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    7Jul, 2021
    Quantitative Aptitude: Probability Questions – Set 21
    1. If coins are tossed, then find the probability of getting at least 3 tails on the face.
      8/9
      4
      1/4
      1/2
      2/5
      Option D
      Required = (5C3) + (5C4) + (5C5) = 10 + 5 + 1 = 16
      total = 2^5 = 32
      probability = 16/32 = 1/2

       

    2. A bag contains 4 red balls, 2 black balls and 5 yellow balls. 3 balls are drawn randomly, find the probability of getting all balls are of red balls.
      2/65
      1/5
      4/165
      5/8
      2/165
      Option C
      Required = 4C3 = 4
      total = 11C3 = 165
      probability = 4/165

       

    3. A box contains 4 white balls and 8 blue balls. 2 balls are drawn randomly from the box in succession without replacement. What is the probability that they are different colors ?
      6/17
      5/12
      18/25
      16/33
      1/8
      Option D
      Probability = 4/12 * 8/11 * 4/11 * 8/12 = 2 * 4/12 * 8/11 = 16/33

       

    4. If 2 cards are selected randomly from a pack of 52 card, then what is the probability that all are face cards ?
      11/221
      8/25
      4/225
      8/29
      2/441
      Option A
      Probability = (12C2) / (52C2)
      = 12 * 11 / 52 * 51 = 11/221

       

    5. Five men and 4 women sit in a row for eating food. What is the probability that they will sit in alternate position ?
      1/26
      2/85
      3/82
      1/126
      2/ 85
      Option D
      Probability = 5! * 4! / 9! = 1/126

       

    6. What is the probability that number selected from number 1, 2 , 3 … 100 is a prime number ?
      2/5
      1/4
      5/8
      1/2
      4/7
      Option B
      Probability = 25/100 = 1/4

       

    7. In how many different ways can the letters of the word “SHARE” be arranged ?
      260
      150
      160
      120
      140
      Option D
      Number of ways = 5! = 120

       

    8. One bag contains 4 blue balls and 3 green balls. Another bag contains 5 red balls and 7 blue balls. If one ball is drawn randomly from each bag then, what is the probability that both are blue balls ?
      2
      60
      1/8
      1/3
      4/17
      Option D
      Probability = (4C1) / (7C1) * (7C1) / (12C1) = 1/3

       

    9. A box contains 4 green balls , 2 white balls and 4 blue balls. If three balls are drawn together from the box, then what is the probability of selecting that these three balls are the same colors ?
      8/17
      17/18
      2/25
      1/15
      1/30
      Option D
      Probability = (4C3) / (10C3) + (4C3) / (10C3)
      = 1/30 + 1/30 = 1/15

       

    10. How many words can be formed with the help of the letters of the word “SCHOOL” in such a way that all the words start with ‘L’ ?
      40
      60
      42
      85
      70
      Option B
      Number of ways = 5!/2! = 120/2 = 60

       

    01
    6Jul, 2021
    Quantitative Aptitude: Time and Work Set 26
    1. A, B and C alone can do a work in 8 days , 12 days and 6 days respectively. Find how many days they take together to complete work ?
      6 days
      8 days
      2 2/3 days
      4 days
      3 days
      Option C
      LCM of 8 , 12 and 6 = 24
      total work = 24
      efficiency of A = 24/8 = 3
      efficiency of B = 24/12 = 2
      efficiency of C = 24/6 = 4
      time taken = 24/9 = 2 2/3 days

       

    2. P and Q alone can do a work in 30 days and 20 days respectively. P works for 15 days and left the work, remaining work done by B. Find how many days required to complete the remaining work ?
      10 days
      8 days
      20 days
      18 days
      16 days
      Option A
      LCM of 30 and 20 = 60
      total work = 60
      efficiency of P = 60/30 = 2
      efficiency of Q = 60/20 = 3
      P completed work in 15 days = 15 * 2 = 30
      time taken by Q to complete remaining work = 60 – 30 /3 = 10 days

       

    3. A can complete 40% of work in 8 hours and while B alone can do the same work in 24 hours. Find the time taken by A and B together to complete the 60% of the work ?
      5 2/3 days
      8 3/5 days
      4 days
      6 6/11 days
      8 days
      Option D
      A alone can do all work = 8/40 * 100 = 20 days
      LCM of 20 and 24 = 120
      efficiency of A = 120/20 = 6
      efficiency of B = 120/24 = 5
      time taken by A and B together to complete 60% of the work = 120/11 * 60/100 = 6 6/11 days

       

    4. A and B alone can do a piece of work in 12 hours and 15 hours respectively. If they do the work alternatively for 1 hours each starting with A, then find how many hours will the work be completed ?
      5 hours
      3 hours
      8 1/5 hours
      12 1/4 hours
      13 1/4 hours
      Option E
      LCM of 12 and 15 = 60
      total work = 60
      efficiency of A = 60/12 = 5
      efficiency of B = 60/15 = 4
      work completed in 2 hours = 5 + 4 = 9 works
      (2 * 6) hours = (9 * 6) work
      12 hours = 54 works
      A works in another hours = 5 work
      remaining 1 work completed by B = 14 hours
      total time = 12 + 1 + 1/4 = 13 1/4 hours

