1. Direction: What should be come in place of question (?) mark in the given number series ?
   23, 23, 27, 43, 79, 160
   23
   27
   43
   79
   160
   Option E
   the series is, 0^2=0 , 2^2=4, 4^2=16, 6^2=36…

    

2. 16, 9, 11, 19.5, 45, 112.5
   16
   45
   11
   9
   19.5
   Option B
   the series is, (*.5+1), (*1+2), (1.5+3)…

    

3. 320, 328, 344, 368, 440, 568
   320
   344
   368
   440
   568
   Option C
   the series is, +8, +16,+32, +64…

    

4. 22, 44, 88, 528, 2640, 15840
   528
   88
   2640
   44
   22
   Option B
   the series is *2, *3, *4, *5…

    

5. 56, 80, 112, 136, 168, 200
   56
   112
   168
   136
   200
   Option E
   the series is, +24, +32, +24, +32…

    

6. 20, 30, 50, 80, 120, ?
   170
   150
   160
   190
   200
   Option A
   the series is, +10, +20, +30, +40, +50

    

7. 15, 28, 48, 82, 137, ?
   210
   220
   230
   200
   180
   Option B
   the series is difference of difference.

    

8. 330, 343, 360, 379, 402, ?
   431
   427
   432
   435
   440
   Option A
   the series is, 13, 17, 19, 23, 29 difference of consecutive prime numbers.

    

9. 9600, 1920, 480, ?, 80, 80
   200
   320
   80
   240
   160
   Option E
   the series is, ÷5, ÷4, ÷3, ÷2, ÷1

    

10. 25, 55, 85, 115, 145, ?
    165
    160
    170
    175
    180
    Option D
    the series is +30, +30, +30…

     

1. A and B can do a work together in 20 days . B and C can do the same work in 15 days C and A also can do the same work in 12 days . In how many days all together can complete the total work and also find the who of them works of the fasted speed.
   20 days, B
   10 days, C
   12 days,A
   18 days, B
   15 days, C
   Option B
   LCM of 20,15 and 12 = 60
   total work =60
   efficiency of A and B together = 60/20=3
   efficiency of B and C together = 60/15 =4
   efficiency of C and A together =60/12=5
   2A+2B+2C =12
   (A+B+C)’s total efficiency = 6
   A,B and C together complete the work =60/6 =10 days .
   A’s efficiency =6-4 =2
   B’s efficiency= 6-5 =1
   C’s efficiency=6-3 = 3
   C works at the fastest speed.

    

2. A works at half the speed of B and C works at double the speed of B . If they all together can do a work in 40 days. In how many days will A and C complete the same work together ?
   60
   56
   58
   65
   70
   Option B
   Let,
   B’s works speed =2x
   A’s works speed = x
   C’s works speed =4x
   Total work=40*7x=280x
   A & C complete the same work together=280x/5x=56 days

    

3. M, N & P can do a work individually in 10, 15, and 20 days respectively. If they work together then in how many days the work will be completed ?
   60/13
   60/14
   55/12
   50/11
   5
   Option A
   LCM of 10,15,20=60
   total work=60
   M’s efficiency=60/10=6
   N’s efficiency=60/15=4
   P’s efficiency=60/20=3
   all together can complete the total work=60/13 days

    

4. X & Y can do a work individually in 20 and 30 days respectively. X starts and works for 10 days. Then he leaves the work and remaining work completed by Y. If they got rs.600, in how much amount did A got ?
   250
   200
   450
   300
   350
   Option D
   LCM of 20 and 30=60
   total work=60
   X works in a day=60/20=3 works
   Y works in a day=60/30=2 works
   X alone work for 10 days= 3*10=30 works
   remaining wrk done by Y=30/2=15 days
   they got rs.600
   A complete half of the work
   so, A will get=600/2= rs.300
   

    

5. 102 men can complete a work in 21 days, then how many men would it take to complete 17 days ?
   120
   140
   126
   128
   none of these
   Option C
   102 men can complete a work in 21 days.
   17 days work completed =102*21/17
   =126 men

    

6. P can don a piece of work in 12 days and Q in 8 days. They begin together, but P goes away 3 days before the work is completed. In how many days the work will be finished ?
   6
   8
   2
   5
   none of these
   Option A
   P can complete in 12 days.
   Q can complete in 8 days.
   Let, the total work =48
   P’s efficiency =48/12 =4
   Q’s efficiency =48/8 =6
   Q worked for 3 days =6*3= 18 work.
   P and Q worked remaining work in days =30/10 =3days.
   Total work will be finished in 6 days.

