Quantitative Aptitude: Inequalities Set 11 (For Mains Exams)
Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer.
- A and B started a business with Rs.10000 and Rs.15000 respectively. After 6 months C joined them with Rs.20000.
Quantity I: B′s share in total profit of Rs.4,00,000 at the end of 2 years.
Quantity II: Annual Salary of Druv after tax deduction if he earns Rs.20,000 per month and pays a tax of 20% each month.
Quantity I < Quantity IIQuantity I <= Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIOption A
Quantity I: A: B: C = 10000*24 : 15000*24 : 20000*18=2:3:3B=3/8 *400,000= Rs.150000
Quantity II: Salary after deduction = 20,000*12*80/100 = Rs.192000
Hence, Quantity I < Quantity II - Lalith can do a work in 16 days. Arul is 60% more efficient than Lalith.
Quantity I: Time taken by Lalith and Arul together to do the work.Quantity II: Time taken by Lalith and Arul to do the work together when Lalith works at doubles his original efficiency and Arul works at half his original efficiency.
Quantity I < Quantity IIQuantity I <= Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIOption C
Quantity I: Lalith =16 days; Arul= 16 * 100/160=10 daysLalith+arul together = 16*10/(26)=80/13 days
Quantity II: Lalith = 16 days; Arul = 10 days
Lalith (double efficiency) = 8 day; Arul (half efficiency) = 20 days
Lalith+Arul together = 80/14
Hence, Quantity I > Quantity II - A bag contains 3 Yellow, 4 black and 2 white balls. Two balls are drawn at random.
Quantity I: Probability that none of the flowers drawn is white.
Quantity II: Fraction of work completed by Thanu in 7 days if she is 20% more efficient than Meenu who can complete the work in 12 days.
Quantity I < Quantity IIQuantity I <= Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIOption A
Quantity I: 7C2/9C2=7/12Quantity II: Meenu-> 10 days => fraction of work in 7 days = 7/10
Hence, Quantity I < Quantity II
- The Person took a loan from bank at 12% P.A. simple interest. After 3 years he had to pay back Rs.16200 as interest.
Quantity I: Loan taken by person from the bank.
Quantity II: Amount after 2 years for a principal of Rs.35,000 at interest rate of 10% compounded annually.
Quantity I < Quantity IIQuantity I <= Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIOption C
Quantity I: P=16200*100/(3*12)=Rs.45,000Quantity II: A= 35000*121/100=Rs.42350
Hence, Quantity I > Quantity II
- A fisherman can row 9Kmph in still water. It takes him twice as long to row up as to row down the river.
Quantity I: Rate of stream.
Quantity II: Speed of a person in still water who can row upstream at 4kmph and downstream at 2kmph.
Quantity I < Quantity IIQuantity I <= Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIOption E
Quantity I: 9+y=2(9-y)y = 3kmph
Quantity II: x = (4+2)/2=3kmph
Hence Quantity I = Quantity II
- Quantity I: Train A crosses the pole in 28 sec at the speed of 90 kmph.
Quantity II: Train B crosses the 500 m platform in 54 sec at the speed of 108 kmph.
Quantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I <= Quantity IIQuantity I = Quantity IIOption A
Answer: b)Distance = speed * time
Quantity I:
Let the length of train A be x,
Then,
x = 90 * 5/18 * 28
x = 700 m
Quantity II:
Let the length of train B be x,
Then,
500 + x = 108 * 5/18 * 54
500 + x = 1620
x = 1120
Quantity I > Quantity II
- Quantity I: The Simple interest on that sum at the rate of 20 % per annum for 2 years is Rs. 1000.
Quantity II: Rs. 2500
Quantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I <= Quantity IIQuantity I = Quantity IIOption E
Quantity I:SI = pnr/100
1000= p * 20/100 * 2
p = Rs. 2500
Quantity II: Rs. 2500
Quantity I = Quantity II
- Quantity I: If the ratio of ages of Vishnu and Thaja, 5 years ago is 10: 16 and difference of their age is 30 years, then find the sum of the present age of Varun and Tharun?
Quantity II: If the average age of A, B, C and D is 40 years, then find the sum of the ages of all of them?
Quantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I <= Quantity IIQuantity I = Quantity IIOption C
Quantity I:The ratio of ages of Vishnu and Thaja, 5 years ago = 10: 16 (10x, 16x)
16x – 10x = 30
x = 5
Required sum = 16x + 10 = (16 * 5) + 10 = 90 years
Quantity II:
Required sum = 40 * 4 = 160 years
Quantity I < Quantity II
- Quantity I: A bag contains 3 orange balls and 4 blue balls. If one ball is taken out randomly, then find the probability of selecting the ball of blue color.
Quantity II: A bag contains 3 lime balls and 4 yellow balls. If one ball is taken out randomly, then find the probability of selecting the ball of lime color.
Quantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I <= Quantity IIQuantity I = Quantity IIOption A
Quantity I:Required probability = 4C1 / 7C1 = 4/7
Quantity II:
Required probability = 3C1 / 7C1 = 3/7
Quantity I > Quantity II
- Quantity I: Find the volume of the sphere, whose radius is 10.5 cm.
Quantity II: Find the volume of the cone whose height and diameter is 3.5 cm and 16 cm respectively?
Quantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I <= Quantity IIQuantity I = Quantity IIOption A
Quantity I:Volume of the sphere = (4/3)*πr3 = 4/3 * 22/7 * 10.5 * 10.5 * 10.5 = 4851 cm3
Quantity II:
Volume of the cone = (1/3)*πr2h = 1/3 * 22/7 * 16/2 * 16/2 * 3.5 = 234.66 cm3
Quantity I > Quantity II
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