 * πr^2h = 1/3 * 22/7 * 4 * 5 = 440 / 21
      volume = 1/3 * πr^2h = 1/3 * 22/7 * 3 * 3 = 198/21
      decrease = 242 / 440 * 100 = 55%

       

    01
    30Jul, 2021
    Quantitative Aptitude: Probability Questions – Set 22
    1. Two dice are rolled randomly. Find the probability to get sum is 10.
      2/5
      14
      2/9
      1/12
      5/8
      Option D
      Required = (6 , 4 ) , (4 , 6) , ( 5, 5) = 3
      total = 6 * 6 = 36
      probability = 3/36 = 1/12

       

    2. Two dices are rolled out together, then what is the probability of getting a number of one dice greater than the number of other dice ?
      2/3
      1/6
      3/8
      1/8
      5/6
      Option E
      Non-favorable events = (1 , 1) , (2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) , (6,6) = 6
      total = 6 * 6 = 36
      probability of non-favorable events = 6/36 = 1/6
      probability of favorable events = 1 – 1/6 = 5/6

       

    3. If 2 cards is drawn at randomly from 52 cards, then find the probability of getting both are red cards.
      13/28
      26/105
      28/108
      25/102
      none of these
      Option D
      Required = 26C2 = 26 * 25/2 = 13 * 25
      total = 52C2 = 52 * 51 / 2 = 26 * 51
      probability = 13 * 25 / 26 * 51 = 25 /102

       

    4. In how many ways, we can arrange the letters of the word ‘LIGHT’ ?
      84
      28
      140
      160
      120
      Option E
      Ways = 5! = 5 * 4 * 3 * 2 * 1 = 120

       

    5. In how many different ways, we can arrange the letters of the word ‘MOUSE’ , so that the middle position is always occupied by ‘S’ ?
      25
      24
      48
      42
      68
      Option B
      Ways = 4! = 4 * 3 * 2 * 1 = 24

       

    6. How many ways 6 books can be selected from 14 different books , if two particular books are always selected ?
      495
      480
      231
      384
      520
      Option A
      Available objects = 14 – 2 = 12
      Ways = 12C4 = 12 * 11 * 10 * 9/4 * 3 * 2 * 1 = 495

       

    7. A bag contains 2 white balls, 3 pink balls and 2 black balls. 2 balls are drawn randomly. What is the probability that there is no black balls ?
      8/21
      10/21
      1/8
      3/5
      6/11
      Option B
      Required = 5C2 = 5*4/2 = 10
      total = 7C2 = 7 * 6 / 2 = 21
      probability = 10/21

       

    8. When two coins are tossed simultaneously, then find the probability of getting at least one tail.
      5
      3
      3/4
      1/4
      2/5
      Option C
      Required = ( 1 head , 1 tail ) , ( 2 tails) = (2C1) + (2C2) = 2 + 1 = 3
      total = 2^2 = 4
      probability = 3/4

       

    9. A bag contains 4 red balls, 2 blue balls and 2 green balls . If two balls are drawn randomly from the bag , then find the probability of getting both balls of different color.
      2/7
      5/8
      5/7
      4
      8
      Option C
      probability = 4C1 * 2C1 / 8C2 + 4C1 * 2C1 / 8C2 + 2C1 * 2C1 / 8C2
      (4 * 2 * 2)/ 8 * 7 + (4 * 2 * 2)/ 8 * 7 + (2 * 2 * 2) / 8 * 7 = 2/7 + 2/7 + 1/7 = 5/7

       

    10. A group of students sitting around a rectangular table, find probability of 2 specified students sitting together.
      3/8
      2/7
      8/7
      3/8
      6/11
      Option B
      Favorable cases = 6! * 2!
      total cases = 7!
      probability = 6! * 2! /7! = 2/7

       

    02
    29Jul, 2021
    Quantitative Aptitude: Number Series Set 154
    1. 32, 80, 200, 500, 1250 ?
      3125
      4125
      2500
      3750
      5125
      Option A
      The series is (32*2.5), (80*2.5), (200*2.5)…..