    

7. A group of workers worked to finish the work in 25 days . But 10 of the total workers did not come to work and the work is finshed in 35 days. find how many workers worked in the group initially.
   35
   38
   25
   56
   none of these
   Option A
   Let
   the number of workers worked initially is x.
   25*x =(x-10) 35
   25x= 35x-350
   10x=350
   x =35

    

8. 6 men 4 boys can complete a work in 12 days . A man completes double the work than a boy. In how many days 8 men and 16 boys will complete the work.
   8
   6
   5
   4
   none of these
   Option B
   Let,
   A man can complete 2 work and A boy can complete 1 work.
   1 man=2 boys
   According to questing,
   (6 men + 4 boys) can complete the work =12 days
   6 men + 2 men =8 men + 8men =16 men.
   1 man can do the work =(12*8)days
   (8 men +16 boys) =8 men + 8 men =16 men
   16 men will complete the work = 12*8/16=6 days

    

9. Avi can complete a work in 30 days. Bibhu is 20% more efficient than Avi and Pintu is 20% less efficient than Avi. In how many days the total work will be completed if they work for together.
   10
   20
   30
   40
   none of these
   Option A
   let,
   efficiency of Avi ,Bibhu and Pintu be 5x, 6x, 4x respectively
   total work =5x*30 = 150x
   Avi, Bibhu, and Pintu will be completed total work= 150x/15x =10 days.

    

10. P can do work in 25 days and Q is 40% more efficient than P. If Q starts the work and works for 5 days and leaves the work, then in how many days the total work will be finished ?
    25
    26
    24
    23
    none of these
    Option D
    Let,
    efficiency of P and Q = 5x and 7x
    P can do a work in 25 days.
    total work = 25*5x =125x
    Q works for 5 days = 7x*5 =35x
    remaining work done by P=90x/5=18 days
    total work will be completed = 5+18 =23 days.

     

1. Direction: Find the value of ‘x’ in the following questions given below.
   12^2-9^2+79= x+8^2
   68
   78
   75
   70
   none of this
   Option B
   144-81+79 = x+64
   x = 144-81+79-64
   = 78

    

2. 1/8 of 512-35% 200+84 = x/5*30
   13
   14
   15
   16
   none of these
   Option A
   64-70+84 = 6x
   6x =78
   x =13

    

3. 9871+2520+3920-x = 550
   
   11761
   12761
   14760
   10761
   none of these
   Option D
   16311-x = 5550
   x=10761

    

4. x^2 = √1156+32+55
   14
   12
   11
   15
   none of this
   Option C
   x^2 = 34+32+55
   x = 11

    

5. x/8*160*5*0.5 =250
   6
   5
   8
   2
   none of these
   Option B
   x/8*160*5*0.5 =250
   50x =250
   x=5

    

6. Direction: What will come in place of question marks (?) in the following questions below. (you are not need to calculate exact value)
   299.99+529.01+320.99+625.99 =?
   1776
   1888
   2000
   2200
   none of these
   Option A
   300+529+321+626 =1776

    

7. √2025.01+√3024.99-28+20-40+180=?
   154
   160
   180
   200
   152
   Option E
   45+55-28+20-40+100=152

    

8. 550.01÷11÷5+30.10+5*15.96 = ?
   120
   140
   160
   180
   none of this
   Option A
   550/11*5+30+80 = 10+30+80 = 120

    

9. 39% of 2500.05+350+403 =(?)^3
   14
   12
   16
   18
   none of these
   Option B
   975+753 = (?)^3
   ?=12

    

10. (?*5*20*4)/(32*120) = 30/36
    1
    2
    4
    6
    none of this
    Option A
    ?*5/6 =30/36
    ?=(30/36)*(6/5) =1

     

1. I. x^2+15x+56=0
   II. y^2+9y+14=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option D
   I. x^2+8x+7x+56=0
   x=-8, -7
   II. y^2+7y+2y+14=0
   y=-7, -2

    

2. I. x^2+2x-48=0
   II. y^2-9y+20=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option E
   I. x^2+8x-6x-48=0
   x=-8, 6
   II. y^2-5y-4y+20=0
   y=5, 4

    

