1Dec, 2021
Mixed Quantitative Aptitude Questions Set 239
  1. A train , 240 m long crosses a man, walking along the line in opposite direction at the rate of 3 km/hr in 10 seconds. What is the speed of train ?
    80 km/hr
    75 km/hr
    83.4 km/hr
    92.8 km/hr
    68 km/hr
    Option C
    Let speed of train = x m/hr
    240/(3 + x) 5/18 = 10
    x = 83.4 km/hr

     

  2. A boat takes a total of 24 hours to over 90 km in downstream and 90 km in upstream. If the ratio of speed of boat in sill water and speed of stream is 4 : 1, then find how much time is required to cover 120 km distance in down stream speed ?
    8 hours
    14 hours
    20 hours
    15 hours
    12 hours
    Option E
    Let speed of boat in still water = 4x
    speed of stream = x
    downstream speed = 4x + x = 5x
    upstream speed = 4x – x = 3x
    90/5x + 90/3x = 24
    x = 2
    downstream speed = 5 * 2 = 10 km/hr
    time = 120/10 = 12 hours

     

  3. A equilateral tringle and a square have the same area. If the perimeter of the square is 88cm, then find what is area of the equilateral tringle ?
    196 cm^2
    256 cm^2
    144 cm^2
    484 m^2
    125 cm^2
    Option D
    Perimeter of square = 88cm
    side of square = 88/4 = 22cm
    area of square = 22 * 22 = 484 cm^2
    area of tringle = 484 cm^2

     

  4. Pipe A can fill a tank in 15 hours and pipe B can fill the same tank in 60 hours, pipe C can empty in 10 hours. Pipe A and B are kept opened for 10 hours in the beginning and then pipe C is also opened, what is the time taken to empty the tank ?
    60 hours
    40 hours
    30 hours
    25 hours
    50 hours
    Option E
    Capacity of the tank = 15, 60, 10 = 60 units
    efficiency of pipe A = 60/15 = 4 units
    efficiency of pipe B = 60/60 = 1
    efficiency of pipe C = 60/10 = 6 units
    tank filled in 1st 10 hours = (4 + 1) * 10 = 50 units
    now, when all the pipe work together, 1 unit of water will out in every minute from tank.
    50 units of water will be in 50 hours.

     

  5. The ratio of age of A and B, 6 years ago was 3 : 4. Sum of the present age of B and C is 80 years. C is 12 years elder to A. Find the difference of age of B and C after 4 years ?
    5 years
    6 years
    8 years
    4 years
    12 years
    Option D
    6 years ago age of A = 3x
    age of B = 4x
    present age of A = 3x + 6
    present age of B = 4x + 6
    present age of C = 3x + 6 + 12 = 3x + 18
    4x + 6 + 3x + 18 = 80
    7x = 56
    x = 8
    age of B after 4 years = 4x + 6 + 4 = 42 years
    age of C after 4 years = 3x + 18 + 4 = 46 years
    difference = 46 – 42 = 4 years

     

  6. Directions : What will be wrong number in the following wrong number series ?
    120, 83, 113, 93, 105, 99, 101
    113
    83
    105
    120
    99
    Option D
    The series is, (- 6 * 7), (+ 5 * 6), ( – 4 * 5), ( + 3 * 4), ( – 2 * 3), ( + 1 * 2)

     

  7. 1898, 1870, 1657, 1608, 1096, 1015, 15
    1096
    1015
    1898
    15
    1870
    Option E
    The series is ( – 5^2 ), (- 6^3), (- 7^2), (- 8^3 ), (- 9^2), (- 10^3)

     

  8. 48, 84, 156, 300, 590, 1164
    48
    156
    300
    590
    1164
    Option D
    The series is, ( * 2 – 12), ( * 2 – 12)…

     

  9. 2, 6, 12, 24, 30, 42, 56
    24
    12
    30
    42
    2
    Option A
    The series is , (1^2 + 1), (2^2 + 2), (3^2 + 3)…

     

  10. 1, 6, 24, 60, 120, 210
    6
    1
    60
    24
    210
    Option B
    The series is, (1^3 – 1), (2^3 – 2), (3^3 – 3), (4^3 – 4)…