       

    2. 12, 29, 63, 131, 267, ?
      541
      538
      429
      539
      342
      Option D
      The series is (*2+5), (*2+5)…

       

    3. 48, 51, 56, 63, ?, 87
      72
      74
      75
      78
      76
      Option B
      The series (+3), (+5), (+7), (+11), (+13) the addition of prime numbers.

       

    4. 1248, 1184, 1135, 1099, 1074, ?
      1158
      538
      1058
      1220
      625
      Option C
      The series (-8^2), (-7^2), (-6^2)…

       

    5. 6420, 6435, 6465, 6510, ?, 6645
      6420
      6500
      6530
      6570
      6424
      Option D
      The series is (+15), (+30), (+45)…

       

    6. 8, 8, 12, 28, 88, 932
      28
      88
      932
      12
      8
      Option B
      The series is (*.5+4), (*1+4), (*2+4), (*4+4), (*8+4)

       

    7. 320, 330, 310, 340, 300, 360
      300
      360
      340
      320
      310
      Option B
      The series is (+10), (-20), (+30), (-40), (+50)

       

    8. 32, 33, 41, 68, 114, 257
      257
      68
      41
      114
      33
      Option D
      The series is (+1^3), (+2^3), (+3^3), (+4^3), (+5^3 )

       

    9. 18, 36, 108, 432, 2160, 12360
      12360
      2160
      432
      108
      36
      Option A
      The series is (*2), (*3), (*4)…

       

    10. 45, 49, 41, 45, 37, 42
      45
      49
      41
      42
      37
      Option D
      The series is (+4), (-8), (+4), (-8), (+4)

       

    03
    28Jul, 2021
    Quantitative Aptitude: Partnership Set 23
    1. Three partners A,B and C undergo a partnership. Their investment are rs.2500, rs.30000 and rs.45000 for a time period of 4years, 3years and 2years respectively, find the ratio of their profit ?
      15:8:7
      10:9:9
      5:4:3
      8:7:5
      none of these
      Option B
      The ratio are their profit =
      25000*4:30000*3:45000*2
      =100000:90000:90000
      =10:9:9

       

    2. Sakti stands business with rs.5000 and after 6 months Sagar joins with Sakti as his partner. After a year the profit are divided in the ratio of 4:5 How much did Sagar contribute ?
      14000
      9500
      10000
      13500
      12500
      Option E
      Let Sagar contributes in business =x
      profit ratio= 4:5
      (5000*12)/x*6=4/5
      24x=300000
      x =12500

       

    3. P,Q,R invested capitals in the ratio of 3:4:7. The timing of their investment being in the ratio of 4:6:3. What ratio would their profits be distributed ?
      4:8:7
      7:8:9
      9:9:9
      2:3:7
      none of these
      Option A
      let the capitals invested by P,Q,R be 3x, 4x, 7x respectively
      and timing of their investments be 4y, 6y, 3y respectively
      profit ratio of P, Q, R=(3x*4y):(4x*6y):(7x*3y)
      =12xy:24xy:21xy
      =4:8:7

       

    4. A is working partner and B is a sleeping partner. A puts in rs. 10000 and B puts 12000. A received 12.5% of profit for managing the business and rest is divided in proportion to their capitals. What is A’s share of profit in a profit of rs.880 after a year.
      540
      380
      460
      480
      500
      Option C
      A’s share for managing the business=12.5% of 880=110
      remaining profit=880-110=770
      profit ratio of A and B= 10000:12000=5:6
      A’s share=770*5/11=350
      A’s total profit=110+350=460

       

    5. C and D started a business with initial investments in the ratio of 9:10 and their annual profits were in the ratio of 3:5. If C invested the money for 8 months, for how many months did D invests his money ?
      12 months
      10 months
      11 months
      8 months
      6 months
      Option A
      let D invests his money for x months
      ATQ, (9*8)/10*x=3/5
      30x=360
      x=12 months

       