3. I. 4x^2+16x+15=0
   II. 2y^2+11y+15=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option C
   I.4x^2+10x+6x+15=0
   4x=-10, -6
   x=-2.5, -1.5
   II.2y^2+6y+5y+15=0
   2y=-6, -5
   y=-3, -2.5

    

4. I. x^2-12x-108=0
   II. y^2+3y-54=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option E
   I. x^2-18x+6x-108=0
   x=18, -6
   II. y^2+9y-6y-54=0
   y=-9, 6

    

5. I. x^2-35x+306=0
   II. y^2-31y+238=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option C
   I. x^2-18x-17x+306=0
   x=18, 17
   II. y^2-17y-14y+238=0
   y=17, 14

    

6. I. 4x^2+20x+24=0
   II. 5y^2+27y+10=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option E
   I. 4x^2+12x+8x+24=0
   4x=-12, -8
   x=-3, -2
   II. 5y^2+25y+2y+10=0
   5y=-25, -2
   y=-5, -.4

    

7. I. x^2-10x+24=0
   II. y^2-5y+6=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option A
   I.x^2-6x-4x+24=0
   x=6, 4
   II. y^2-3y-2y+6=0
   y=3, 2

    

8. I. 2x^2+6x-20=0
   II.3y^2-21+36=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option B
   I. 2x^2+10x-4x-20=0
   2x=-10, 4
   x=-5, 2
   II. 3y^2-12y-9y+36=0
   3y=12, 9
   y=4, 3

    

9. I. x^2-x-132=0
   II. y^2-27y+180=0
   x>y
   x
   x≥y
   x≤y
   x=y or no relation
   Option D
   I. x^2-12x+11x-132=0
   x= 12, -11
   II. y^2-15y-12y+180=0
   y=15, 12

    

10. I. x^3=216
    II. 3y^2-11y+6=0
    x>y
    x
    x≥y
    x≤y
    x=y or no relation
    Option A
    I. x=6, 6
    II. 3y^2-9y-2y+6=0
    3y=9, 2
    y=3, 2/3

     

1. The still of boat in skill water is 7.5 km/h. If the speed of stream is 2.5 km/h, then find the time taken to go a distance of 15km and come back to starting point.
   4.5
   3
   4
   5
   3.5
   Option A
   Speed of boat = 7.5km/h
   speed of stream =2.5km/h
   downstream speed of boat = 7.5+2.5 =10km/h.
   Upstream speed of boat =7.5-2.5 =5km/h.
   Time required =15/10+15/5 =1.5+3 =4.5 hours.

    

2. If the speed of boat in upstream and in downstream 10km/h and 20km/h respectively. Find the total distance covered by boat in still water in 6 hours .
   80km.
   90km.
   80km.
   85km.
   50km.
   Option B
   Upstream speed of boat= 10km/h.
   downstream speed of boat =20km/h.
   speed of boat in still water =20+10/2 =15 km/h.
   Total distance covered by boat =15*6 =90 km.

    

3. The ratio of speed of boat in skill water and the current speed is 5:1 distance covered by boat in downstream speed and upstream speed is 120km. each find the speed of boat in skill water if total time taken boat in both downstream and upstream speed ids 10 hours.
   25
   28
   30
   40
   60
   Option A
   Let the speed of boat in skill water= 5x
   current speed =x
   downstream speed of boat =5x+x =6x
   upstream speed of boat =5x-x =4x
   120/6x+120/4x= 10
   20/x+30/x =10
   x=5
   speed of boat in still water =5*5 =25 km/hr

    

4. A boat along the current takes 3 hours to cover a certain distance and against the current in takes 9 hours to cover the same distance . If speed of boat in still water is 4km/h, then find the speed the current.
   2
   3
   1
   1.5
   2.5
   Option A
   speed of boat in skill water =4km/h.
   Let current speed =x
   downstream speed =(4+x) km/h
   upstream speed =(4-x) km/h
   Let distance covered by boat =D km.
   ATQ,
   D/4+x =3
   D =12+3x……….(1)
   D /4-x =9
   D =36-9x…………(2)
   12+3x=36-9x
   12x =24
   x=2
   speed of current =2 km/h.

    

5. A man’s speed with the current is 20 km/h and the speed of the current is 5km/h. Then find how much time will take by man to cover 90km in against the current.
   8
   6
   5
   9
   4
   Option D
   downstream speed of boat =20
   speed of current =5
   speed of boat =20-5 =15
   upstream speed of boat =15-5 =10
   Time required =90/10 =9 hour.