       

    5. A, B and C alone can do a piece of work in 3 days. If A alone can do in 6 days and C alone can do it in 18 days, how long will B alone take to complete the work ?
      8 days
      9 days
      18 days
      6 days
      4 days
      Option B
      LCM of 3, 6 and 18 = 18
      total work = 18
      efficiency of A, B and C = 18/3 = 6
      efficiency of A = 18/6 = 3
      efficiency of C = 18/18 = 1
      efficiency of B = 6 – ( 3 + 1 ) = 2
      B alone can do the work = 18/2 = 9 days

       

    6. P and Q undertook to do a piece of work for rs.3500. P alone can do it in 12 days and Q alone in 20 days. If they finished the work with the help of R in 6 days. What is share of R ?
      800
      700
      850
      650
      725
      Option B
      LCM of 12, 20 and 6 = 60
      efficiency of P = 60/12 = 5
      efficiency of Q = 60/20 = 3
      efficiency of P, Q and R = 60/6 = 10
      efficiency of R = 10 – ( 5 + 3 ) = 2
      share of R = 3500 * 2 / 10 = 700

       

    7. Rita and Gita can do a piece of work individually in 40 days and 60 days respectively. If they work on alternate days starting with Gita, then in how many days will the work get finished ?
      28 days
      24 days
      17 days
      48 days
      46 days
      Option D
      LCM of 40 and 60 = 120
      efficiency of Rita = 120/40 = 3
      efficiency of Gita = 120/60 = 2
      starting with Gita work completed in 2 days = 5
      time required to complete total work = 24 * 2 = 48 days

       

    8. A and B can do a work in 12 days. B and C can do the same work in 20 days. A and C can also do the same work in 30 days. If they all work together in how many days will they complete the work ?
      10 days
      14 days
      12 days
      13 days
      15 days
      Option C
      LCM of 12, 20 and 30 = 120
      efficiency of A and B = 120/12 = 10
      efficiency of B and C = 120/20 = 6
      efficiency of A and C = 120/30 = 4
      A + B + B + C + A + C = 10 + 6 + 4 = 20
      2(A + B + C) = 20
      A + B + C = 10
      time 120/10 = 12 days

       

    9. 8 men or 12 women can finish a work in 25 days. How many days will 6 men ad 11 women can finish the same work ?
      15 days
      14 days
      28 days
      30 days
      32 days
      Option A
      8 men = 12 women
      men/women = 12/8 = 3/2
      total work = 8 * 3 * 25 = 600
      time required = 600 /(6 * 3 + 11 * 2) = 600/40 = 15 days

       

    10. A, B and C can complete a job in 9 days, 10 days and 15 days respectively. A, B and C start the work together and after 2 days B and C leave the work. Find how many days taken by A to complete the remaining work ?
      6 days
      18 days
      14 days
      4 days
      8 days
      Option D
      LCM of 9, 10 and 15 = 90
      efficiency of A = 90/9 = 10
      efficiency of B = 90/10 = 9
      efficiency of C = 90/15 = 6
      A, B and C complete work in 2 days = 2(10 + 9 + 6) = 50
      remaining work = 90 – 50 = 40
      time taken by A to complete remaining work = 40/10 = 4 days

       

    02
    5Jul, 2021
    Partnership Questions Quantitative Aptitude: Partnership Set 22
    1. A started a business with an initial investment of rs.4200 and after 5 months B and c joined the business investing rs.5400 and rs.6000 respectively. If total profit of the business at the end of the year is rs.15500 , then find the profit share of B ?
      4800
      3750
      2840
      4500
      4450
      Option D
      Profit sharing ration of A , b and C = (4200 *12) : (5400 * 7) : (6000 * 7) = 12 : 9 : 10
      total profit = 15500
      profit share of B = 15500 * 9/31 = 4500

       

    2. The investment ratio of A , B and C in a business is 4 :3 :7. If they invested their capital for 7 months , 8 months and 6 months respectively , then in which ratio they distributed their profit at the end of the year ?
      5 : 3 : 2
      6 : 4 :3
      5 : 2 : 3
      2 : 3 : 8
      14 : 12 : 21
      Option E
      Profit sharing ratio of A, B and C = (4 * 7) : (3 * 8) : (7 * 6) = 14 : 12 : 21

       

    3. A , B and C started a business. a receives 3/5 of the profit and the remaining profit shared by B and C equally. If difference between profit of A and B is rs.500, then what is total profit of the business ?
      3450
      1400
      2000
      1250
      600
      Option D
      Let total profit of the business = 5x
      profit share of A = 5x * 3/5 = 3x
      remaining profit = 2x
      profit share of B and C = x and x respectively
      3x – x = 500
      x = 250
      total profit of the business = 5x = 5 * 250 = 1250

       

