3Dec, 2021
Mixed Quantitative Aptitude Questions Set 241
  1. A bag contains (x + 1), green balls and (x + 4) yellow balls. If one ball is drawn at random from the bag, the probability of getting a green ball is 3/7. Find the total number of balls in the bag ?
    34
    23
    28
    42
    21
    Option E
    Probability = 3/7
    x + 1/x + 1 + x + 4 = 3/7
    x + 1/2x + 5 = 3/7
    x = 8
    total balls in the bag = 9 + 12 = 21 balls

     

  2. A alone can do a work in 20 days and efficiency of A is 7 1/7% more than B. If efficiency of C is 20% less than A, then find in how many days B and C together can complete the same work ?
    100/9 days
    15 days
    18 days
    200/3 days
    30 days
    Option A
    Fraction value 7 1/7% = 1/14
    efficiency of B = 14
    efficiency of A = 15
    total work = 15 * 20 = 300
    efficiency of C = 15 * 4/5 = 12
    time = 300/15 + 12 = 100/9 days

     

  3. The ratio of milk and water in a mixture is 11 : 4. When 30 liters of mixture is taken out and 18 liters of milk is added in the remaining mixture, the ratio of milk to water is 5 : 1, find the initial quantity of milk.
    44 liters
    65 liters
    40 liters
    50 liters
    62 liters
    Option A
    Let quantity of milk = 11x
    and water = 4x
    (11x – 30 * 11/15 + 18)/4x – 30 * 4/15 = 5/1
    11x – 4/4x – 8 = 5/1
    11x – 4 = 20x – 40
    x = 4
    initial quantity of milk = 11 * 4 = 44 liters

     

  4. An amount is divided among A, B and C, amount of B is average of amount A and C and when amount of B is reduced by 20% of that of A, it becomes equal to that of C. Find amount of C is what percent of total amount ?
    20%
    30%
    40%
    15%
    25%
    Option E
    Let amount of A and C is rs.x and rs.y respectively.
    amount of B = x + y/2
    x + y/2 – x/5 = y
    3x = 5y
    x/y = 5/3
    amount of A = rs.5a
    amount of B = rs.4a
    amount of C = rs.3a
    % = 3a/12a * 100 = 25%

     

  5. Train A running at speed of 108 km/hr crosses a platform having twice the length of train in 24 sec. Train B whose length is 420m crosses same platform in 36 sec, then find the speed of train B ?
    108 km/hr
    45 k/hr
    76 km/hr
    90 km/hr
    72 km/hr
    Option D
    Let length of train A = x
    length of platform = 2x
    x + 2x/24 = 108 * 5/18
    x = 240m
    let speed of train B is y km/hr
    420 + 2 * 240/36 = y * 5/18
    y = 90 km/hr

     

  6. Directions : In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
    I. x^2 – 17x – 84 = 0
    II. y^2 + 4y – 117 = 0
    X > Y
    X < Y
    X ≥ Y
    X ≤ Y
    X = Y or no relation.
    Option E
    I. x^2 – 21x + 4x – 84 = 0
    x = 21, -4
    II. y^2 + 13y – 9y – 117 = 0
    y = -13, 9

     

  7. I. x^2 + 23x + 132 = 0
    II. y^2 + 21y + 110 = 0
    X > Y
    X < Y
    X ≥ Y
    X ≤ Y
    X = Y or no relation.
    Option D
    I. x^2 + 12x + 11x + 132 = 0
    x = -12, -11
    II. y^2 + 11y + 10y + 110 = 0
    y = -11, -10

     

  8. I. x^2 = 196
    II. y = √196
    X > Y
    X < Y
    X ≤ Y
    X ≥ Y
    X = Y or no relation.
    Option C
    I. x^2 = 196
    x = 14, -14
    II. y = √196
    y = 14, 14

     

  9. I. 3x^2 + 13x + 12 = 0
    II. y^2 + 9y + 20 = 0
    X > Y
    X < Y
    X ≥ Y
    X ≤ Y
    X = Y or no relation.
    Option A
    I. 3x^2 + 9x 4x + 12 = 0
    3x = -9, -4
    x = -3, -1.33
    II. y^2 + 5y + 4y + 20 = 0
    y = -5, -4

     

  10. I. x^3 = 216
    II. 2y^2 – 25y + 78 = 0
    X > Y
    X < Y
    X ≥ Y
    X ≤ Y
    X = Y or no relation.
    Option D
    I. x^3 = 216
    x = 6
    II. 2y^2 – 13y – 12y + 78 = 0
    2y = 13, 12
    y = 6.5, 6