    

6. Time taken by boat to cover 200 km in upstream is 10 hours more than the time taken by boat to cover 200 km in downstream. Total time taken by boat to cover 80 km in upstream is 8 hours. Find speed of boat in still water.
   15
   20
   25
   24
   10
   Option A
   let speed of boat and current be x km/hr and y km/hr respectively
   upstream speed of boat=80/8=10 km/hr
   downstream =x+y
   ATQ, 200/10-200/x+y=10
   20-200/x+y=10
   x+y=20
   downstream speed of boat=20 km/hr
   speed of boat in still water=20+10/2=15km/h

    

7. The upstream speed of a boat is 20% less than the downstream speed. Find speed of boat in still water if it covers 100 km in downstream and 60 km in upstream in total 7 hours.
   25
   22.5
   24
   25.5
   28
   Option B
   let the downstream speed=5x
   upstream speed=4x
   ATQ, 100/5x+60/4x=7
   20/x+15/x=7
   x=5
   downstream speed=5*5=25
   upstream speed=4x=4*5=20
   boat speed=(25+20)/2=22.5 km/hr

    

8. The speed of boat in still water is 18 km/hr and current speed is 6 km/hr. If time taken by boat to cover certain distance both downstream and upstream is 12 hours. Find the distance.
   100
   90
   75
   96
   84
   Option D
   speed of boat in still water=18
   speed of current=6
   downstream speed of boat=18+6=24
   upstream speed of boat=18-6=12
   let distance be D km
   D/24+D/12=12
   D=96 km
   

    

9. The sum of the speed of a boat in still water and the current is 20 km/hr. The boat takes 8 hours to cover 96 km upstream. Find the difference between the speed of boat in still water and speed of current.
   14
   18
   16
   12
   10
   Option D
   let speed of boat in still water=x
   current speed=20-x
   upstream speed=96/8=12 km/hr
   x-(20-x)=12
   2x-20=12
   x=16 km/hr
   speed of boat in still water=16 km/hr
   current speed=20-16=4 km/hr
   difference=16-4=12 km/hr

    

10. A boat takes 20 hours to cover 400 km in upstream and 12 hours to cover 480 km in downstream. Speed of boat in still water is how much percent more than speed of stream ?
    100%
    80%
    120%
    60%
    200%
    Option E
    upstream speed of boat=400/20=20 km/hr
    downstream speed of boat=480/12=40 km/hr
    speed of boat in still water=40+20/2=30 km/hr
    speed of current=40-20/2=10 km/hr
    percentage=30-10/10*100=200%

     

1. Average age of A and B is 5 years more than the present age of C. The age of D is 3 years less than the age of C and total age of A, B, C and D is 39 years. Find the sum of age of A and B.
   26
   28
   32
   24
   20
   Option A
   Let the age of C =x years
   ATQ, A+B/2 =x+5
   A+B =2x+10
   age of D =x-3
   Total age of A, B, C and D =39 years.
   2x+10+x+x-3 =39
   4x+7= 39
   x= 8years
   The sum of ages of A and B =2x+10 =26 years

    

2. Ratio of the present age of Deepak and Subham is 5:8. After 4 years ratio of their ages is 2:3, then find the age of Subham after 8 years.
   45
   48
   40
   30
   35
   Option C
   Let the present age of Deepak and Subham be 5x and 8x respectively.
   ATQ, 5x+4/8x+4 =2/3
   16x+8 =15x+12
   x=4
   age of Subham after 8 years = 8x+8 =40 years.

    

3. The age of Vicky is 25% more than the age of Vikram. The age of Rashmi is 6 years more than the age of Vikram and difference between the age of Vicky and Rashmi is 2 years. What is the age of Vicky after 4 years ?
   40
   42
   32
   35
   44
   Option E
   let the age of Vicky=5x
   and the age of Vikram=4x
   the age of Rashmi=4x+6
   difference between the age of Vicky and Rashmi=2 years
   5x-(4x+6)=2
   5x-4x-6=2
   x=8 years
   Vicky after 4 years=5x+4=44 years

    

4. The average of the present age of mother and his son is 50% more than the present age of the son. If 5 years hence the sum of age of mother and his son is 70 years, then find the present age of the mother.
   40
   48
   30
   35
   45
   Option A
   let the present age of mother and son be x and y years respectively
   x+y/2=150/100x
   x+y/2=3x/2
   y=2x
   also given that, x+5+2x+5=70
   3x+10=70
   x=20 years
   present age of mother=y=2x=2*20=40 years