    4. Three partners A , B and C started a business with investing rs.4000, rs.6500 and rs.5500 respectively. After 2 years A invested rs.2500 more , B withdraws rs.1500 and C invests rs.500 more in the business. Total profit of the business at the end of the three years rs.19800, then find the profit share of A ?
      4850
      5800
      3540
      4800
      5800
      Option E
      Profit sharing ratio of A , B and C = (4000 * 2 + 6500 * 1) : (6500 * 2 + 5000 * 1) : (5500 * 2 + 6000 * 1)
      = 29 : 36 : 34
      profit share of A = 19800 * 29/99 = 5800

       

    5. A , B and C enter into a partnership farm. Profit share of A and B rs.1200 ad rs.1800 respectively out of the total profit of rs.4500. If investment made by A rs.25000, then ho much amount invested by C in the business ?
      25500
      28000
      40000
      31250
      45000
      Option D
      Total profit = 4500
      total profit of A and B = 1200 + 1800 = 3000
      profit share of C = 4500 – 3000 = 1500
      investment = of c = 25000/1200 * 1500 = 31250

       

    6. A and B started a business with capitals of rs.45000 and rs.40000 respectively. After 4 months A withdraws from the business. At the end of a year they got rs. 7700 as total profit. Find the share of A ?
      2800
      2100
      4400
      5500
      3800
      Option B
      Profit sharing ratio of A , B = (45000 * 4) : (40000 * 12) = 3 :8
      profit share of A = 7700 * 3/11 = 2100

       

    7. Ram , Hari and Shiva started a business with total capital of rs.15000. Hari invests rs.1600 less than Ram and Shiva invests rs.3200 more than Hari. If total profit at the end of a year is rs.4500, then how much profit Shiva gets ?
      2240
      3450
      1520
      1980
      2480
      Option D
      Let Ram invests = rs.x
      Hari invests = x – 1600
      Shiva invests = x – 1600 + x +3200
      total profit = 15000
      x + x – 1600 + x + 600 = 15000
      Ram invests = 5000
      Hari invests = 5000 – 1600 = 3400
      Shiva invests = 3400 + 3200 = 6600
      their profit sharing ratio = 5000 : 3400 : 6600
      profit share of Shiva = 4500 * 33/75 = 1980

       

    8. A and B started a business with capitals of rs.2500 and rs.3000. A got 20% the profit for maintaining the business and the rest distributed in their 744 in all . what is the profit share of B ?
      840
      530
      520
      576
      790
      Option D
      Profit sharing ratio of A , B = 2500 : 3000 = 5 : 6
      let total profit = 110x
      A get 20% of the profit = 10x * 20/100 = 22x
      remaining profit = 110x – 22x = 88x
      profit share of A = 88x
      profit share of A = 88x * 5/11 = 40x
      profit share of B = 88x * 6 / 11 = 48x
      A got in all = 744
      62x = 744
      x = 12
      profit share of B = 48 * 12 = 576

       

    9. Total capital invested by P , Q, R and S in the business is rs.41600. At the end of the year the shares of their profit are rs.400 , rs, 600 , rs240 rs.840 respectively. What is the capital invested by R ?
      5400
      5800
      3200
      4800
      5320
      Option D
      Profit sharing ratio of P, Q, R and S = 400 : 600 : 240 : 840
      = 10 : 15 : 6 : 21
      investment by R 41600 * 6/52 = 4800

       

    10. A, B and C started a partnership business rs. 8400 , rs 5000 and rs.6200 respectively. If they invested their capital for 5 months , 6 months and 8 months , how much profit B gets at the end of the year ?
      480
      520
      380
      can’t determined.
      350
      Option D
      Here , profit is not given so, we can’t calculate profit share of B.

       

    03
    4Jul, 2021
    Quantitative Aptitude: Simplification Questions Set 112
    1. Directions : What should come in place of questions marks ( ? ) in the following questions ?
      √1296 + √2025 – √2916 = ?
      25
      27
      37
      36
      18
      Option B
      36 + 45 – 54 = ?
      ? = 27

       

    2. 45% of 830 + 22% 740 – 148 = ?
      463.5
      825.6
      388.3
      540
      332.4
      Option C
      373.5 + 162.8 – 148 = ?
      ? = 388.3

       

    3. (18)^2 + (52)^2 – 140 + 245 = ?
      2520
      3240
      2824
      2923
      3048
      Option D
      324 + 2704 – 105 = ?
      ? = 2923

       

    4. 7862 – 2136 + 5625 – 6524 = ?
      5328
      3428
      3625
      2450
      4827
      Option E
      13487 – 8660 = ?
      ? = 4827

       

    5. 25% of 480 + 24% of 420 – 8^2 = ?
      520
      324
      219
      319
      450
      Option C
      120 + 100.8 – 64 + 62.2 = ?
      ? = 283 – 64
      ? = 219

       

    6. 23% of 1200 + 11.11% of 729 + 375 = ?
      520
      732
      632
      534
      420
      Option B
      276 + 81 + 375 = ?
      ? = 732

       

    7. 1/9 of 3/5 of 375 + 185 = ?
      320
      260
      420
      440
      360
      Option B
      1/9 * 3/5 * 375 + 235 = ?
      25 + 235 = ?
      ? = 260

       

