Quantitative Aptitude Questions Bank PO Tricks for SBI PO, IBPS PO, NIACL, NICl, BoB, Dena Bank PGDBF and other competitive exams

1. If 75 is added to 75% of a number then the number becomes 125% of it. Find the original number.
   A) 187.5
   B) 150
   C) 200
   D) 112.5
   E) 165.5
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option B
   Solution:
   75% = 3/4, 125% = 5/4
   We have to make 3/4 to 5/4
   3 => 5 means increase of 2
   So 2 = 75 (the number that is to be added
   And 4 (denominator – the original number)  = 75/2 * 4 = 150[/su_spoiler]
2. After a discount of 11.11%, a trader still makes a gain of 14.28%. At how much percent above the cost price does he mark his goods?
   A) 16.67%
   B) 23.37%
   C) 22.22%
   D) 28.56%
   E) 31.22%
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option D
   Solution:
   Discount is calculated on MP
   11.11% = 1/9  (1 – discount, 9 – MP)
   MP – Discount = SP
   So 9 – 1 = 8
   Profit% = 14.28% = 1/7 (1 – gain, 7 – CP)
   SP = CP + Profit
   So SP = 7 + 1 = 8
   Both SP are found to be same
   So CP : SP : MP = 7 : 8 : 9
   Required % = (9-7)/7 * 100 = 200/7% [/su_spoiler]
3. A water tank has three taps A, B, and C. A fills four buckets in 24 mins, B fills 8 buckets in 1 hour and C fills 2 buckets in 20 minutes. If all the taps are opened together a full tank is emptied in 2 hours. If a bucket can hold 5 litres of water, what is the capacity of the tank?
   A) 240 l
   B) 280 l
   C) 200 l
   D) 300 l
   E) 250 l
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option A
   Solution:
   Bucket is to be emptied in 2 hours or 120 minutes
   In 24 mins, A can fill 4 buckets
   So in 120 minutes, it can fill 20 buckets
   Similarly
   In 120 minutes, B can fill 16 buckets
   In 120 minutes, C can fill 12 buckets
   Total = 20+16+12 = 48
   1 bucket = 5 litre
   So 48 buckets = 240 litres [/su_spoiler]
4. 7 men, 5 women and 8 children together have to distribute 1740 books in a total 3 days. On the first day all distribute books. On second day 2 women and 3 children were absent and on the third day 3 men and 5 children were absent. If the ratio of the number of books distributed in a day by a man, a woman and a child was 5 : 4 : 2 respectively, a total of approximately how many books were distributed on the second day?
   A) 650
   B) 700
   C) 510
   D) 600
   E) 570
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option E
   Solution:
   The ratio 5 : 4: 2 specifies the efficiency
   In 3 days, total men = 7 + 7 + 4 = 18
   In 3 days, total women = 5 + 3 + 5 = 13
   In 3 days, total children = 8 + 5 + 3 = 16
   So 18*5x + 13*4x + 16*2x = 1740
   Solve, x = 10
   So second day distribution:
   7*5x + 3*4x + 5*2x = 57x = 57*10 = 570  [/su_spoiler]
5. Keshav invests some amount. It amounts to Rs 6000 in 2 years and to Rs 8000 in 4 years if compounded annually. Fin the sum invested by him.
   A) Rs 4000
   B) Rs 5400
   C) Rs 5000
   D) Rs 4500
   E) Rs 4800
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option D
   Solution:
   When difference of year is same in CI (like here 2 years and then 2+2 = 4 years):
   x(principal) : 6000 = 6000 : 8000
   Solve, x = Rs 4500 [/su_spoiler]
6. The price of an article is first increased by 25%, then by 10% and at last increased by 14 2/7%. If the original price was Rs 140, find the new price after 3 increments.
   A) 180
   B) 160
   C) 200
   D) 230
   E) None of these
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option E
   Solution:
   25% = 1/4
   10% = 1/10
   14 2/7% = 1/7
   Original price = 140
   After first increment = 140 + 1/4 * 140 = 175
   After second increment = 175 + 1/10 * 175 = 192.5
   After third increment = 192.5 + 1/7 * 192.5 = Rs 220   [/su_spoiler]
7. A shopkeeper bought an article for Rs 12000. He marked the price 25% above the cost price. If during selling a discount of 10% is given on the marked price, find the profit/loss% incurred by the shopkeeper.
   A) 15%
   B) 12.5%
   C) 12%
   D) 10%
   E) 14.5%
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option B
   Solution:
   MP is 25% above CP
   25% = 1/4 (1 – increased price, 4 – CP)
   So MP = CP + increased price = 4(CP) + 1 = 5(MP)  ……..(i)
   Discount = 10% = 1/10
   So SP = 10(MP)  – 1 = 9(SP)  …….(ii)
   Now make MP same in both equations by multiplying equation(i) by 2
   So 8(CP) + 2 = 10 (MP)
   So
   CP : MP : SP = 8 : 10 : 9
   So profit% = (9-8)/8 * 100 = 12.5%
   [/su_spoiler]
8. A solution of sugar syrup has 35% of sugar. Another solution has 20% sugar. How many litres of the second solution must be added to 40 litres of the first solution to make a solution of 25% sugar?
   A) 40 l
   B) 60 l
   C) 80 l
   D) 70 l
   E) 50 l
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]   Option C
   Solution:
   35% of 40 + 20% of x = 25% of (40+x)   [/su_spoiler]
9. Train A crosses a pole and a platform in 18 seconds and 39 seconds respectively. The length of the platform is 157.5 m. What will be the length of train B if it is equal to the sum of half of the length of train A and twice the length of the platform?
   A) 328.5 m
   B) 382.5 m
   C) 238.5 m
   D) 315 m
   E) None of these
   [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option B
   Solution:
   (l+ 157.5)/s =  39
   Also l/s = 18
   Solve both, l = length of train = 135m
   So length of train B = (135/2) + 2 * 157.5 = 382.5 m [/su_spoiler]
10. A plane left 30 minutes later than the scheduled time and in order to reach its destination 1500 km away in time, it had to increase its speed by 250km/hr from its usual speed. Find its usual speed.
    A) 720 km/hr
    B) 750 km/hr
    C) 790 km/hr
    D) 840 km/hr
    E) None of these
    [su_spoiler title=” View Answer ” icon=”chevron-circle”]  Option B
    Solution:
    Solve with options:
    Take 750. It cancels out 1500, so 1500/750 = 2 hours
    it left 30 minutes later, so it has to cover distance in 2 – 1/2 = 1 hour 30 minutes  = 3/2 hours
    then speed should be 1500/(3/2) = 1000 km/hr
    Speed is increased by 250 km/hr
    And 750 + (250) = 1000 – satisfies the condition. [/su_spoiler]