    

5. Average age of B and C is 20 years. The age of A is 4 years more than B and total age of A,B and C is 60 years, then find the age of A before 4 years.
   20
   18
   15
   16
   24
   Option D
   average age of B and C=20 years
   B+C/2=20
   B+C=40
   let the age of B=x
   age of C=40-x
   age of A=x+4
   x+4+x+40-x=60
   x+44=60
   x=16
   age of A before 4 years=x+4-2=16+4-4=16 years

    

6. Average of present age of P & Q is 24 years, average of present age of P & R is 20 years and average of present of Q & R is 16 years. Find the age of R after 8 years.
   18
   20
   25
   28
   24
   Option B
   average of present age of P & Q=24
   P+Q/2=24
   P+Q=48
   average of present age of P & R=20
   P+R/2=20
   P+R=40
   average of present age of Q & R=16
   Q+R/2=16
   Q+R=32
   P+Q+P+R+Q+R=48+40+32
   2(P+Q+R)=120
   P+Q+R=60
   P+Q=48
   R=60-48=12
   the age of R after 8 years=12+8=20 years

    

7. Present age of son is 30% of his father age and after 5 years the ratio of age of father and son will become 5:2. What is the sum of the present age of father and son ?
   48
   45
   38
   39
   40
   Option D
   let present age of father=10x
   and present age of son=3x
   after 5 years, 10x+5/3x+5=5/2
   20x+10=15x+25
   5x=15
   x=3
   sum=10x+3x=13x=13*3=39 years

    

8. A is 3 years older than B and after 2 years age of A will be 30 % more than that of B. Find the age of A after 5 years.
   16
   20
   25
   24
   28
   Option A
   let age of B=x
   and age of A=x+3
   after 2 years, x+3+2=130/100(x+2)
   x+5=13/10(x+2)
   10x+50=13x+26
   3x=24
   x=8
   age of A after 5 years =x+3+5=8+3+5=16 years

    

9. 5 years ago, average age of a family of 6 members was 30 years. At present one family member who is a girl got married whose age is 30 years. What is the average age of remaining 5 members of family after 4 years ?
   25
   20
   24
   28
   26
   Option B
   5 years ago, average age of 6 members=30 years
   at present total age of 6 members=(30*6)+(6*5)=210
   one member got married who is a girl whose age is 30 years
   remaining age of 5 members=180
   after 4 years total age of 5 members =180+(5*4)=100
   average age of 5 members after 4 years=100/5=20 years

    

10. Ratio of present age of P & Q is 4:3 and before 2 years ratio of their age is 3:2. The age of R is 12 years more than the present age of P, then find the age of R.
    25
    20
    24
    18
    40
    Option B
    let present age of P & Q be 4x and 3x respectively
    before 2 years, 4x-2/3x-2=3/2
    8x-4=9x-6
    x=2
    present age pf P=4x=4*2=8
    present age of R=8+12=20 years

     

1. If the length of a rectangular field is increased by 15% and breadth is also increased by 10%, the area of the rectangle will be 253 m^2. What is the area of the original area of rectangle ?
   400
   240
   350
   180
   200
   Option E
   let original area of rectangle =100
   percentage change in area=15+10+15*10/100=26.5
   126.5=253
   original area=253/126.5*100=200 m^2

    

2. The side of square is 25% more than the length of rectangular and perimeter of square is 80cm. Ratio of length and breadth of rectangular is 4:3, then find the area of rectangular.
   192
   215
   180
   220
   240
   Option A
   let the length of rectangular=4x
   side of square=5x
   perimeter of square=5x*4=20x
   20x=80
   x=4
   length of rectangular=4*4=16
   ratio of length and breadth=4:3
   breadth=16/4*3=12
   area of rectangular=16*12=192 cm^2

    

3. The area of square 50m^2 less than the area of a rectangular, whose breadth is 12m. If the perimeter of a square is 40m, then find the perimeter of a rectangular.
   