    8. 520 + 389 – (13)^2 + (15)^2 = ?
      965
      845
      320
      740
      670
      Option A
      520 + 389 + 225 – 169 = ?
      ? = 1134 – 169
      ? = 965

       

    9. 20% of 540 + 24% of 1200 – √1728 = ?
      285
      384
      280
      320
      296
      Option B
      108 + 288 – 12 = ?
      ? = 396 – 12
      ? = 384

       

    10. 640/20 – 180 + 324 – 20 = ?
      120
      156
      124
      320
      450
      Option B
      32 + 324 – 180 – 20 = ?
      ? = 356 – 200
      ? = 156

       

    04
    3Jul, 2021
    Quantitative Aptitude: Ratio and Proportion Questions Set 11
    1. Vessels A and B contain the mixture of alcohol and water in the ratio of 4 : 5 and 3 : 2 respectively. If vessels A and B are mixed then what is the ratio of new mixture which is obtained ?
      5 : 8
      35 : 29
      47 : 43
      5 : 2
      2 : 5
      Option C
      Quantity of alcohol and water in vessel B = 3/5 and 2/5
      New ratio = (4/9 + 3/5) : (5/9 + 2/5)
      = (20 + 27/45) : (25 + 18/45)
      = 47 : 43

       

    2. The ratio of total students to number girl of a particular class is 8 : 5. If numbers of boys of that class is 450 , then find the total number of students.
      1220
      1100
      1200
      1345
      1000
      Option C
      Let total number of students = 8x
      number of girls = 5x
      number of boys = 8x – 5x = 3x
      3x = 450
      x = 150
      Total students = 1200

       

    3. Sipun has three types of coins 10 paisa, 50 paisa and 20 paisa of coin is 4 : 2 : 5. If total coins worth is rs.96, then find the number of 50 paisa coins.
      60
      75
      48
      80
      40
      Option D
      Let number of 10 paisa, 50 paisa and 20 paisa coins are 4x, 2x and 5x respectively.
      4x * 10 + 2x * 50 + 5x * 20 = 9600
      40x + 100x + 100x = 9600
      x = 40
      number of 50 paisa coins = 2x = 80

       

    4. The ratio of monthly income of A and B is 3 : 5 and the ratio of the expenditure of A and B is 6 : 11. If the savings of A and B are rs.6000 and rs.8000 respectively. What is expenditure of B ?
      48000
      42000
      43000
      35000
      30000
      Option E
      Let income of A and B are 3x and 5x.
      3x – 6000/5x – 8000 = 6/11
      33x – 66000 = 30x – 48000
      3x = 18000
      x = 6000
      income of B = 5 * 6000 = 30000

       

    5. There are total of 48 employees in a company. The ratio of male employees to the female employees is 5 : 3. How many more female employees to be recruited to that the ratio becomes 1 : 1 ?
      10
      15
      12
      20
      25
      Option C
      Number of male employees = 48 * 5/8 = 30
      number of female employees = 48 * 3/8 = 18
      Let number female employees recruited = x
      30/18 +x = 1/1
      18 + x = 30
      x = 12

       

    6. The ratio of milk and water in a mixture is 6 : 5 and 22 liter of mixture is replaced with water, so that ratio of milk and water in new mixture is 3 : 8, then how much quality of water in the mixture initially ?
      20 liters
      32 liters
      28 liters
      35 liters
      40 liters
      Option A
      Let quality of milk and water are 6x and 5x respectively.
      (6x – 22 * 6/11)/(5x – 22 * 5/11+22)= 3/8
      6x – 12/5x + 12 = 3/8
      48x – 96 = 15x + 36
      33x = 132
      x = 4
      quality of water initially = 5x = 5 * 4 = 20 liters.

       

    7. The ratio of income to expenditure of A is 4 : 3 and that of B 5 : 3. If savings of B is double that of A, then what could be the ratio of total income of A and B together to the total expenditure of A and B together ?
      2 : 3
      4 : 5
      3 : 2
      5 : 8
      6 : 9
      Option C
      Let income and expenditure of A = 4x and 3x
      income and expenditure of B = 5x and 3x
      saving of A = 4x – 3x = x
      saving of B = 5x – 3x = 2x
      ratio = (4x + 5x) : (3x + 3x)
      = 9x : 6x = 3 : 2

       

    8. The ratio of male employees to female employees of a bank is 5 : 4. If 10 male employees left the job and 4 more female employees joined the bank, so that ratio between male to female employees is 7 : 8, then find the total employees of the bank initially ?
      85
      81
      92
      78
      48
      Option B
      Let male and female employees are 5x and 4x respectively.
      5x – 10/4x + 4 = 7/8
      40x – 80 = 28x + 28
      12x = 108
      x = 9
      total male and female employees initially = 5x + 4x = 9x = 9 * 9 = 81

       

    9. The seats for commerce, science and arts in a college are in the ratio of 5 : 4 : 8. If these seats are increased by 20%, 50% and 75% respectively, what will be the ratio of the increased seats of the college ?
      5 : 2 : 8
      6 : 2 : 3
      5 : 4 : 8
      6 : 6 : 14
      4 : 3 : 2
      Option D
      Let commerce seats = 5x
      science seats = 4x
      Arts seats = 8x
      ratio of commerce, science and arts seats after increased = (5x * 6/5) : (4x * 3/2) : (8x * 7/4)
      = 6x : 6x : 14x
      = 6 : 6 : 14