    6. Meena started a business investing rs.12000. After 4 months Leena joined her with a capital of rs.15000 at the end of the year the total profit was rs.4400. What is the share of profit of Meena ?
      3600
      2000
      3000
      2400
      3200
      Option D
      Profit ratio of Meena and Leena
      = 12000*12:15000*8
      =144000:120000
      =6:5
      Meena’s profit share = 4400*6/11
      =2400

       

    7. Amit and Sumit invested rs.2000 and rs.3000 respectively in a partnership. After 1 year Sumit increased his amount by 33.33% and at the end of the 3 years, difference between his profit share is rs.500 .Find the profit share of sumit.
      1200
      1100
      800
      1000
      700
      Option B
      Ratio of profit share of Amit and Sumit
      =(2000*3):(3000*1+4000*2)
      =6000:11000 =6:11
      Difference of profit share =500
      profit share of sumit =500/5*11 =1100

       

    8. P and Q invested total rs.8000 in business and ratio of time period for which P and Q invested is 3:2. If they got total profit of rs.3600 and profit share of P is rs.1200, then find investment of Q ?
      5000
      6000
      4000
      3000
      4500
      Option B
      Let P’s invested =x
      Q’s invested = 8000-x
      ratio of their time =3:2
      3x/2(8000-x) =1200/2400
      3x/16000-2x =1/2
      6x = 16000-2x
      8x =16000
      x =2000
      invested by Q =8000-2000 =6000

       

    9. Miki and Liza entered into partnership by investing rs.6000 and rs.7000 respectively. Period of investment of Miki and Liza is 5 months and x months respectively. In at the end of the year, Miki received rs.30000 as profit out of total profit of rs.72000, then find x.
      5 months
      6 months
      8 months
      4 months
      2 months
      Option B
      Profit ratio of Miki and Liza =6000*5:7000*x
      30:7x
      Miki’s profit =30000
      Liza’s profit =72000-30000
      = 42000
      30/7x =30000/42000
      7x =42
      x= 6months .

       

    10. Deepak and Dinesh invested rs.25000 and rs.50000 respectively in a business. If Dinesh invested for 8 months and total profit at the end of the year is rs.63000, then find profit share of Deepak.
      20000
      48000
      25000
      40000
      27000
      Option E
      profit sharing ratio of Deepak and Dinesh=(25000*12):(50000*8)=3:4
      total profit=63000
      Deepak’s profit share=63000*3/7=27000

       

    04
    27Jul, 2021
    Quantitative Aptitude: Ratio and Proportion Questions Set 12
    1. In a mixture of 80 liters, the ratio of milks and water is 3:2 . How much water must be added to this mixture so that the ratio of milk and water becomes 3:4.
      24
      28
      40
      36
      32
      Option E
      Total mixture =80 liters.
      milk =80*3/5 =48
      water =80*2/5 =32
      Let, x liters of water is added.
      48/32+x =3/4
      32+x =64
      x =64-32 =32 liters.

       

    2. In a school the students of three classes are in the ratio of 2:3:5 . If 20 students are increased in every class the ratio of changes is 4:5:7. What is the total number of students in the three classes before the class increased .
      200
      100
      250
      300
      400
      Option B
      Let students in three classes be
      2x, 3x and 5x respectively.
      According to the question ,
      (2x+20):(3x+20):(5x+20) =4:5:7
      2x+20/3x+20 =4/5
      12x+80 =10x+100
      2x=20
      x=10
      Total students =(2*10)+(3*10)+(5*10)
      = 20+30+50 =100

       

    3. If 16 cows cost as much as 8 bullocks, 10 bullocks cost as much as 5 horses and 3 horses cost as much as 4 camels. If the cost of one camel is rs.3300. Find the cost of one cow is,
      2100
      2200
      2300
      1100
      1200
      Option D
      1 camel cost=3300
      4 camel cost=13200
      3 horses cost=13200
      1 horses cost=4400
      5 horses cost=22000
      10 bullocks cost=22000
      1 bullocks cost=2200
      8 bullocks cost =17600
      16 cows cost =17600
      1 cows cost =1100

       