   50
   49
   60
   65
   70
   Option B
   perimeter of square=40
   side of square=40/4=10m
   area of square=10^2=100
   area of rectangular=100+50=150m^2
   breadth=12m
   length=150/12=12.5m
   perimeter=2(12.5+12)=49
   

    

4. The area of the square is in the ratio of 1444:1296. What will be the ratio of their perimeter ?
   20:21
   19:18
   22:25
   23:24
   18:19
   Option B
   The ratio of area= 1444:1296
   a^2:b^2=38:36=19:18
   ratio of their perimeter=19*4:18*4=19:18

    

5. The side of square is 5cm more than the radius of a circle. The area of the circle is 154cm^2. What is the perimeter of the square ?
   44
   64
   56
   48
   52
   Option D
   area of the circle=154cm^2
   πr^2=154
   r^2=49
   r=7
   side of square=7+5=12cm
   perimeter of square=12*4=48cm
   

    

6. The length of rectangular is 18cm which is 4cm more than diameter of a circle. What is the area of the circle ?
   154
   240
   150
   176
   198
   Option A
   diameter of circle=18-4=14
   2r=14
   r=7
   area of the circle=πr^2=22/7*7*7=154cm^2

    

7. There is a rectangular field of 40cm in length and 30cm in breadth. On the inside of which a 5cm wide road, then find the area of road.
   800
   500
   700
   600
   1000
   Option D
   area of the outside rectangular field=40*30=1200cm^2
   length of inside rectangular=40-10=30
   breadth of the inside rectangular=30-10=20
   area of the inside rectangular=30*20=600
   the area of the road=1200-600=600cm^2
   

    

8. The height and radius of a cylinder is 21cm and 12cm respectively. Find the volume of cone.
   4268
   3168
   4360
   4530
   4840
   Option B
   height of the cylinder=21cm
   radius of the cylinder=12cm
   volume of the cylinder=22/7*12*12*21=22*144*3
   volume of the cone=1/3*volume of cylinder
   =1/3*22*144*3=3168cm^2

    

9. The ratio of the length of the diagonals of a rhombus is 4:3. If the perimeter of the rhombus is 160m. What is the length of the diagonal of a square whose area is same as that of rhombus ?
   15√3
   16√3
   20√2
   25√5
   24√2
   Option B
   let the diagonals of the rhombus be 4x and 3x
   side length of the rhombus=√(4x)^2+(3x)^2
   =√16x^2+9x^2
   =25x^2=5x
   perimeter=4*5x=20x=160
   20x=160
   x=8
   two diagonal of the rhombus=32 and 24
   area=1/2*32*24=384
   let the diagonal of the square=D
   side of the square=D/√2
   (D/√2)^2=384
   D^2/2=384
   D=16√3

    

10. The circumference of the circle is 176cm and the radius of circle is 4 less than side of the square. Find the area of the square.
    576
    1000
    784
    1024
    1444
    Option D
    2πr=176
    r=176*7/44=28
    side of square=28+4=32
    area of square=32*32=1024

     

1. Directions: What will come in place of questions (?) marks in the following given below questions?
   3030*8/15-1500÷ 6+1000=?
   2408
   2505
   3200
   3418
   2366
   Option E
   202*8-1500/6+1000=?
   1616-250+1000=2366

    

2. 52*45+32*12-45*80=?
   -876
   -875
   -976
   -850
   -880
   Option A
   2340+384-3600
   2724-3600=-876

    

3. 60% of 180+1331÷ 11+48=?
   278
   277
   375
   477
   240
   Option B
   108+121+48=277

    

4. √196*25*4+1800÷ 60+30=?
   240
   200
   340
   180
   250
   Option B
   14*5*2+30+30=?
   140+60=200

    

5. 2 5/3+8 4/6+ 5 4/6- 7 2/3 =?
   8 11/3
   6 12/5
   5 9/10
   10 7/8
   8 4/11
   Option A
   2+8+5-7 (10+4+4+4/6)
   = 8 (22/6) =8 11/3

    

6. Directions: What will come in place of questions (?) marks in the following given below questions ? (you are not calculate exact value)
   ∛1728.04+ √2304.02 + √2024.86= ?
   105
   108
   110
   210
   420
   Option A
   12+48+45 =105

    

7. 1350.04*8/45+366*4-10% of 899.99 =?
   1520
   1614
   1640
   2845
   2840
   Option B
   1350*8/45+366*4-10% of 900
   =240+1464-90 =1704-90
   =1614

    

8. 240% of 600.05 +45.88*10 -40% of 499.99= ?
   800
   820
   450
   804
   480
   Option D
   144+460+200 =804

    

9. 12.5% of 800 + 48.05*2 – √1295.96
   170
   180
   200
   160
   100
   Option D
   1/8*800 + 96 -36
   =100+60 =160