       

    10. Total income of A, B and C is rs.9400. If A’s income is 4/5th of B’s income and B’s income is 3/4th of C’s income, then find the income of C.
      3400
      4000
      5200
      3200
      2800
      Option B
      A = 4/5 B
      A/B = 4/5
      A/B = 4 * 3/5 * 3 = 12/15
      B = 3/4 *C
      B/C = 3/4
      B/C = 3 * 5/4 * 5
      B/C = 15/20
      ratio of A, B and C = 12 : 15 : 20
      B’s income = 9400 * 20/47 = 4000

       

    05
    2Jul, 2021
    Quantitative Aptitude: Number Series Set 151
    1. Directions : what should come in place of questions (?) marks in the following number series ?
      18, 37, 56, ?, 94
      72
      60
      80
      75
      74
      Option D
      The series is, +19, +19, +19…

       

    2. 15, 8, 9, 20, ?, 256
      68
      40
      42
      92
      63
      Option E
      The series is, (*.5 + 5), (*1 + 1), (*2 + 2), (*3 + 3), (*4 + 4)

       

    3. 1448, 936, 593, 377, ?, 188
      354
      252
      192
      264
      260
      Option B
      The series is, -8^3, -7^3, -6^3, -5^3, -4^3

       

    4. 23, 18, 25, 14, 27, 10, ?
      30
      25
      6
      32
      29
      Option E
      The series is , +2, -4, +2, -4 of alternate numbers.

       

    5. 34, 53, 76, 105, ?, 169
      136
      125
      140
      142
      148
      Option A
      The series is, +19, +23, +29… ( additions of prime numbers )

       

    6. Directions : What will be the wrong number in the given wrong number series ?
      17, 33, 69, 133, 233, 354
      69
      133
      17
      233
      354
      Option E
      The series is, +4^2, +6^2, +8^2, +10^2, +12^2

       

    7. 4, 10, 22, 42, 72, 120
      120
      22
      42
      4
      72
      Option A
      The series is, +(2^2 + 2), +(3^2 + 3), +(4^2 + 4), +(5^2 + 5), +(6^2 + 6)

       

    8. 45, 83, 128, 215, 339, 550
      215
      339
      128
      550
      83
      Option A
      The series is (45 + 83), (83 + 128), (128 + 211), (211 + 339)

       

    9. 32, 64, 192, 768, 3846, 23040
      192
      32
      64
      3846
      23040
      Option D
      The series is *2, *3, *4, *5, *6

       

    10. 28, 34, 46, 70, 118, 220
      46
      220
      28
      118
      46
      Option B
      The series is (+6), (+12), (+24), (+48), (+96)

       

    06
    1Jul, 2021
    Quantitative Aptitude: Problems on Ages Set 20
    1. The present age of A and B are 29 and 32 years respectively, after how many years ratio of ages of B and A becomes 14 : 13 ?
      5 years
      8 years
      12 years
      10 years
      14 years
      Option D
      Let after x years ratio of ages of A and B becomes 13 : 14
      29 + x/32 + x = 13/14
      x = 10 years.

       

    2. The ratio of present ages of A and B is 3 : 2 and ratio of present ages of C and B is 5 : 4. If total present age of A, B and C is 120 years then, what the age of B before 6 years.
      28
      18
      32
      29
      26
      Option E
      Ratio of age A and B = 3 : 2
      ratio of B and C = 4 : 5
      A : B : C = 6 : 4 : 5
      Let total ages of A, B and C = 15x
      15x = 120
      x = 8
      present age of B = 8 * 4 = 32 years.
      before 5 years age of B = 32 – 5 = 26 years.

       

    3. The ratio of present age of Papu and Sipu is 4 : 5. The ratio of age of Papu after 4 years and Sipu before 8 years is 9 : 8, then find the age of Papu after 14 years.
      45 years
      35 years
      28 years
      46 years
      52 years
      Option D
      Let present age of Papu and Sipu are 4x and 5x respectively.
      4x + 4/5x – 8 = 9/8
      45x – 72 = 32x + 32
      13x = 104
      x = 8
      the age of Papu after 14 years = 4x + 14 = 46 years

       

    4. The present age of father is two times more than the present age of son. If after 6 years the ratio of age of father and son is 7 : 3, then find the age of son after 5 years.
      15
      18
      17
      20
      28
      Option C
      Let present age of son = x
      present age of father = 3x
      3x + 6/ x + 6 = 7/3
      9x + 18 = 7x + 42
      x = 12
      age of son after 5 years = 12 + 5 = 17 years.

       

    5. The age of brother is four times of his sister and after 18 years the ratio of age of brother and sister is 2 : 1. What is age of brother after 4 years ?
      20
      28
      46
      40
      52
      Option D
      Let the age of sister = x
      the age of brother = 4x
      4x + 18/x + 18 = 2/1
      4x + 18 = 2x + 36
      2x = 18
      x = 9
      The age of brother after 4 years = 4x + 4 = 40 years.