    4. The ratio of the earning of A and B is 3:5. If the earning of a increased by one-forth and the earning of B decreased by one-forth, then find the new ratio of their earning ?
      2:3
      1:1
      3:4
      5:2
      2:5
      Option B
      Let earning of A and B be 3x and 5x.
      New ratio of their earning = 3x*5/4:5x*3/4 =1:1

       

    5. A some of money is to be distributed among A,B,C,D in the proportion of 3:5:2:4 . If D gets 3000 more than C, then find total money which is distribute among all.
      30000
      21000
      25000
      28000
      24000
      Option B
      Let the money is distributed among A,B,C and D be 3x,5x,2x and 4x respectively.
      4x-2x =3000
      2x =3000
      x =1500
      total amount of money distributed =3x+5x+2x+4x =14x
      = 14*1500 =21000

       

    6. The ratio of the number of boys and girls in a college is 7:9. If the percentage increase in the number of boys and girls be 20% and 30% respectively. The total number of boys and girls in college before increase is 1440, then find ratio of boys and girls in the college after increased.
      28:39
      38:43
      25:28
      35:28
      30:37
      Option A
      ratio of boys and girls=7:9
      total boys and girls=1440
      boys=1440*7/16=630
      girls=1440*9/16=810
      the number of boys after increased=630*120/100=756
      the number of girls after increased=810*130/100=1053
      ratio of boys and girls after increased=756:1053=28:39

       

    7. Salaries of Ram and Rohit are in the ratio of 4:5. If the salary of each is increased by rs.3000, the new ratio becomes 10:11. What is initial salary of Rohit.
      2700
      3000
      4200
      2500
      3500
      Option D
      let salaries of Ram and Rohit be 4x and 5x
      (4x+3000)/(5x+3000)=10/11
      44x+33000=50x+30000
      6x=3000
      x=500
      initial salary of Rohit=5x=5*500=2500

       

    8. A contains a mixture of 56 liters of wine and water in the ratio of 3:4 . If 28 liter of mixture is taken and 8 liter of wine is added , then find the ratio of new mixture .
      3:2
      8:3
      5:5
      5:4
      3:4
      Option D
      Ratio of wine and water =3:4
      wine =56*3/7 =24
      water =56*4/7 =32
      28 liter of mixture taken out wine = 24-(28*3/7) =24-12 =12
      water=32-(24*4/7) =32-16 =16
      8 liters of wined is added then ,
      new ratio of wine and water =(12+8):16 =20:16 =5:4

       

    9. 48% of A is equal to 64% of B, then find the ratio of A and B ?
      3:2
      3:4
      7:3
      5:4
      4:3
      Option E
      48% of A = 64% of B
      A/B=64/48=4:3

       

    10. The ratio of three numbers is 2:4:5 and sum of their squares is 1125. Find the sum of the numbers.
      60
      45
      50
      55
      65
      Option D
      ratio of three numbers=2:4:5
      let the numbers be 2x, 4x and 5x
      sum of their squares=1125
      4x^2+16x^2+25x^2=1125
      45x^2=1125
      x^2=25
      x=5
      the sum of the numbers=2x+4x+5x=11x=11*5=55

       

    05
    26Jul, 2021
    Quantitative Aptitude: Number Series Set 153
    1. 960, 839, 758, 709, 684, ?
      685
      550
      485
      675
      745
      Option D
      the series is, (-11^2), (-9^2), (-7^2)…

       

    2. 340, 356, 382, 418, 464, ?
      520
      480
      540
      516
      496
      Option A
      the series is, +16, +26, +36, +46, +56

       

    3. 15, 41, 78, 128, 193, ?
      278
      275
      385
      345
      264
      Option B
      the series is, +(5^2+1), +(6^2+1), +(7^2+1)…

       

    4. 335, 351, 383, 431, ?, 575
      487
      535
      530
      485
      495
      Option E
      the series is, +16, +32, +48, +64, +80

       

    5. 13, 15, 21, 33, 53, ?
      83
      96
      95
      85
      80
      Option A
      the series is, +(1*2), +(2*3), +(3*4), +(4*5), +(5*6)

       