    

10. 4400+3815.99 + 5600.04 +6449.96 =?
    18140
    20266
    24160
    20466
    16266
    Option B
    4400 + 3816 + 5600 +6450 =20266

     

1. A, B and C alone can do a work in 8 days , 12 days and 6 days respectively. Find how many days they take together to complete work ?
   6 days
   8 days
   2 2/3 days
   4 days
   3 days
   Option C
   LCM of 8 , 12 and 6 = 24
   total work = 24
   efficiency of A = 24/8 = 3
   efficiency of B = 24/12 = 2
   efficiency of C = 24/6 = 4
   time taken = 24/9 = 2 2/3 days

    

2. P and Q alone can do a work in 30 days and 20 days respectively. P works for 15 days and left the work, remaining work done by B. Find how many days required to complete the remaining work ?
   10 days
   8 days
   20 days
   18 days
   16 days
   Option A
   LCM of 30 and 20 = 60
   total work = 60
   efficiency of P = 60/30 = 2
   efficiency of Q = 60/20 = 3
   P completed work in 15 days = 15 * 2 = 30
   time taken by Q to complete remaining work = 60 – 30 /3 = 10 days

    

3. A can complete 40% of work in 8 hours and while B alone can do the same work in 24 hours. Find the time taken by A and B together to complete the 60% of the work ?
   5 2/3 days
   8 3/5 days
   4 days
   6 6/11 days
   8 days
   Option D
   A alone can do all work = 8/40 * 100 = 20 days
   LCM of 20 and 24 = 120
   efficiency of A = 120/20 = 6
   efficiency of B = 120/24 = 5
   time taken by A and B together to complete 60% of the work = 120/11 * 60/100 = 6 6/11 days

    

4. A and B alone can do a piece of work in 12 hours and 15 hours respectively. If they do the work alternatively for 1 hours each starting with A, then find how many hours will the work be completed ?
   5 hours
   3 hours
   8 1/5 hours
   12 1/4 hours
   13 1/4 hours
   Option E
   LCM of 12 and 15 = 60
   total work = 60
   efficiency of A = 60/12 = 5
   efficiency of B = 60/15 = 4
   work completed in 2 hours = 5 + 4 = 9 works
   (2 * 6) hours = (9 * 6) work
   12 hours = 54 works
   A works in another hours = 5 work
   remaining 1 work completed by B = 14 hours
   total time = 12 + 1 + 1/4 = 13 1/4 hours

    

5. A, B and C alone can do a piece of work in 3 days. If A alone can do in 6 days and C alone can do it in 18 days, how long will B alone take to complete the work ?
   8 days
   9 days
   18 days
   6 days
   4 days
   Option B
   LCM of 3, 6 and 18 = 18
   total work = 18
   efficiency of A, B and C = 18/3 = 6
   efficiency of A = 18/6 = 3
   efficiency of C = 18/18 = 1
   efficiency of B = 6 – ( 3 + 1 ) = 2
   B alone can do the work = 18/2 = 9 days
   

    

6. P and Q undertook to do a piece of work for rs.3500. P alone can do it in 12 days and Q alone in 20 days. If they finished the work with the help of R in 6 days. What is share of R ?
   800
   700
   850
   650
   725
   Option B
   LCM of 12, 20 and 6 = 60
   efficiency of P = 60/12 = 5
   efficiency of Q = 60/20 = 3
   efficiency of P, Q and R = 60/6 = 10
   efficiency of R = 10 – ( 5 + 3 ) = 2
   share of R = 3500 * 2 / 10 = 700

    

7. Rita and Gita can do a piece of work individually in 40 days and 60 days respectively. If they work on alternate days starting with Gita, then in how many days will the work get finished ?
   28 days
   24 days
   17 days
   48 days
   46 days
   Option D
   LCM of 40 and 60 = 120
   efficiency of Rita = 120/40 = 3
   efficiency of Gita = 120/60 = 2
   starting with Gita work completed in 2 days = 5
   time required to complete total work = 24 * 2 = 48 days
   

    

8. A and B can do a work in 12 days. B and C can do the same work in 20 days. A and C can also do the same work in 30 days. If they all work together in how many days will they complete the work ?
   10 days
   14 days
   12 days
   13 days
   15 days
   Option C
   LCM of 12, 20 and 30 = 120
   efficiency of A and B = 120/12 = 10
   efficiency of B and C = 120/20 = 6
   efficiency of A and C = 120/30 = 4
   A + B + B + C + A + C = 10 + 6 + 4 = 20
   2(A + B + C) = 20
   A + B + C = 10
   time 120/10 = 12 days

