24Nov, 2021
Mixed Quantitative Aptitude Questions Set 233
  1. A container which contains 80 liters of milk and water in the ratio of 3 : 2. How much quantity of mixture should be replaced with water so that in the final mixture, ratio of milk to water is 9 : 11 ?
    25 liters
    32 liters
    28 liters
    20 liters
    42 liters
    Option D
    Quantity of milk = 80 * 3 /5 = 48 liters
    Quantity of water = 80 * 2 /5 = 32 liters
    let ‘x’ liters of mixture is replaced with water.
    (48 – x * 3/5 ) / (32 – x * 2/5 + x) = 9/11
    x = 20 liters

     

  2. Ram bought a chair for rs.480 and marked is at rs.720. If he made a profit of 25% on selling the table then find percentage discount allowed by Ram on the chair ?
    15%
    20%
    18%
    45%
    16.67%
    Option E
    SP of chair = 480 * 125/100 = 600
    MP = 720
    discount percentage = 720 – 600/720 * 100 = 16.67%

     

  3. A alone can do a work in 25 days whereas B and C together can do some work in 20 days. A and B together worked for 8 days then A left the work. If efficiency of C is half of efficiency of A, then in how many days remaining work will be completed b A and C together ?
    5 days
    7 1/3 days
    15 days
    8 days
    14 days
    Option B
    LCM of 25 and 20 = 100
    efficiency of A = 100/25 = 4
    efficiency of B and C = 100/20 = 5
    efficiency of C = 4/2 =2
    efficiency of B = 5 – 2= 2
    A and B worked for 8 days = 8 ( 4 + 3) = 56 work
    remaining work = 100 – 56 = 44
    remaining work will be completed A and C together = 44/4 + 2 = 7 1/3 days

     

  4. Train A travelling at 72 km/hr crosses a platform of 160 m in 18 seconds and train B travelling at 90 km/hr crosses the same platform in 15 seconds. Find the length of train B ?
    320m
    240m
    210m
    225m
    215m
    Option E
    Speed of train A = 72 * 5/18 = 20 m/sec
    distance covered by train A = 20 * 18 = 360 m
    length of train A = 360 – 160 = 200m
    speed of train B = 90 * 5/18 = 25 m/sec
    distance covered by train B = 25 * 15 = 375 m
    length of train B = 375 – 160 = 215 m

     

  5. A is 6 years younger than B and ratio of present age of B to C is 12 : 5. If ratio of present age of A to C is 2 : 1, then find present age of B ?
    32 years
    34 years
    42 years
    36 years
    40 years
    Option D
    Let present age of B = 12x
    age of C = 5x
    age of A = 12x – 6
    12x – 6/5x = 2/1
    12x – 6 = 10x
    2x = 6
    x = 3
    present age of B = 12 * 3 = 36 years

     

  6. Directions : What will come in place of questions marks ( ? ) in the following questions below ?
    35% of 320 + 440 – √1024 = ?
    540
    320
    340
    620
    520
    Option E
    112 + 440 – 32 = ?
    ? = 520

     

  7. 124 * 4 – 320 ÷ 5 + √361 – 18 = ?
    225
    320
    435
    433
    520
    Option D
    496 – 64 + 19 – 18 = ?
    ? = 433

     

  8. 495 ÷ 5 + (21)^2 – (20)^2 = ?
    324
    420
    325
    140
    260
    Option D
    99 + 441 – 400 = ?
    ? = 140

     

  9. 1240 + 2520 – 3540 + 4250 = ?
    4340
    5470
    4240
    3450
    4470
    Option E
    ? = 8010 – 3540
    ? = 4470

     

  10. (12)^2 + (18)^2 – (20)^2 + (14)^2 = ?
    365
    264
    345
    420
    540
    Option B
    144 + 324 + 196 – 400 = ?
    ? = 264