    6. 8, 18, 57, 232, 1165, 6994
      1165
      232
      57
      6994
      8
      Option D
      the series is, (*2+2), (*3+3), (*4+4)…

       

    7. 14, 20, 32, 44, 58, 74
      14
      20
      32
      74
      44
      Option B
      the series is, +8, +10, +12, +14, +16

       

    8. 244, 202, 172, 152, 140, 132
      132
      140
      244
      172
      152
      Option A
      the series is, -(6^2+6), -(5^2+5), -(4^2+4)…

       

    9. 35, 44, 28, 53, 17, 65
      35
      65
      17
      53
      28
      Option B
      the series is, +3^2, -4^2, +5^2, -6^2, +7^2

       

    10. 36, 23, 28, 47, 99, 252
      99
      47
      28
      252
      36
      Option D
      the series is, (*.5+5), (*1+5), (*1.5+5), (*2+5), (*2.5+5)

       

    06
    25Jul, 2021
    Quantitative Aptitude: Quadratic Equations Questions Set 77
    1. x^2+14x+24 =0
      y^2+18x+65 =0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option E
      I. x^2+12x+2x+24 =0
      x= -12, -2
      II. x^2+13x+5x+65 =0
      x= -13, -5

       

    2. I. 2x^2+23x++65 =0
      II. 3x^2+25x+50=0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option D
      I. 2x^2+13x+10x+65=0
      2x=-13, -10
      x=-6.5, -5
      II. 3x^2+15x+10x+50 =0
      3x= -15,-10
      x=-5, -3.33

       

    3. I. x^2-18x+72=0
      II. y^2-8y+15 =0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option A
      I. x^2-12x-6x+72=0
      x =12, 6
      II. y^2-5y-3y+15 =0
      y=5, 3

       

    4. I. x^3= 729
      II. y =√81
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option E
      I. x^3=729
      x=9
      II. y=9

       

    5. I. x^2-11x+18 =0
      II. y^2-23y+132 =0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option B
      I. x^2-9x-2x+18 =0
      x=9, 2
      II. y^2-12y-11y+132 =0
      y^2 =12, 11

       

    6. I. 4x^2-12x+5 =0
      II. 2y^2+3y-5=0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option E
      I. 4x^2-10x-2x+5 =0
      4x=10, 2
      x= 2.5, .5
      II. 2y^2+5y-2y-5 =0
      2y= -5, 2
      y= -2.5, 1

       

    7. I. x^2-3x+28 =0
      II. y^2+3y-18=0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option E
      I. x^2-7x+4x+28=0
      x=7, -4
      II. y^2+6y-3y-18=0
      y=-6, 3

       

    8. I. x^4=256
      II. y^3=64
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option D
      I. x^4=256
      x=4, -4
      II. y^3=64
      y=4, 4

       

    9. I. x^2-35x+250=0
      Ii. y^2-14y+40=0
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option C
      I. x^2-25x-10x+250=0
      x=25,10
      II. y^2-10y-4y+40=0
      y=10,4

       

    10. I. x+5=√100
      II. y+8=√144
      X>Y
      X
      X≥Y
      X≤Y
      X=Y or no relation
      Option A
      I. x+5=√100
      x+5=10
      x=5
      II. y+8=√144
      y+8=12
      y=4

       

    07
    25Jul, 2021
    Quantitative Aptitude: Simplification Questions Set 116
    1. Direction: What will come in place of question(?) marks in the following questions ?
      13540+12981+1519-? =25000
      4260
      3140
      3340
      3040
      none of these
      Option D
      13540+12981+1519-25000 =3040

       

    2. (1696÷4-?)10=1200
      404
      304
      340
      420
      520
      Option B
      (424-x)10 =1200
      4240-10x =1200
      x =304

       

    3. 19*12*8+94 =?
      1918
      2018
      2200
      1900
      1920
      Option A
      1824+94=1918

       

    4. 120% of 55+240% of 25+? =140
      16
      14
      20
      22
      24
      Option B
      66+60+? =140
      ?=14

       

    5. (196/27*4)*(8/20)*(180/9)*(81/7)= ?
      178
      210
      180
      168
      none of these
      Option D
      7*8*3 =168