    

9. 8 men or 12 women can finish a work in 25 days. How many days will 6 men ad 11 women can finish the same work ?
   15 days
   14 days
   28 days
   30 days
   32 days
   Option A
   8 men = 12 women
   men/women = 12/8 = 3/2
   total work = 8 * 3 * 25 = 600
   time required = 600 /(6 * 3 + 11 * 2) = 600/40 = 15 days

    

10. A, B and C can complete a job in 9 days, 10 days and 15 days respectively. A, B and C start the work together and after 2 days B and C leave the work. Find how many days taken by A to complete the remaining work ?
    6 days
    18 days
    14 days
    4 days
    8 days
    Option D
    LCM of 9, 10 and 15 = 90
    efficiency of A = 90/9 = 10
    efficiency of B = 90/10 = 9
    efficiency of C = 90/15 = 6
    A, B and C complete work in 2 days = 2(10 + 9 + 6) = 50
    remaining work = 90 – 50 = 40
    time taken by A to complete remaining work = 40/10 = 4 days

     

Direction: Given below the table shows the total number of books shopkeeper and also given that the ratio of Math and English book sold by each shopkeeper.

1. Total number of math book sold by A and C together is how much more/less then total number of English book sold by C and D together .
   285
   185
   100
   120
   none of these
   Option B
   Math book sold by A =400*12/20=240
   Math book sold by B =525*3/5 =315
   English book sold by C =525*2/5 =210
   English book sold by D =280*4/7 =160
   Difference =(240+315)-(210+160)
   =555-370 =185

    

2. What is the ratio of English book sold by B to math book sold by E.
   49:18
   18:49
   20:20
   12:14
   none of these
   Option B
   English book sold by B = 330*6/11=180
   Math book sold E = 630*7/9 =490
   Ratio =180:490 =18:49

    

3. Find the average numbers total of books sold by B and E together.
   400
   490
   300
   480
   none of these
   Option D
   (330+630)/2 =960/2 =480

    

4. Total number of math books sold by C and B together is what present more/less than total numbers of English book sold by shopkeeper A and E together.
   40%
   50%
   60%
   55%
   none of these
   Option D
   math book sold by C =525*3/5=315
   math book sold by B =330*5/11=150
   English book sold by A = 400*8/20=160
   English book sold by E =630*2/9=140
   present more =(465-300)/300*100=55%

    

5. Find the total English sold by shopkeeper D and E together .
   200
   300
   350
   220
   none of these
   Option B
   English book sold by D =280*4/7
   English book sold by E =630*2/9=140
   total=160+140=300

    

6. Direction: Given below the pie-chart shows percentage distribution of mobile mobile produced by different company. Study the following pie-chart and solve the following questions given below.
   
   
   Total no. of mobile produced by company O is what percent of total no. of mobile produced by company M.

   160
   150
   120
   100
   80
   Option B
   15/10*100=150%

    

7. Find the ratio of no. of mobile produced by company Q and M together to company P and O together .
   2:3
   4:5
   6:8
   8:4
   none of these
   Option A
   No. of mobile produced by Q =240*25/100 =600
   No. of mobile produced by M =240*10/100 =240
   No. of mobile produced by P=240*3/8 =900
   No. of mobile produced by O=240*15/100 =360
   Ratio =(600+240):(900+360)=840:1260= 2:3

    

8. What is the average no. of mobile produced by M, O, Q together ?
   280
   420
   520
   400
   440
   Option D
   Average no. mobile produced by M,O and Q =(10+15+25)/3%
   =50/300*2400=400
   

    

9. Find the difference between total no. of mobile produced by O and Q together how much percent more/less total no. of mobile produced by P and N together.
   
   20%, more
   20%, less
   10%, less
   25%, more
   15%, more
   Option B
   P and N together=50%
   O and Q together=40%
   percent less=(50-40)/50*100=20%

    

10. Find the difference between total no. of mobile produced by M and N together to no. of mobile produced by O.
    180
    200
    240
    300
    160
    Option A
    No. of mobile produced by M=2400*10/100=240
    No. of mobile produced by N=2400*1/8=300
    No. of mobile produced by O=2400/*15/100=360
    Difference=(240+300)-360=180