       

    6. A is as much younger to B as he is elder to C and the sum of the age of B and C is 52 years, then what is the age of A ?
      14
      17
      28
      23
      26
      Option E
      Total age of B and C = 52
      B – A = A – C
      2A = B + C
      2A = 52
      A = 26 years.

       

    7. The ratio of the present age of A and B is 8 : 5. If the A’s present age is 5 years more than B’s age after 10 years, then what is the sum of age A and B after 5 years ?
      80
      75
      60
      64
      82
      Option B
      Let present age of A and B are 8x and 5x respectively.
      8x – (5x + 10) = 5
      8x – 5x – 10 = 5
      3x = 15
      x = 5
      age of A after 5 years = 8x + 5 = 45
      age of B after 5 years = 5x + 5 = 30
      sum = 45 + 30 = 75 years.

       

    8. The ratio between the present ages of A and B is 5 : 6. If the ratio between the one – third age of A and half that of B is 5 : 9, then what is the present age of A ?
      45
      38
      62
      54
      can not determined.
      Option E
      Let the present age of A and B are 5x and 6x respectively.
      (5x/3)/(6x/2) = 5/9
      5x/3 * 9 = 6x/2 * 5
      Here, we can not calculate the present age of A.

       

    9. Two years ago, the age of mother was four times as old as her daughter. After four years, difference between the age of mother and the age of daughter is 18 years. Find the age of mother after 8 years.
      38
      34
      42
      56
      48
      Option B
      Two years ago let age of daughter = x
      age of mother = 4x
      present age of mother and daughter = (4x + 2), (x + 2)
      After 4 years, the age of mother = 4x + 2 + 4 = 4x + 6
      the age of daughter = x + 2 + 4 = x + 6
      difference = 20
      4x + 6 – (x + 6) = 18
      4x + 6 – x – 6 = 18
      3x = 18
      x = 6
      the age of mother after 8 years = 4x + 2 + 8 = 24 + 10 = 34 years.

       

    10. The ratio between the present ages of P and Q is 4 : 5. If the ratio between their ages 4 years hence, becomes 14 : 17. What is Q’s age of present ?
      45
      30
      32
      57
      26
      Option B
      Let present age of P and Q are 4x and 5x respectively.
      4x + 4/5x + 4 = 14/17
      70x + 56 = 68x + 68
      2x = 12
      x = 6
      Q’s present age = 5x = 30 years.

       

    07
    30Jun, 2021
    Quantitative Aptitude: Quadratic Equations Questions Set 75
    1. I. x^2 – 8x + 12 = 0
      II. 2y^2 + 7y + 5 = 0
      X ≥ Y
      X ≤ Y
      X > Y
      X < Y
      X= Y or no relation.
      Option C
      I. x^2 – 6x – 2x + 12 = 0
      x = 6, 2
      II. 2y^2 + 5y + 2y + 5 = 0
      2y = -5, -2
      y = -2.5, -1

       

    2. I. y^2 = 196
      II. x^2 – 30x + 225 = 0
      X ≥ Y
      X > Y
      X ≤ Y
      X= Y or no relation.
      X < Y
      Option B
      I. y = 14, -14
      II. x^2 – 15x – 15x + 225 = 0
      x = 15, 15

       

    3. I. 4x^2 + 14x – 8 = 0
      II. y^2 + 8y + 16 = 0
      X ≤ Y
      X= Y or no relation.
      X < Y
      X > Y
      X ≥ Y
      Option E
      I. 4x^2 + 16x – 2x – 8 = 0
      4x = -16, 2
      x = -4, .5
      II. y^2 + 4y + 4y + 16 = 0
      y = -4, -4

       

    4. I. x^3 = 1728
      II. y^2 – 24y + 144 = 0
      X < Y
      X ≤ Y
      X= Y or no relation.
      X ≥ Y
      X > Y
      Option C
      I. x = 12
      II. y^2 – 12y – 12y + 144 = 0
      y = 12, 12

       

    5. I. x^2 – 32x + 156 = 0
      II. y^2 – 33y + 140 = 0
      X ≥ Y
      X > Y
      X ≤ Y
      X= Y or no relation.
      X < Y
      Option D
      I. x^2 – 26x – 6x + 156 = 0
      x = 26, 6
      II. y^2 – 28y – 5y + 140 = 0
      y = 28, 5

       

    6. I. 2x^2 – 24x + 64 = 0
      II. y^3 = 512
      X < Y
      X= Y or no relation.
      X ≤ Y
      X > Y
      X ≥ Y
      Option C
      I. 2x^2 – 16x – 8x + 64 = 0
      2x = 16, 8
      x = 8, 4
      II. y^3 = 512
      y = 8

       

    7. I. x^2 = 400
      II. y = √400
      X ≥ Y
      X < Y
      X ≤ Y
      X= Y or no relation.
      X > Y
      Option C
      I. x^2 = 400
      x = 20, -20
      II. y = √400
      y = 20

       