       

    6. Direction: What will come in place of ‘x’ in the following questions given below ?
      20% of 25% of 40% of 1200 =x+8
      22
      16
      12
      18
      15
      Option B
      1/5*1/4*2/5*1200 =x+8
      x= 24-8 =16

       

    7. 52^2+62^2+75^2-85^2 =x+48
      5000
      6000
      5200
      4200
      none of these
      Option A
      2704+3844+5625-7225-48 =x
      12273-7225-48 =x
      x =5000

       

    8. √3025+√1600-81+x=79
      55
      64
      60
      65
      70
      Option D
      55+40-81+x =79
      x= 65

       

    9. 520/13+980-1020/17+20% of 55 =x+88
      883
      880
      920
      780
      783
      Option A
      40+980-60+11 =x+88
      x= 883

       

    10. 168÷21*8+218+x =525
      345
      445
      355
      245
      280
      Option D
      64+218+x =527
      x= 527-282
      x= 245

       

    08
    24Jul, 2021
    Quantitative Aptitude: Simplification Questions Set 115
    1. Directions : What will come in place of questions mark ( ? ) in the following questions ?
      37.5% of 288 + 17.5% of 1600 – 292 = ?
      85
      42
      98
      56
      96
      Option E
      3/8 * 288 + 7/40 * 1600 – 292 = ?
      108 + 280 – 292 = ?
      ? = 96

       

    2. 442 – 1325 + 2480 – 225 = ?
      2372
      4220
      1372
      2420
      3250
      Option C
      2480 + 442 – 1325 – 225 = ?
      2922 – 1550 = ?
      ? = 1372

       

    3. 54% of 5200 – 338 + 288/12 = ?
      2850
      3250
      348
      2494
      3296
      Option D
      2808 – 338 + 24 = ?
      ? = 2494

       

    4. 450 ÷ 25 + 328 + 19% of 2200 = ?
      286
      664
      764
      280
      250
      Option C
      18 + 328 + 418 = ?
      ? = 764

       

    5. 1520 ÷ 5 ÷ 2 * 20 + 325 = ?
      8250
      3268
      3365
      5240
      4280
      Option C
      1520 / (5 * 2 ) * 20 + 325 = ?
      3040 + 325 = ?
      ? = 3365

       

    6. 8^3 + 5^3 + 260 – √1024 = ?
      980
      865
      1250
      740
      634
      Option B
      512 + 125 + 260 – 32 = ?
      ? = 897 – 32
      ? = 865

       

    7. √4624 + √1296 – ∛5832 = ?
      67
      56
      89
      45
      86
      Option E
      68 + 36 – 18 = ?
      ? = 86

       

    8. 5 2/3 + 2 1/4 – 1 1/2 = ?
      3 2/5
      5 1/4
      2 1/5
      3 5/6
      6 5/12
      Option E
      5 2/3 + 2 1/4 – 1 1/2 = ?
      6 ( 8 + 3 – 6 / 12 ) = ?
      ? = 6 5/12

       

    9. (169 + √225) * 2 = ?
      86
      66
      52
      56
      42
      Option D
      (13 + 15) * 2 = ?
      ? = 56

       

    10. ( 8 * 6 ÷ 12 ) * 5 + 12 = ?
      38
      32
      54
      89
      46
      Option B
      8 * 6 /12 * 5 + 12 = ?
      20 + 12 = ?
      ? = 32

       

    09
    23Jul, 2021
    Quantitative Aptitude: Mixture and Alligation Set 16
    1. In what ratio must tea at rs.36 per kg be mixed with tea at rs.40 per kg so that the mixture must be worth rs.37 per kg ?
      2:1
      5:2
      2:3
      3:1
      2:2
      Option D
      let tea at rs.36 per kg mixed=x kg
      and tea at rs.40 per kg mixed=y kg
      (36x+40y)x+y=37
      36x+40y=37x+37y
      x=3y
      x:y=3:1

       