    8. I. x^2 – 7x + 12 = 0
      II. y^2 + 5y + 6 = 0
      X ≤ Y
      X < Y
      X= Y or no relation.
      X > Y
      X ≥ Y
      Option D
      I. x^2 – 4x – 3x + 12 = 0
      x = 4, 3
      II. y^2 + 3y + 2y + 6 = 0
      y = -3, -2

       

    9. I. x^2 – 14x + 48 = 0
      II. y^2 = 64
      X > Y
      X < Y
      X ≥ Y
      X ≤ Y
      X= Y or no relation.
      Option E
      I. x^2 – 8x – 6x + 48 = 0
      x = 8, 6
      II. y^2 = 64
      y = + 8, – 8

       

    10. I. 2x^2 + 19x + 34 = 0
      II. y – 8y + 15 = 0
      X < Y
      X > Y
      X ≤ Y
      X ≥ Y
      X= Y or no relation.
      Option A
      I. 2x^2 + 17x + 2x + 3 = 0
      2x = – 17, – 2
      x = – 8.5, – 1
      II. y – 5y – 3y + 15 = 0
      y = 5, 3

       

    08
    29Jun, 2021
    Quantitative Aptitude: Profit and Loss Set 28
    1. A person sold an article earned a profit of rs.2500 after giving a discount of 25%. If he had sold it for rs.500 more he would have earned a profit of 60%, then what is the cost price of the article ?
      6500
      6000
      5500
      7500
      5000
      Option E
      Let MP of an article = 4x
      SP of an article = 4x – x = 3x
      profit = 2500
      CP = 3x – 2500
      If he sold it rs.500 more,
      3x + 500 = (3x – 2500)8/5
      15x + 2500 = 24x – 20000
      9x = 22500
      x = 2500
      CP = 3x – 2500 = 5000

       

    2. A shopkeeper marked a book 40% above the cost price and sold it after giving a discount of 30%, so that he made a loss of rs.4, what is the marked price of the article ?
      240
      420
      280
      300
      320
      Option C
      Let CP a book = 100x
      MP = 100x * 140/100 = 140x
      SP = 140x * 70/100 = 98x
      loss = 100x – 98x = 2x
      2x = 4
      x = 2
      MP = 140x = 140 * 2 = 280

       

    3. A dishonest salesman professes to sell his goods at the cost price but use faulty measure. His 1kg weight measures 950gms only. Find the gain percentage ?
      200/6%
      15%
      20%
      100/19%
      28%
      Option D
      Let CP = 950gm
      SP = 1000gm
      profit = 50
      profit % = 50/950 * 100 = 100/19%

       

    4. A person sells 18 chocolates, so that he losses the selling price of 2 chocolates. Find his loss percentage ?
      5%
      10%
      8%
      12%
      20%
      Option B
      Let SP of 1 chocolate = rs.1
      SP of 18 chocolate = rs.18
      loss = rs.2
      CP = 18 + 2 = 20
      loss % = 2/20 * 100 = 10%

       

    5. A person bought two articles for rs.2000 and rs.2500 respectively. He sold first at a gain of 10%. At what price should he sell the other to get a profit of 20% on the whole transaction ?
      3200
      3000
      4000
      4500
      6500
      Option A
      CP of first article = 2000
      SP = 2000 * 110/100 = 2200
      Total CP = 2000 + 2500 = 4500
      total SP = 4500 * 120/100 = 5400
      SP of second article = 5400 – 2200 = 3200

       

    6. A man sells the product for rs.800 and make some profit. If he sells it for rs.300 his loss is 2/3 of the earlier profit then what is the cost price of the product ?
      400
      500
      650
      550
      740
      Option B
      Let CP the product = x
      SP = 800
      profit = 800 – x
      he sells for rs.300
      loss = x – 300
      (800 – x)2/3 = x – 300
      1600 – 2x = 3x – 900
      5x = 2500
      x = 500

       

    7. A shopkeeper sells a table 4% discount on the marked price. The cost price of the table is 500 and he sells it at a profit of 20%, then what is marked price of the table ?
      480
      320
      680
      625
      420
      Option D
      CP of the table = 500
      SP = 500 * 120/100 = 600
      MP = 600 * 100/96 = 625

       

    8. Sita buys two books a total cost of rs.1400. She sells one for 3/4 of its cost and other for 2 times of its cost, so that she makes a profit of rs.400 on the whole transaction. What is the cost price of the lower price book.
      600
      800
      500
      600
      700
      Option D
      Total CP of the book = rs.1400
      total SP of book = 1400 + 400 = 1800
      Let CP of one book = x
      CP of other book = 1400 – x
      x * 3/4 + (1400 – x)^2 = 1800
      x * 3/4 + 2800 – 2x = 1800
      3x + 11200 – 8x = 7200
      x = 800
      CP of lower price book = 1400 – 800 = 600

       

    9. Sanju buys an old cycle for rs.1400 and spends rs.600 for its repair. After some days he sells his cycle at rs.2500, find profit percent of cycle ?
      20%
      25%
      28%
      32%
      14%
      Option B
      CP of cycle = 1400
      he spend on it = 600
      total CP = 1400 + 600 = 2000
      he sold it = 2500
      profit percentage = 500/2000 * 100 = 25%