    2. A person has a chemical of rs.25 per liter. In what ratio should water be mixed in that chemical so that after selling the mixture at rs.20 per liter he may get a profit of 25% ?
      15:12
      16:9
      5:4
      8:4
      4:5
      Option B
      CP of chemical =rs.25
      CP of water=rs.0
      SP of mixture=rs.20
      CP of mixture=20*4/5=rs.16
      ratio of chemical and water be mixed=0-16/16-25=16/9=16:9

       

    3. A vessel contains 700 liters mixture of milk and water in the ratio 4:3 respectively. If 140 liters mixture from the vessel is completely replaced with milk, then find ratio of milk to water in the final mixture in the vessel.
      12:25
      23:12
      13:28
      23:15
      12:23
      Option B
      total mixture=700
      ratio of milk to water=4:3
      milk=700*4/7=400
      water=700*3/7=300
      140 liter mixture is replace with milk
      ratio=(400-140*4/7+140)/(300-140*3/7)=320+140/240=460/240=23:12

       

    4. In a 88 liters of mixture the ratio of milk and water 7:4. If x liter of water is mixed in this mixture, so that ratio of water to milk 3:4. Find the value of x.
      12
      15
      10
      20
      18
      Option C
      milk in the mixture =88*7/11=56
      water in the mixture=88*4/11=32
      x liter of water mixed
      56/32+x=4/3
      42=32+x
      x=10 liter

       

    5. Two vessels A & B contains mixture of milk and water in the ratio of 8:7 and 3:2 respectively. If ratio of quantity of mixture in vessels A and B 6:5 and both mixed together, then find ratio of milk to water in resulting mixture.
      34:25
      31:24
      8:9
      15:28
      24:25
      Option B
      let total mixture in vessel A and B be 60x and 50x respectively
      total milk in resulting mixture=60x*8/15+50x*3/5=32x+30x=62x
      total water in resulting mixture=60x*7/15+50x*2/5=28x+20x=48x
      ratio of milk and water=62x:48x=31:24

       

    6. In a mixture of 45 liters, the ratio of chemical and water is 5:4. How much chemical must be added to make the ratio of 3:2 ?
      8
      6
      10
      5
      12
      Option D
      chemical in the mixture=45*5/9=25
      water in the mixture=45*4/9=20
      let chemical added to the mixture=x
      25+x/20=3/2
      2x+50=60
      x=5

       

    7. Ratio between milk and water in a mixture is 5:2. When 15 liters of water is added in the mixture then ratio becomes 5:3. Find the initial quantity of mixture.
      100
      105
      90
      120
      95
      Option B
      let milk in the mixture =5x
      and water=2x
      5x/2x+15=5/3
      15x=10x+75
      5x=75
      x=15
      initial mixture=7x=7*15=105 liters

       

    8. Ratio between chemical and water in a 120 liters of mixture is 8:7. When 30 liters of mixture is taken out and 6 liter of water is added, then what will be the ratio between chemical and water in new mixture ?
      2:1
      5:4
      3:4
      3:1
      1:1
      Option E
      milk in the mixture=120*8/15=64
      water in the mixture=120*7/15=56
      ATQ, ratio=(64-30*8/15)/(56-30*7/15+6)
      =64-16/56-14+6=48/48
      =1:1

       

    9. In a vessel ratio of milk to water is 5:3. 40 liters of mixture is taken out and 20 liters of water is added so that quantity of milk in the new mixture is 10 liters more than that of water. Find initial quantity of the mixture.
      180
      160
      150
      170
      120
      Option B
      let milk and water in the mixture be 5x and 3x respectively
      5x-40*5/8-(3x-40*3/8)=10
      5x-25-(3x-15+20)=10
      5x-2x-3x-5=10
      2x-30=10
      2x=40
      x=20
      initial mixture=8x=8*20=160

       

    10. Container A and B contains 400 liters of milk and 160 liters of water respectively. 40% of the milk and 40% of water is mixed together in a separate container. Find the ratio of milk to water in the mixture thus formed.
      3:2
      2:1
      8:5
      5:4
      2:5
      Option D
      ratio milk to water=400*40/100:160*40/100=160:64=10:8=5:4

       

    10