       

    10. The cost price of item Q is 300 more than the cost price item P. If item P was sold at a profit of 20% and item Q was sold at a loss of 40%. The ratio between selling price of P and Q is 8 : 7. What is the cost price of item Q ?
      800
      700
      850
      640
      520
      Option B
      Let cost price of item P = x
      and item Q = x + 300
      SP of item P = x * 120/100 = 6x/5
      SP of item Q = (x + 300) 60/100 = (x + 300)3/5
      (6x/5)/(x + 300)3/5 = 8/7
      6x/5/3x + 900/5 = 8/7
      42x = 24x + 7200
      18x = 7200
      x = 400
      cost price of item Q = x + 300 = 700

       

    09
    28Jun, 2021
    Quantitative Aptitude: Simple/Compound Interest Set 22
    1. Sivam invested some money in a scheme at the rate of 20% for 3 years. If he withdraws 40% of total amount and left remaining amount is rs.2304. What is total money which he invested at earlier.
      2500
      2400
      3500
      3200
      4200
      Option B
      Let principal = 100x
      SI = 100x * 20/100 * 3 = 60x
      Total amount = 100x + 60x = 160x
      remaining = 160x * 60/100 = 96x
      96x = 2304
      x = 24
      He invested = 100x = 2400

       

    2. Simple interest on rs.2750 for 2 years at certain rate of interest is rs.120 more than simple interest on rs.1500 for 3 years at same rate of interest. What is the rate of interest ?
      12%
      14%
      15%
      13%
      18%
      Option A
      Let rate of interest = R%
      (2750*R/100*2) – (1500*R/100*3) = 120
      55 R – 45R = 120
      10 R = 120
      R = 12%

       

    3. Simple interest on a certain sum of money at rate of 20% for 2 years is two times of the compound interest on rs.5000 for 2 years at the rate of 14% per annum. What is the sum on simple interest ?
      8340
      8000
      12000
      7490
      14000
      Option D
      Rate of compound interest after 2 years = 14 + 14 + 14 * 14/100 = 29.96%
      compound interest = 5000 * 29.96/100 = 1498
      simple interest = 1498 * 2 = 2996
      Let principal on simple interest = x
      2996 = x * 20/100 * 2
      x = 7490

       

    4. A man invested an amount of rs.4800 for 3 years a certain rate of simple interest become rs.7248. If the rate of interest increases by 3%, what amount will rs.5000 becomes in 2 years ?
      7200
      6320
      8450
      8240
      6830
      Option A
      Simple interest = 7248 – 4800 = 2448
      2448 = 4800 * 3 * 12/100
      R = 17%
      Now rate of interest = 17 + 3 = 20%
      Amount = 5000 * 120/100 * 120/100 = 7200

       

    5. In how many years a sum will become four times itself at the rate of 12% per annum in simple interest ?
      12 years
      24 years
      25 years
      26 years
      20 years
      Option C
      Let the principal = x
      Amount = 4x
      Simple interest = 4x – x = 3x
      3x = x * 12/100 * T
      T = 25 years.

       

    6. A deposited rs.6800 in a bank at 8% per annum for 5 years simple interest. B deposited rs.8000 at 20% per annum for 2 years in compound interest. What is difference between compound interest and simple interest.
      850
      240
      836
      800
      840
      Option D
      Simple interest = 6800 * 8/100 * 5 = 2720
      By using successive,
      20 + 20 + 20 * 20/100 = 44%
      compound interest = 8000 * 44/100 = 3520
      Difference = 3520 – 2720 = 800

       

    7. A certain sum in simple interest becomes rs.6600 in 4 years and becomes rs.7400 in 6 years, then find the rate of interest.
      4%
      8%
      20%
      14%
      18%
      Option B
      Simple interest for 2 years = 7400 – 6600 = 800
      simple interest for 1 year = 400
      simple interest for 4 years = 4 * 400 = 1600
      sum = 6600 – 1600 = 5000
      1600 = 5000 * R/100 * 4
      R = 8%

       

    8. The difference between compound and simple interests on a sum for 2 years at 15% per annum is 450. Find the sum.
      12000
      25000
      20000
      38000
      35000
      Option C
      CI – SI = PR^2/100^2
      450 = P * 225/10000
      P = 20000

       

    9. The population of a town increased by 25% p.a. If the present population is 50000. Find the population of town 3 years ago.
      25600
      24480
      32540
      24000
      30340
      Option A
      Let the population of town 3 year ago = x
      x * 5/4 * 5/4 * 5/4 = 50000
      x = 50000 * 64/125
      x = 25600

       

    10. What is difference between compound interest and simple interest for 2 years on a principal of rs.4000 at the annual rate of 25% ?
      340
      125
      250
      350
      300
      Option C
      Simple interest = 4000 * 25/100 * 2 = 2000
      Rate of compound interest after 2 years = 25 + 25 + 25 * 25/100 = 56.25%
      compound interest = 4000 * 56.25/100 = 2250
      difference = 2250 – 2000 = 250

       

    10